I have a table 'tblBaseResults' setup like this
Column 1 = Name
Column 2 = Activity
The Activity column is supposed to be unique. However there are multiple Name fields. So im not sure how to get the Activity column to unique values and keep just one value from Name.
I would prefer to just keep the values from name that DO NOT have any '?' characters.
The current Count query i have works great. However i need only ONE of the Name fields to carry over with it
SELECT tblBaseResults.Activity, Count(tblBaseResults.Activity) AS CountOfActivity INTO tblCountResults
FROM tblBaseResults
GROUP BY DISTINCT tblBaseResults.Activity;
In Excel if i do a VLookup i get what i need, but want to do it in access.
INSERT INTO tblCountResults (Activity, Name, CountOfActivity)
SELECT Activity, min(Name), Count(tblBaseResults.Activity)
FROM tblBaseResults
WHERE instr(Name, '?') = 0
GROUP BY Activity
Related
suppose I Have below table
A
B
1
one
2
two
1
three
2
four
1
last
for value in A=1
then I need the output as one;three;last
how can I query this in Oracle's SQL?
If you care whether you get the string "one;three;last" or "three;one;last" or some other combination of the three values, you'd need some additional column to order the results by (a database table is inherently unordered). If there is an id column that you're not showing, for example, that could do that, you'd order by id in the listagg.
If you don't care what order the values appear in the result, you could do something like this
select listagg( b, ';' ) within group (order by a)
from your_table
where a = 1
Let's say there are 3 tables: Genders, Countries and Users. Users has among others a column named Gender and also a column named Country.
I want to add a new entry to Users and select one of the columns Male/Female {M, F} and a country from the rows of Countries dynamically just for testing purposes.
insert into dbo.[Users] (Gender, UserName, Country)
select Genders.Male, 'newbie', Countries.(the one which matches column CountryId) FROM Genders, Countries
I want to achieve this: 'M', 'newbie', MyCountry
After applying the suggestion from 'zip' I get the result 2 rows affected, same number as the external tables I'm referencing. The Query added 2 rows, so I guess I am missing the WHERE conditions.
The Genders Table is meant as a Property and will have only one row that I manually added.
Table Genders; 1 row
Male : uniqueidentifier
Female : uniqueidentifier
Countries is a table with many rows, so I want to select one matching the criteria of one of it's column values, say the value of column CountryId.
You can get a random value using:
insert into dbo.[Users] (Gender, UserName)
select top (1) g.Male, 'newbie'
from Genders.Male
order by newid();
I figuored the solution out. Thank you all who responded for pointing me in the right direction.
INSERT INTO dbo.[Users] (Gender, UserName, Country)
SELECT Genders.Male, 'newbie', Countries.CountryId
FROM Genders, Countries
WHERE Countries.ISO2 = '##'
'##' = 2 letter ISO of country.
Explanation:
1. INSERT INTO dbo.[Users] = Add a new row to Table "Users"
2. (Gender, UserName, Country) = Includes the columns in table "Users". If a column is not specified and it had a property of not allowing Nulls, an exception would be thrown!
3. FROM Genders, Countries = Include the external tables associated to look for
4. WHERE Countries.ISO2 = '##' = This condition allows you to precisely select which column of which row you seek. So I searched for a certain row where a column named ISO2 had a value '##' and looked then for the CountryId value in the same row (entry). There may be cases when multiple rows have identical value so you would have to further specify the conditions by using AND or OR oeprators.
When a table does not contain more than 1 row, I should not have to apply WHERE Conditions. It will select the default one existing. But because the Countries Table had multiple items (3 Rows), leaving the WHERE clause out, caused to add 3 times the same User, with each row having a distinct CountryId!
I have a SQL table with "name" as one column, date as another, and location as a third. The location column supports null values.
I am trying to write a query to determine the number of times a null value occurs in the location column for each distinct value in the name column.
Can someone please assist?
One method uses conditional aggregation:
select name, sum(case when location is null then 1 else 0 end)
from t
group by name;
Another method that involves slightly less typing is:
select name, count(*) - count(location)
from t
group by name;
use count along with filters, as you only requires Null occurrence
select name, count(*) occurances
from mytable
where location is null
group by name
From your question, you'll want to get a distinct list of all different 'name' rows, and then you would like a count of how many NULLs there are per each name.
The following will achieve this:
SELECT name, count(*) as null_counts
FROM table
WHERE location IS NULL
GROUP BY name
The WHERE clause will only retrieve records where the records have NULL as their location.
The GROUP BY will pivot the data based on NAME.
The SELECT will give you the name, and the COUNT(*) of the number of records, per name.
I have a table that has multiple rows for a distinct CARD_ID listing different roles assigned to that CARD_ID. I'd like to have a query that creates a single row for each distinct CARD_ID that has multiple columns listing the different roles. See image for example of current table. Duplicates are highlighted.
So, I'd like one row for CARD_IDs 1-10, with columns in each row for Cardholder, Reconciler, and Approver.
If a particular CARD_ID doesn't have one of those roles, I'm ok with that field being null or having some other type of indicator.
One method i conditional aggregation:
select card_id,
max(iif(role = 'Reconciler', col, NULL)) as reconciler_col,
max(iif(role = 'Approver', col, NULL)) as approver_col,
max(iif(role = 'Cardholder', col, NULL)) as cardholder_col
from t
group by card_id;
col is a column that you want to pivot. You can add more than one column, just by adding more max(iif . . .) to the select.
Sorry for the Title, But didn't know how to explain.
I have a table that have 2 fields A and B.
I want find all rows in the table that have duplicate A (more than one record) but at the same time A will consider as a duplicate only if B is different in both rows.
Example:
FIELD A Field B
10 10
10 10 // This is not duplicate
10 10
10 5 // this is a duplicate
How to to this in a single query
Let's break this down into how you would go about constructing such a query. You don't make it clear whether you're looking for all values of A or all rows but let's assume all values of A initially.
The first step therefore is to create a list of all values of A. This can be done two ways, DISTINCT or GROUP BY. I'm going to use GROUP BY because of what else you want to do:
select a
from your_table
group by a
This returns a single column that is unique on A. Now, how can you change this to give you the unique values? The most obvious thing to use is the HAVING clause, which allows you to restrict on aggregated values. For instance the following will give you all values of A which only appear once in the table
select a
from your_table
group by a
having count(*) = 1
That is the count of all values of A inside the group is 1. You don't want this of course, you want to do this with the column B. You need there to exist more than one value of B in order for the situation you want to identify to be possible (if there's only one value of B then it's impossible). This gets us to
select a
from your_table
group by a
having count(b) > 1
This still isn't enough as you want two different values of B. The above just counts the number of records with the column B. Inside an aggregate function you use the DISTINCT keyword to determine unique values; bringing us to:
select a
from your_table
group by a
having count(distinct b) > 1
To transcribe this into English this means select all unique values of A from YOUR_TABLE that have more than one values of B in the group.
You can use this method, or something similar, to build up your own queries as you create them. Determine what you want to achieve and slowly build up to it.
select FIELD from your_table group by FIELD having count(b) > 1
take in consideration that this will return count of all duplicate
example
if you have values
1
1
2
1
it will return 3 for value 1 not 2