I'm trying to fill a sort of table of arraylists.
The idea I'm tried doing is a two dimensional arraylist:
ArrayList<ArrayList<Integer>> mainAutresHauteValeur = new ArrayList<ArrayList<Integer>>();
except that in one dimension I always have N values
I tried initializing by adding null N times in one dimension but then I have a null pointer exception when I want to add an integer to the arraylist number I (0<=i<=N)
I also tried creating an arraylist and adding it N times to initialize it but then all the arraylists number I stay equal.
The idea I'm trying to conceive is a merging between a table in one direction and an arraylist in the other direction
i also tried creating an arraylist and adding it N times to initialize it but then all the arraylists number i stay equal...
Just add N different array lists instead of the same one; for instance, with something like this:
for (int i = 0; i < n; i++)
{
mainAutresHauteValeur.Add(new ArrayList<Integer>());
}
(Note that the above is pseudo-code; adapt as necessary for your language/libraries of choice.)
Related
The goal of this post is to find a more efficient way to create this method. Right now, as I start adding more and more values, I'm going to have a very messy and confusing app. Any help is appreciated!
I am making a workout app and assign an integer value to each workout. For example:
Where the number is exersiceInt:
01 is High Knees
02 is Jumping Jacks
03 is Jog in Place
etc.
I am making it so there is a feature to randomize the workout. To do this I am using this code:
-(IBAction) setWorkoutIntervals {
exerciseInt01 = 1 + (rand() %3);
exerciseInt02 = 1 + (rand() %3);
exerciseInt03 = 1 + (rand() %3);
}
So basically the workout intervals will first be a random workout (between high knees, jumping jacks, and jog in place). What I want to do is make a universal that defines the following so I don't have to continuously hard code everything.
Right now I have:
-(void) setLabelText {
if (exerciseInt01 == 1) {
exercise01Label.text = [NSString stringWithFormat:#"High Knees"];
}
if (exerciseInt01 == 2) {
exercise01Label.text = [NSString stringWithFormat:#"Jumping Jacks"];
}
if (exerciseInt01 == 3) {
exercise01Label.text = [NSString stringWithFormat:#"Jog in Place"];
}
}
I can already tell this about to get really messy once I start specifying images for each workout and start adding workouts. Additionally, my plan was to put the same code for exercise02Label, exercise03Label, etc. which would become extremely redundant and probably unnecessary.
What I'm thinking would be perfect if there would be someway to say
exercise01Label.text = exercise01Int; (I want to to say that the Label's text equals Jumping Jacks based on the current integer value)
How can I make it so I only have to state everything once and make the code less messy and less lengthy?
Three things for you to explore to make your code easier:
1. Count from zero
A number of things can be easier if you count from zero. A simple example is if your first exercise was numbered 0 then your random calculation would just be rand() % 3 (BTW look up uniform random number, there are much better ways to get a random number).
2. Learn about enumerations
An enumeration is a type with a set of named literal values. In (Objective-)C you can also think of them as just a collection of named integer values. For example you might declare:
typedef enum
{
HighKnees,
JumpingJacks,
JogInPlace,
ExerciseKindCount
} ExerciseCount;
Which declares ExerciseCount as a new type with 4 values. Each of these is equivalent to an integer, here HighKnees is equivalent to 0 and ExerciseKindCount to 3 - this should make you think of the first thing, count from zero...
3. Discover arrays
An array is an ordered collection of items where each item has an index - which is usually an integer or enumeration value. In (Objective-)C there are two basic kinds of arrays: C-style and object-style represented by NSArray and NSMutableArray. For example here is a simple C-style array:
NSString *gExerciseLabels[ExerciseKindCount] =
{ #"High Knees",
#"Jumping Jacks",
#"Jog in Place"
}
You've probably guessed by now, the first item of the above array has index 0, back to counting from zero...
Exploring these three things should quickly show you ways to simplify your code. Later you may wish to explore structures and objects.
HTH
A simple way to start is by putting the exercise names in an array. Then you can access the names by index. eg - exerciseNames[exerciseNumber]. You can also make the list of exercises in an array (of integers). So you would get; exerciseNames[exerciseTable[i]]; for example. Eventually you will want an object to define an exercise so that you can include images, videos, counts, durations etc.
I have a label that I want to set its text as an object from and array peopleQuestionArray. I have generated an random int with values ranging from 1-4. My array currently has 4 objects in it. I expect that either the first, second, third, or fourth objects in my array will be displayed, but instead xcode gave me and exception. Does anyone know why. Here's the code I used to set the labels text :
int random = (arc4random() % 4) +1;
[quesetionLabel setText:[peopleQuestionArray objectAtIndex:random]];
Your index may go out of range. NSArray indices start from 0. So you need to generate a random number ranging from 0-3, not 1-4. Remove the +1 while calculating the random number.
So I recently had this as an interview question and I was wondering what the optimal solution would be. Code is in Objective-c.
Say we have a very large data set, and we want to get a random sample
of items from it for testing a new tool. Rather than worry about the
specifics of accessing things, let's assume the system provides these
things:
// Return a random number from the set 0, 1, 2, ..., n-2, n-1.
int Rand(int n);
// Interface to implementations other people write.
#interface Dataset : NSObject
// YES when there is no more data.
- (BOOL)endOfData;
// Get the next element and move forward.
- (NSString*)getNext;
#end
// This function reads elements from |input| until the end, and
// returns an array of |k| randomly-selected elements.
- (NSArray*)getSamples:(unsigned)k from:(Dataset*)input
{
// Describe how this works.
}
Edit: So you are supposed to randomly select items from a given array. So if k = 5, then I would want to randomly select 5 elements from the dataset and return an array of those items. Each element in the dataset has to have an equal chance of getting selected.
This seems like a good time to use Reservoir Sampling. The following is an Objective-C adaptation for this use case:
NSMutableArray* result = [[NSMutableArray alloc] initWithCapacity:k];
int i,j;
for (i = 0; i < k; i++) {
[result setObject:[input getNext] atIndexedSubscript:i];
}
for (i = k; ![input endOfData]; i++) {
j = Rand(i);
NSString* next = [input getNext];
if (j < k) {
[result setObject:next atIndexedSubscript:j];
}
}
return result;
The code above is not the most efficient reservoir sampling algorithm because it generates a random number for every entry of the reservoir past the entry at index k. Slightly more complex algorithms exist under the general category "reservoir sampling". This is an interesting read on an algorithm named "Algorithm Z". I would be curious if people find newer literature on reservoir sampling, too, because this article was published in 1985.
Interessting question, but as there is no count or similar method in DataSet and you are not allowed to iterate more than once, i can only come up with this solution to get good random samples (no k > Datasize handling):
- (NSArray *)getSamples:(unsigned)k from:(Dataset*)input {
NSMutableArray *source = [[NSMutableArray alloc] init];
while(![input endOfData]) {
[source addObject:[input getNext]];
}
NSMutableArray *ret = [[NSMutableArray alloc] initWithCapacity:k];
int count = [source count];
while ([ret count] < k) {
int index = Rand(count);
[ret addObject:[source objectAtIndex:index]];
[source removeObjectAtIndex:index];
count--;
}
return ret;
}
This is not the answer I did in the interview but here is what I wish I had done:
Store pointer to first element in dataset
Loop over dataset to get count
Reset dataset to point at first element
Create NSMutableDictionary for storing random indexes
Do for loop from i=0 to i=k. Each iteration, generate a random value, check if value exists in dictionary. If it does, keep generating a random value until you get a fresh value.
Loop over dataset. If the current index is within the dictionary, add it to a the array of random subset values.
Return array of random subsets.
There are multiple ways to do this, the first way:
1. use input parameter k to dynamically allocate an array of numbers
unsigned * numsArray = (unsigned *)malloc(sizeof(unsigned) * k);
2. run a loop that gets k random numbers and stores them into the numsArray (must be careful here to check each new random to see if we have gotten it before, and if we have, get another random, etc...)
3. sort numsArray
4. run a loop beginning at the beginning of DataSet with your own incrementing counter dataCount and another counter numsCount both beginning at 0. whenever dataCount is equal to numsArray[numsCount], grab the current data object and add it to your newly created random list then increment numsCount.
5. The loop in step 4 can end when either numsCount > k or when dataCount reaches the end of the dataset.
6. The only other step that may need to be added here is before any of this to use the next command of the object type to count how large the dataset is to be able to bound your random numbers and check to make sure k is less than or equal to that.
The 2nd way to do this would be to run through the actual list MULTIPLE times.
// one must assume that once we get to the end, we can start over within the set again
1. run a while loop that checks for endOfData
a. count up a count variable that is initialized to 0
2. run a loop from 0 through k-1
a. generate a random number that you constrain to the list size
b. run a loop that moves through the dataset until it hits the rand element
c. compare that element with all other elements in your new list to make sure it isnt already in your new list
d. store the element into your new list
there may be ways to speed up the 2nd method by storing a current list location, that way if you generate a random that is past the current pointer you dont have to move through the whole list again to get back to element 0, then to the element you wish to retreive.
A potential 3rd way to do this might be to:
1. run a loop from 0 through k-1
a. generate a random
b. use the generated random as a skip count, move skip count objects through the list
c. store the current item from the list into your new list
Problem with this 3rd method is without knowing how big the list is, you dont know how to constrain the random skip count. Further, even if you did, chances are that it wouldnt truly look like a randomly grabbed subset that could easily reach the last element in the list as it would become statistically unlikely that you would ever reach the end element (i.e. not every element is given an equal shot of being select.)
Arguably the FASTEST way to do this is method 1, where you generate the random numerics first, then traverse the list only once (yes its actually twice, once to get the size of the dataset list then again to grab the random elements)
We need a little probability theory. As others, I will ignore the case n < k. The probability that the n'th item will be selected into the set of size k is just C(n-1, k-1) / C(n, k) where C is the binomial coefficient. A bit of math says shows that this is just k/n. For the rest, note that the selection of the n'th item is independent of all other selections. In other words, "the past doesn't matter."
So an algorithm is:
S = set of up to k elements
n = 0
while not end of input
v = next value
n = n + 1
if |S| < k add v to S
else if random(0,1) >= k/n replace a randomly chosen element of S with v
I will let the coders code this one! It's pretty trivial. All you need is an array of size k and one pass over the data.
If you care about efficiency (as your tags suggest) and the number of items in the population is known, don't use reservior sampling. That would require you to loop through the entire data set and generate a random number for each.
Instead, pick five values ranges from 0 to n-1. In the unlikely case, there is a duplicate among the five indexes, replace the duplicate with another random value. Then use the five indexes to do a random-access lookup to the i-th element in the population.
This is simple. It uses a minimum number of calls the random number generator. And it accesses memory only for the relevant selections.
If you don't know the number of data elements in advance, you can loop-over the data once to get the population size and proceed as above.
If you aren't allow to iterate over the data more than once, use a chunked form of reservior sampling: 1) Choose the first five elements as the initial sample, each having a probability of 1/5th. 2) Read in a large chunk of data and choose five new samples from the new set (using only five calls to Rand). 3) Pairwise, decide whether to keep the new sample item or old sample element (with odds proportional the the probablities for each of the two sample groups). 4) Repeat until all the data has been read.
For example, assume there are 1000 data elements (but we don't know this in advance).
Choose the first five as the initial sample: current_sample = read(5); population=5.
Read a chunk of n datapoints (perhaps n=200 in this example):
subpop = read(200);
m = len(subpop);
new_sample = choose(5, subpop);
loop-over the two samples pairwise:
for (a, b) in (current_sample and new_sample): if random(0 to population + m) < population, then keep a, otherwise keep *b)
population += m
repeat
Premesis:
I am using ActionScript with two arraycollections containing objects with values to be matched...
I need a solution for this (if in the framework there is a library that does it better) otherwise any suggestions are appreciated...
Let's assume I have two lists of elements A and B (no duplicate values) and I need to compare them and remove all the elements present in both, so at the end I should have
in A all the elements that are in A but not in B
in B all the elements that are in B but not in A
now I do something like that:
for (var i:int = 0 ; i < a.length ;)
{
var isFound:Boolean = false;
for (var j:int = 0 ; j < b.length ;)
{
if (a.getItemAt(i).nome == b.getItemAt(j).nome)
{
isFound = true;
a.removeItemAt(i);
b.removeItemAt(j);
break;
}
j++;
}
if (!isFound)
i++;
}
I cycle both the arrays and if I found a match I remove the items from both of the arrays (and don't increase the loop value so the for cycle progress in a correct way)
I was wondering if (and I'm sure there is) there is a better (and less CPU consuming) way to do it...
If you must use a list, and you don't need the abilities of arraycollection, I suggest simply converting it to using AS3 Vectors. The performance increase according to this (http://www.mikechambers.com/blog/2008/09/24/actioscript-3-vector-array-performance-comparison/) are 60% compared to Arrays. I believe Arrays are already 3x faster than ArrayCollections from some article I once read. Unfortunately, this solution is still O(n^2) in time.
As an aside, the reason why Vectors are faster than ArrayCollections is because you provide type-hinting to the VM. The VM knows exactly how large each object is in the collection and performs optimizations based on that.
Another optimization on the vectors is to sort the data first by nome before doing the comparisons. You add another check to break out of the loop if the nome of list b simply wouldn't be found further down in list A due to the ordering.
If you want to do MUCH faster than that, use an associative array (object in as3). Of course, this may require more refactoring effort. I am assuming object.nome is a unique string/id for the objects. Simply assign that the value of nome as the key in objectA and objectB. By doing it this way, you might not need to loop through each element in each list to do the comparison.
I am not sure how this is possible but I have a for loop not incrementing properly through an array.
Basically what I have is:
for (AISMessage *report in disarray){
NSLog(#"Position of array = %ld\n", [aisArray indexOfObject:report]);
}
There is more code in the loop but is nothing strange just formatting some of the data in the object and outputting it to a file.
The output of these lines would look something like:
Position of array = 0
...
Posiiton of array = 78176
Posiiton of array = 78177
Posiiton of array = 78178
Posiiton of array = 78178
Posiiton of array = 78180
Posiiton of array = 78181
...
Posiiton of array = 490187
For some reason the report at index 78178 gets read in twice and the report at 78179 gets skipped completely.
Any ideas on what may cause this?
I am totally confused.
Thanks in advance,
Jason
The object occurs twice in the array, so the indexOfObject finds the element at index 78179 at index 78178.
In other words, you have this case:
...
[78177] = x
[78178] = y
[78179] = y
[78180] = z
...
Also, you're not searching the same array you're iterating over, that might have something to do with it as well.
Since the positions reported are so high, I would try to find a better data structure than a simple array. For it to report a position of 78178, it will have to have compared the object against the preceeding 78177 elements, and this will only take more and more time as you get further into the array.
From the posted code you are iterating over AISMessage objects in the disarray array, but you are reporting on the position of the object in the aisArray array.
I have no idea if these are meant to be the same array or not. But if they are different arrays, then do you expect the objects to be in the same order?