I have a table and its width is to fit the size of the window.
I've a couple of FormField and PlainTextContentControls used in this table.
But the FormField text input fields are small in width by default.
I want the size of these FormField text input fields to fit the size of this cell.
How can I achieve this?
If I am not wrong (And I could be wrong), the formfields have a predefined size and expand only when you fill the data in. There is no predefined setting which you can set to increase the width.
Alternative way to increase the width.
Increasing the font size of it but this will also increase the height of the formfield.
Fill the Default Text with spaces.
Related
Is there any hack for v-aligning images in a cell
I am trying to create a dashboard,those traffic lights are images.
Since once of the columns is a text-wrap and the height of those rows
are dynamic, I have no way of knowing the row height to calculate the y_offset for those images
Does anyone have a recommendation on how I can handle this? Is there a way of getting the row_height after sheet.write and text_wrap format is applied?
Is there a way of getting the row_height after sheet.write and text_wrap format is applied?
Probably not without access to Windows APIs for calculating bounding boxes for strings.
You could probably make some working estimates based on the length of your string. Each new line in text wrap is equal to 15 character units or 20 pixels.
Since once of the columns is a text-wrap and the height of those rows are dynamic, I have no way of knowing the row height to calculate the y_offset for those images
This is the main problem. In order to specify the image position exactly you will need to specify explicit row heights so that XlsxWriter can calculate where the image will go based on the size of the cell. In order words you will have to avoid the automatic row height that Excel gives you when wrapping text.
Once the row height is fixed you can position images exactly where you want them using the 'x_offset' and 'y_offset' options.
Note, you can also use conditional formatting to create traffic lights based on cell values. See Sheet9/Example 9 of this code from the XlsxWriter docs and image below. These can be centered automatically even with with text wrapping.
I'm working with python-ppt to create a portfolio of candidates in a Powerpoint presentation. There is one candidate per slide and each of them has provided information about themselves like name, contacts and a minibio (the problem I'm here to solve)
The text_frame, created with values of height and width, must fit the slide but must a contain all lenght of minibios, which is not happening.
In a long phase (>200 char, with font size 12) it exceeds the size of the text box and get "out" of the slide, so, in presentation mode or a PDF file, the "overrun" of text is lost
Is there any way to confine the text to the shape/size of the text_frame? (extra help if the solution wont change font size)
Just found one parameter that helped to find the answer
When creating a text_box object with slides.shapes.add_textbox() and adding a text_frame to it, the text_frame.word_wrap = True limits the text to be contained inside the dimentions of the text_box
The code shows it better
# creates text box with add_textbox(left, top, width, height)
txBox = slide.shapes.add_textbox(Cm(16),Cm(5),Cm(17),Cm(13))
tf = txBox.text_frame
tf.word_wrap = True
Before word_wrap parameter
After word_wrap parameter
The short answer is "No". PowerPoint is a page-layout environment, and much like the front page of a newspaper, text "story" content needs to be trimmed to fit the allotted space.
We're perhaps not used to this because word-processing, spreadsheet, and web-page content is "flowed" into a (practically) unlimited space, but the area of a PowerPoint slide is quite finite. Also, using it for large text blocks is somewhat of an off-label use. There is a certain amount of flexibility provided by reducing the font size, but not as much as one might expect. Even accommodating 20% additional text requires what appears as a pretty radical change in font size.
I've encountered this problem again and again, and the only solution I have ever seen work reliably is hand-curating the content to fit.
python-pptx has one experimental feature to address this but its operation has never been very satisfactory and it's tricky to get working. https://python-pptx.readthedocs.io/en/latest/api/text.html#pptx.text.text.TextFrame.fit_text
The business of fitting text is the role of a rendering engine, which python-pptx is not.
What is the default measurement unit of Excel cell size? Is it Point or Pixel or Millimeter ?
By default, excel cell Row height is 15, what is the meaning of this value? Is it 15 Pixels or 15 Points
By default, excel cell Column Width is 8.43, what is the meaning of this value? Is it 8.43 Pixels or 8.43 Points
If both row and column units are same, then Row height should be smaller than to column width. But the measurement is reverse, row height shows bigger number than column width. In Cell appearance also, row is small than column width.
I need to create box with Height 90 mm (millimeter) and Width 195 mm (millimeter). Please let me know what are values to be put in Row and Column textboxes.
Thanks in advance.
The default units for column and row are indeed different when accessed through the GUI.
The displayed column width in the GUI refers to the Range.ColumnWidth property, where One unit of column width is equal to the width of one character in the Normal style. For proportional fonts, the width of the character 0 (zero) is used (source). This means as you change the worksheet style, your column width may change too.
The height, however, displays a normal height in points.
In VBA, you can both get both this font-related unit, and the normal point unit for the width. For the height, you can only get the value in points:
Debug.Print Range("A1").ColumnWidth '8.43 characters wide by default
Debug.Print Range("A1").Width '48 points wide by default
Debug.Print Range("A1").Height '12.75 points high by default
Of course, you can calculate a conversion factor between character width and points: Range("A1").Width / Range("A1").ColumnWidth = 5.69 when using Arial, 10 pt. This means that if you want to have a size of 195mm by 90mm, you need to enter 97.0777 as column width, and 255.118 as column height if you're using Arial, 10 pt as normal style.
As per the Microsoft documentation....
You can specify a row height of 0 (zero) to 409. This value represents the height measurement in points (1 point equals approximately 1/72 inch or 0.035 cm). The default row height is 12.75 points (approximately 1/6 inch or 0.4 cm). If a row has a height of 0 (zero), the row is hidden.
Read it more here.
Please throw this link: Microsoft reference
You can change and define this unit manually where pointed in above link:
On the File tab, click Options, click the Advanced category, and under Display, select an option from the Ruler Units list.
So please visit Here Microsoft reference that exactly explain
what you asked.
Above you asked are the pixel width retranslated into character units (based on the Normal font) for display.
I have a PDF, which has WinAnsiEncoding(Times) and it do not have any toUnicode or differences encoding.
When I try to select or highlight text, width of text is not calculated properly.
I have all the widths but somehow width is calculated incorrectly. What can be the problem? How can I get correct CID of character in order to find correct width of the glyph? I have attached screenshots for the same. "EXPLANATIONS" word is not selected completely. This can happen only if the widths of glyph are calculated incorrectly.
I want to print bill on a roll paper using vb.net.
The requirements are as follows:
The width of the page is 300 pixels or 3 inches.
The height of the page is variable, depending on the number of the rows in the datagrid.
The page header will have an image.
The names of the items could be long, so they should not be chopped, rather print on the next line.
How should I go about it?
Get your Image height and xRows (dgv.rows.count) * Rowheight
So you have an Dynamic height.
Additional you could count string lengtht of your long Values and add for longer datarows the addidtional height
But that is just my idea.
Im sure there are better solutions