Assistance with creating SQL query - sql

Question

I'm trying to create a query that only returns rows with objects that have three or more orders in a week's timeframe and are only orders submitted after 9/1/13.
SELECT OrderID, DateSubmitted, ObjectID = i.ObjectID
FROM dbo.Object i
JOIN dbo.Order j
ON i.ObjectID = j.ObjectID
WHERE DateSubmitted >= '9/1/2013'
I just can't figure out how to narrow the results to those objects with three or more orders in a week. I've tried numerous GROUP BY and HAVING clauses with no luck. Any help would be greatly appreciated.

Answer 1

Try:
SELECT ObjectID
FROM dbo.Object i
JOIN dbo.Order j ON J.ObjectID = i.ObjectID
WHERE DateSubmitted >= '9/1/2013'
GROUP BY ObjectID
HAVING COUNT(1) >=3

Answer 2

not sure but i need more info on the tables
best guess is in sql
SELECT count(OrderID), i.ObjectID
FROM dbo.Object i
JOIN dbo.Order j
ON i.ObjectID = j.ObjectID
group by i.ObjectID
having DateSubmitted >= '9/1/2013' and count(OrderID)>2

Answer 3

based on your last comments the query you looking for is very simple. use the DatePart function and find out WEEK of that object's order-date. check the below query. also unless you data base is configured already by default Sunday(int 7) is the First Day set in the SQL server. so you for this query purpose you need to set Monday(int 1) as the first day of Week.
you can check the current setting by executing SELECT ##DATEFIRST
if same object has places 3 or more times for multiple weeks below query is returning that object for each of that week. if you needed only Objects then you can skip weekNumber from result set and do Distinct ObjectID.
Do not forget to Reset the DATEFIRST setting to its original Value at the END.
DECLARE #Object TABLE
(
objectID INT
)
DECLARE #Order TABLE
(
orderID INT
,objectID INT
,DateSubmitted DATE
)
INSERT INTO #Object( objectID )
SELECT 1 UNION ALL SELECT 2 UNION ALL SELECT 3 UNION ALL SELECT 4 UNION ALL SELECT 5 UNION ALL SELECT 6
INSERT INTO #Order ( orderID, objectID, DateSubmitted )
SELECT 1,1,'10/2/2013'
UNION ALL SELECT 2,1,'10/3/2013'
UNION ALL SELECT 3,1,'10/5/2013'
UNION ALL SELECT 4,1,'10/09/2013'
UNION ALL SELECT 5,1,'10/10/2013'
UNION ALL SELECT 6,1,'10/13/2013'
UNION ALL SELECT 4,2,'10/15/2013'
UNION ALL SELECT 5,2,'10/16/2013'
UNION ALL SELECT 6,2,'10/21/2013'
UNION ALL SELECT 7,3,'09/02/2013'
UNION ALL SELECT 8,3,'09/03/2013'
UNION ALL SELECT 9,3,'09/04/2013'
DECLARE #CurrentDateFirst INT=##DATEFIRST
SET DATEFIRST 1;
SELECT i.objectID,DATEPART(week,DateSubmitted) AS weekNumber
FROM #Object i
JOIN #Order j
ON i.ObjectID = j.ObjectID
WHERE DateSubmitted >= '9/1/2013'
GROUP BY i.objectID,DATEPART(week,DateSubmitted)
HAVING(COUNT(DISTINCT orderID) >= 3)
ORDER BY i.objectID
SET DATEFIRST #CurrentDateFirst

Answer 4

Convoluted, but I think this will get you what you want...
With WeekSets As
(
Select i.ObjectID,
j.DateSubmitted,
j2.OrderID
From dbo.Object i
JOIN dbo.Order j
ON i.ObjectID = j.ObjectID
JOIN dbo.Order j2
On j.DateSubmitted <= j2.DateSubmitted
And j2.DateSubmitted < DateAdd(Day,7,j.DateSubmitted)
And j.ObjectID = j2.ObjectID
WHERE j.DateSubmitted >= '9/1/2013'
), GroupsOfThree As
(
Select ObjectID,
DateSubmitted
From WeekSets
Group By ObjectID,
DateSubmitted
Having Count(OrderID) >= 3
)
Select Distinct j.OrderID,
j.DateSubmitted,
w.ObjectID
From GroupsOfThree g
Join WeekSets w
On g.ObjectID = w.ObjectID
And g.DateSubmitted = w.DateSubmitted
Join dbo.Order j
On w.ObjectID = j.ObjectID
And w.OrderID = j.OrderID