I have table called TrainingMatrix and it has a column called ExpiryDate. I am trying to write an SQL statement which can show me all records of 2012 as following:
SELECT * FROM "TrainingMatrix" WHERE "ExpiryDate" - current_date < 0 AND EXTRACT(YEAR FROM TIMESTAMP "ExpiryDate") = 2012;
But this doesn't work, can any one help?
I am using PostgreSQL.
No timestamp word when using column:
... AND EXTRACT(YEAR FROM "ExpiryDate") = 2012 ...
If you have index on ExpiryDate column - it's better to avoid using functions and have exact date/timestamp range:
and "ExpiryDate">='2012-01-01' and "ExpiryDate"<'2013-01-01';
Related
Im new to SQL. I have a field (ContractDays) with an integer (number of days from a datediff) and want to create a date field with a value of todays date minus the number in ContractDays field. Can you help please?
If you are using mssql. You can do this:
SELECT DATEADD(day, -ContractDays, GETDATE())
FROM Table1
MS SQL contains datetime as number value. Integer part is number of days since 1/1/1753.
So you can write
select GetDate() - ContractDays
But it is better to use DATEADD
You need to alter the table in Oracle, MySQL or MS SQL to add a new column, let's call it ContractDate.
After you have this column, you need to update it to have the correct value.
Oracle:
update Contracts
set ContractDate = (SYSDATE - ContractDays)
MySQL:
update Contracts
set ContractDate = date_add(now(), INTERVAL -ContractDays DAY)
MS SQL (courtesy to Arion):
update Contracts
set ContractDate = DATEADD(day, -ContractDays, GETDATE())
I'm writing a SQL query on a timesheet report. I need the report to return only the details for the week of the selected date.
E.g., if I pick 02/01/2012 (dd/MM/yyyy), then it should only return results between 02/01/2012 and 08/01/2012.
Thanks
SELECT
*
FROM
yourTable
WHERE
dateField >= #yourDate
AND dateField < #yourDate + 7
Some variations of SQL may have specific ways of adding 7 days to a datevalue. Such as...
- DateAdd(Day, 7, #date)
- DATE_ADD(#date, INTERVAL 7 DAYS)
- etc, etc
This option is both index friendly, and is resilient to database fields that have time parts as well as date parts.
You easiest is the equivalent of WEEK_OF_YEAR function in your SQL engine
But you can also use DATE_ADD
WHERE table.date BETWEEN target_date AND DATE_ADD(target_date,INTERVAL 7 DAY)
That depends on the database system you're using. MySQL has a function calles WEEK(), SQL Server can do something like this with the DATEPART() function:
MySQL:
SELECT
*
FROM table
WHERE WEEK(date_col) = WEEK('02/01/2012');
SQL SERVER:
SELECT
*
FROM table
WHERE DATEPART(WEEK, datecol) = DATEPART(WEEK,'02/01/2012');
SELECT * FROM table_name
WHERE date BETWEEN '1/02/2012' AND '1/08/2012';
you can replace the example date with your date and yourdate + 6.
Look here for example: http://www.roseindia.net/sql/sql-between-datetime.shtml
Suppose I have a date 2010-07-29. Now I would like to check the result of one day ahead. how to do that
For example,
SELECT *
from table
where date = date("2010-07-29")
How to do one day before without changing the string "2010-07-29"?
I searched and get some suggestion from web and I tried
SELECT *
from table
where date = (date("2010-07-29") - 1 Day)
but failed.
MySQL
SELECT *
FROM TABLE t
WHERE t.date BETWEEN DATE_SUB('2010-07-29', INTERVAL 1 DAY)
AND '2010-07-29'
Change DATE_SUB to DATE_ADD if you want to add a day (and reverse the BETWEEN parameters).
SQL Server
SELECT *
FROM TABLE t
WHERE t.date BETWEEN DATEADD(dd, -1, '2010-07-29')
AND '2010-07-29'
Oracle
SELECT *
FROM TABLE t
WHERE t.date BETWEEN TO_DATE('2010-07-29', 'YYYY-MM-DD') - 1
AND TO_DATE('2010-07-29', 'YYYY-MM-DD')
I used BETWEEN because the date column is likely DATETIME (on MySQL & SQL Server, vs DATE on Oracle), which includes the time portion so equals means the value has to equal exactly. These queries give you the span of a day.
If you're using Oracle, you can use the + and - operators to add a number of days to a date.
http://psoug.org/reference/date_func.html
Example:
SELECT SYSDATE + 1 FROM dual;
Will yield tomorrow's date.
If you're not using Oracle, please tell use what you ARE using so we can give better answers. This sort of thing depends on the database you are using. It will NOT be the same across different databases.
Depends of the DateTime Functions available on the RDBMS
For Mysql you can try:
mysql> SELECT DATE_ADD('1997-12-31',
-> INTERVAL 1 DAY);
mysql> SELECT DATE_SUB('1998-01-02', INTERVAL 31 DAY);
-> '1997-12-02'
If youre using MSSQL, you're looking for DateAdd() I'm a little fuzzy on the syntax, but its something like:
Select * //not really, call out your columns
From [table]
Where date = DateAdd(dd, -1, "2010-07-29",)
Edit: This syntax should be correct: it has been updated in response to a comment.
I may have the specific parameters in the wrong order, but that should get you there.
In PL SQL : select sysdate+1 from dual;
I need some help figuring out and SQL Statement.
I know what I want I just cant express it.
Im using php, so it doesnt need to be exclusivly SQL, its to act as a filter.
Pseudo code
$query="SELECT * FROM MyTable WHERE 'TIS' is not older than 2 days or empty = ''$ORDER"; }
TIS in the name of the column in my table were I store dates in this format 03-12-09 (d,m,y).
The $ORDER is for ordering the values based on values from other fields not dates.
Im looking at
SELECT *
FROM orders
WHERE day_of_order >
(SELECT DATEADD(day,-30, (SELECT MAX(day_of_order) FROM orders)) AS "-30 Days");
But i dont quite think im on the rigth track with this.
Thanks
Try the following:
SELECT *
FROM MyTable
WHERE COALESCE(TIS, SYSDATE) > SYSDATE - INTERVAL '2' DAY
$ORDER
I don't know what database you're using - the above uses Oracle's method of dealing with time intervals. If you're using SQL Server the following should be close:
SELECT *
FROM MyTable
WHERE COALESCE(TIS, GETDATE()) > DATEADD(Day, -2, GETDATE())
$ORDER
In MySQL try this:
SELECT *
FROM MyTable
WHERE COALESCE(TIS, NOW()) > DATE_SUB(NOW(), INTERVAL 2 DAYS)
$ORDER
I hope this helps.
So, I was pretty lost in all this.
How did it got solved:
First I understood that the Statement I was using was not supported by MySql thanks to eligthment from Bob Jarvis.
_ Second In a comment by vincebowdren wich "strongly" adviced me to change the data type on that field to Date wich indeed I had not, it was a string.
It was pretty Dumb for me to try using SQL operations for Dates on a field that had String values.
So I just RTFM: http://dev.mysql.com/doc/refman/5.1/en/date-and-time-functions.html
and:
mysql> SELECT something FROM tbl_name
-> WHERE DATE_SUB(CURDATE(),INTERVAL 30 DAY) <= date_col;
Then proceeded to change the field value to date.
and this is my perfectly working query:
$query="SELECT * FROM MyTable WHERE DATE_SUB(CURDATE(),INTERVAL 2 DAY) <= TIS OR TIS = 0000-00-00 $ORDER "; }
I would like to thank the posters for their aid.
using a Oracle 10g db I have a table something like this:
create table x(
ID NUMBER(10) primary key,
wedding DATE NOT NULL
);
how can I
select * from x where wedding is in june 2008???
I know it is probably an easy one but I couldn't find any satisfying answer so far.
Help is very much appreciated.
Use:
SELECT *
FROM x
WHERE x.wedding BETWEEN TO_DATE('2008-JUN-01', 'YYYY-MON-DD')
AND TO_DATE('2008-JUL-01', 'YYYY-MON-DD')
Use of TO_DATE constructs a date with a time portion of 00:00:00, which requires the end date to be one day ahead unless you want to use logic to correct the current date to be one second before midnight. Untested:
TO_DATE('2008-JUN-30', 'YYYY-MON-DD') + 1 - (1/(24*60*60))
That should add one day to 30-Jun-2008, and then subtract one second in order to return a final date of 30-Jun-2008 23:59.
References:
TO_DATE
This is ANSI SQL, and supported by oracle as of version 9i
SELECT *
FROM x
WHERE EXTRACT(YEAR FROM wedding) = 2008
AND EXTRACT(MONTH FROM wedding) = 06
Classic solution with oracle specific TO_CHAR():
SELECT *
FROM x
WHERE TO_CHAR(wedding, 'YYYY-MMM') = '2008-JUN'
(the latter solutions was supported when dinosaurs still walked the earth)