Transform select count(*) inside a inner join - sql

My problem here is that i'm modifying an existing query and i cannot use count(*) in the query.
I have to use inner join subqueries.
What i need to "transform" into my inner join is like this (this works):
SELECT count(distinct t1.id)
FROM table1 t1
WHERE t1.column1 = 'value1' AND
t2.column2 = 'value2' AND
EXISTS(select 1 from table2 t2 where t2.id = t1.id)
My global query looks like this:
SELECT [many many column]
FROM table2 t2
INNER JOIN [...]
LEFT OUTER JOIN [...]
--[I NEED MY COUNT HERE, see below for example]
WHERE [some conditions are true]
ORDER BY [some column]
What i found to help me is something like this:
SELECT [many many column], myJoin.Count
FROM table2 t2
INNER JOIN (
SELECT tt2.id, count(distinct tt2.id) as Count
FROM table2 tt2
WHERE EXISTS (SELECT 1 FROM table1 tt1 where tt1.id = tt2.id)
GROUP BY tt2.id) myJoin
on t2.id = myJoin.id;
See what i'm trying to acheive? I need to count the ids, joining 2 tables, but i can't have a count in my main query, i can't possibly copy-paste all the "group by" condition that would go with it...
I'm on sql server.
If i find the answer i will come back and post it.
Thanks for any advice/tricks about this.

How about the following:
SELECT table2.*, TopQ.MyCount
FROM (
SELECT t2.id, myJoin.MyCount
FROM table2 t2
INNER JOIN (
SELECT tt2.id, count(distinct tt2.id) as MyCount
FROM table2 tt2
WHERE EXISTS
(SELECT 1 FROM table1 tt1 where tt1.id = tt2.id)
GROUP BY tt2.id) AS myJoin
on t2.id = myJoin.id
)AS TopQ
INNER JOIN table2 ON TopQ.id = table2.id

I came across this:
select count(distinct t1.id) over (partition by t1.aColumn) as myCount,
[many many column]
from table2 t2
inner join table1 t1 on [someConditions] = value1 and
[someConditions] = value2 and
t2.id = t1.id;
I get the same results as my first select i posted in my question, and without adding a "group by" anywhere and a lot of inner join that im not that familliar with. I'm gonna stick with this solution.
Thanks!

Related

How do I look for non-matching values across 3 SQL tables?

I'm looking to do what I believe is a double-nested check across three tables, but have no idea how to do so.
I have Table1, Table2, and Table3.
All are tied by an ID and a "Longform" and "Shortform" in Table1:
I'm trying to find:
Entries whose IDs appear in Table2 that have the same Longform as those in Table3, but don't share the same Shortform.
This is about as far as I've gotten:
SELECT T2.Longform,T2.Shortform FROM(
SELECT Table1.Longform,Table1.Shortform,Table1.ID FROM OuterTable1.Table1
LEFT JOIN OuterTable2.Table2 on Table1.ID = Table2.ID)
WHERE Table2.ID IS NOT NULL) T2
;
I know I'm probably going to have to do another nested select, or a join, on Outertable3.Table3 but I'm not sure which... Or where...
Any help appreciated as always.
Try the following:
Select *
(
Select T1.*
from T2
inner join T1
on T1.ID = T2.ID
) as Tab
inner join
(
Select T1.*
from T3
inner join T1
on T1.ID = T3.ID
) as Tab2
on Tab.id = Tab2.id
and Tab.Longform = Tab2.Longform
and Tab.Shortform <> Tab2.Shortform
To get the longform join table1 to table2 or table3. Then use EXISTS to check in a subquery if the IDs of table1 are different but the longform is equal.
SELECT *
FROM table2 t21
INNER JOIN table1 t11
ON t11.id = t21.id
WHERE EXISTS (SELECT *
FROM table3 t32
INNER JOIN table1 t12
ON t12.id = t32.id
WHERE t12.id <> t11.id
AND t12.longform = t11.longform);
Assuming ID is unique in all three tables
Select t2.id,t2.shortform, t1.shortform AS shortformTab1, t2.longform
FROM table2 t2
JOIN table3 t3
ON t2.id = t3.id AND t2.longform = t3.longform
JOIN table1 t1
ON t2.id = t1.id AND t2.shortform != t1.shortform

Convert to join query

select t.* from table1 t where t.id NOT IN(
select Id from t2 where usrId in
(select usrId from t3 where sId=value));
I the result i need is like if there are matching id's in t1 and t2 then those id's should be omitted and only the remaining rows should be given to me. I tried converting into join but it is giving me the result i wanted. Below is my join query.
SELECT t.* FROM table1 t JOIN table2 t2 ON t.Id <> t2.Id
JOIN table3 t3 ON t3.Id=t2.Id WHERE t3.sId= :value
This doesn't feth me the correct result. it was returning all the rows, but i want to restrict the result based on the matching id's in table t1 and table t2. Matching id's should be ommited from the result.I will be passing the value for sId.
I believe this to be an accurate refactor of your query using joins. I don't know if we can do away with the subquery, but in any case the logic appears to be the same.
select t1.*
from table1 t1
left join
(
select t2.Id
from table2 t2
inner join table3 t3
on t2.usrId = t3.usrId
where t3.sId = <value>
) t2
on t1.Id = t2.Id
where t2.Id is null
Let's break down and solve problem step by step.
So your query
select t.* from table1 t where t.id NOT IN(
select Id from t2 where usrId in
(select usrId from t3 where sId=value));
on converting the inner query to JOIN will yield
select t.* from table1 t where t.id NOT IN
(SELECT T2.ID FROM T2 JOIN T3 on T2.UsrID =T3.UsrID and T3.sID=value)
which on further converting to JOIN with outer table will be
select t.* from table1 t LEFT JOIN
(SELECT T2.ID FROM T2 JOIN T3 on T2.UsrID =T3.UsrID and T3.sID=value)t4
ON t.id =T4.ID
WHERE t4.ID is NULL
In case you completely want to remove sub-query you can try like this
SELECT t.*
FROM table1 t
LEFT JOIN T2
ON T.ID=T2.ID
LEFT JOIN T3
ON T3.UsrId=T2.UsrID AND T3.sId=value
WHERE T3.UsrID IS NULL

SQL Query, how to get data from two tables

Table 1:
ID (unqiue), Name, Address
Table 2:
RecordId, ID (key of table 1), Child name
In one query, I want to retrieve all rows of Table 1 with one additional column which will be the count of all record in table 2 from ID (that is number of children for each ID in table 1). Can't figure out how to format a query to retrieve this data.
Simply Join and apply count
select T1.*, COUNT(T2.RECORDID)AS T2COUNT from Table1 T1
INNER JOIN TABLE2 T2 ON T1.ID= T2.ID
--LEFT JOIN TABLE2 T2 ON T1.ID= T2.ID --if you need 0 child records (from commets by #Cha)
GROUP BY T1.ID , T1.Name, T1.Address
The correct way of doing this will be with a OUTER JOIN:
SELECT a.ID, a.Name, a.Address, b.cnt
FROM Table1 a
LEFT OUTER JOIN
(SELECT ID, count(*) cnt from Table2 GROUP BY ID) b
ON a.ID = b.ID
The incorrect way will be with a help of a correlated sub-query:
SELECT a.ID, a.Name, a.Address,
(SELECT count(*) FROM Table2 b WHERE b.ID = a.ID) as cnt
FROM Table1 a
Here is a discussion about correlated subqueries vs OUTER JOINs, if you are interested
Group by table1 fields and count total records in table2:
here T1 alias of table1 and T2 alias of table2.
select T1.ID, T1.Name, T1.Address, count(T2.ID) as total_records
from table1 as T1
left outer join table2 as T2 on T2.ID=T1.ID
group by T1.ID, T1.Name, T1.Address

Applying joins conditionally in SQL Server

I have some set of records, but now i have to select only those records from this set which have theeir Id in either of the two tables.
Suppose I have table1 which contains
Id Name
----------
1 Name1
2 Name2
Now I need to select only those records from table one
which have either their id in table2 or in table3
I was trying to apply or operator witin inner join like:
select *
from table1
inner join table2 on table2.id = table1.id or
inner join table3 on table3.id = table1.id.
Is it possible? What is the best method to approach this? Actually I am also not able to use
if exist(select 1 from table2 where id=table1.id) then select from table1
Could someone help me to get over this?
Use left join and then check if at least one of the joins has found a relation
select t1.*
from table1 t1
left join table2 t2 on t2.id = t1.id
left join table3 t3 on t3.id = t1.id
where t2.id is not null
or t3.is is not null
I would be inclined to use exists:
select t1.*
from table1 t1
where exists (select 1 from table2 t2 where t2.id = t1.id) or
exists (select 1 from table3 t3 where t3.id = t1.id) ;
The advantage to using exists (or in) over a join involves duplicate rows. If table2 or table3 have multiple rows for a given id, then a version using join will produce multiple rows in the result set.
I think the most efficient way is to use UNION on table2 and table3 and join to it :
SELECT t1.*
FROM table1 t1
INNER JOIN(SELECT id FROM Table2
UNION
SELECT id FROM Table3) s
ON(t.id = s.id)
Alternatively, you can use below SQL as well:
SELECT *
FROM dbo.Table1
WHERE id Table1.IN ( SELECT table2.id
FROM dbo.table2 )
OR Table1.id IN ( SELECT table3.id
FROM Table3 )

sql left outer join order by column in left table but preserve all rows

I have the following:
SELECT
table1.id
FROM
table1
LEFT OUTER JOIN table2 ON table2.table1_id = table1.id
WHERE
(table1.entry_id=2)
AND
parent_id=0
ORDER BY
SUM(table2.column1) - SUM(table2.column2)
Works fine until I add the 'order by', I need it to get all relevant rows from table1, even if they have unmatched rows in table2, ordering would place them at the bottom.
Try this instead:
SELECT
t1.id
FROM table1 AS t1
LEFT OUTER JOIN
(
SELECT table1_id, SUM(column1) sum1, SUM(column2) sum2
FROM table2
GROUP BY table1_id
) AS t2 ON t2.table1_id = t.id
AND t1.entry_id = 2
AND t1.parent_id = 0
ORDER BY t2.sum1 - t2.sum2;