Oracle Order By different columns same select statement - sql

Question

I have an interesting problem here. But it is just for knowledge because I already solve it in a non elegant way.
I have a table that have costumers and they can be holders or dependants and this relation is described as a
family. Each family can have only a holder and 0-n dependants. A holder is identified by an H and a Dependant by a D.
What I need is a way to order the data by name of holder and theirs dependants. So the sample data below
idcostumer name idfamily relation
1 Natalie Portman 1 H
2 Mark Twain 3 D
3 Carl Sagan 2 D
4 Bob Burnquist 2 H
5 Sheldon Cooper 1 D
6 Anakin Skywalker 4 H
7 Luke Skywalker 4 D
8 Leia Skywalker 4 D
9 Burnquist Jr. 2 D
10 Micheal Jackson 3 H
11 Sharon Stone 1 H
12 Michelle Pfeiffer 3 D
Is it possible to get the above results in just one query? As you can see the order is name (just for the holders)
idcostumer name idfamily relation
6 Anakin Skywalker 4 H
8 Leia Skywalker 4 D
7 Luke Skywalker 4 D
4 Bob Burnquist 2 H
9 Burnquist Jr. 2 D
3 Carl Sagan 2 D
10 Micheal Jackson 3 H
2 Mark Twain 3 D
12 Michelle Pfeiffer 3 D
11 Sharon Stone 1 H
1 Natalie Portman 1 D
5 Sheldon Cooper 1 D
The test case data for this example.
create table costumer (
idcostumer integer primary key,
name varchar2(20),
idfamily integer,
relation varchar2(1)
);
This is the inserts statments for this table:
insert into costumer values ( 1 , 'Natalie Portman' , 1, 'D');
insert into costumer values ( 2 , 'Mark Twain' , 3, 'D');
insert into costumer values ( 3 , 'Carl Sagan' , 2, 'D');
insert into costumer values ( 4 , 'Bob Burnquist' , 2, 'H');
insert into costumer values ( 5 , 'Sheldon Cooper' , 1, 'D');
insert into costumer values ( 6 , 'Anakin Skywalker' , 4, 'H');
insert into costumer values ( 7 , 'Luke Skywalker' , 4, 'D');
insert into costumer values ( 8 , 'Leia Skywalker' , 4, 'D');
insert into costumer values ( 9 , 'Burnquist Jr.' , 2, 'D');
insert into costumer values ( 10, 'Micheal Jackson' , 3, 'H');
insert into costumer values ( 11, 'Sharon Stone' , 1, 'H');
insert into costumer values ( 12, 'Michelle Pfeiffer', 3, 'D');
I've tried some things, create a father sun relationship with connect by statement and familyid concatenated with the relation.
Used a row_count with a over clause ordering by relation desc and family id, but this way I lost the name order.

Answer 1

If I understand you correctly, you want to first order the families by the name of the holder, then by the names of the dependents. The following does that.
with family_order as (
select idfamily, rownum r from (
select idfamily from costumer where relation = 'H' order by name
)
)
select c.* from costumer c
inner join family_order fo on c.idfamily = fo.idfamily
order by fo.r, relation desc, name
Fiddle here

Answer 2

Try:
select * from table order by idfamily desc, relation desc, name asc
Link to Fiddle
For un-natural order you can use "union all":
select * from (select idcostumer, name, idfamily, relation from costumer
where idfamily > 3
order by idfamily desc, relation desc, name asc)
union all
select * from (
select idcostumer, name, idfamily, relation from costumer
where idfamily = 2
order by idfamily desc, relation desc, name asc)
union all
select * from (
select idcostumer, name, idfamily, relation from costumer
where idfamily != 2 and idfamily < 4
order by idfamily desc, relation desc, name asc)
Link to Fiddle