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SQL transpose full table
(1 answer)
Closed 9 years ago.
Hello I am new to SQL and would really appreciate some help with transposing a table as follows. Looking at similar posts it seems that this may be accomplished with pivot/unpivot, but I am not sure since the examples I read about have much fewer columns. Any suggestions would be great!
Table.
CATEGORY Value1 Value2 Value3 Value4 ... Value15
Hot 18 17 9 17 ... 18
Warm 5 3 0 1 ... 3
Cold 20 2 1 2 ... 2
Desired Result.
CATEGORY Hot Warm Cold
Value1 18 5 20
Value2 17 3 2
Value3 9 0 1
Value4 17 1 2
… … … …
Value15 18 3 2
select *
from tbl
unpivot (value for name in (Value1, Value2, Value3, Value4, ... Value15)) unpiv
pivot (max(value) for category in ([hot],[warm],[cold])) piv
The following is a simple code i tried out. Just run and see if it meets your requirement!!
declare #Tbl1 table(Category Varchar(10), Value1 Int, Value2 Int, Value3 Int, Value4 Int, Value5 Int)
insert into #Tbl1(Category, Value1, Value2, Value3, Value4, Value5)
Values ('Hot', 12, 23, 43, 5, 6)
insert into #Tbl1(Category, Value1, Value2, Value3, Value4, Value5)
Values ('Warm', 41, 28, 4, 45, 16)
insert into #Tbl1(Category, Value1, Value2, Value3, Value4, Value5)
Values ('Cold', 1, 3, 543, 15, 26)
select * from #Tbl1
Declare #TblUP Table(Category Varchar(100), Value Int, [Types] Varchar(10))
Insert into #TblUP(Category, Value, Types)
select * from #Tbl1 unpivot ([values] for Types in (Value1, Value2, Value3, Value4, Value5)) as UNPIV
select * from #TblUP
Select Types, Hot, Warm, Cold
From
(Select Types, Category, Value from #TblUP) as TUP
PIVOT (SUM(Value) for [Category] in ([Hot], [Warm], [Cold]))
as PT
Related
Assume we have the following records:
Id
Column A
Column B
Column C
Common
1
Value1
Value2
Value3
12
2
Value1
Value2
Value3
13
3
Value1
Value2
Value3
08
4
Value1
Value2
Value3
10
5
Value4
Value5
Value6
18
6
Value4
Value5
Value6
22
7
Value4
Value5
Value6
37
How can we get the following result
Id
Column A
Column B
Column C
CommonCount
1
Value1
Value2
Value3
4
5
Value4
Value5
Value6
3
I wrote this query:
SELECT
jr.*,
CommonCount = (SELECT COUNT(1)
FROM la.JudicialReference AS jr1
WHERE ((jr.ColumnA = jr1.ColumnA)
OR ISNULL(jr.ColumnA, jr1.ColumnA) IS NULL)
AND ((jr.ColumnB = jr1.ColumnB)
OR ISNULL(jr.ColumnB, jr1.ColumnB) IS NULL)
AND ((jr.ColumnC = jr1.ColumnC)
OR ISNULL(jr.ColumnC, jr1.ColumnC) IS NULL))
FROM
la.JudicialReference AS jr
But it doesn't get me the first Id and I'm looking for a better query to save IO
Simply
SELECT MIN(ID), ColumnA, ColumnB, ColumnC, COUNT(*)
FROM la.JudicialReference
GROUP BY ColumnA, ColumnB, ColumnC
Optionally with HAVING COUNT(*) > 1
I have table as below. If I need to create another table as shown in the output, how can I do it?
CREATE TABLE TestTable
(JobID int, isAllowType1 bit, value1 int, isAllowType2 bit, value2 int)
;
INSERT INTO TestTable
(JobID, isAllowType1, value1, isAllowType2, value2)
VALUES
(1, 1, 11, 0, 111),
(2, 0, 22, 1, 222),
(3, 1, 33, 0, 333)
;
--output
JOBID isAllow Value Type
1 1 11 Type1
1 0 111 Type2
2 0 22 Type1
2 1 222 Type2
3 1 33 Type1
3 0 333 Type2
You can use the query the type1 and type2 records separately, and use the union all operator to combine the results:
SELECT jobid, isAllowType1 AS isAllow, value1 AS value, 'Type1' AS type
FROM testtable
UNION ALL
SELECT jobid, isAllowType1 AS isAllow, value1 AS value, 'Type2' AS type
FROM testtable
To add to Mureinik's answer, you can create a new table using result of a UNION ALL like so:
select *
into new_table
from (
select JobID,
isAllowType1 isAllowType,
value1 value,
'Type1' Type
from TestTable
union all
select JobID,
isAllowType2,
value2,
'Type2'
from TestTable
) t
I need to build a SQL query in SQL SERVER 10.50.1600.1. I have the following model situation:
id1 | value1
id1 | value2
id2 | value1
id3 | value1
id3 | value2
...
and would like to end up in a situation as
id1 | value1 | value2
id2 | value1 | null
id3 | value1 | value2
...
I only know that for each id[n] there are at most 4 values recorded.
EDIT: I know there are at most 4 values for each, but they could be anything. They can be any number included in [0, 9000] or a string (about 10 possibilities). My bad, I didn't explain well.
If you know the values in advance, and the values are unique per ID (as they seem to be from your question statement) it's fairly straightforward:
-- Setup
declare #a table (id nvarchar(50), value nvarchar(50))
insert #a(id, value) values
('id1', 'value1'),
('id1', 'value2'),
('id2', 'value1'),
('id3', 'value1'),
('id3', 'value2')
;
SELECT id,
MAX(CASE value WHEN 'value1' THEN value END) AS value1,
MAX(CASE value WHEN 'value2' THEN value END) AS value2,
MAX(CASE value WHEN 'value3' THEN value END) AS value3,
MAX(CASE value WHEN 'value4' THEN value END) AS value4
FROM #a
GROUP BY id
Below query will help you :-
declare #test table (id nvarchar(50), value nvarchar(50))
insert #test(id, value) values
('id1', 'value1'),
('id1', 'value2'),
('id1', 'value3'),
('id1', 'value4'),
('id2', 'value1'),
('id3', 'value1'),
('id3', 'value2'),
('id3', 'value3');
select ROW_NUMBER() OVER (PARTITION BY id ORDER BY id) AS ROWNUM,id,value into #t1 from #test
SELECT distinct id,
(select value from #t1 b where b.id=a.id AND b.ROWNUM=1) AS Value1,
(select value from #t1 b where b.id=a.id AND b.ROWNUM=2) AS Value2,
(select value from #t1 b where b.id=a.id AND b.ROWNUM=3) AS Value3,
(select value from #t1 b where b.id=a.id AND b.ROWNUM=4) AS Value4
FROM #t1 a
drop table #t1
Output :-
id Value1 Value2 Value3 Value4
id1 value1 value2 value3 value4
id2 value1 NULL NULL NULL
id3 value1 value2 value3 NULL
Assumtion: TABLE: table_name(id_column, value_column). With each value of id_column there are at most 4 values of value_column
Then you could use this
WITH tmp as
(SELECT
*
,ROW_NUMBER() over (PARTITION BY id_column order by value_column) rwn
FROM
table_name
)
SELECT
id_column
,MAX(CASE WHEN rwn = 1 THEN value_column END) value1
,MAX(CASE WHEN rwn = 2 THEN value_column END) value2
,MAX(CASE WHEN rwn = 3 THEN value_column END) value3
,MAX(CASE WHEN rwn = 4 THEN value_column END) value4
FROM
tmp
GROUP BY
id_column;
I have the following table:
oDate value1 value2 value3 value4
2014-06-01 10 20 30 40
2014-06-02 20 25 35 50
I want to have the following result
oDate oField oValue
2014-06-01 Value1 10
2014-06-01 Value2 20
2014-06-01 Value3 30
2014-06-01 Value4 40
Is it possible to do that in SQL?
Need advice. Cheers,
You could do this:
Test data:
DECLARE #tbl TABLE(oDate DATETIME,value1 INT,value2 INT,value3 INT,value4 INT)
INSERT INTO #tbl
VALUES
('2014-06-01',10,20,30,40),
('2014-06-02',20,25,35,50)
UNPIVOT query
SELECT
*
FROM
(
SELECT
oDate,
value1,
value2,
value3,
value4
FROM
#tbl
) sourceTable
UNPIVOT
(
oField FOR oValue IN
(value1,value2,value3,value4)
) AS unpvt
Reference:
Using PIVOT and UNPIVOT
Try this
SELECT DISTINCT ODATE,VALUE,FIELD
FROM
(SELECT odate,value1,value2,value3,value4
FROM #temp) p
UNPIVOT
(VALUE FOR FIELD IN
(value1,value2,value3,value4)
)AS unpvt;
GO
How about this?
select
oDate,
'Value1' as oField,
value1 as oValue
from yourTable
union all
select
oDate,
'Value2' as oField,
value2 as oValue
from yourTable
union all
select
oDate,
'Value3' as oField,
value3 as oValue
from yourTable
union all
select
oDate,
'Value4' as oField,
value4 as oValue
from yourTable
order by oDate, oField
I have the following row from a table in MSSQL
Person | value1 | value2 | value3 | value4
John | 4 | 7 | 1 | 2
I want this row sorted according to the values as shown below.
Person | value2 | value1 | value4 | value3
John | 7 | 4 | 2 | 1
May be I'm asking a stupid question , I want the column names to be sorted according to the values in those column.
I know that this can be achieved using query
SELECT *
FROM tableName
ORDER BY value2, value1, value4, value3 DESC
But when I change the any column value, I have to change the query to get the result sorted.
Please help...
-- sample data
declare #t table
(
person varchar(50),
value1 int,
value2 int,
value3 int,
value4 int
)
insert into #t select 'John', 4, 7, 1, 2
insert into #t select 'Name1', 14, 7, 1, 16
insert into #t select 'Name2', 24, 8, 1, 2
-- query
select
person, v1 = [1], v2 = [2], v3 = [3], v4 = [4]
from
(
select person, rn = row_number() over(partition by person order by a desc), a
from #t t1
unpivot
(
a for b in (value1, value2, value3, value4)
) t2
) t1
pivot
(
max(a) for rn in ([1], [2], [3], [4])
) t2
unless I'm missing something, you should just append 'order by person, value2, value1, value4, value3' at the end of your select statement.
I think you want:
SELECT Person, Value2, Value1, Value4, Valuer
FROM YourTable
try this:
SELECT * FROM tableName ORDER BY value2, value1, value4, value3 DESC