Use the result from one column to make column names - sql

Question

I have select statement, something like:
select trim(time), type, count(1) from table
group by trim(time),type
The results are:
02.10.13 REZ1 1
02.10.13 REZ2 5
02.10.13 REZ3 3
Is it possible to make some select statement with some Oracle function to get the following result:
REZ1 REZ2 REZ3
1 5 3
So, results from one column are column names in the other statement, something like:
select ?SOMETHING?
from (
select trim(time), type, count(1)
from table
group by trim(time),type) s

Answer 1

WITH t(l_date, val, l_count)
AS
(SELECT to_date('02.10.13', 'dd.mm.yy'), 'REZ1' , 1 FROM dual UNION
SELECT to_date('02.10.13', 'dd.mm.yy'), 'REZ2' , 5 FROM dual UNION
SELECT to_date('02.10.13', 'dd.mm.yy'), 'REZ3' , 3 FROM dual
)
SELECT *
FROM
( SELECT val, l_count FROM t
) PIVOT (MAX(l_count) FOR (val) IN ('REZ1' REZ1,'REZ2' REZ2 ,'REZ3' REZ3));

Answer 2

Perhaps you can try the SQL alternative for this:
SELECT MAX(CASE type
WHEN 'REZ1' THEN cnt
ELSE NULL
END) AS REZ1,
MAX(CASE type
WHEN 'REZ2' THEN cnt
ELSE NULL
END) AS REZ2,
MAX(CASE type
WHEN 'REZ3' THEN cnt
ELSE NULL
END) AS REZ3
FROM (SELECT trim(time), type, count(1) as cnt FROM table
GROUP BY trim(time), type);
Or even better:
SELECT COUNT(CASE type
WHEN 'REZ1' THEN 1
ELSE NULL
END) AS REZ1,
COUNT(CASE type
WHEN 'REZ2' THEN 1
ELSE NULL
END) AS REZ2,
COUNT(CASE type
WHEN 'REZ3' THEN 1
ELSE NULL
END) AS REZ3
FROM table;
OUTPUT:
REZ1 | REZ2 | REZ3
1 | 5 | 3
This is applicable when you know the values in the type column. Even pivot, which is available in 11g, requires you to know the values in the column in order to pivot this as described in ajmalmhd04's answer.

Answer 3

Assuming the 2nd column will not have any value other than REZ1..3 then following solution will transpose the table data and take care of repetition as well by adding up the values.
WITH t
AS (SELECT TO_DATE ('02.10.13', 'dd.mm.yy') AS dt,
'REZ1' AS typ,
1 AS cnt
FROM DUAL
UNION
SELECT TO_DATE ('02.10.13', 'dd.mm.yy') AS dt,
'REZ2' AS typ,
5 AS cnt
FROM DUAL
UNION
SELECT TO_DATE ('02.10.13', 'dd.mm.yy') AS dt,
'REZ3' AS typ,
3 AS cnt
FROM DUAL
UNION
SELECT TO_DATE ('03.10.13', 'dd.mm.yy') AS dt,
'REZ1' AS typ,
7 AS cnt
FROM DUAL
UNION
SELECT TO_DATE ('03.10.13', 'dd.mm.yy') AS dt,
'REZ2' AS typ,
2 AS cnt
FROM DUAL)
SELECT dt,
SUM (CASE WHEN typ = 'REZ1' THEN cnt ELSE 0 END) AS "REZ1",
SUM (CASE WHEN typ = 'REZ2' THEN cnt ELSE 0 END) AS "REZ2",
SUM (CASE WHEN typ = 'REZ3' THEN cnt ELSE 0 END) AS "REZ3"
FROM t
GROUP BY dt;
DT REZ1 REZ2 REZ3
--------- ---------- ---------- ----------
02-OCT-13 1 5 3
03-OCT-13 7 2 0
2 rows selected.
Incase column#2 is going to have random values, probably some kind of cursor needs to use to tweak this query for considering dynamic columns.
I will try to post that if I able to get that designed.

Answer 4

select trim(time),
count(decode(type, 'REZ1', 1)) AS REZ1,
count(decode(type, 'REZ2', 1)) AS REZ2,
count(decode(type, 'REZ3', 1)) AS REZ3
from table
group by trim(time)