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Let's assume I have a table: Where x is value of chose1 and y value of chose2
ID Chose1 Chose2 x y
1 A B 2 3
2 C D 3 5
From this I would like to get something like this: Where z is x*y (if chose is empty,y=1).
NR ID Chose1 Chose2 z
1 1 A 2
2 1 A B 6
3 1 B 3
4 2 C 3
5 2 C D 15
6 2 D 5
This select statement will get the data above with the examples you gave:
select (ID-1)*3+1 as NR, id, Choose1, null as Choose2, x as z from tbl_values
union
select (ID-1)*3+2, id, Choose1, Choose2, x*y from tbl_values
union
select (ID-1)*3+3, id, null, Choose2, y from tbl_values
order by NR
Demo here (tested in MySQL, SQL Server): http://sqlfiddle.com/#!2/5af4b/3
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Example tables:
Table A Table B
A 1
B 2
C 3
Expected output:
A 1
A 2
A 3
B 1
B 2
B 3
C 1
C 2
C 3
You need a cross join between the two tables:
SELECT a.column_a, b.column_b
FROM a
CROSS JOIN b
ORDER BY a.column_a, b.column_b
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Need to write SQL query for getting below output with the given input table:
Input Table:
Col1
1
2
3
Output:
Col1
1
2
2
3
3
3
WITH CTE(NN)AS
(
SELECT 1 UNION ALL
SELECT 2 UNION ALL
SELECT 3 UNION ALL
SELECT 4 UNION ALL
SELECT 5
)
SELECT C.NN
FROM CTE AS C
CROSS JOIN CTE C2
WHERE C2.NN<=C.NN
CTE is your input table
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This is the table I have and I have 5 distinct programs. when a user like a program it reads as follows:
User Program
----------------
A 1
A 4
B 2
B 4
B 5
However I want to write a query that will allow me to also see the 5 distinct programs for each of my user and create a new column that will take two value (binary) 1 if the user liked a specific program and if not 0. Any help will be appreciated. Thanks
User Program NewColumn
A 1 1
A 2 0
A 3 0
A 4 1
A 5 0
B 1 0
B 2 1
B 3 0
B 4 1
B 5 1
You can do this with a cross join and left join:
select u.user, p.program,
(case when t.user is not null then 1 else 0 end) as NewCol
from (select distinct user from table) u cross join
(select distinct program from table) p left join
table t
on u.user = t.user and p.program = t.program;
Note: You may already have tables with the users and the programs. If so, use those instead of the subqueries.
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Hi all
i am facing a problem and need a query for that ,
I have a table and data like
----------
seq_id run_id mark_Flag
1 10 A
2 11 A
3 12 A
4 13 Z
5 14 A
6 15 A
7 16 Z
8 17 Z
9 18 A
10 19 A
11 20 Z
----------
Now i required the output like
seq runidFrom runidTo mark_Flag
1 10 12 A
2 13 13 Z
3 14 15 A
4 16 17 Z
5 18 19 A
6 20 20 Z
Thanks in advance ....
Try this query the main idea is to group by count of previous Mark_flag not equal to current
SELECT min(run_id),max(run_id),max(mark_Flag)
FROM T as T1
GROUP BY mark_flag,
(
SELECT COUNT(*) FROM T
WHERE seq_id<T1.seq_id
and
mark_flag<>T1.Mark_flag
)
ORDER BY MIN(seq_id)
SQLFiddle demo
This query have to work on any database system but when you post a question please add a tag with your RDBMS (not just SQL) so a query can be optimized for your data base system.
UPD: Here is the MS SQL version:
SELECT min(run_id),max(run_id),max(mark_Flag)
FROM
(
Select run_id, mark_flag,seq_id,
(
SELECT COUNT(*) FROM T
WHERE seq_id<T1.seq_id
and mark_flag<>T1.Mark_flag
) as group_id
From t as T1
) as T2
GROUP BY mark_flag,group_id
ORDER BY MIN(seq_id)
SQLFiddle demo
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CNo Wno Lno
12 1 1
12 1 2
12 2 3
12 3 15
9 1 1
13 1 1
13 2 2
13 3 5
10 1 1
10 1 2
10 1 3
10 2 4
11 1 1
for Cno i need the missing sequence numbers in Lno
Eg:
for Cn0=12
the line no is missing from 4 to 14
and for Cno=13 the sequence number(3,4) of Lno is missing
i need to find out the missing sequence no's for the clno
You can use common table expression for generating range of numbers and then find missing ones:
with cte as (
select t.CNo, min(t.Lno) as Lno, max(t.Lno) as max_Lno from Table1 as t
group by t.CNo
union all
select c.CNo, c.Lno + 1 as Lno, c.max_Lno
from cte as c
where c.Lno < c.max_Lno
)
select c.Cno, c.Lno
from cte as c
where
not exists (
select *
from Table1 as t
where t.CNo = c.CNo and t.Lno = c.Lno
)
order by 1, 2
option (maxrecursion 0);
if you have tables with sequential numbers, you can do this:
select c.Cno, n.n as Lno
from numbers as n
inner join (
select
tt.CNo, min(tt.Lno) as min_Lno, max(tt.Lno) as max_Lno
from Table1 as tt
group by tt.CNo
) as c on c.min_Lno <= n.n and c.max_Lno >= n.n
where
not exists (
select *
from Table1 as t
where t.CNo = c.CNo and t.Lno = n.n
)
order by 1, 2;
sql fiddle demo
not 100% sure what you are trying to do but you could use a number table to help with this.
if you have a table called numbers like this:
number
1
2
3
4
5.. up to highest number you are interested in
then you could do something like:
select
n.number
from
numbers as n
left outer join table as t
on n.number = t.Lno
and t.cno = 12
where
n.number <= (select max(lno) from table where cno = 12)
and t.nco is null
I don't know what type of output you are looking for or how you want to select the missing numbers you are looking for.