Course name
Section number
Course type
MATH 101
1
In person
MATH 101
2
In person
MATH 101
3
Online
MATH 101
4
In person
SOC 101
1
In person
SOC 101
2
In person
SOC 101
3
In person
ENGL 201
1
In person
ENGL 201
2
Online
ENGL 201
3
Online
ENGL 201
4
In person
PHY 101
1
Online
PHY 101
2
Online
From this table, I'd like to count Courses with only an 'In person' course, an 'Online' course, and both course types.
The query I tried is below.
SELECT
SUM(CASE WHEN coursetype = 'Inperson' AND coursetype = 'Online' THEN 1 ELSE 0 END) AS bothtype,
SUM(CASE WHEN coursetype = 'Online' THEN 1 ELSE 0 END) AS Onlineonly,
SUM(CASE WHEN coursetype = 'Inperson' THEN 1 ELSE 0 END) AS Onlineonly
From Course
The result what I expected is
bothtpye
Onlineonly
Inpersononly
2
1
1
but I got
bothtpye
Onlineonly
Inpersononly
0
7
6
Please advise me to get through this.
Thank you.
My solution uses double conditional aggregation.
SELECT SUM (CASE WHEN In_Person > 0 AND Online > 0 THEN 1 ELSE 0 END) as bothtype,
SUM (CASE WHEN In_Person > 0 AND Online = 0 THEN 1 ELSE 0 END) as inpersononly,
SUM (CASE WHEN In_Person = 0 AND Online > 0 THEN 1 ELSE 0 END) as onlineonly
FROM (
SELECT Course_name,
SUM(CASE WHEN Course_type='In Person' THEN 1 ELSE 0 END) as In_Person,
SUM(CASE WHEN Course_type='Online' THEN 1 ELSE 0 END) as Online
FROM Course
GROUP BY Course_name
) tot
DEMO Fiddle
SUGGESTION ( using PL/SQL ! ) :
CREATE PROCEDURE countCourses(OUT bothtype INT,OUT Inpersononly INT,OUT Onlineonly INT)
begin
SELECT COUNT(*) INTO bothtype FROM Course;
select COUNT(*) INTO Inpersononly FROM Course
WHERE courseType = "In person";
select COUNT(*) INTO Onlineonly FROM Course
WHERE courseType = "Online";
end;
call countCourses(#bothtype,#Inpersononly,#Onlineonly);
SELECT #bothtype,#Inpersononly,#Onlineonly;
EXPLICATION :
Creating procedure to store the count of each type of course in OUT variable
Call the procedure with convenient parameters
Select out given parameters
I have two tables which I can generate with SELECT statements (joining multiple tables) as follows:
Table 1:
ID
Site
type
time
1
Dallas
2
01-01-2021
2
Denver
1
02-01-2021
3
Chicago
1
03-01-2021
4
Chicago
2
29-11-2020
5
Denver
1
28-02-2020
6
Toronto
2
11-05-2019
Table 2:
ID
Site
collected
deposited
1
Denver
NULL
29-01-2021
2
Denver
01-04-2021
29-01-2021
3
Chicago
NULL
19-01-2020
4
Dallas
NULL
29-01-2019
5
Winnipeg
13-02-2021
17-01-2021
6
Toronto
14-02-2020
29-01-2020
I would like the result to be grouped by Site, having on each column the COUNT of type=1 , type=2, deposited and collected, all of the 4 columns between a selected time interval. Example: (interval between 01-06-2020 and 01-06-2021:
Site
type1
type2
deposited
collected
Dallas
0
1
0
0
Denver
1
0
2
1
Chicago
1
1
0
0
Toronto
0
0
0
0
Winnipeg
0
0
1
1
How about union all and aggregation?
select site,
sum(case when type = 1 then 1 else 0 end) as type_1,
sum(case when type = 2 then 1 else 0 end) as type_2,
sum(deposited) as deposited, sum(collected) as collected
from ((select site, type, 0 as deposited, 0 as collected
from table1
) union all
(select site, null,
(case when deposited is not null then 1 else 0 end),
(case when collected is not null then 1 else 0 end)
from table2
)
) t12
group by site;
Combine your tables 1 and 2 with a join on Site
Use COUNT(CASE WHEN type = 1 then 1 END) as type1 and a similar construct for type 2
Use COUNT(CASE WHEN somedate BETWEEN '2020-06-01' and '2021-06-01' then 1 END) as ... for your dates
I have the following SQLite DB table app_vendor:
app | vendor | active
---------------------
123 | 10 | 1
123 | 20 | 0 // + 1 (10 is 1, 20 is 0)
255 | 10 | 1
255 | 20 | 0 // + 1 (10 is 1, 20 is 0)
675 | 10 | 0
675 | 20 | 0 // 0 (10 is 0, 20 is 0)
I would like to run a query that compares, in all occurrences of the same app:
if vendor 10 is active: 1 and vendor 20 is not: 0 and
return a count of how many times that happens throughout this DB table.
In the example above, it happens twice (for app 123 and app 255) so the return value should be 2. I'm new to SQL and I have no idea how to group together by 'app', for example.
If for all apps there is 1 row (top) for vendor 10 and 1 row (top) for vendor 20 then:
SELECT DISTINCT COUNT(*) OVER() counter
FROM app_vendor
WHERE vendor IN (10, 20)
GROUP BY app
HAVING MIN(CASE WHEN vendor = 10 THEN active END) = 1
AND MAX(CASE WHEN vendor = 20 THEN active END) = 0
Another way to do it with INTERSECT:
SELECT COUNT(*) counter
FROM (
SELECT app FROM app_vendor WHERE vendor = 10 AND active = 1
INTERSECT
SELECT app FROM app_vendor WHERE vendor = 20 AND active = 0
)
See the demo.
Results:
counter
2
select count(1)
from (select * from test where vendor = 10 and active = 1) t1
join (select * from test where vendor = 20 and active = 0) t2
on t1.app = t2.app;
One way is to use conditional aggregation
select count(*)
from (select app
from t
group by app
having max(case when vendor=10 and active=1 then 1 end)
+ max(case when vendor=20 and active=0 then 1 end) = 2) t2
I want to be able to count the total type of apples (organic only) from each continent, broken down by countries; including the total count if they're mixed.
For example, food item B1 is organic golden apples from the USA. Thus there should be a count of "1" golden_bag and "1" for organic. Now, A1 is also organic from Argentina - however, it has both granny and red delicious apples - thus it is counted as "1" mixed_bag and "1" for granny_bag and "1" for red_bag as well.
Finally, E1 and F1 are both fuji apples from laos, but one is organic the other isn't; so total count is 2 fuji_bag and it should have a total count of 1 for organic_fd.
Table X:
food_item | food_area | food_loc | food_exp
A1 lxgs argentina 1/1/20
B1 iyan usa 5/31/21
C1 lxgs peru 4/1/20
D1 wa8e norway 10/1/19
E1 894a laos 5/1/19
F1 894a laos 9/17/19
Table Y:
food_item | organic
A1 Y
B1 Y
C1 N
D1 N
E1 Y
F1 N
Table Z:
food_item | food_type
A1 189
A1 190
B1 191
C1 189
D1 192
E1 193
F1 193
SELECT continent, country,
SUM(organic) AS organic_fd, SUM(Granny) AS granny_bag,
SUM(Red_delc) AS red_bag, SUM(Golden) AS golden_bag,
SUM(Gala) AS gala_bag, SUM(Fuji) AS fuji_bag,
SUM(CASE WHEN Granny + Red_delc + Golden + Gala + Fuji > 1 THEN 1 ELSE 0 END) AS mixed_bag
FROM (SELECT (CASE SUBSTR (x.food_area, 4, 1)
WHEN 's' THEN 'SA' WHEN 'n' THEN 'NA'
WHEN 'e' THEN 'EU' WHEN 'a' THEN 'AS' ELSE NULL END) continent,
x.food_loc country, COUNT(y.organic) AS Organic
COUNT(CASE WHEN z.food_type = '189' THEN 1 END) AS Granny,
COUNT(CASE WHEN z.food_type = '190' THEN 1 END) AS Red_delc,
COUNT(CASE WHEN z.food_type = '191' THEN 1 END) AS Golden,
COUNT(CASE WHEN z.food_type = '192' THEN 1 END) AS Gala,
COUNT(CASE WHEN z.food_type = '193' THEN 1 END) AS Fuji
FROM x LEFT JOIN z ON x.food_item = z.food_item
LEFT JOIN y on x.food_item = y.food_item and y.organic = 'Y'
WHERE x.exp_date > sysdate
GROUP BY SUBSTR (x.food_area, 4, 1), x.food_loc, y.organic) h
GROUP BY h.continent, h.country, h.organic
I'm not getting the correct output, since for example, Laos will show TWICE to account for the organic count and non-organic count. So it will show 1 organic_fd and 0 organic_fd and 1 fuji_bag and the other line will be another 1 fuji_bag. I would like the TOTAL count. (Also, if I add more food items, my mixed_bag shows mostly "1" count for each record/lines).
Below is the desired output:
| continent | country |organic_fd | granny_bag| red_bag| golden_bag| gala_bag|fuji_bag | mixed_bag
| SA | argentina | 1 | 1 | 1 | 0 | 0 | 0 | 1
| SA | peru | 0 | 1 | 0 | 0 | 0 | 0 | 0
| NA | usa | 1 | 0 | 0 | 1 | 0 | 0 | 0
| EU | norway | 0 | 0 | 0 | 0 | 1 | 0 | 0
| AS | laos | 1 | 0 | 0 | 0 | 0 | 2 | 0
So, say I want to add another food item, G1 from Norway and it has 3 types of organic apples: fuji, red, granny... then Norway will now have a count of 1 for the following columns: mixed_bag, organic_fd, fuji_bag, red_bag ,granny_bag (in addition to the previous count of 1 gala_bag). If you add H1, which is exactly the same as G1, then it will now have a total count of 2 for the following: mixed_bag, organic_fd, fuji_bag,red_bag, granny_bag
The query:
WITH
t AS (
SELECT
CASE SUBSTR(X.food_area, LENGTH(X.food_area), 1)
WHEN 's' THEN 'SA'
WHEN 'n' THEN 'NA'
WHEN 'e' THEN 'EU'
WHEN 'a' THEN 'AS'
ELSE NULL
END AS continent,
x.food_loc AS country,
COUNT(DISTINCT CASE Y.organic WHEN 'Y' THEN X.food_item END) OVER (
PARTITION BY x.food_loc
) AS organic_fd,
CASE
WHEN MIN(Z.food_type) OVER (
PARTITION BY x.food_loc, X.food_item
) = Z.food_type AND
MAX(Z.food_type) OVER (
PARTITION BY x.food_loc, X.food_item
) > Z.food_type THEN 1 END AS mixed,
Z.food_type
FROM X
JOIN Y ON X.food_item = Y.food_item
JOIN Z ON Y.food_item = Z.food_item
)
SELECT
continent, country, organic_fd,
COUNT(CASE WHEN food_type = '189' THEN 1 END) AS Granny,
COUNT(CASE WHEN food_type = '190' THEN 1 END) AS Red_delc,
COUNT(CASE WHEN food_type = '191' THEN 1 END) AS Golden,
COUNT(CASE WHEN food_type = '192' THEN 1 END) AS Gala,
COUNT(CASE WHEN food_type = '193' THEN 1 END) AS Fuji,
COUNT(mixed) AS mixed_bag
FROM t
GROUP BY continent, country, organic_fd
You can try this query here: https://rextester.com/TSSH87409.
You have one to many relationship between x and z, and join may produce many rows for each row in x, like in case of A1. So you have to number rows in x at first, this is what my subquery t1 do, except of mapping values. Then group them taking max() for each counted column (granny, organic etc.), like in subquery t2. Finally sum values.
dbfiddle demo
with
t1 as (
select rn, food_item, food_area, food_loc country, food_exp, food_type,
decode(substr(food_area, 4, 1), 's', 'SA', 'n', 'NA', 'e', 'EU', 'a', 'AS') continent,
case organic when 'Y' then 1 else 0 end org,
case when food_type = '189' then 1 else 0 end gra,
case when food_type = '190' then 1 else 0 end red,
case when food_type = '191' then 1 else 0 end gol,
case when food_type = '192' then 1 else 0 end gal,
case when food_type = '193' then 1 else 0 end fuj
from (select rownum rn, x.* from x) x join y using (food_item) join z using (food_item)
where food_exp > sysdate),
t2 as (
select rn, country, continent, max(org) org, max(gra) gra,
max(red) red, max(gol) gol, max(gal) gal, max(fuj) fuj,
case when max(gra) + max(red) + max(gol) + max(gal) + max(fuj) > 1
then 1 else 0
end mix
from t1 group by rn, country, continent)
select continent, country, sum(org) organic_fd, sum(gra) granny, sum(red) red_delc,
sum(gol) golden_bag, sum(gal) gala_bag, sum(fuj) fuji_bag, sum(mix) mixed_bag
from t2
group by continent, country
Above query gave expected output, please test it and adjust if needed. I noticed you use left joins. If there is possibility that for some rows in X there is no data in Y or Z you may have to add nvl()s in calculations. Maybe you should also put mapped, hardcoded values into tables. Hardcoding them is not good practice. Hope this helps :)
I am trying to write a simple SQL code that can get the desired output, from this table -
Original Table :
id | type
123 0
123 1
123 1
345 0
345 0
What I'm trying to get is:
id | zeroCount | oneCount
123 1 2
345 2 0
I tried to group by the id and also type but, both of them gives the same thing!
How to get desired output?
Here is a simple way, assuming the values are only 0 and 1:
select id, sum(1 - type) as zerocount, sum(type) as onecount
from t
group by id;
A more typical approach would use case (or even pivot):
select id, sum(case when type = 0 then 1 else 0 end) as zerocount,
sum(case when type = 1 then 1 else 0 end) as onecount
from t
group by id;
You could get fancy and use a pivot function. But this will work:
Select id,
sum(case when type = 0 then 1 else 0 end) as ZeroCount,
Sum(case when type = 1 then 1 else 0 end) as OneCount
from table
group by id
order by id