Im new to zf2.
zfcuser is setup as in the installation guide. Im able to register, login and logout.
I had created modules for frontend and backend. Im trying to check if user is login for the backend - admin and all the child modules.
I tried to include
$sm = $app->getServiceManager();
$auth = $sm->get('zfcuser_auth_service');
if (!$auth->hasIdentity()) {
//redirect to login page
}
in my admin/module.php function onBootStrap
it did check for login, BUT not only for the admin, is for the entire modules including the frontend.
I just need to check login for the admin modules, and all the child modules of admin.
Couldn't figure out how. Please help
In you module.config.php
<?php
namespace AdminModule;
use Zend\Authentication\AuthenticationService;
return array(
__NAMESPACE__ => array(
'params' => array(),
'service_manager' => array(
'invokables' => array(
'Zend\Authentication\AuthenticationService' => 'Zend\Authentication\AuthenticationService',
),
),
'services' => array(
// Keys are the service names
// Values are objects
'Auth' => new AuthenticationService(),
),
),
);
Example in your controller/Manager
$this->auth = new AuthenticationService();
if($this->auth->hasIdentity()){
$this->userid = $this->auth->getIdentity();
}
You can use a factory too.
Example in your controller
using tools from ZfcUser module
$this->zfcUserAuthentication()->hasIdentity()
Related
For cakephp 3.6, cakephp.org tell how to customise user finder query for auth component at following link:
link
But I am not getting how to implement it?
I have 'department_id' column in users table which belongs to departments table. I want to change the following query:
public function findAuth(){
$query
->select(['id', 'username', 'password'])->contain(['Departments'])
->where(['Users.active' => 1]);
return $query;
}
Will the above code work?
Please tell me in which file I have to write the function?
And what are other necessary steps to get it done, so that I get all user related info in $this->Auth->User ?
Firstly, you will need to load the Auth component and pass in custom configuration in any controller that you want to use the custom finder like so:
public function initialize()
{
parent::initialize();
$this->loadComponent('Auth', [
'authenticate' => [
'Form' => [
'finder' => 'auth'
]
],
]);
}
then, in your UsersTable you would have the custom finder:
public function findAuth(\Cake\ORM\Query $query, array $options)
{
$query
->select(['id', 'username', 'password'])->contain(['Departments'])
->where(['Users.active' => 1]);
return $query;
}
This answer may also help Containing tables in custom Auth finder
I have setup Laravel 5.5 and installed the default authentication scaffolding.
My application has two types of users - customers and staff - so I prefer to name the authentication guards that way, and the following configuration seems to work.
'guards' => [
'web' => [
'driver' => 'session',
'provider' => 'users',
],
'customers' => [
'driver' => 'session',
'provider' => 'customer-users',
],
'staff' => [
'driver' => 'session',
'provider' => 'staff-users',
],
'api' => [
'driver' => 'token',
'provider' => 'users',
],
My providers, customer-users and staff-users, use the standard eloquent driver, however they each return a different user type.
The problem is that I would like to remove the 'web' guard, since it's just cluttering the config file. When I do however, I get an exception somewhere deep in the Laravel middleware.
I can live with the extra clutter of course, but it does bother me that Laravel is relying on a configuration item that I can't change. Is this a Laravel bug, perhaps?
BTW - I don't have 'web' set as the default guard when I get the error...
By default web guard given by laravel which used for web authentication based on session driver with the table users. Now you have created your own custom guards and you are using it. So your wish to keep that web guard. But if you remove, you might be facing some internal issue, so best you keep it and it's not going to be the performance issue too.
How can I use middleware with resources?
Route::resource('myitem', ['middleware' => 'auth', 'uses' => 'App\\Controllers\\MyitemsController']);
Just followed https://laracasts.com/discuss/channels/general-discussion/struggling-with-routeresource-and-auth-middleware but unfortunately could not solve.
Getting error:
ErrorException (E_UNKNOWN)
Array to string conversion
Open: /vendor/laravel/framework/src/Illuminate/Routing/Router.php
protected function getResourceAction($resource, $controller, $method, $options)
{
$name = $this->getResourceName($resource, $method, $options);
return array('as' => $name, 'uses' => $controller.'#'.$method);
}
Using filter with resource was not working that why had to use Route::group
Route::group(array('before' => 'auth'), function()
{
Route::resource('myitem', 'App\\Controllers\\MyitemsController');
});
https://stackoverflow.com/a/17512478/540144
Middleware is a new feature of Laravel 5. In Laravel 4, filters where something similar. So instead of using the key middleware you should use before or after. Also, and that's where the error comes from, the second argument of Route::resource should be the controller name as string and the third one is an array of options:
Route::resource('myitem', 'App\\Controllers\\MyitemsController', ['before' => 'auth']);
Edit
Apparently before filters only work with resource routes when you wrap a group around it. See the OPs answer for an example...
I just came up against this and found the easiest way is to add the middleware straight to the controller.
I found my answer here:
http://laravel.com/docs/master/controllers
class MyitemsController extends Controller {
/**
* Instantiate a new MyitemsController instance.
*/
public function __construct()
{
$this->middleware('auth');
}
}
How to do this in Laravel 5. The Answer you have been waiting for.
Use middleware instead of before
Route::group(array('middleware' => 'auth'), function()
{
Route::resource('user', 'UserController',
['only' => ['edit']]);
}
To check if the route is setup, run:
php artisan route:list
which should show the following:
GET|HEAD | user/{user}/edit | user.edit | App\Http\Controllers\UserController#edit | auth
Note auth instead of guest
Better solution
Use middleware instead of before
Route::group(['middleware' => 'auth'], function(){
Route::resource('myitem', 'MyitemsController');
});
You can check if it's ok with:
php artisan route:list
I've started playing around with Laravel. I want to create simple authentication logic using 'auth' filter for my route. The problem is when I set the route like this:
Route::get('/user', array('before' => 'auth', 'as' => 'user', function() {
return Redirect::action('UserController#index');
}));
Route::get('/login', 'UserController#login');
I get: [InvalidArgumentException] - Route [UserController#index] not defined
However, when I go with a basic route:
Route::get('/user', 'UserController#index');
the page renders successfully.
Can anyone see the problem?
You could try adjusting the route to use UserController#index
Route::get('/user', array(
'before' => 'auth',
'as' => 'user',
'uses' => 'UserController#index'
));
I use custom routes which include namespace besides controller and action. So for ACL purposes I use MVC route name as ACL resource name. Now I need to obtain currently DISPATCHING route name. The only solution I've come up with is to get namespace/controller/action from Dispatcher and iterating over all the routes find an appropriate one.
Is there any easiest way to obtain currently dispatching (not just matched) route name?
Pretty easy
\Phalcon\DI::getDefault()->get('router')->getMatchedRoute()->getName();
You can use your router, dispatcher and base controller to get what you need. Consider this:
$router = new \Phalcon\Mvc\Router(false);
$routes = array(
'/{namespace:"[a-zA-Z]+}/:controller' => array(
'controller' => 2,
),
'/{namespace:"[a-zA-Z]+}/:controller/:action/:params' => array(
'controller' => 2,
'action' => 3,
'params' => 4,
),
);
foreach($routes as $route => $params) {
$router->add($route, $params);
}
Now in your base controller you can do this:
public function getNamespace()
{
return $this->dispatcher->getParam('namespace');
}
This way you can have the namespace currently being served in your controllers (so long as they extend your base controller).
If you need to get the namespace in a model you can always use the DI like so (base model):
public function getNamespace()
{
$di = \Phalcon\DI::getDefault();
return $di->dispatcher->getParam('namespace');
}