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how can I filter in Django to get a data row one times if the same value in on column?
columns:
a | b
x | y
a | y
y | s
Want one data row set with y (b) and one data row set with s (b).
If not clear what I mean I edit with SQL script...
EDIT: SELECT DISTINCT b FROM table;
Sorry to be blind...
http://docs.djangoproject.com/en/dev/ref/models/querysets/
Have a nice day.
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There is no error, but the results show the values excluding the row that meets both conditions. The result shows 3, in fact, it should be 4 excluding data that has 22 for age and UK for the country. Any idea why the result is 3, not 4?
SELECT COUNT(*) FROM CUSTOMERS WHERE CUSTOMERS.AGE = '22' OR CUSTOMERS.COUNTRY = 'UK';
You have two customers at the age of 22 and 2 residing in the UK.
This is actually a correct result here - how on earth do you come to the conclusion that you have four people meeting that criteria? If more than one point matches for a database entry, it will only count as one for the result, since it's still the same database entry.
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Team Table
Player (column)
A
B
C
Expected Output: with Two columns
Player vsPlayer
A B
B C
C A
How to write a sql query to get the exact output as Expected output mentioned above.
Thanks in advance
The normal way to get combination (pairs) is to take all permutations, but where column 1 is less than column 2.
SELECT
l.player,
r.player
FROM
player l
INNER JOIN
player r
ON l.player < r.player
Demo : https://dbfiddle.uk/?rdbms=sqlserver_2019&fiddle=9ce7af3d0afe89c6434cc2800dfbd2ef
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Need a query to check ids with multiple revisionnums
id reviionnum
1 0
2 0
1 1
3 1
2 1
The query should result
id revisionnum
3 1
Please help
If you want ids with only one revision number, you can use aggregation:
select id, min(revissionnum)
from t
group by id
having count(*) = 1;
The min() is the value if there is only one row.
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I have a table in a SQL Server 2000 database with a column with several entries like 01-03, 04-05. The first 2 digits are the room number and the last two digits are the bed number.
I want to replace the 01-05, 03-07 etc. with only the bed number. So only the last two charcters have to be in the column.
How do I accomplish this?
Sample data is:
In the column [Bed] with values:
22-01
08-01
09-03
01-16
Result has to be:
01
01
03
16
RIGHT should solve your problem:
SELECT RIGHT(RTRIM(Bed), 2) FROM tbl
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I have got table like below after sorting in SQL:
M_ID
-----
2013/01
2013/02
2013/03
2013/04
2013/05
2013/06
Now I want to assign each entries a particular value like below
M_ID Days
--------------
2013/01 20
2013/02 30
2013/03 40
2013/04 50
2013/05 60
2013/06 70
So, can you please let me know how to do that in SQL Query?
Do you mean something like this (presuming sql-server)?
SELECT M_ID,
Days = (ROW_NUMBER()OVER(ORDER BY M_ID) + 1) * 10
FROM dbo.TableName
Demo