Randomize a list in Microsoft Word - vba

I am a teacher and I have been making a number of multiple choice tests for students using Microsoft Word. Is there a way for me to automatically shuffle the questions so that I can have multiple versions of the test without needing to copy and paste the questions around my test?
Looking online I found a one solution posted by Steve Yandl in which he used macro after putting each question on a separate row in a table. I am trying to get his macro to work but it has and error. I know next to nothing about coding, so I am stuck. Here is his code:
Sub ShuffleQuestions()
Dim Tmax As Integer
Dim strCell As String
Dim strQ As Variant
Dim strText As String
Dim I As Integer
Dim Z As Integer
Dim intQsLeft As Integer
Dim rndQ As Integer
Dim Q As Integer
Dim vArray As Variant
Dim strNew As String
Set objDict = CreateObject("Scripting.Dictionary")
Tmax = ThisDocument.Tables(1).Rows.Count
For I = 1 To Tmax
strCell = ThisDocument.Tables(1).Cell(I, 1).Range.Text
strQ = Left(strCell, Len(strCell) - 1)
objDict.Add strQ, strQ
Next I
ReDim arrQs(I - 1)
intQsLeft = I - 2
Z = 0
Do While intQsLeft = 0
Randomize
rndQ = Int((intQsLeft + 1) * Rnd)
intQsLeft = intQsLeft - 1
vArray = objDict.Items
strText = vArray(rndQ)
arrQs(Z) = strText
Z = Z + 1
objDict.Remove strText
Loop
For Q = 1 To Tmax
strNew = arrQs(Q - 1)
strNew = Left(strNew, Len(strNew) - 1)
ThisDocument.Tables(1).Cell(Q, 1).Range.Text = strNew
Next Q
End Sub
The error message I get says "run time error 5941 the requested member of the collection does not exist"
When I choose the 'Debug' button it brings me to the line of code in the macro that says "Tmax = ThisDocument.Tables(1).Rows.Count"
Ultimately I just want to reorder the questions, but I would be delighted if there was also a way to reorder my multiple choice options for each question.

Does your document have a table?
Where did you put the sub (ShuffleQuestions)?
Are you sure you added it to your document and didn't add it to the document template (probably normal).
If, after running the code, reaching the error and clicking debug, you highlight ThisDocument.Tables, right clicking on the highlighted text and select "Add Watch" from the popup menu you should be able to see if ThisDocument.Tables contains any data.
I suspect it will be empty. It will be empty if:
You haven't added a table to your document
You have added the sub to normal.dot in which case ThisDocument will refer to the normal template and not the document you are actually editing.
So, the solution is either:
Make sure your sub is in the document you are editing (and not the document template)
That you have a table in your document.
There are also some programming errors in the sub ShuffleQuestions (e.g. Do While intQsLeft = 0 should be something like Do While intQsLeft > 0).
The following code works (and is a lot simpler):
Sub ShuffleQuestions()
Dim numberOfRows As Integer
Dim currentRowText As String
Dim I As Integer
Dim doc As Document
Set doc = ActiveDocument
'Find the number of rows in the first table of the document
numberOfRows = doc.Tables(1).Rows.Count
'Initialise (seed) the random number generator
Randomize
'For each row in the table
For I = 1 To numberOfRows
'Find a new row number (any row in the table)
newRow = Int(numberOfRows * Rnd + 1)
'Unless we're not moving to a new row
If newRow <> I Then
'Get the current row text
currentRowText = CleanUp(doc.Tables(1).Cell(I, 1).Range.Text)
'Overwrite the current row text with the new row text
doc.Tables(1).Cell(I, 1).Range.Text = CleanUp(doc.Tables(1).Cell(newRow, 1).Range.Text)
'Put the current row text into the new row
doc.Tables(1).Cell(newRow, 1).Range.Text = currentRowText
End If
Next I
End Sub
Function CleanUp(value As String) As String
'Remove control characters from the end of the string (the cell text has a 'BELL' character and CR at the end)
While (Len(value) > 0 And Asc(Right(value, 1)) < 32)
value = Left(value, Len(value) - 1)
Wend
CleanUp = value
End Function

For those who wants to randomize all the paragraphs in a document.
To make it work, put your cursor at the end of your document with no selections.
Sub ran_para()
n = ActiveDocument.Paragraphs.Count
ReDim a(1 To 2, 1 To n)
Randomize
For i = 1 To n
a(1, i) = Rnd
a(2, i) = i
Next
For i = 1 To n - 1
For j = i + 1 To n
If a(1, j) > a(1, i) Then
t = a(2, i)
a(2, i) = a(2, j)
a(2, j) = t
End If
Next
Next
'Documents.Add
For i = 1 To n
Set p = ActiveDocument.Paragraphs.Add
p.Range.Text = ActiveDocument.Paragraphs(a(2, i)).Range.Text
Next
End Sub

Related

Manipulating Collections and Arrays in Excel VBA to accommodate missing values and error handling

I did not know how to explain the question so I will attach images for explaining my situation. Here is the view of my Excel Sheet:
My Excel Sheet
The highlighted cells contain multiple values called ID's and are associated with respective Versions in the columns beside them. I use the following macro (details with great explanation here) to split these values into multiple rows in the same sheet.
Option Explicit
Private Const ID_IDX As Long = 0
Private Const VER_IDX As Long = 1
Private Const RNG_IDX As Long = 2
Private Sub RunMe()
Dim data As Variant, cols As Variant, items As Variant
Dim r As Long, c As Long, i As Long, n As Long
Dim ids() As String, vers() As String
Dim addItems As Collection, concatItems As Collection
Dim dataRng As Range, rng As Range
Dim writeID() As Variant, writeVer() As Variant, writeConcat() As Variant
Dim dataStartRow As Long
On Error Resume Next
'Define the range we're interested in and read into an array.
With Sheet1 'adjust for your worksheet object
Set dataRng = Application.InputBox(prompt:="Select the Range of cells:", Type:=8)
End With
data = dataRng.Value2
dataStartRow = 2
'Find the two target columns
cols = AcquireIdAndVerCol(data, 3, 8)
If IsEmpty(cols) Then
MsgBox "Unable to find Id and Ver columns."
Exit Sub
End If
With dataRng
'Add a column next to the version number column.
.Columns(cols(VER_IDX)).Offset(, 1).Insert Shift:=xlShiftToRight, CopyOrigin:=xlFormatFromLeftOrAbove
'Add a column to our range.
'This is to cover the case that the rightmost column is the version number column.
Set dataRng = .Resize(, .Columns.Count + 1)
End With
'Find the rows that need to be split and concatenate the target strings.
Set addItems = New Collection
Set concatItems = New Collection
For r = dataStartRow To UBound(data, 1)
ids = Split(data(r, cols(ID_IDX)), vbLf)
vers = Split(data(r, cols(VER_IDX)), vbLf)
n = IIf(UBound(ids) >= UBound(vers), UBound(ids), UBound(vers))
If n = 0 Then 'it's just one line of text.
'Add concatenated text to list.
concatItems.Add data(r, cols(ID_IDX)) & " " & data(r, cols(VER_IDX))
ElseIf n > 0 Then 'it's multiple lines of text.
'Transpose the id array.
ReDim writeID(1 To UBound(ids) + 1, 1 To 1)
For i = 0 To UBound(ids)
writeID(i + 1, 1) = ids(i)
Next
'Transpose the version array.
ReDim writeVer(1 To UBound(vers) + 1, 1 To 1)
For i = 0 To UBound(ids)
writeVer(i + 1, 1) = vers(i)
Next
'Add concatenated text to list.
For i = 0 To n
concatItems.Add (IIf(UBound(ids) <= n And UBound(vers) <= n, ids(i) & " " & vers(i), Empty))
Next
'Add the range to be split to the collection.
addItems.Add Array(writeID, writeVer, dataRng.Rows(r + 1).Resize(n))
Else 'it's an empty cell
'Add empty item to concatenated list in order to keep alignment.
concatItems.Add Empty
End If
Next
Application.ScreenUpdating = False
'Split the ranges in the list.
If addItems.Count > 0 Then
For Each items In addItems
'Add the rows.
With items(RNG_IDX)
.Insert Shift:=xlDown, CopyOrigin:=xlFormatFromLeftOrAbove
Set rng = .Offset(-.Rows.Count - 1).Resize(.Rows.Count + 1)
'Note: format your rng Range obect as desired here.
End With
'Write the id and version values.
rng.Columns(cols(ID_IDX)).Value = items(ID_IDX)
rng.Columns(cols(VER_IDX)).Value = items(VER_IDX)
Next
End If
'Write the concatenated values.
If concatItems.Count > 0 Then
ReDim writeConcat(1 To concatItems.Count + dataStartRow - 1, 1 To 1)
'Header to array.
writeConcat(1, 1) = "Concat values"
'Values from the collection to array.
i = dataStartRow
For Each items In concatItems
writeConcat(i, 1) = items
i = i + 1
Next
'Output array to range.
With dataRng.Columns(cols(VER_IDX) + 1)
.Value = writeConcat
.AutoFit
End With
End If
Application.ScreenUpdating = True
End Sub
Private Function AcquireIdAndVerCol(data As Variant, minCol As Long, maxCol As Long) As Variant
Dim result(1) As Long
Dim r As Long, c As Long, i As Long
Dim items() As String
'Check we're not operating outside bounds of data array.
If minCol < LBound(data, 2) Then minCol = LBound(data, 2)
If minCol > UBound(data, 2) Then minCol = UBound(data, 2)
If maxCol < LBound(data, 2) Then maxCol = LBound(data, 2)
If maxCol > UBound(data, 2) Then maxCol = UBound(data, 2)
'Loop through data to find the two columns.
'Once found, leave the function.
For r = 1 To UBound(data, 1)
For c = minCol To maxCol
items = Split(data(r, c), vbLf)
For i = 0 To UBound(items)
If result(ID_IDX) = 0 Then
If IsDocId(items(i)) Then
result(ID_IDX) = c
If result(VER_IDX) = 0 Then
Exit For
Else
AcquireIdAndVerCol = result
Exit Function
End If
End If
End If
If result(VER_IDX) = 0 Then
If IsDocVer(items(i)) Then
result(VER_IDX) = c
If result(ID_IDX) = 0 Then
Exit For
Else
AcquireIdAndVerCol = result
Exit Function
End If
End If
End If
Next
Next
Next
End Function
Private Function IsDocId(val As String) As Boolean
Dim n As Long
n = TryClng(val)
IsDocId = (n > 9999 And n <= 999999999)
End Function
Private Function IsDocVer(val As String) As Boolean
Dim n As Long, m As Long
Dim items() As String
items = Split(val, ".")
If UBound(items) <> 1 Then Exit Function
n = TryClng(items(0))
m = TryClng(items(1))
IsDocVer = (n > 0 And n <= 99) And (m >= 0 And m <= 9)
End Function
'-------------------------------------------------------------------
'Converts a variant to a Long or returns a fail value as a Long
'if the conversion failed.
'-------------------------------------------------------------------
Private Function TryClng(expr As Variant, Optional fail As Long = -1) As Long
Dim n As Long
n = fail
On Error Resume Next
n = CLng(expr)
On Error GoTo 0
TryClng = n
End Function
It gives the following output with an addition column named, Concat Values, which contains combined values of Id's and corresponding Versions:
Output
Problem:
It works flawlessly if all the ID's have corresponding Versions specified in the sheet separately as I mentioned above. However in cases, where there is only one Version number, and it's bound to 4 or more Id's, i.e. Same Version number is applicable for all the ID's, like such:
The output in the column Concat Values gets disoriented because we are using an array to output the Concat Values and the array is not accommodating the missing Versions for corresponding Id's. It looks like this:
Dislocated row values
I am trying to learn and figure out a way to update the collection and the array with new Concat Values before Outputting it to the column, so that each Concat Value gets placed in their corresponding ID and Version location. I hope that it makes sense. Please let me know for more clarification.
EDIT:
I will try and list all the possible Cases and Expected Output, including the worst case scenarios:
Here is the link to my excel sheet.
Usual Scenarios
Number of Id's = Number of Versions (Works perfectly, Concat Values get aligned in corresponding rows in the columns)
Multiple Id's - Single Version (In such cases, the Version # applicable to all the ID's is same i.e. one Version should be applied to all the ID's.)
Issue:
The Macro does the task of splitting the columns into rows, except the part where Concat values get misaligned.
Worst Case Scenarios
Multiple Id's - Multiple Versions, but less than total #ID's (In such cases, Versions should align to the topmost ID's and fill the ID's below with blanks)
Issue:
The Macro does the task of splitting the columns into rows, except the part where Concat values get misaligned.
Here 4 ID's have been given only 3 Versions, so Top 3 ID's are assigned 3 Versions and the 4th ID has no Version linked to it.
Similarly,
Here 4 ID's have been given only 2 Versions, so Top 2 ID's are assigned 2 Versions and the 3rd and 4th ID's have no Version linked to them.
Multiple Id's - No Version (In such cases, columns should split into rows based on #ID's and corresponding Version rows should be filled with blanks)
Issue:
The Macro does the task of splitting the columns into rows, except the part where Concat values get misaligned.
The complexity of the solution will depend on the complexity and variety of 'special cases'. Given your scenarios, it seems as if you could just take the last of the given versions and, for any versions missing below that line, just use that last used version.
When I gave my first answer, I anticipated this kind of issue, so changes to the code are trivial.
Firstly add an additional declaration in the RunMe Sub:
Dim curVer As String
and then you just need to adjust the ElseIf n > 0 case. Replace the code with this:
ElseIf n > 0 Then 'it's multiple lines of text.
'Resize the output arrays to max ('n')
ReDim writeID(1 To n + 1, 1 To 1)
ReDim writeVer(1 To n + 1, 1 To 1)
'Loop through the arrays to align id and versions.
For i = 0 To n
If i <= UBound(ids) Then
writeID(i + 1, 1) = ids(i)
End If
If i <= UBound(vers) Then
curVer = vers(i)
End If
writeVer(i + 1, 1) = curVer
Next
'Add concatenated text to list.
For i = 0 To n
concatItems.Add writeID(i + 1, 1) & " " & writeVer(i + 1, 1)
Next
'Add the range to be split to the collection.
addItems.Add Array(writeID, writeVer, dataRng.Rows(r + 1).Resize(n))
Too much code for me to read but I came up with my solution if I understood you problem correctly.
I guess it could be a good solution if you modify it. With my code it will be easier to produce a new table instead of adding rows I guess. Then you could just add the formatting which should be very easy.
Sub Test()
Dim xRange As Range
Dim xArrRange() As Variant
Dim xNewArrRange() As Variant
Dim xNewArrRangeResize() As Variant
Dim xNumberColumns As Long
Dim i As Long
Dim j As Long
Dim k As Long
Dim l As Long
Dim ii As Long
Dim jj As Long
Set xRange = Range("A2:C5")
xNumberColumns = 3
xArrRange = xRange.Value2
ReDim xNewArrRange(xRange.Rows.Count + 10, xNumberColumns) ' "xNumberColumns - 1" to have the number of columns
' "xNumberColumns" is one more
For i = LBound(xArrRange, 1) To UBound(xArrRange, 1)
Dim xTempArrVer As Variant
Dim xTempArrID As Variant
xTempArrVer = Split(xArrRange(i, 3), vbLf)
If UBound(xTempArrVer) = -1 Then ' If there are no version, initialize it with ""
ReDim xTempArrVer(0)
xTempArrVer(0) = ""
End If
xTempArrID = Split(xArrRange(i, 2), vbLf)
For j = LBound(xTempArrID, 1) To UBound(xTempArrID, 1)
If j > UBound(xTempArrVer, 1) Then
l = UBound(xTempArrVer, 1)
Else
l = j
End If
xNewArrRange(k, 0) = xArrRange(i, 1)
xNewArrRange(k, 1) = xTempArrID(j)
xNewArrRange(k, 2) = xTempArrVer(l)
If xTempArrVer(l) <> "" Then
xNewArrRange(k, 3) = xTempArrID(j) & " " & xTempArrVer(l)
Else
xNewArrRange(k, 3) = xTempArrID(j)
End If
k = k + 1
If k + 1 > UBound(xNewArrRange, 1) Then
ReDim Preserve xNewArrRange(UBound(xNewArrRange, 1) + 30, xNumberColumns)
End If
Next j
Next i
ReDim xNewArrRangeResize(k - 1, xNumberColumns) ' "xNumberColumns - 1" to have the number of columns
' "xNumberColumns" is one more
For ii = LBound(xNewArrRangeResize, 1) To UBound(xNewArrRangeResize, 1)
For jj = LBound(xNewArrRangeResize, 2) To UBound(xNewArrRangeResize, 2)
xNewArrRangeResize(ii, jj) = xNewArrRange(ii, jj)
Next jj
Next ii
Range(Cells(2, 6), Cells(UBound(xNewArrRangeResize, 1) + 1, 6 + UBound(xNewArrRangeResize, 2))).Value2 = xNewArrRangeResize
Debug.Print "Finish"
End Sub
This code produces this:
If your code produces good number of rows for each id etc, the most lazy solution would be just to populate columns of your table with part of my array which is produced at the end.
Edit:
I see there is something missing but that is because I calculated wrongly that Range.
Range(Cells(2, 6), Cells(UBound(xNewArrRangeResize, 1) + 1, 6 + UBound(xNewArrRangeResize, 2))).Value2 = xNewArrRangeResize

VBA to extract names from a list at random isn't working

I want to randomly extract 280 names from a list (dynamic range) of thousands of authors, then concatenate them into 1 string with each name separated by OR.
So far I'm stuck at the first part. When I run the following code, nothing happens. Can anyone explain why? Thanks.
Sub Authors()
Dim InputRange As Range
Dim AuthorCount As Long
Dim AuthorRange As Excel.Range
Set InputRange = Range("A:A")
AuthorCount = Application.WorksheetFunction.CountA(InputRange) - 1
Set AuthorRange = ThisWorkbook.Worksheets("Sheet").Range("A2:A" & AuthorCount)
Const nItemsToPick As Long = 280
Dim Authorlist As Variant
Dim i As Long
ReDim Authorlist(1 To nItemsToPick)
For i = 1 To nItemsToPick
Authorlist(i) = AuthorRange.Cells(Int(AuthorCount * Rnd + 1), 1)
Next i
End Sub
Using the below code
Sub PickSample(intSampleSize As Integer, intPicks As Integer)
Dim arr() As String
Dim intCounter As Integer
ReDim arr(intPicks)
For intCounter = 0 To UBound(arr)
arr(intCounter) = CStr(Int((intSampleSize - (i - 1)) * Rnd + 1) + (i - 1))
Next intCounter
Debug.Print Join(arr(), ",")
End Sub
I ran this on the following, PickSample(10,5) and got the following, showing the duplicate possibilities, this will become less as the difference between picks and samples increases.
9,9,6,10,10,2
5,3,6,7,2,3
10,4,5,8,0,6
9,8,4,10,9,0
0,8,8,7,0,4
7,5,6,3,3,8
If your selection is 280, but the data set is only 300, dupes still arise
PickSample 300,280
228,**92**,248,216,269,66,**107**,166,**107**,61,174,189,41,18,190,252,192,127,56,149,292,231,114,145,164,202,11,194,270,102,35,128,232,**107**,124,225,131,216,152,52,83,26,294,85,186,**92**,256,96,239,52,90,21,148,136,179,9,95,40,98,228,188,290,249,166,182,57,271,95,180,179,230,215,206,228,77,165,153,170,84,125,105,292,156,175,139,9,113,41,196,46,59,112,28,185,211,132,126,101,210,64,13,266,13,138,222,227,247,63,141,261,249,123,139,105,75,242,163,162,188,26,214,77,17,82,289,98,194,109,111,98,64,63,127,185,72,206,177,181,23,13,46,74,120,175,86,251,270,158,116,0,75,49,194,295,93,72,264,39,171,182,183,208,255,29,118,247,80,204,119,251,130,251,65,220,270,65,295,290,262,157,195,137,47,193,184,257,110,15,152,16,112,135,89,291,3,195,184,160,8,215,94,295,87,109,96,106,70,178,211,80,173,173,298,280,75,243,231,122,189,148,150,40,291,53,177,205,32,195,222,234,129,24,150,172,17,124,35,43,94,298,181,82,125,141,19,137,131,284,82,52,152,103,154,119,78,20,192,109,164,265,127,178,114,17,32,43,43,228,79,41,12,208,254,155,240,296,157,20,188,99,83
4,50,49,153,122,31,83,193,255,149,56,269,112,97,232,65,134,71,264,183,112,117,259,176,280,155,99,261,77,78,53,104,0,223,253,83,211,121,244,223,131,23,123,102,213,93,240,45,178,287,73,282,34,296,190,180,271,173,73,258,22,132,228,73,113,119,158,81,174,63,23,269,33,196,271,69,285,254,132,148,231,251,115,58,98,124,45,186,29,61,208,151,55,298,141,1,128,86,226,268,247,53,32,3,45,113,56,294,262,175,219,43,77,8,249,235,238,100,135,167,241,169,61,62,109,172,103,158,128,172,15,164,62,289,280,298,252,123,242,297,77,52,209,5,102,208,33,33,87,120,168,93,88,243,93,113,120,253,123,218,198,122,286,194,155,67,175,225,137,272,85,200,267,84,110,4,88,296,229,174,182,80,152,238,258,28,163,125,22,135,210,150,122,284,296,178,160,185,26,55,85,5,45,126,165,168,235,12,122,17,93,181,155,179,99,273,231,173,129,220,49,17,73,228,286,103,205,238,10,239,145,62,181,273,284,196,4,199,290,2,287,22,88,175,243,12,16,169,94,124,153,220,135,97,22,123,172,229,174,196,243,125,239,217,208,219,57,232,21,74,286,246,66,55,71,278,77,77,215,200,232
209,294,73,160,32,300,203,4,173,30,31,240,85,13,89,114,90,285,294,120,83,48,49,194,123,124,214,98,190,62,55,175,24,137,272,78,236,114,87,276,190,188,128,29,168,209,275,251,6,163,275,129,204,151,154,139,106,121,81,16,73,294,18,117,109,147,46,142,77,189,163,47,282,197,152,117,32,235,138,226,179,250,5,63,22,31,99,38,0,161,197,163,249,24,57,204,136,107,45,212,279,159,26,228,120,139,148,62,99,28,177,51,279,29,133,82,262,225,82,202,77,27,9,97,237,89,70,144,76,102,13,145,62,260,177,227,279,99,163,24,190,123,289,34,277,186,104,44,144,66,299,39,8,103,164,277,162,122,255,248,202,217,300,102,149,124,209,53,127,163,245,162,128,153,68,186,147,204,266,111,91,88,45,159,67,175,109,263,143,57,205,224,184,235,48,243,60,287,19,18,238,114,139,35,34,52,14,215,160,168,65,140,224,226,120,271,224,26,191,214,4,129,120,82,296,241,209,125,221,83,107,130,284,36,194,104,31,55,23,130,288,163,148,292,65,114,119,84,151,41,155,290,167,273,197,132,208,19,227,210,149,46,67,98,236,15,155,227,241,97,292,242,203,272,263,125,37,287,239,209,120
Using a dictionary to handle the dupes, using this code
Sub PickSample(intSampleSize As Integer, intPicks As Integer)
Dim dicPicked As New Scripting.Dictionary
Dim arr() As String
Dim intCounter As Integer
Dim intPicked As Integer
ReDim arr(intPicks)
For intCounter = 0 To UBound(arr)
RetryPick:
intPicked = CStr(Int((intSampleSize - (i - 1)) * Rnd + 1) + (i - 1))
If dicPicked.Exists(CStr(intPicked)) Then
GoTo RetryPick
Else
dicPicked.Add CStr(intPicked), 1
arr(intCounter) = intPicked
End If
Next intCounter
Debug.Print Join(arr(), ",")
dicPicked.RemoveAll
Set dicPicked = Nothing
End Sub
Gives results, hopefully dupe free
PickSample 300,280
203,125,69,114,26,208,39,219,36,174,220,113,24,74,104,282,128,112,223,205,200,147,44,143,152,162,157,300,70,54,108,177,13,276,153,91,7,168,89,145,127,12,16,257,187,229,61,213,117,214,254,171,59,242,23,51,224,52,185,165,193,189,21,296,63,173,160,280,190,232,235,141,256,56,87,98,32,5,267,195,77,120,197,82,288,68,57,136,132,182,122,15,47,48,261,96,110,258,49,105,155,86,186,97,225,80,264,140,11,46,199,230,275,19,34,83,222,66,116,294,298,259,292,271,272,84,115,101,124,43,183,71,289,291,25,188,55,158,150,216,243,92,58,0,290,148,255,149,250,167,27,233,228,265,9,299,65,283,62,88,207,240,109,179,161,178,268,278,175,139,237,234,169,297,269,281,184,262,270,164,202,279,253,295,196,212,8,274,159,75,172,163,130,38,154,73,99,247,249,263,273,67,40,20,221,138,14,33,218,286,227,251,94,166,209,156,211,37,137,90,131,111,107,2,215,85,146,100,293,204,231,285,79,53,126,60,239,260,248,78,4,217,29,64,121,226,201,210,45,206,134,17,1,192,246,3,35,191,236,93,28,41,244,287,129,277,142,118,6,81,18,135,181,241,180,103,50,252,31,95,30
44,278,132,10,232,56,146,193,284,276,236,155,79,117,102,61,119,200,229,131,138,133,235,173,204,34,7,98,3,202,167,143,130,30,126,206,13,262,221,166,174,298,111,116,39,288,263,76,47,170,89,268,154,253,52,91,217,148,12,22,83,33,77,264,85,214,55,127,279,251,101,86,230,35,172,59,198,62,286,296,220,29,191,242,271,5,54,84,297,158,38,270,231,107,95,110,57,129,9,273,53,269,68,4,234,228,211,207,70,153,151,194,179,128,169,63,142,109,145,58,186,24,245,60,87,0,17,246,225,222,218,184,258,26,161,226,247,31,144,178,223,122,88,124,137,210,293,94,99,213,190,281,80,72,104,40,6,123,290,259,254,45,78,66,227,289,261,141,65,135,8,274,69,257,203,168,196,42,248,67,73,125,37,11,287,181,92,291,238,108,212,1,118,28,216,244,164,249,240,150,46,74,277,36,189,188,255,224,195,260,15,175,267,280,49,180,27,165,50,113,243,201,237,149,205,156,199,292,136,48,71,75,285,41,81,239,209,185,266,160,176,152,171,163,100,2,32,183,16,97,19,294,187,20,282,272,157,182,121,140,106,112,265,295,51,21,256,64,241,114,162,90,252,115,25,82,103,23,299,120,197
57,241,105,1,247,289,284,72,89,68,101,225,295,242,290,5,291,217,267,87,62,80,24,106,103,38,285,197,286,300,151,222,219,254,201,113,195,245,243,15,179,98,145,192,74,118,142,109,70,58,11,4,154,277,129,115,250,202,293,163,181,168,288,268,281,112,79,49,60,175,236,23,266,186,59,167,190,187,41,228,174,157,48,231,165,253,227,171,66,176,135,238,120,258,19,110,194,164,131,296,91,206,159,255,8,189,124,148,114,13,75,121,95,272,119,214,50,117,279,213,205,133,96,196,137,173,246,218,233,77,27,264,141,184,193,263,102,83,244,210,78,127,36,63,188,42,0,152,198,271,169,298,207,111,3,158,182,282,30,226,199,17,273,297,191,166,46,144,252,55,25,26,200,86,162,237,211,299,212,287,161,12,40,45,69,216,54,125,71,47,132,93,22,20,76,126,51,262,107,229,234,257,2,39,278,235,84,37,280,208,153,251,67,136,104,28,221,149,248,276,170,140,14,269,180,16,108,34,94,43,92,52,204,65,134,85,183,7,146,143,97,270,64,259,139,160,260,223,32,81,177,33,178,185,90,292,9,232,209,265,10,88,283,147,123,99,261,240,6,138,274,122,61,203,249,155,256,44,294,116,35
this function picks nItemsToPick random elements up from arr array and returns them into an array:
Function PickNRandomElementsFromArray(arr As Variant, nItemsToPick As Long) As Variant
Dim arrSize As Long
Dim i As Long, iPick As Long
Dim temp As String
arrSize = UBound(arr) '<--| count the values as the array size
If nItemsToPick > arrSize Then nItemsToPick = arrSize '<--| the items to be picked cannot exceed array size
For i = 1 To nItemsToPick
iPick = Int((arrSize - (i - 1)) * Rnd + 1) + (i - 1) '<--| pick a random number between 'i' and 'arrSize'
' swap array elements in slots 'i' and 'iPick'
temp = arr(iPick)
arr(iPick) = arr(i)
arr(i) = temp
Next i
ReDim Preserve arr(1 To nItemsToPick) '<--| resize the array to first picked items
PickNRandomElementsFromArray = arr '<--| return the array
End Function
which you can exploit as follows:
Option Explicit
Sub Authors()
Dim Authors As Variant, AuthorsList As Variant
With ThisWorkbook.Worksheets("Sheet") '<--| reference your relevant worksheet
Authors = Application.Transpose(.Range("A2", .Cells(.rows.count, 1).End(xlUp)).Value) '<--| fill 'Authors' array with its column "A" values from row 2 down to its last not empty one
AuthorsList = PickNRandomElementsFromArray(Authors, 280) '<--| fill 'AuthorsList' array with a selection of 280 random elements of 'Authors'
.Range("B1").Value = Join(AuthorsList, " OR ") '<--| fill cell "B1" with a string build by concatenating 'AuthorsList' values delimited with " OR "
End With
End Sub
that can be quite contracted (and made as much less readable) to:
Sub Authors()
With ThisWorkbook.Worksheets("Sheet") '<--| reference your relevant worksheet
.Range("B1").Value = Join(PickNRandomElementsFromArray(Application.Transpose(.Range("A2", .Cells(.rows.count, 1).End(xlUp)).Value), 280), " OR ")
End With
End Sub
From your comments, you seem to want to concatenate the array of strings, then put it back into excel. This, put just before the End Sub, will put it into cell B1 for example:
ThisWorkbook.Worksheets("Sheet1").Range("B1").Value = Join(Authorlist, "OR")

VBA-Excel / How to randomly pick up a word from a dictionary?

Lets say I have a database of words in Sheet2; it goes from A1 to B200.
I need to randomly select one of those words; and show it in Sheet1.
Moreover, I need to have on blank cell between each letter of the word.
Example: The randomly selected word is COLD; it has to appear like this:
A1: C
A3: O
A5: L
A7: D
How can I code this?
try this code:
Option Explicit
Sub main()
Dim word As String
word = GetRandomWord(Worksheets("Sheet2").Range("A1:B200")) '<--| get content of a random cell in passed range
Worksheets("Sheet1").Range("a1").Resize(2 * Len(word) - 1).Value = Application.Transpose(SeparatedChars(word)) '<--| write it down from given worksheet cell A1 down skipping every two cells
End Sub
Function SeparatedChars(strng As String) As Variant
Dim i As Long
ReDim chars(0 To Len(strng) - 1) As String '<--| size a 'String' array to the length of passed word
For i = 1 To Len(strng)
chars(i - 1) = Mid$(strng, i, 1) '<--| fill array elements with word single characters
Next
SeparatedChars = Split(Join(chars, " "), " ") '<--| return an array whose elements are those of the 'String' array and interposed spaces
End Function
Function GetRandomWord(rng As Range) As String
Randomize
GetRandomWord = rng.Cells(Int((rng.Count) * Rnd() + 1)).Text
End Function
Assuming the words are written in column A of sheet2 you could do the following (part of this solution comes from here:
Sub randomWord()
Dim rndWordRow As Integer
Dim arr() As String
Dim buff() As String
'Select row between 1 and 200 randomly'
rndWordRow = Int((200 - 1 + 1) * Rnd + 1)
'Write text of the randomly selected row into variable'
rndWord = Sheets("Sheet2").Cells(rndWordRow, 1)
'Write letters of text into array'
ReDim buff(Len(rndWord) - 1)
For i = 1 To Len(rndWord)
buff(i - 1) = Mid$(rndWord, i, 1)
Next
'Loop through array and write letters in single cells'
For i = 0 To UBound(buff)
Sheets("Sheet1").Cells(i + 1, 1) = buff(i)
Next i
End Sub
Sub Test()
Dim x As Long
Dim aWord
With Worksheets("Sheet1")
For x = 1 To 15
aWord = getRandomWord
.Cells(1, x).Resize(UBound(aWord)).value = aWord
Next
End With
End Sub
Function getRandomWord()
Dim Source As Range
Dim result
Dim i As Integer
Set Source = Worksheets("Sheet2").Range("A1:B200")
i = Int((Rnd * Source.Cells.Count) + 1)
result = StrConv(Source.Cells(i).Text, vbUnicode)
result = Split(Left(result, Len(result) - 1), vbNullChar)
getRandomWord = Application.Transpose(result)
End Function
Here's a simple solution to your problem. This routine gives you a blank cell between two letters with the first letter in the first cell.
R1 = Int(Rnd() * 200)
R2 = Int(Rnd() * 2)
anyword = Sheet2.Cells(R1, R2)
x = Len(anyword)
n = -1: i = 1
Do
n = n + 2
Sheet1.Cells(n, 1) = Mid(anyword, i, 1)
i = i + 1
Loop Until n > x * 2

excel vba add a set number of items to a collection

I have the following set of code:
For loopCounter = 2 To endRow
Dim item As Variant
Dim lineArray()
Dim myString As String
myString = Cells(loopCounter, 3).Value
ReDim lineArray(1 To endColumn)
If Not (Left(myString, 1) = "P" Or Left(myString, 1) = "I" Or myString = "RESW" Or myString = "REPC") Then
For x = 1 To endColumn
lineArray(x) = dataArray(loopCounter, x)
Next x
itemCollection.Add lineArray
End If
Next loopCounter
For the purpose of keeping this question short and to the point, I have a bunch of excel worksheets that contains hundreds of rows of data. To make a long story short, the code above add items from the worksheet to the collection, but it's adding every row (minus the conditions I set - if statement). However, I only want to add a fix amount of items to the collection, 15. I can't seem to figure it out and haven't found any help online.
My question for help is, does anyone know how I can make it that once 15 items are added to the collection it will exit out of the loop and finish the rest of the subroutine?
I purposely didn't add the whole code because it's quite lengthy and not necessary.
Thank you.
Sure thing, just check on the collection.Count > 14 then exit for
For loopCounter = 2 To endRow
Dim item As Variant
Dim lineArray()
Dim myString As String
myString = Cells(loopCounter, 3).Value
ReDim lineArray(1 To endColumn)
If Not (Left(myString, 1) = "P" Or Left(myString, 1) = "I" Or myString = "RESW" Or myString = "REPC") Then
For x = 1 To endColumn
lineArray(x) = dataArray(loopCounter, x)
Next x
itemCollection.Add lineArray
if itemCollection.Count = 15 then exit for
End If
Next loopCounter
if it would have been an array, then use if UBOUND(array) = 14 then exit for

Randomise numbers without repeating the number

My end result is to output the names in column A to column B in random order.
I have been researching but cant seem to find what I need.
So far I can kinda of randomise the numbers but its still giving me repeated numbers + the heading (A1).
I need it to skip A1 because this is the heading\title of the column and start at A2.
I assume once that is working correctly I add the randomNumber to a random name to Worksheets("Master Sheet").Cells(randomNumber, "B").Value ...something like that...?
OR if there is a better way of doing this let me know.
Sub Meow()
Dim CountedRows As Integer
Dim x As Integer
Dim i As Integer
Dim PreviousCell As Integer
Dim randomNumber As Integer
i = 1
PreviousCell = 0
CountedRows = Worksheets("Master Sheet").Range("A" & Rows.Count).End(xlUp).Row
If CountedRows < 2 Then
' If its only the heading then quit and display a messagebox
No_People_Error = MsgBox("No People entered or found, in column 'A' of Sheetname 'Master Sheet'", vbInformation, "Pavle Says No!")
Exit Sub
End If
Do Until i = CountedRows
randomNumber = Int((Rnd * (CountedRows - 1)) + 1) + 1
If Not PreviousCell = randomNumber Then
Debug.Print randomNumber
i = i + 1
End If
PreviousCell = randomNumber
Loop
Debug.Print "EOF"
End Sub
Here's a quick hack...
Sub Meow()
'On Error GoTo err_error
Dim CountedRows As Integer
Dim x As Integer
Dim i As Integer
Dim PreviousCell As Integer
Dim randomNumber As Integer
Dim nums() As Integer
PreviousCell = 0
CountedRows = Worksheets("Master Sheet").Range("A" & Rows.Count).End(xlUp).Row
ReDim nums(CountedRows - 1)
If CountedRows < 2 Then
' If its only the heading then quit and display a messagebox
No_People_Error = MsgBox("No People entered or found, in column 'A' of Sheetname 'Master Sheet'", vbInformation, "Pavle Says No!")
Exit Sub
End If
For i = 1 To CountedRows
rand:
randomNumber = randomNumbers(1, CountedRows, nums)
nums(i - 1) = randomNumber
Worksheets("Master Sheet").Range("B" & randomNumber) = Range("A" & i)
Next i
Exit Sub
err_error:
Debug.Print Err.Description
End Sub
Public Function randomNumbers(lb As Integer, ub As Integer, used As Variant) As Integer
Dim r As Integer
r = Int((ub - lb + 1) * Rnd + 1)
For Each j In used
If j = r Then
r = randomNumbers(lb, ub, used)
Else
randomNumbers = r
End If
Next
End Function
I've managed something similar previously using two collections.
Fill one collection with the original data and leave the other collection empty. Then keep randomly picking an index in the first collection, adding the value at that index to the second collection and delete the value from the original collection. Set that to loop until the first collection is empty and the second collection will be full of a randomly sorted set of unique values from your starting list.
***Edit: I've thought about it again and you don't really need the second collection. You can pop a random value from the first collection and write it directly to the worksheet, incrementing the row each time:
Sub Meow()
Dim lst As New Collection
Dim rndLst As New Collection
Dim startRow As Integer
Dim endRow As Integer
Dim No_People_Error As Integer
startRow = 2
endRow = Worksheets("Master Sheet").Cells(startRow, 1).End(xlDown).Row
If Cells(startRow, 1).Value = "" Then
' If its only the heading then quit and display a messagebox
No_People_Error = MsgBox("No People entered or found, in column 'A' of Sheetname 'Master Sheet'", vbInformation, "Pavle Says No!")
Exit Sub
End If
' Fill a collection with the original list
Dim i As Integer
For i = startRow To endRow
lst.Add Cells(i, 1).Value
Next i
' Create a randomized list collection
' Use i as a row counter
Dim rowCounter As Integer
rowCounter = startRow
Dim index As Integer
Do While lst.Count > 0
'Find a random index in the original collection
index = Int((lst.Count - 1 + 1) * Rnd + 1)
'Place the value in the worksheet
Cells(rowCounter, 2).Value = lst(index)
'Remove the value from the list
lst.Remove (index)
'Increment row counter
rowCounter = rowCounter + 1
Loop
End Sub
P.S. I hope there's an excellent story behind naming your sub Meow() :P