Selenium. How to navigate element who's href contains a certain string? [duplicate] - selenium

Question

The following is a bunch of links <a elements. ONLY one of them has a substring "long" as a value for the attribute href
<a class="c1" href= "very_lpng string" > name1 </a>
<a class="g2" href= "verylong string" > name2 </a> // The one that I need
<a class="g4" href= "very ling string" > name3 </a>
<a class="g5g" href= "very ng string" > name4 </a>
...................
I need to click the link whose href has substring "long" in it. How can I do this?
PS: driver.findElement(By.partialLinkText("long")).click(); // b/c it chooses by the name

Answer 1

I need to click the link who's href has substring "long" in it. How can I do this?
With the beauty of CSS selectors.
your statement would be...
driver.findElement(By.cssSelector("a[href*='long']")).click();
This means, in english,
Find me any 'a' elements, that have the href attribute, and that attribute contains 'long'
You can find a useful article about formulating your own selectors for automation effectively, as well as a list of all the other equality operators. contains, starts with, etc... You can find that at: http://ddavison.io/css/2014/02/18/effective-css-selectors.html

Answer 2

use driver.findElement(By.partialLinkText("long")).click();

Answer 3

You can do this:
//first get all the <a> elements
List<WebElement> linkList=driver.findElements(By.tagName("a"));
//now traverse over the list and check
for(int i=0 ; i<linkList.size() ; i++)
{
if(linkList.get(i).getAttribute("href").contains("long"))
{
linkList.get(i).click();
break;
}
}
in this what we r doing is first we are finding all the <a> tags and storing them in a list.After that we are iterating the list one by one to find <a> tag whose href attribute contains long string. And then we click on that particular <a> tag and comes out of the loop.

Answer 4

With the help of xpath locator also, you can achieve the same.
Your statement would be:
driver.findElement(By.xpath(".//a[contains(#href,'long')]")).click();
And for clicking all the links contains long in the URL, you can use:-
List<WebElement> linksList = driver.findElements(By.xpath(".//a[contains(#href,'long')]"));
for (WebElement webElement : linksList){
webElement.click();
}