How to find which indexes and constraints contain a specific column? - sql

Question

I am planing a database change and I have a list of columns included in process. Can I list all indexes in which is a specific column included?
Edit
So far I have (combined from answers):
declare #TableName nvarchar(128), #FieldName nvarchar(128)
select #TableName= N'<<Table Name>>', #FieldName =N'<<Field Name>>'
(SELECT distinct systab.name AS TABLE_NAME,sysind.name AS INDEX_NAME, 'index'
FROM sys.indexes sysind
INNER JOIN sys.index_columns sysind_col
ON sysind.object_id = sysind_col.object_id and sysind.index_id = sysind_col.index_id
INNER JOIN sys.columns sys_col
ON sysind_col.object_id = sys_col.object_id and sysind_col.column_id = sys_col.column_id
INNER JOIN sys.tables systab
ON sysind.object_id = systab.object_id
WHERE systab.is_ms_shipped = 0 and sysind.is_primary_key=0 and sys_col.name =#FieldName and systab.name=#TableName
union
select t.name TABLE_NAME,o.name, 'Default' OBJ_TYPE
from sys.objects o
inner join sys.columns c on o.object_id = c.default_object_id
inner join sys.objects t on c.object_id = t.object_id
where o.type in ('D') and c.name =#FieldName and t.name=#TableName
union
SELECT u.TABLE_NAME,u.CONSTRAINT_NAME, 'Constraint' OBJ_TYPE
FROM INFORMATION_SCHEMA.CONSTRAINT_COLUMN_USAGE u
where u.COLUMN_NAME = #FieldName and u.TABLE_NAME = #TableName
) order by 1
But I am not too happy with combining of sys. and 'INFORMATION_SCHEMA.' Can it be avoided?

Answer 1

---Using sp_helpindex and your TableName
exec sp_helpindex YourTableName
---Using sys.tables with your TableName and ColumnName
select distinct c.name, i.name, i.type_desc,...
from sys.indexes i
join sys.index_columns ic on i.index_id = ic.index_id
join sys.columns c on ic.column_id = c.column_id
where i.object_id = OBJECT_ID(N'YourTableName') and c.name = 'YourColumnName'
EDIT: As per comment, you can also join object_Ids without using distinct
select c.name, i.name, i.type_desc
from sys.indexes i
join sys.index_columns ic on i.index_id = ic.index_id and i.object_id = ic.object_id
join sys.columns c on ic.column_id = c.column_id and ic.object_id = c.object_id
where i.object_id = OBJECT_ID(N'YourTableName') and c.name = 'YourColumnName'

Answer 2

SELECT * FROM INFORMATION_SCHEMA.CONSTRAINT_COLUMN_USAGE
USE TABLE_NAME IN WHERE if you what to know the constraint on a table.
and use column_name if you know the column name.

Answer 3

To get information regarding all indexes in which is a specific column is included following two catalog views can be used:
sys.indexes , sys.index_columns
Query:
SELECT
sysind.name AS INDEX_NAME
,sysind.index_id AS INDEX_ID
,sys_col.name AS COLUMN_NAME
,systab.name AS TABLE_NAME
FROM sys.indexes sysind
INNER JOIN sys.index_columns sysind_col
ON sysind.object_id = sysind_col.object_id and sysind.index_id = sysind_col.index_id
INNER JOIN sys.columns sys_col
ON sysind_col.object_id = sys_col.object_id and sysind_col.column_id = sys_col.column_id
INNER JOIN sys.tables systab
ON sysind.object_id = systab.object_id
WHERE (1=1)
AND systab.is_ms_shipped = 0
AND sys_col.name IN(specific column list for which indexes are to be queried)
ORDER BY
systab.name,sys_col.name, sysind.name,sysind.index_id
Hope this helps!

Answer 4

If you have access to the sys schema on your database then you can query sys.indexes to get the index ID and use that with the function index_col to get the columns. The final parameter for index_col is the index of the column within the index (i.e. if there are 3 columns in the index you would have to call index_col 3 times with 1, 2, 3 in the last parameter)
select index_id from sys.indexes
where object_id = object_id(#objectname)
select index_col(#objectname, #indexid, 1)
This should give you constraints as well as they are just special indexes.