There is a strange behaviour in the connection of the commandline tools of ARQ, TDB and Named Graphs. If importing data via tdbloader in a named graph it can not be queried via GRAPH clause in a SPARQL SELECT query. However, this query is possible when inserting the data in the same graph with SPARQL INSERT.
I have following assembler description file tdb.ttl:
#prefix rdfs: <http://www.w3.org/2000/01/rdf-schema#> .
#prefix rdf: <http://www.w3.org/1999/02/22-rdf-syntax-ns#> .
#prefix ja: <http://jena.hpl.hp.com/2005/11/Assembler#> .
#prefix tdb: <http://jena.hpl.hp.com/2008/tdb#> .
[] ja:loadClass "com.hp.hpl.jena.tdb.TDB" .
tdb:DatasetTDB rdfs:subClassOf ja:RDFDataset .
tdb:GraphTDB rdfs:subClassOf ja:Model .
[] rdf:type tdb:DatasetTDB ;
tdb:location "DB" ;
.
There is a dataset in the file data.ttl:
<a> <b> <c>.
Now, I am inserting this data with tdbloader and secondly another triple with SPARQL INSERT, both in the named graph data:
tdbloader --desc tdb.ttl --graph data data.ttl
update --desc tdb.ttl "INSERT DATA {GRAPH <data> {<d> <e> <f>.}}"
Now, the data can be queried with SPARQL via:
$arq --desc tdb.ttl "SELECT * WHERE{ GRAPH ?g {?s ?p ?o.}}"
----------------------------
| s | p | o | g |
============================
| <a> | <b> | <c> | <data> |
| <d> | <e> | <f> | <data> |
----------------------------
Everything seems perfect. But now I want to query only this specifc named graph data:
$ arq --desc tdb.ttl "SELECT * WHERE{ GRAPH <data> {?s ?p ?o.}}"
-------------------
| s | p | o |
===================
| <d> | <e> | <f> |
-------------------
Why is the data imported from tdbloader missing? What is wrong with this query? How can I get results back from both imports?
Try this query:
PREFIX : <data>
SELECT * { { ?s ?p ?o } UNION { GRAPH ?g { ?s ?p ?o } } }
and the output is
----------------------------
| s | p | o | g |
============================
| <a> | <b> | <c> | <data> |
| <d> | <e> | <f> | : |
----------------------------
or try:
tdbquery --loc DB --file Q.rq -results srj
to get the results in a different form.
The text output is makign things look nice but two different things end up as <data>.
What you are seeing is that
tdbloader --desc tdb.ttl --graph data data.ttl
used data exactly as is to name the graph. But
INSERT DATA {GRAPH <data> {<d> <e> <f>.}}
does a full SPARQL parse, and resolves against the base URI, probably looking like file://*currentdirectory*.
When printing in text, URIs get abbreviated, including using the base. So both the original data (from tdbloader) and file:///path/data appear as <data>.
PREFIX : <data>
gives the text output a different way to write it as :.
Finally try:
BASE <http://example/>
SELECT * { { ?s ?p ?o } UNION { GRAPH ?g { ?s ?p ?o } } }
which sets the base URI to something no where near your data URIs so switching off nice formatting by base URI:
----------------------------------------------------------------------------------------------------------------
| s | p | o | g |
================================================================================================================
| <file:///home/afs/tmp/a> | <file:///home/afs/tmp/b> | <file:///home/afs/tmp/c> | <data> |
| <file:///home/afs/tmp/d> | <file:///home/afs/tmp/e> | <file:///home/afs/tmp/f> | <file:///home/afs/tmp/data> |
----------------------------------------------------------------------------------------------------------------
Related
My data is basically an event log in RDF. I have cases and events, the latter belong to the former. Events have timestamps and an actor who triggered them.
For each case I now need the latest event, when it happened, and who triggered it.
This is roughly my current query:
PREFIX rdf: <http://www.w3.org/1999/02/22-rdf-syntax-ns#>
PREFIX ex: <http://example.org/>
SELECT ?case ?event ?timestamp ?actor
WHERE {
?case rdf:type ex:Case ;
ex:hasEvent ?event .
?event ex:timestamp ?timestamp ;
ex:hasActor ?actor .
}
ORDER BY ASC(?case) DESC(?timestamp)
Which yields something like this:
| case | event | timestamp | actor |
=================================================================================
| ex:case1 | ex:event1 | "2020-01-01T02:00:00Z"^^xsd:dateTimeStamp | ex:Alice |
| ex:case1 | ex:event2 | "2020-01-01T01:00:00Z"^^xsd:dateTimeStamp | ex:Bob |
| ex:case2 | ex:event3 | "2020-01-01T03:00:00Z"^^xsd:dateTimeStamp | ex:Charlie |
| ex:case2 | ex:event4 | "2020-01-01T02:00:00Z"^^xsd:dateTimeStamp | ex:Dan |
However I would like to only get the first and third row, as they correspond to the latest events for this case. Like this:
| case | event | timestamp | actor |
=================================================================================
| ex:case1 | ex:event1 | "2020-01-01T02:00:00Z"^^xsd:dateTimeStamp | ex:Alice |
| ex:case2 | ex:event3 | "2020-01-01T03:00:00Z"^^xsd:dateTimeStamp | ex:Charlie |
In order to achieve this I tried to use SELECT ?case ?event (MAX(?timestamp) AS ?latest) ?actor combined with GROUP BY ?case however SPARQL complains I need to group by ?event and ?actor as well which is not what I want of course.
I am aware that PostgreSQL has DISTINCT ON which would solve my problem, but I need to do it in SPARQL. Is there a nice way to achieve this?
Self answer based on #UninformedUser's comment:
PREFIX rdf: <http://www.w3.org/1999/02/22-rdf-syntax-ns#>
PREFIX ex: <http://example.org/>
SELECT ?case ?event (?latest as ?timestamp) ?actor WHERE {
?case ex:hasEvent ?event .
?event ex:timestamp ?latest ;
ex:hasActor?actor .
{ SELECT ?case (MAX(?timestamp) AS ?latest) {
?case rdf:type ex:case ;
ex:hasEvent ?event .
?event ex:timestamp ?timestamp }
group by ?case }
}
Suppose i have data inserted into ANZO:
insert data {<a> rdf:type <c1>}
When I issue query:
prefix rdf: <http://www.w3.org/1999/02/22-rdf-syntax-ns#>
select ?s ?p ?o where {bind(rdf:type as ?p). ?s ?p ?o}
I've got the answer from console:
s | p | o
---+-------------------------------------------------+----
a | http://www.w3.org/1999/02/22-rdf-syntax-ns#type | c1
Now my question: is any way in ANZO I can get answer to console where rdf:type is shown as compressed URI:
s | p | o
---+----------+----
a | rdf:type | c1
This question already has answers here:
How to find similar content using SPARQL
(2 answers)
Closed 5 years ago.
I wanted to query the movies that have the highest number of shared type with Matrix movie.
PREFIX rdf: <http://www.w3.org/1999/02/22-rdf-syntax-ns#>
PREFIX rdfs: <http://www.w3.org/2000/01/rdf-schema#>
PREFIX dbo: <http://dbpedia.org/ontology/>
PREFIX owl: <http://www.w3.org/2002/07/owl#>
SELECT ?movie_name (count(distinct ?atype) as ?numatype)
FROM <http://dbpedia.org/>
WHERE {
?movie rdf:type dbo:Film;
rdf:type ?ftype.
dbr:The_Matrix rdf:type ?ttype.
?atype a owl:class;
owl:intersectionOf [?ftype ?ttype].
?movie rdfs:label ?movie_name.
FILTER (LANG(?movie_name)="en").
}
GROUP BY ?movie_name
ORDER BY DESC(?numatype)
LIMIT 100
I defined ?ttype as the type for The matrix movie and ?ftype as the type of ?movie.
when I query this in http://dbpedia.org/sparq there are no results.
The idea is to use a simple join on the types:
PREFIX rdf: <http://www.w3.org/1999/02/22-rdf-syntax-ns#>
PREFIX rdfs: <http://www.w3.org/2000/01/rdf-schema#>
PREFIX dbo: <http://dbpedia.org/ontology/>
SELECT (SAMPLE(?l) as ?movie_name)
(count(distinct ?ttype) as ?numSharedTypes)
WHERE {
VALUES ?s {dbr:The_Matrix}
?s a ?ttype .
?movie a dbo:Film ;
a ?ttype .
FILTER(?movie != ?s)
?movie rdfs:label ?l .
FILTER (LANGMATCHES(LANG(?l), 'en'))
}
GROUP BY ?movie
ORDER BY desc(?numSharedTypes)
LIMIT 100
The JOIN itself might be expensive, thus, you could get a timeout resp. due to the anytime feature of Virtuoso get an incomplete result back.
It looks like the query optimizer isn't that smart enough, especially the labels make the performance worse. A bunch of sub-SELECTs make it much faster, although more complex in reading the query:
PREFIX dbo: <http://dbpedia.org/ontology/>
PREFIX rdfs: <http://www.w3.org/2000/01/rdf-schema#>
PREFIX rdf: <http://www.w3.org/1999/02/22-rdf-syntax-ns#>
PREFIX dbr: <http://dbpedia.org/resource/>
SELECT ?movie_name ?numSharedTypes
WHERE
{ ?movie rdfs:label ?l
FILTER langMatches(lang(?l), "en")
BIND(replace(replace(str(?l), "\\(film\\)$", ""), "[^0-9]*\\sfilm\\)$", ")") AS ?movie_name)
{ SELECT ?movie (COUNT(?type) AS ?numSharedTypes)
WHERE
{ ?movie rdf:type dbo:Film ;
rdf:type ?type
{ SELECT ?type
WHERE
{ dbr:The_Matrix rdf:type ?type
}
}
FILTER ( ?movie != dbr:The_Matrix )
}
GROUP BY ?movie
ORDER BY DESC(?numSharedTypes) ASC(?movie)
LIMIT 100
}
}
ORDER BY DESC(?numSharedTypes) ASC(?movie_name)
Result (chunk):
+------------------------+----------------+
| movie_name | numSharedTypes |
+------------------------+----------------+
| The Matrix Reloaded | 36 |
| The Matrix Revolutions | 33 |
| The Matrix (franchise) | 30 |
| Demolition Man | 28 |
| Freejack | 28 |
| Conspiracy Theory | 27 |
| Deep Blue Sea (1999) | 27 |
| Fair Game (1995) | 27 |
| Judge Dredd | 27 |
| Revenge Quest | 27 |
| Screamers (1995) | 27 |
| Soldier (1998) | 27 |
| The Invasion | 27 |
| Timecop | 27 |
| Total Recall (1990) | 27 |
| V for Vendetta | 27 |
| Assassins | 26 |
| ... | ... |
+------------------------+----------------+
I am using TopBraid Composer for writing SPARQL queries. I have queried the following result:
| Header | Total |
|-------- |------- |
| | |
| A | 5 |
| | |
| B | 6 |
| | |
| C | 7 |
| | |
| D | 8 |
Now my humble question is whether we can transpose the result somehow as follows:
| Header | A | B | C | D |
|-------- |--- |--- |--- |--- |
| Total | 5 | 6 | 7 | 8 |
Yes and no. The first notation you use is essential for understanding SPARQL SELECT - each row represents a separate graph pattern match on the data where the first column shows the binding for ?Header and the second column shows the binding for ?Total, per your unstated query. E.g. in one of the matches, ?Header is bound to "A" and ?Total is bound to "5". Another match is ?Header = "B" and ?Total = "6", etc. (I'd suggest doing some homework on SPARQL)
From that, any language computing the SPARQL query will have some means of iterating over the result set, and you can place them in an inverted table as you show.
So, no, SPARQL can't do that (look into SPARQL graph pattern matching), but whatever language you are using should be able to iterate over the result set to get what you are looking for.
you can use a filtered left outer join query to build your own transposed table (aka pivot table).
PREFIX wd: <http://cocreate-cologne.wiki.opencura.com/entity/>
PREFIX wdt: <http://cocreate-cologne.wiki.opencura.com/prop/direct/>
PREFIX wikibase: <http://wikiba.se/ontology#>
PREFIX p: <http://cocreate-cologne.wiki.opencura.com/prop/>
PREFIX ps: <http://cocreate-cologne.wiki.opencura.com/prop/statement/>
PREFIX pq: <http://cocreate-cologne.wiki.opencura.com/prop/qualifier/>
PREFIX rdfs: <http://www.w3.org/2000/01/rdf-schema#>
PREFIX bd: <http://www.bigdata.com/rdf#>
select ?item ?itemLabel ?enthalten_in1Label ?enthalten_in2Label ?enthalten_in3Label {
SELECT ?item ?itemLabel ?enthalten_in1Label ?enthalten_in2Label ?enthalten_in3Label WHERE {
SERVICE wikibase:label { bd:serviceParam wikibase:language "[AUTO_LANGUAGE],de". }
?item p:P3 ?statement.
?statement ps:P3 wd:Q15.
?statement pq:P13 wd:Q17.
OPTIONAL { ?item wdt:P11 ?buendnis. FILTER (?buendnis in (wd:Q32)) }
OPTIONAL { ?item wdt:P11 ?sdgKarte. FILTER (?sdgKarte in (wd:Q14)) }
OPTIONAL { ?item wdt:P11 ?agora. FILTER (?agora in (wd:Q3)) }
BIND(?buendnis as ?enthalten_in1).
BIND(?sdgKarte as ?enthalten_in2).
BIND(?agora as ?enthalten_in3).
#debug
#Filter (?item in (wd:Q1))
}
LIMIT 2000
} ORDER BY ?itemLabel
I want to extract a chain of instances between two instances of my ontology by asking a SPARQL query. for example in the following figure if I want to know how A is connected to E, the result of query should be something like a list of A, B, D, F, E.
how the ontology should be designed and query should be built?
Is it even possible?
This isn't too hard. In RDF, your data can be something as simple as a direct encoding of the graph:
#prefix : <urn:ex:>
:A :connectedTo :B .
:B :connectedTo :C, :D .
:D :connectedTo :F .
:F :connectedTo :E, :G .
Then, using SPARQL property paths, you can find every node such that there's a path of connectedTo properties from A to it and from it to E, including A and E themselves:
prefix : <urn:ex:>
select ?mid where {
:A :connectedTo* ?mid .
?mid :connectedTo* :E .
}
-------
| mid |
=======
| :D |
| :F |
| :B |
| :A |
| :E |
-------
If you want to get those in order, you can additionally count how many things are between A and the "mid-node". (This is described in my answer to Is it possible to get the position of an element in an RDF Collection in SPARQL?)
prefix : <urn:ex:>
select ?mid (count(?premid) as ?i) where {
:A :connectedTo* ?premid .
?premid :connectedTo* ?mid .
?mid :connectedTo* :E .
}
group by ?mid
-----------
| mid | i |
===========
| :D | 3 |
| :F | 4 |
| :E | 5 |
| :B | 2 |
| :A | 1 |
-----------
If you actually want a single result that looks more or less like "A, B, C, D, E, F", then you adapt these queries using the techniques from my answer to Aggregating results from SPARQL query, which shows how to concatenate these into a single string.