Oracle Apex Pie Chart SQL Statement - sql

i'm not really much into SQL & Apex, but i need one statement and I would really appreciate your help on this.
The syntax of Apex pie charts is this:
SELECT link, label, value
My table looks like these simple sketch:
+------+-----------+---------+
| ID | Company | Item |
+------+-----------+---------+
| 1 | AAA |Some |
| 2 | BB |Stuff |
| 3 | BB |Not |
| 4 | CCCC |Important|
| 5 | AAA |For |
| 6 | DDDDD |Question?|
+------+-----------+---------+
I want to show the percentage of the companies.
Problem: All companies with less than 5 items should combine to one colum "other". The difficulty for me is to combine the "unimportant" companies.
Until now my statement looks like this:
SELECT null link,
company label,
COUNT(ID) value FROM table HAVING COUNT(ID) > 5 GROUP BY company
Here a wonderful diagram-sketch. :D
Thank you for your ideas!

I've not got SQL Developer in front of me but this (or a close variation) should work for you:
WITH company_count
AS (
SELECT CASE
WHEN count(*) < 5
THEN 'Other'
ELSE company
END AS company_name,
id
FROM tablename
),
company_group
AS (
SELECT company_name,
count(id) item_count
FROM company_count
GROUP BY company_name
)
SELECT NULL AS link,
company_name AS label,
item_count AS value
FROM company_group;
Hope it helps!

Okay Guys, I found the answer for my use case. Its quite similar to Ollies answer. Thanks again for the help!
WITH sq1 AS (SELECT company, COUNT (*) AS count FROM
(SELECT CASE WHEN COUNT (*) OVER (Partition By company) > 5 THEN company
ELSE 'other' END AS company, id FROM table) GROUP BY company)
SELECT null link, company label, count value FROM sq1 ORDER BY count desc

Related

Counting distinct stores SQL

I am fairly new to SQL and was wondering if anyone could help with my code.
I am trying to count the distinct number of stores that are tied to a certain Warehouse which is tied to a purchase order.
Example: If there are 100 stores with this PO that came from Warehouse #2 or #5 or etc... then I would like:
| COUNT_STORE | WH_LOCATION |
1 | 100 | 2 |
2 | 25 | 5 |
3 | 56 | 1 |
[]
My Code:
select count(distinct Store_ID) as Count_Store, WH_Location
from alc_Loc
where alloc_PO = 11345
group by Store_ID, WH_Location
When I run this I get a 1 for "count_store" and it shows me the WH_Location multiple times. I feel as if something is not tying in correctly.
Any help is appreciated!
Just remove store_id from the group by:
select count(distinct Store_ID) as Count_Store, WH_Location
from alc_Loc
where alloc_PO = 11345
group by WH_Location;
When you include Store_ID in the group by, you are getting a separate row for each Store_ID. The distinct count is then obviously 1 (or 0 if the store id is NULL).

"Transpose" of a table in Oracle

I'm having quite a bit of trouble figuring out exactly how to rearrange a table. I have a large table that looks something like this:
+--------+-----------+
| NAME | ACCOUNT # |
+--------+-----------+
| Nike | 87 |
| Nike | 12 |
| Adidas | 80 |
| Adidas | 21 |
+--------+-----------+
And I want to rearrange it to look like this:
+------+--------+
| Nike | Adidas |
+------+--------+
| 87 | 80 |
| 12 | 21 |
+------+--------+
But I can't seem to figure out how. I tried using PIVOT, but that only works with aggregate functions. I tried using a FOR LOOP as well, but couldn't get it work just right.
You can do this in several ways, but all being by enumerating the rows. Here is an example using conditional aggregation:
select max(case when name = 'Nike' then account end) as Nike,
max(case when name = 'Adidas' then account end) as Adidas
from (select t.*,
row_number() over (partition by name order by account desc) as seqnum
from t
) t
group by seqnum;
Consider again a pivot solution but first adding a rownumber for rolling Name group counts. Below assumes an autonumber ID field:
SELECT * FROM
(
SELECT Name, "Account #",
(ROW_NUMBER() OVER(PARTITION BY Name ORDER BY ID)) GrpRowNum
/* ALT: (SELECT Count(*) FROM Table1 sub
* WHERE sub.Name = Table1.Name AND sub.ID <= Table1.ID) GrpRowNum */
FROM Table1
)
PIVOT
(
SUM("Account #")
FOR Name IN ('Nike', 'Adidas')
)
ORDER BY RowNum;
However, for your ~200 items, you cannot easily render the Pivot's IN clause without various workarounds including PIVOT XML output or stored procedures with PL/SQL. Similarly, you could use general purpose coding (Java, PHP, Python, R) to retreive SELECT DISTINCT Name FROM Table1 resultset in vector/array, joining element values (collapsing or imploding arrays) with quotes and comma separators, and dropping the entire list in IN clause.

How to find every customers' favourite category with a query

I have a table in MS Access which looks basically like this:
Table Name : Customer_Categories
+----------------------+------------+-------+
| Email | CategoryID | Count |
+----------------------+------------+-------+
| jim#example.com | 10 | 4 |
+----------------------+------------+-------+
| jim#example.com | 2 | 1 |
+----------------------+------------+-------+
| simon#example.com | 5 | 2 |
+----------------------+------------+-------+
| steven#example.com | 10 | 16 |
+----------------------+------------+-------+
| steven#example.com | 5 | 3 |
+----------------------+------------+-------+
In this table there are ≈ 350,000 records. The characteristics are this:
Duplicate values for Email, CategoryID and Count
Count refers to the number of times this customer has ordered from this category
What I want
I want to create a table that consists of a unique email address along with the CategoryID this customer has purchased from the most.
So the above example would be:
+----------------------+------------+
| Email | CategoryID |
+----------------------+------------+
| jim#example.com | 10 |
+----------------------+------------+
| simon#example.com | 5 |
+----------------------+------------+
| steven#example.com | 10 |
+----------------------+------------+
What I have tried
I have written a query that achieves what I want:
SELECT main.Email, (SELECT TOP 1 CategoryID
FROM Customer_Categories
WHERE main.Email = Email
GROUP BY CategoryID
ORDER BY MAX(Count) DESC, CategoryID ASC) AS Category
FROM Customer_Categories AS main
GROUP BY main.Email;
This works a treat and does exactly what I want. It returns results in around 8 seconds. However I need this data in a new table because I then want to update another table with the categoryID. When I add INTO Customer_Favourite_Categories after the sub-query to add this data to a new table rather than just return the result set and run the query it never finishes. I've left it running for about 45 minutes and it does nothing.
Is there any way around this?
If select into doesn't work, use insert into:
create table Customer_Favorite_Categories (
email <email type>,
FavoriteCategory <CategoryId type>
);
insert into Customer_Favorite_Categories
SELECT main.Email, (SELECT TOP 1 CategoryID
FROM Customer_Categories
WHERE main.Email = Email
GROUP BY CategoryID
ORDER BY MAX(Count) DESC, CategoryID ASC) AS Category
FROM Customer_Categories AS main
GROUP BY main.Email;
Try this:
SELECT Distinct(Email),Max(CategoryID )
FROM Customer_Categories group by Email
I use sub-queries for this quite frequently. Your query in "What I have tried" is close, but just a little off in syntax. Something like the following should get what you are after. Count is in square-brackets since it's a reserved word in SQL. The spacing I use in my SQL is conventional, so edit to your liking.
SELECT Email,
CategoryID
FROM MyTable AS m,
(
SELECT Email,
MAX( [Count] ) AS mc
FROM MyTable
GROUP BY Email
) AS f
WHERE m.Email = f.Email
AND m.[Count] = f.mc;

MIN() Function in SQL

Need help with Min Function in SQL
I have a table as shown below.
+------------+-------+-------+
| Date_ | Name | Score |
+------------+-------+-------+
| 2012/07/05 | Jack | 1 |
| 2012/07/05 | Jones | 1 |
| 2012/07/06 | Jill | 2 |
| 2012/07/06 | James | 3 |
| 2012/07/07 | Hugo | 1 |
| 2012/07/07 | Jack | 1 |
| 2012/07/07 | Jim | 2 |
+------------+-------+-------+
I would like to get the output like below
+------------+------+-------+
| Date_ | Name | Score |
+------------+------+-------+
| 2012/07/05 | Jack | 1 |
| 2012/07/06 | Jill | 2 |
| 2012/07/07 | Hugo | 1 |
+------------+------+-------+
When I use the MIN() function with just the date and Score column I get the lowest score for each date, which is what I want. I don't care which row is returned if there is a tie in the score for the same date. Trouble starts when I also want name column in the output. I tried a few variation of SQL (i.e min with correlated sub query) but I have no luck getting the output as shown above. Can anyone help please:)
Query is as follows
SELECT DISTINCT
A.USername, A.Date_, A.Score
FROM TestTable AS A
INNER JOIN (SELECT Date_,MIN(Score) AS MinScore
FROM TestTable
GROUP BY Date_) AS B
ON (A.Score = B.MinScore) AND (A.Date_ = B.Date_);
Use this solution:
SELECT a.date_, MIN(name) AS name, a.score
FROM tbl a
INNER JOIN
(
SELECT date_, MIN(score) AS minscore
FROM tbl
GROUP BY date_
) b ON a.date_ = b.date_ AND a.score = b.minscore
GROUP BY a.date_, a.score
SQL-Fiddle Demo
This will get the minimum score per date in the INNER JOIN subselect, which we use to join to the main table. Once we join the subselect, we will only have dates with names having the minimum score (with ties being displayed).
Since we only want one name per date, we then group by date and score, selecting whichever name: MIN(name).
If we want to display the name column, we must use an aggregate function on name to facilitate the GROUP BY on date and score columns, or else it will not work (We could also use MAX() on that column as well).
Please learn about the GROUP BY functionality of RDBMS.
SELECT Date_,Name,MIN(Score)
FROM T
GROUP BY Name
This makes the assumption that EACH NAME and EACH date appears only once, and this will only work for MySQL.
To make it work on other RDBMSs, you need to apply another group function on the Date column, like MAX. MIN. etc
SELECT T.Name, T.Date_, MIN(T.Score) as Score FROM T
GROUP BY T.Date_
Edit: This answer is not corrected as pointed out by JNK in comments
SELECT Date_,MAX(Name),MIN(Score)
FROM T
GROUP BY Date_
Here I am using MAX(NAME), it will pick one name if two names were found with the same goal numbers.
This will find Min score for each day (no duplicates), scored by any player. The name that starts with Z will be picked first than the name that starts with A.
Edit: Fixed by removing group by name

Problem with advanced distinct SQL query

Ok this one is realy tricky :D
i have a this table
bills_products:
- bill_id - product_id - action -
| 1 | 4 | add |
| 1 | 5 | add |
| 2 | 4 | remove |
| 2 | 1 | add |
| 3 | 4 | add |
as you can see product with the id 4 was added at bill 1 then removed in bill 2 and added again in bill 3
All Bills belong to a bill_group. But for the simplicity sake let's assume all the bills are in the same group.
Now i need a SQL Query that shows all the products that are currently added at this group.
In this example that would be 5, 1 and 4. If we would remove the bill with id 3 that would be 5 and 1
I've tried to do this with DISTINCT but it's not powerful enough or maybe I'm doing it wrong.
This seems to work in SQL Server at least:
select product_id
from (
select product_id,
sum((case when action='add' then 1 else -1 end)) as number
from bills_products
group by product_id
) as counts
where number > 0
SELECT DISTINCT product_id FROM bills_products WHERE action = 'add';
GSto almost had it, but you have to ORDER BY bill_id DESC to ensure you get the latest records.
SELECT DISTINCT product_id FROM bills_products
WHERE action = 'add'
ORDER BY bill_id DESC;
(P.S. I think most people would say it's a best practice to have a timestamp column on tables like this where you need to be able to know what the "newest" row is. You can't always rely on ids only ascending.)