How to display the calculated value only one time using sql query - sql

Question

I have the following query :
`
select e.empid, convert(char(5), tr.In_Time, 108) as In_time,
convert(char(5), tr.Out_Time, 108) as Out_time,
convert(varchar(5), sum(datediff(minute, trr.In_Time, isnull(trr.Out_Time, null))) / 60)
+ ':' +
convert(varchar(5),sum(datediff(minute, trr.In_Time, isnull(trr.Out_Time,null))) % 60)
as TotalHours,
from EMPLOYEES e
Left Join EMPLOYEE_TIME tr
on (e.empid=tr.empid)
Left Join EMPLOYEE_TIME trr
on (e.empid=trr.empid)
where (
trr.In_Time BETWEEN '2013-09-11' AND DATEADD(DAY, 1, '2013-09-11')
and tr.In_Time BETWEEN '2013-09-11' AND DATEADD(DAY, 1, '2013-09-11')
) group by e.empid, tr.In_Time, tr.Out_Time e.JoiningDate order by e.JoiningDate ASC
`
After executing above query, i get the following result :
`
EmpID in_time out_time totalhours
1 9:30 18:00 8:30
2 10:00 13:00 8:00
2 14:00 19:00
3 10:30 13:30 3:00
3 14:30 NULL 3:00
`
But i don't want to print the totalhours twice when multiple time entry Out_time is Null, as like below :
`
EmpID in_time out_time totalhours
1 9:30 18:00 8:30
2 10:00 13:00 8:00
2 14:00 19:00
3 10:30 13:30 3:00
3 14:30 NULL
`
Could anybody please help me? thanks in advance
WORKING SQL
SELECT e.empid ,
CONVERT(CHAR(5), tr.In_Time, 108) AS In_time ,
CONVERT(CHAR(5), tr.Out_Time, 108) AS Out_time ,
CONVERT(VARCHAR(5), SUM(DATEDIFF(minute, trr.In_Time,
ISNULL(trr.Out_Time, NULL))) / 60)
+ ':' + CONVERT(VARCHAR(5), SUM(DATEDIFF(minute, trr.In_Time,
ISNULL(trr.Out_Time, NULL)))
% 60) AS TotalHours
FROM EMPLOYEES e
LEFT JOIN EMPLOYEE_TIME tr ON ( e.empid = tr.empid )
LEFT JOIN EMPLOYEE_TIME trr ON ( e.empid = trr.empid )
WHERE ( trr.In_Time BETWEEN '2013-09-11'
AND DATEADD(DAY, 1, '2013-09-11')
AND tr.In_Time BETWEEN '2013-09-11'
AND DATEADD(DAY, 1, '2013-09-11')
)
GROUP BY e.empid ,
tr.In_Time ,
tr.Out_Time ,
e.JoiningDate
ORDER BY e.JoiningDate ASC

Answer 1

JUST USE CASE WHEN
LIKE
CASE WHEN Out_Time IS NOT NULL THEN convert(varchar(5),sum(datediff(minute, trr.In_Time, isnull(trr.Out_Time,null))) % 60)
ELSE NULL END

Answer 2

Based on your example, it seems that you only want the hours on the first row for each EmpID. (If not, please update the question with additional data that are exceptions to this.)
Assuming this, here is a method using row_number():
with yourquery as (<your query here>)
select EmpID, in_time, out_time,
(case when seqnum = 1 then totalhours end) as totalhours
from (select yq.*,
row_number() over (partition by EmpId order by in_time) as seqnum
from yourquery yq
) yq;
EDIT:
This is what it should look like:
with yourquery as (
SELECT e.empid ,
CONVERT(CHAR(5), tr.In_Time, 108) AS In_time ,
CONVERT(CHAR(5), tr.Out_Time, 108) AS Out_time ,
CONVERT(VARCHAR(5), SUM(DATEDIFF(minute, trr.In_Time,
ISNULL(trr.Out_Time, NULL))) / 60)
+ ':' + CONVERT(VARCHAR(5), SUM(DATEDIFF(minute, trr.In_Time,
ISNULL(trr.Out_Time, NULL)))
% 60) AS TotalHours
FROM EMPLOYEES e
LEFT JOIN EMPLOYEE_TIME tr ON ( e.empid = tr.empid )
LEFT JOIN EMPLOYEE_TIME trr ON ( e.empid = trr.empid )
WHERE ( trr.In_Time BETWEEN '2013-09-11'
AND DATEADD(DAY, 1, '2013-09-11')
AND tr.In_Time BETWEEN '2013-09-11'
AND DATEADD(DAY, 1, '2013-09-11')
)
GROUP BY e.empid ,
tr.In_Time ,
tr.Out_Time ,
e.JoiningDate
)
select yq.EmpID, yq.in_time, yq.out_time,
(case when seqnum = 1 then yq.totalhours end) as totalhours
from (select yq.*,
row_number() over (partition by yq.EmpId order by in_time) as seqnum
from yourquery yq
) yq
ORDER BY yq.JoiningDate ASC