Multiple join not joining as expected - sql

I have the following tables
table 2 with a fk to table 1
table 3 with a fk to table 1
In table 2 I have two rows linked to table 1
In table 3 I have one row linked table 1
I am trying to produce a table that has
| table1 pk | table 2 pk | null |
| table1 pk | table 2 pk | null |
| table1 pk | null | table 3 pk |
However when I try the following I get
select tab1.id, tab2.id, tab3.id
from table1 tab1
left join tab2 on tab1.id = tab2.tab1_id
left join tab3 on tab1.id = tab3.tab1_id
gives this table
| table1 pk | table 2 pk | table 3 pk |
| table1 pk | table 2 pk | table 3 pk |
Can anyone help with this SQL please?
Thanks in advance
EDIT
I think I may have simplified this a bit too much. Ideally output would be
| table1 pk | table 2 pk |
| table1 pk | table 3 pk |
| table1 pk | table 3 pk |
Once I get this join working it will be added to another massive query...

One unusual solution is
select coalesce(t2.tab1_id, t3.tab1_id) pk,
t2.pk, t3.pk
from table2 t2
full join table3 t3
on t3.tab1_id = t2.tab1_id
where exists (select * from table1
where pk in (t2.tab1_id, t3.tab1_id)
NOTE (Edit) As noted by Andriy M in comment, the where clause only eliminates rows from table2 and table3 where the FK does not exist in table1, which cannot exist if FK constraints have been properly applied to table2 and table3.

I don't see anything crazy here
WITH TAB1
AS (SELECT 1 AS ID FROM DUAL
UNION ALL
SELECT 2 AS ID FROM DUAL
UNION ALL
SELECT 3 AS ID FROM DUAL),
TAB2
AS (SELECT 1 AS TAB1_ID, 'A' AS ID FROM DUAL
UNION ALL
SELECT 2 AS TAB1_ID, 'B' AS ID
FROM DUAL),
TAB3
AS (SELECT 3 AS TAB1_ID, 'C' AS ID
FROM DUAL)
SELECT
TAB1.ID,
COALESCE ( TAB2.ID,
TAB3.ID )
FROM
TAB1
LEFT JOIN TAB2
ON TAB1.ID = TAB2.TAB1_ID
LEFT JOIN TAB3
ON TAB1.ID = TAB3.TAB1_ID;
1 A
2 B
3 C

You could use a join to the result of a union:
SELECT
t1.table1pk,
t23.table2pk,
t23.table3pk
FROM table1 t1
INNER JOIN
(
SELECT table2pk, NULL AS table3pk, table1fk
FROM table2
UNION ALL
SELECT NULL AS table2pk, table3pk, table1fk
FROM table3
) t23
ON t1.table1pk = t23.table1fk
;
Or you could use a union of two joins' results:
SELECT
t1.table1pk,
t2.table2pk,
NULL AS table3pk
FROM table1 t1
INNER JOIN table2 t2
ON t1.table1pk = t2.table1fk
UNION ALL
SELECT
t1.table1pk,
NULL AS table2pk,
t3.table3pk
FROM table1 t1
INNER JOIN table3 t3
ON t1.table1pk = t3.table1fk
;
Both methods could be adapted to produce the two-column version of the desired output:
a join to a union:
SELECT
t1.table1pk,
t23.otherpk
FROM table1 t1
INNER JOIN
(
SELECT table2pk AS otherpk, table1fk
FROM table2
UNION ALL
SELECT table3pk AS otherpk, table1fk
FROM table3
) t23
ON t1.table1pk = t23.table1fk
;
a union of joins:
SELECT
t1.table1pk,
t2.table2pk AS otherpk
FROM table1 t1
INNER JOIN table2 t2
ON t1.table1pk = t2.table1fk
UNION ALL
SELECT
t1.table1pk,
t3.table3pk AS otherpk
FROM table1 t1
INNER JOIN table3 t3
ON t1.table1pk = t3.table1fk
;

Related

prefer table 3 over table 2 and table 2 over table 1

I have 3 tables with names and number of few of my friends.
Table 3 has correct data, table 2 has minute errors in data and table 1 has more than table 2.
if a user exists in table 2 and 3 then show table 3 details in output else table 2 details, if user is not even there in table 2 then show user data from table1.
more like a preference order.
DUMMY DATA:
table 1 :
name phone
abc 2343
bcd 3434
ccd 3455
ffc 4545
table 2 :
name phone
abc 2313
bcd 3414
ccd 3415
table 3 :
name phone
abc 2344
bcd 3431
expected output :
name phone
abc 2344
bcd 3431
ccd 3415
ffc 4545
I tried this query but unable to find correct output.
select phone,
coalesce(table1.name, TABLE2.name,TABLE3.name) as namee
FROM TABLE1
left JOIN TABLE2
ON table1.name = table2.name
INNER JOIN table3
ON table3.name = table2.name
Would be a huge, huge heeelppppp.
Gordon was close; he had the preference backwards. Please make sure you understand why the script works.
-- grab all our preferred data first
select t3.*
from table3 t3
union all
-- grab anything that doesn't exist in our preferred table
select t2.*
from table2 t2
where not exists (select 1 from table3 t3 where t3.name = t2.name)
union all
-- grab anything that doesn't exist in our preferred tables
select t1.*
from table1 t1
where not exists (select 1 from table2 t2 where t2.name = t1.name) and
not exists (select 1 from table3 t3 where t3.name = t1.name);
Use union all:
select t1.*
from table1 t1
union all
select t2.*
from table2 t2
where not exists (select 1 from table1 t1 where t1.name = t2.name)
union all
select t3.*
from table3 t3
where not exists (select 1 from table1 t1 where t1.name = t3.name) and
not exists (select 1 from table2 t2 where t2.name = t3.name);

Eliminating NOT IN from query

I'm trying to eliminate the need to use NOT IN in my query:
select count(*)
FROM TABLE1 T1
LEFT OUTER JOIN TABLE2 T2
ON T1.DATAID = T2.EXISTING_DOCUMENT
AND T1.ownerid = -2000
AND T1.SUBTYPE = 144
AND T1.dataid NOT IN (SELECT T3.dataid
FROM TABLE3 T3
WHERE T3.ID = 123)
Reason: I read that NOT IN is slow (+500k rows) and doesn't use indices
I tried:
select count(*)
FROM TABLE1 T1
LEFT OUTER JOIN TABLE2 T2
ON T1.DATAID = T2.EXISTING_DOCUMENT
AND T1.ownerid = -2000
AND T1.SUBTYPE = 144
left outer join TABLE3 T3
on T3.ancestorid = T1.dataid
where T3.ID = 123
NOT IN does use indices, at least in a competent database such as Oracle. However, you can write this using joins if you prefer.
But, why doesn't this do what you want?
select count(*)
FROM TABLE1 T1
WHERE T1.ownerid = -2000 AND T1.SUBTYPE = 144;
You are using a LEFT JOIN, so the only difference is that your version counts duplicates in TABLE2. But that may not really apply.
Your query doesn't really make sense, because you are comparing T1.dataid to T1.dataid. But, further, the comparison to Table3 has no impact on the result. So, you can just remove it:
select count(*)
FROM TABLE1 T1 LEFT OUTER JOIN
TABLE2 T2
ON T1.DATAID = T2.EXISTING_DOCUMENT AND
T1.ownerid = -2000 AND
T1.SUBTYPE = 144 ;
Because of the LEFT JOIN, filtering in the ON clause will not remove any rows. And because it is NOT IN, there is no possibility of duplication.
Use a WHERE x IS NULL filter to emulate a NOT IN.
SQL Fiddle
Oracle 11g R2 Schema Setup:
CREATE TABLE t1 ( ownerid int, subtype int, dataid int, note varchar(100) ) ;
INSERT INTO t1 ( ownerid, subtype, dataid, note )
SELECT 1 as ownerid, 1 as subtype, 1 as dataid, 'WHERE Filter' as note FROM DUAL UNION ALL
SELECT -2000, 1,1, 'IN WHERE Filter' FROM DUAL UNION ALL
SELECT -2000,144,1, 'IN WHERE, NOT IN t3' FROM DUAL UNION ALL
SELECT -2000,144,2, 'IN WHERE, IN t3' FROM DUAL UNION ALL
SELECT -2000,144,3, 'IN WHERE, NOT IN t3' FROM DUAL
;
CREATE TABLE t2 ( existing_document int, note varchar(100) ) ;
INSERT INTO t2 (existing_document, note)
SELECT 1 as existing_document, 'JOIN t1' as note FROM DUAL UNION ALL
SELECT 2, 'JOIN t1' FROM DUAL UNION ALL
SELECT 2, 'JOIN t1, DUPE' FROM DUAL UNION ALL
SELECT 3, 'JOIN t1' FROM DUAL UNION ALL
SELECT 3, 'JOIN t1, DUPE' FROM DUAL UNION ALL
SELECT 4, 'NOT JOIN t1' FROM DUAL
;
CREATE TABLE t3 ( id int, dataid int, note varchar(100) ) ;
INSERT INTO t3 (id, dataid, note)
SELECT 1 as id, 1 as dataid, 'No filter. No match.' as note FROM DUAL UNION ALL
SELECT 1, 4, 'No filter. No match t1.' FROM DUAL UNION ALL
SELECT 123,2,'Match JOIN filter. Match t1' FROM DUAL
;
Read the notes in the setup to view how I'm building up the data. It's very simple and not a lot to count, but it should give you an idea on how this data works together.
Query:
SELECT * /* Not counting here so you can see what's supposed to be counted. */
FROM t1
INNER JOIN t2 ON t1.dataid = t2.EXISTING_DOCUMENT
LEFT OUTER JOIN t3 ON t1.dataid = t3.dataid
AND t3.ID = 123
WHERE t1.ownerid = -2000
AND t1.subtype = 144
AND t3.dataid IS NULL /* This is the NOT IN */
Results:
| OWNERID | SUBTYPE | DATAID | NOTE | EXISTING_DOCUMENT | NOTE | ID | DATAID | NOTE |
|---------|---------|--------|---------------------|-------------------|---------------|--------|--------|--------|
| -2000 | 144 | 1 | IN WHERE, NOT IN t3 | 1 | JOIN t1 | (null) | (null) | (null) |
| -2000 | 144 | 3 | IN WHERE, NOT IN t3 | 3 | JOIN t1 | (null) | (null) | (null) |
| -2000 | 144 | 3 | IN WHERE, NOT IN t3 | 3 | JOIN t1, DUPE | (null) | (null) | (null) |
The optimizer usually runs very well with the WHERE x IS NULL syntax and indexes should still apply, but if Oracle is able to make use of the indexes in the NOT IN, that is a big plus. If you're dealing with a lot of data, the IS NULL method can be a lot faster. The best check is to just test it with your actual data.
how about NOT EXISTS?
select count(*)
FROM TABLE1 T1
LEFT OUTER JOIN TABLE2 T2
ON T1.DATAID = T2.EXISTING_DOCUMENT
AND T1.ownerid = -2000
AND T1.SUBTYPE = 144
AND NOT EXISTS (SELECT 1
FROM TABLE3 T3
WHERE T3.ID = 123
AND T3.dataid = T1.dataid)

Inner Join on 2 tables having multiple join value

I have the following tables where a few of the columns are included here:
Table 1:
Id RefId PhoneNumber
1 11 919191
2 11 888888
3 11 919191
Table 2:
Id RefId City UniqueId
1 11 Mumbai 111
2 11 Pune 222
3 11 Nashik 333
I want a few columns from Table1 and Table2. Common in both table is RefId. Table2 has UniqueId which is primary key of Table2. If I do an inner join based on RefId I will get 9 records, but I want 3. How do I get that?
Here is my query:
SELECT T1.PhoneNumber,T2.City,T2.UniqueId,T2.RefId
FROM Table1 T1
INNER JOIN Table2 T2
ON T1.RefId = T2.RefId
If the ID is used to join as well then
SELECT t1.Id, t1.RefId, t1.PhoneNumber, t2.City, t2.UniqueId
FROM Table1 t1
INNER JOIN Table2 t2
ON t1.Id = t2.Id
AND t1.RefId = t2.RefId
If the Ids are randomly generated them you probably shouldn't join on them.
If the Ids were random but all of the PhoneNumbers were for the same place then you could just pick the Minimum value PhoneNumber (or Max)
SELECT t2.RefId, t1.PhoneNumber, t2.City, t2.UniqueId
FROM Table2 t2
INNER JOIN (
SELECT RefId, MIN(PhoneNumber) AS PhoneNumber
FROM Table1
GROUP BY RefId
) t1 ON t1.RefId = t2.RefId

Get groups that are exactly equal to a table

I have a query that groups easily. I need to get the groups that have exactly the same records to another table (relationship).
I'm using ANSI-SQL under SQL Server, but I accept an answer of any implementation.
For example:
Table1:
Id | Value
---+------
1 | 1
1 | 2
1 | 3
2 | 4
3 | 2
4 | 3
Table2:
Value | ...
------+------
1 | ...
2 | ...
3 | ...
In my example, the result is:
Id |
---+
1 |
How imagined that it could be the code:
SELECT Table1.Id
FROM Table1
GROUP BY Table1.Id
HAVING ...? -- The group that has exactly the same elements of Table2
Thanks in advance!
You can try the following:
select t1.Id
from Table2 t2
join Table1 t1 on t1.value = t2.value
group by t1.Id
having count(distinct t1.value) = (select count(*) from Table2)
SQLFiddle
To get the same sets use an inner join:
SELECT Table1.Id
FROM Table1
INNER JOIN table2 ON table1.id=table2.id
GROUP BY Table1.Id
HAVING ...? --
CREATE TABLE #T1 (ID INT , [Values] INT) INSERT INTO #T1 VALUES (1,1),(1,2),(1,3),(2,4),(2,5),(3,6)
CREATE TABLE #T2 ([Values] INT) INSERT INTO #T2 VALUES (1),(2),(3),(4)
SELECT * FROM #T1
SELECT * FROM #T2
SELECT A.ID
FROM
( SELECT ID , COUNT(DISTINCT [Values]) AS Count FROM #T1
GROUP BY ID
) A
JOIN
(
SELECT T1.ID, COUNT(DISTINCT T2.[Values]) Count
FROM #T1 T1
JOIN #t2 T2
ON T1.[Values] = T2.[Values]
GROUP BY T1.ID
) B
ON A.ID = B.ID AND A.Count = B.Count

Within a SQL Server view - how to combine multiple column results into one column

I have a SQL Server database with the following 2 tables:
I have created a view with the following query and results:
My question is what query would bring the (3) ID columns in 'Table2' into one master ID List to where the final result would look like this:
ID Table1ID
test1 1
test1 4
test2 1
test2 2
test3 1
test3 2
test3 3
Note: here is the view as shown above:
SELECT
dbo.Table1.Description, Table2_1.ID AS Table2ID_1, Table2_2.ID AS Table2ID_2,
dbo.Table2.ID AS Table2ID_3
FROM
dbo.Table1
LEFT OUTER JOIN
dbo.Table2 ON dbo.Table1.ID = dbo.Table2.Table1ID3
LEFT OUTER JOIN
dbo.Table2 AS Table2_2 ON dbo.Table1.ID = Table2_2.Table1ID2
LEFT OUTER JOIN
dbo.Table2 AS Table2_1 ON dbo.Table1.ID = Table2_1.Table1ID1
My suggestion would be to UNPIVOT the data in Table2 so you can easily join on the data, then you can return the table1 description and the table2 id. The UNPIVOT portion of this query using CROSS APPLY:
select col, value, t2.Id
from table2 t2
cross apply
(
select 'table1id1', table1id1 union all
select 'table1id2', table1id2 union all
select 'table1id3', table1id3
) c (col, value);
See SQL Fiddle with Demo. This gives a result:
| COL | VALUE | ID |
---------------------------
| table1id1 | 1 | 1 |
| table1id2 | 2 | 1 |
| table1id3 | 3 | 1 |
| table1id1 | 2 | 2 |
| table1id2 | 3 | 2 |
| table1id3 | (null) | 2 |
| table1id1 | 3 | 3 |
Now that you have the data in rows, you can easily join on the value column to return the id:
select t1.description,
d.id
from table1 t1
inner join
(
select col, value, t2.Id
from table2 t2
cross apply
(
select 'table1id1', table1id1 union all
select 'table1id2', table1id2 union all
select 'table1id3', table1id3
) c (col, value)
) d
on t1.id = d.value
order by t1.description, d.id;
See SQL Fiddle with Demo
If you really want to use UNPIVOT, then you can use the following which doesn't join on each table multiple times to get the result:
select t1.description, t2.id
from table1 t1
inner join
(
select id, col, value
from
(
select id, [Table1ID1], [Table1ID2], [Table1ID3]
from table2
) d
unpivot
(
value for col in ([Table1ID1], [Table1ID2], [Table1ID3])
) unpiv
) t2
on t1.id = t2.value
order by t1.description, t2.id;
See SQL Fiddle with Demo.
The UNPIVOT and the CROSS APPLY is doing the same thing as a UNION ALL query:
select t1.description, t2.id
from table1 t1
inner join
(
select id, 'table1id1' col, table1id1 value
from table2
union all
select id, 'table1id2' col, table1id2
from table2
union all
select id, 'table1id3' col, table1id3
from table2
) t2
on t1.id = t2.value
order by t1.description, t2.id;
See SQL Fiddle with Demo
Microsoft SQL Server 2005 and higher support an UNPIVOT statement making the CROSS APPLY unnecessary.
SELECT Description AS [ID], Table1ID
FROM (SELECT Table1.Description, Table2_1.ID AS Table2ID_1, Table2_2.ID AS Table2ID_2, Table2.ID AS Table2ID_3
FROM Table1 LEFT OUTER JOIN
Table2 ON Table1.ID = Table2.Table1ID3 LEFT OUTER JOIN
Table2 AS Table2_2 ON Table1.ID = Table2_2.Table1ID2 LEFT OUTER JOIN
Table2 AS Table2_1 ON Table1.ID = Table2_1.Table1ID1) AS pvttbl
UNPIVOT ( Table1ID FOR ID IN (Table2ID_1, Table2ID_2, Table2ID_3)) AS unpvttbl
ORDER BY Description, Table1ID
See Using PIVOT and UNPIVOT on MSDN.