I am now creating a reporting service with visual business intelligent.
i try to count how many users have been created under an org_id.
but the report consist of multiple org_id. and i have difficulties on counting how many has been created under that particular org_id.
TBL_USER
USER_ID
0001122
0001234
ABC9999
DEF4545
DEF7676
TBL_ORG
ORG_ID
000
ABC
DEF
EXPECTED OUTPUT
TBL_RESULT
USER_CREATED
000 - 2
ABC - 1
DEF - 2
in my understanding, i need nested SELECT, but so far i have come to nothing.
SELECT COUNT(TBL_USER.USER_ID) AS Expr1
FROM TBL_USER INNER JOIN TBL_ORG
WHERE TBL_USER.USER_ID LIKE 'TBL_ORG.ORG_ID%')
this is totally wrong. but i hope it might give us clue.
It looks like the USER_ID value is the concatenation of your ORG_ID and something to make it unique. I'm assuming this is from a COTS product and nothing a human would have built.
Your desire is to find out how many entries there are by department. In SQL, when you read the word by in a requirement, that implies grouping. The action you want to take is to get a count and the reserved word for that is COUNT. Unless you need something out of the TBL_ORG, I see no need to join to it
SELECT
LEFT(T.USER_ID, 3) AS USER_CREATED
, COUNT(1) AS GroupCount
FROM
TBL_USER AS T
GROUP BY
LEFT(T.USER_ID, 3)
Anything that isn't in an aggregate (COUNT, SUM, AVG, etc) must be in your GROUP BY.
SQLFiddle
I updated the fiddle to also show how you could link to TBL_ORG if you need an element from the row in that table.
-- Need to have the friendly name for an org
-- Now we need to do the join
SELECT
LEFT(T.USER_ID, 3) AS USER_CREATED
, O.SOMETHING_ELSE
, COUNT(1) AS GroupCount
FROM
TBL_USER AS T
-- inner join assumes there will always be a match
INNER JOIN
TBL_ORG AS O
-- Using a function on a column is a performance killer
ON O.ORG_ID = LEFT(T.USER_ID, 3)
GROUP BY
LEFT(T.USER_ID, 3)
, O.SOMETHING_ELSE;
Related
I have a table called Apartments that has three columns: apartment_type, person, date. It includes the apartment type selected by a certain person and date. I need to count how many people picked each of the apartment types. Some apartment type have 0 population.
Here is my query:
SELECT apartment_type, COUNT(*) AS TOTAL
FROM Apartments
GROUP BY apartment_type
It works great, but it doesn't include apartment types with a value of 0. Please, help me to correct this query.
In case some appartment_type have 0 population - your table will not contain any record with that type - so you must add some join from another table, where all apartment types exists. Or use union to create all 0 populated entries.
Something like:
SELECT apartment_type, COUNT(*) AS TOTAL
FROM (SELECT * FROM Apartments UNION ALL SELECT apartment_type, 0 as person, 0 as date from SomeTableWithFullListOfTypes group by apartment_type) as tmp
GROUP BY apartment_type
I generally agree with Nosyara's answer, but I don't agree with his sample query with the union all. I'm not sure it works, and it's certainly too complicated.
As stated already, if you don't have a table with all the possible apartment types, create one. Then you can write your query using a simple left join:
select t.apartment_type, count(a.apartment_type) as total
from apartment_types t
left join apartments a
on a.apartment_type = t.apartment_type
group by t.apartment_type
Note how count(*) was replaced by count(a.apartment_type). That change is necessary to have an accurate count in the case where you don't have apartments for a certain apartment type.
SELECT apartment_type, COUNT(apartment.*) AS TOTAL
FROM apartment_type
left join apartment
on apartment_type.aparentment_type = apartements.apartment_type
GROUP BY apartment_type
Using a left join will give you everything from the left side of the join (so all your types) and anything from the right that matches.
I have 2 tables. One has been pruned to show only ID's which meet certain criteria. The second needs to be pruned to show only data that matches the previous "array" of id's. there can be multiple results.
Consider the following:
Query_1_final: Returns the ID's of users whom meet certain criteria:
select
t1.[user_id]
from
[SQLDB].[db].[meeting_parties] as t1
inner join
(select distinct
[user_id]
from
[SQLDB].[db].[meeting_parties]
group by
[user_id]
having
count([user_id]) = 1) as t2 on t1.user_id = t2.user_id
where
[type] = 'organiser'
This works great and returns:
user_id
--------------------
22
1255
9821
and so on...
It produces a single column with the ID's of everyone who is a "Meeting Organizer" and also in the active_meetings table. (note, there are multiple types/roles, this was the best way to grab them all)
Now, I need this data to filter another table, another join. Here is the start of my query
Query_2_PREP: returns 5 columns where the meeting has "started" already.
SELECT
[meeting_id]
,[meeting_style]
,[meeting_day]
,[address]
,[promos]
FROM
[SQLDB].[db].[all_meetings]
WHERE
[meeting_started] = 'TRUE'
This works as well
meeting_id | meeting_style | meeting_day ...
---------------------------------------------
23 open M,F,SA
23 discussion TU,TH
23 lead W,F
and so on...
and returns ALL 10,982 meetings that started, but I need it to return only the meetings that are from the distinct 'organiser's ID's from Query_1_final (which should be more like 1200 records or so)
Ideally, I need something "like" this below (but of course it does not work)
Query 2: needs to return all meetings that are from organiser ID's only.
SELECT
[meeting_party_id]
,[meeting_style]
,[meeting_day]
,[address]
,[promos]
FROM
[SQLDB].[db].[all_meetings]
WHERE
[meeting_started] = 'TRUE'
AND [meeting_party_id] = "ANY Query_1_final results, especially multiple"
I have tried nesting JOIN and INNER JOIN's but I think there is something fundamental I am missing here about SQL. In PHP I would use an array compare or just run another query... any help would be much appreciated.
Just use IN. Here is the structure of the logic:
with q1 as (
<first query here>
)
SELECT m.*
FROM [SQLDB].[db].[all_meetings] m
WHERE meeting_started = 'TRUE' AND
meeting_party_id IN (SELECT user_id FROM q1);
I am having a slow brain day...
The tables I am joining:
Policy_Office:
PolicyNumber OfficeCode
1 A
2 B
3 C
4 D
5 A
Office_Info:
OfficeCode AgentCode OfficeName
A 123 Acme
A 456 Acme
A 789 Acme
B 111 Ace
B 222 Ace
B 333 Ace
... ... ....
I want to perform a search to return all policies that are affiliated with an office name. For example, if I search for "Acme", I should get two policies: 1 & 5.
My current query looks like this:
SELECT
*
FROM
Policy_Office P
INNER JOIN Office_Info O ON P.OfficeCode = O.OfficeCode
WHERE
O.OfficeName = 'Acme'
But this query returns multiple rows, which I know is because there are multiple matches from the second table.
How do I write the query to only return two rows?
SELECT DISTINCT a.PolicyNumber
FROM Policy_Office a
INNER JOIN Office_Info b
ON a.OfficeCode = b.OfficeCode
WHERE b.officeName = 'Acme'
SQLFiddle Demo
To further gain more knowledge about joins, kindly visit the link below:
Visual Representation of SQL Joins
Simple join returns the Cartesian multiplication of the two sets and you have 2 A in the first table and 3 A in the second table and you probably get 6 results. If you want only the policy number then you should do a distinct on it.
(using MS-Sqlserver)
I know this thread is 10 years old, but I don't like distinct (in my head it means that the engine gathers all possible data, computes every selected row in each record into a hash and adds it to a tree ordered by that hash; I may be wrong, but it seems inefficient).
Instead, I use CTE and the function row_number(). The solution may very well be a much slower approach, but it's pretty, easy to maintain and I like it:
Given is a person and a telephone table tied together with a foreign key (in the telephone table). This construct means that a person can have more numbers, but I only want the first, so that each person only appears one time in the result set (I ought to be able concatenate multiple telephone numbers into one string (pivot, I think), but that's another issue).
; -- don't forget this one!
with telephonenumbers
as
(
select [id]
, [person_id]
, [number]
, row_number() over (partition by [person_id] order by [activestart] desc) as rowno
from [dbo].[telephone]
where ([activeuntil] is null or [activeuntil] > getdate()
)
select p.[id]
,p.[name]
,t.[number]
from [dbo].[person] p
left join telephonenumbers t on t.person_id = p.id
and t.rowno = 1
This does the trick (in fact the last line does), and the syntax is readable and easy to expand. The example is simple but when creating large scripts that joins tables left and right (literally), it is difficult to avoid that the result contains unwanted duplets - and difficult to identify which tables creates them. CTE works great for me.
Need some help with an homework assignment on SQL
Problem
Find out who (first name and last name) has played the most games in the chess tournament with an ID = 41
Background information
I got a table called Games, which contains information...
game ID
tournament ID
start_time
end_time
white_pieces_player_id
black_pieces_player_id
white_result
black_result
...about all the separate chess games that have taken place in three different tournaments ....
(tournaments having ID's of 41,42 and 47)
...and the first and last names of the players are stored in a table called People....
person ID (same ID which comes up in the table 'Games' as white_pieces_player_id and
black_pieces_player_id)
first_name
last_name
...how to make a SELECT statement in SQL that would give me the answer?
sounds like you need to limit by tournamentID in your where clause, join with the people table on white_pieces_player_id and black_pieces_player_id, and use the max function on the count of white_result = win union black_result = win.
interesting problem.
what do you have so far?
hmm... responding to your comment
SELECT isik.eesnimi
FROM partii JOIN isik ON partii.valge=isik.id
WHERE turniir='41'
group by isik.eesnimi
having count(*)>4
consider using the max() function instead of the having count(*)> number
you can add the last name to the select clause if you also add it to the group by clause
sry, I only speak American. What language is this code in?
I would aggregate a join to that table to a derived table like this:
SELECT a.last_name, a.first_name, CNT(b.gamecount) totalcount
FROM players a
JOIN (select cnt(*) gamecount, a.playerid
FROM games
WHERE a.tournamentid = 47
AND (white_player_id = a.playerid OR black_player_id = a.playerid)
GROUP BY playerid
) b
ON b.playerid = a.playerid
GROUP BY last_name, first_name
ORDER BY totalcount
something like this so that you are getting both counts for their black/white play and then joining and aggregating on that.
Then, if you only want the top one, just select the TOP 1
Let me explain what I mean with that question:
Lets say I have to tables like these:
customers
id customer location
1 Adam UK
2 Pete US
values
id value
1 10
1 7
2 3
2 41
Let's ignore here for a moment that that (and the following query) wouldn't make a lot of sense. It's meant as a simplified example.
Now, if I run this query
SELECT id, customer, value FROM customers INNER JOIN values GROUP BY id
I should get this result (distinct by id)
id customer value
1 Adam 10
2 Pete 3
What I would like to be able to do is get that to use it in a search result list, but for actual displaying of the results I'd like to do something like this:
Customer: Adam
Values: 10, 7
So, basically, while I need to have a result set that's distinct for the ID, I'd still like to somehow save the rows dropped by the GROUP BY to show the values list like above. What is the best way to do this?
Look at http://mysql.com/group_concat - which only will work in MySql.
Better link: http://dev.mysql.com/doc/refman/5.1/en/group-by-functions.html#function_group-concat
Technically, the following is not valid SQL even though MySQL allows it:
Select customers.id, customers.customer, values.value
From customers
Inner Join values
On values.id = customers.id
Group By customers.id
The SQL spec requires that every column in the Select clause be referenced in the Group By or in an aggregate function. However, given what you said later in your post, what I think you want is GROUP_CONCAT as first mentioned by Erik (+1) which is a function specific to MySQL:
Select customers.customer, Group_Concat(values.value)
From customers
Inner Join values
On values.id = customers.id
Group By customers.customer