PDO LastInsertId returning nothing - pdo

For some reason I cannot get the LastInsertId from my PDO insert. I am receiving nothing back, if I place it inside the execute I get -1 because the insert query hasn't run. However when just after the execute to grab the last ID inserted nothing is returned.
php 5.1.6
PECL pdo = 0.1.0
I have looked at following questions and many other stack exchange questions.
lastInsertId does not work in Postgresql
PDO lastInsertId() returns 0
PDO lastInsertId issues, php
However the difference is nothing is returned compared to 0. No errors are recorded either. See the code below.
Connection
try {
$conn = new PDO("pgsql:host=localhost port= dbname=", "", "");
echo "PDO connection object created";
}
catch(PDOException $e) {
echo $e->getMessage();
}
insert / return the last id
$stmt = $conn ->prepare("INSERT INTO sheet_tbl (site_id, username, additionalvolunteers) VALUES(?,?,?)");
$stmt->bindParam(1,$site_id);
$stmt->bindParam(2,$username1);
$stmt->bindParam(3,$additionalvolunteers);
$site_id = $_POST['site_id'];
$username1 = $user->name;
$additionalvolunteers = $_POST['additionalvolunteers'];
$stmt ->execute();
$newsheetID = $conn->lastInsertId('sheet_id');
echo $newsheetID . "last id";

You should be using
$newsheetID = $conn->lastInsertId('sheet_id_**seq**');
Just add _seq after id.

Assumming sheet_id type is SERIAL you can use LASTVAL()
TRY (Not tested as I dont have postgresql)
$newsheetID = $conn->query("SELECT LASTVAL()");
echo $newsheetID . "last id";

I use postgresql in C# with the "RETURNING rowkey" and its has always worked for me.
I also use pdo/php in a lot of applications.
However i dont have a postgres database open to the server right now for testing.
This could should work but it is not tested.
$site_id = $_POST['site_id'];
$username1 = $user->name;
$additionalvolunteers = $_POST['additionalvolunteers'];
$stmt = $conn ->prepare("INSERT INTO sheet_tbl (site_id, username, additionalvolunteers) VALUES(:site_id, :username1, :additionalvolunteers) RETURNING row_id");
$success = $stmt->execute([
'site_id' => $site_id,
'username1' => $username1,
'additionalvolunteers' => $additionalvolunteers
]);
// unsure about this
$newsheetID = $stmt->fetchColumn();
echo $newsheetID . " last id";

Related

I am stuck, mysqli_query() expects at least 2 parameters

I have a problem with a code in php it shows me this as errors.
register
mysqli_query() expects at least 2 parameters, 1 given in
C:\xampp\htdocs\search_engine\insert.php on line 99
And this is the code :
<?php
$db = new PDO('mysql:host=localhost;dbname=srgn;charset=utf8mb4', 'root', '123456');
if(isset($_POST["submit"]))
{
$s_link = $_POST["s_link"];
$s_key = $_POST["s_key"];
$s_des = $_POST["s_des"];
{
$sql = "insert(site_link, site_key, site_des) values('$s_link', '$s_key', '$s_des')";
$rs = mysqli_query($sql);
if($rs)
{
echo "<script> alert('Site uploaded successfully') </script>";
}
else
{
echo "<script> alert('Uploading failed, please try agin.') </script>";
}
}
}
?>
Where is the error please, and how can I set it?
Pass on the connection link as the first parameter and the SQL query as the second parameter. This is required as you are doing procedural code. Refer to the link below for more details
http://php.net/manual/en/mysqli.query.php

How to query REST API

I am using this code below to deal with the REST API query for Adobe Analytics. I always get the message "something went wrong" which means that the first IF is not active.
include_once('/path/SimpleRestClient.php');
$username = 'XXXXX';
$secret = 'XXXXX';
$nonce = md5(uniqid(php_uname('n'), true));
$nonce_ts = date('c');
$digest = base64_encode(sha1($nonce.$nonce_ts.$secret));
$server = "https://api.omniture.com";
$path = "/admin/1.4/rest/";
$rc=new SimpleRestClient();
$rc->setOption(CURLOPT_HTTPHEADER, array("X-WSSE: UsernameToken Username=\"$username\", PasswordDigest=\"$digest\", Nonce=\"$nonce\", Created=\"$nonce_ts\""));
$query="?method=Company.GetTokenUsage";
$rc->getWebRequest($server.$path.$query);
if ($rc->getStatusCode()==200)
{
$response=$rc->getWebResponse();
var_dump($response);
}
else
{
echo "something went wrong\n";
var_dump($rc->getInfo());
}
The $rc->getStatusCode(); does not exit. I get '404' when I use this line :
print_r ($rc->getStatusCode());
After googling, I found https://marketing.adobe.com/developer/blog/how-to-start-with-the-omniture-rest-api-in-php. It uses API version of 1.3 instead of 1.4. By updating the
$path = "/admin/1.4/rest/";
to
$path = "/admin/1.3/rest/";
I was able to stop getting 404 errors in the browser.

PHP 5 display mysql table error - Call to undefined function mysql_results()

I premise I'm new to php. I've tried to create a php page that displays the content of a MySQL database. As I try it in localhost I have this warning:
"Fatal error: Call to undefined function mysql_results() in C:\xampp\htdocs\phplessons\guestbook_displayer_2.php on line 18". It seems the db connection works. Someone have a tip?
This is my code:
<html>
<head></head>
<title>Display MySQL db</title>
<body>
<?php
$db=mysql_connect("localhost","root","mypassword"); //db connection
mysql_select_db ("prova001"); //choose a db
$res=mysql_query("SELECT * from php_guestbook"); //query a table
$num=mysql_num_rows($res);
// begin table
echo "<table border=1>";
echo "<tr><td>Nr.</td><td>First name</td>";
echo"<td>Last name</td><td>Country</td>";
echo"<td>E-Mail address</td><td>Telephone</td></tr>";
// contatore
for ($i=0; $i<$num; $i++)
{
$cg=mysql_results($res,$i,"firstname"); // line 18 this var is undefined.
$nm=mysql_results($res,$i,"lastname"); //Probably also the others have a similar problem.
$np=mysql_results($res,$i,"country"); //Can it be due to a bad record counter?
$st=mysql_results($res,$i,"email");
$tl=mysql_results($res,$i,"telephone");
$lf=$i+1;
//
echo "<tr><td>$lf</td><td>$cg</td><td>$nm</td><td>$np</td><td>$st</td><td>$tl</td></tr>";
}
echo "</table>";
mysql_close($db);
?>
</body>
You have probably made a typo. The method is mysql_result() without 's'.
But, you can shorten your query result handling by this way ;
// query
$res=mysql_query("SELECT * from php_guestbook"); //query a table
// begin table
echo "<table border=1>";
echo "<tr><td>Nr.</td><td>First name</td>";
echo"<td>Last name</td><td>Country</td>";
echo"<td>E-Mail address</td><td>Telephone</td></tr>";
while ($item = #mysql_fetch_assoc($res)) {
// do something with var $item;
$cg = $item['firstname'];
$nm = $item['lastname'];
// ect
}

How to do mysql_fetch_array in Magento

I want to create a drop down option using Magento module that populate the data from the database I created.
Previously, I have this code in My IndexController.php which is work. This is the first code.
public function dropdownAction() {
if (file_exists('./app/etc/local.xml')) {
$xml = simplexml_load_file('./app/etc/local.xml');
$tblprefix = $xml->global->resources->db->table_prefix;
$dbhost = $xml->global->resources->default_setup->connection->host;
$dbuser = $xml->global->resources->default_setup->connection->username;
$dbpass = $xml->global->resources->default_setup->connection->password;
$dbname = $xml->global->resources->default_setup->connection->dbname;
}
else {
exit('Failed to open ./app/etc/local.xml');
}
$link = mysql_connect($dbhost,$dbuser,$dbpass);
mysql_select_db($dbname) or die("Unable to select database");
$tblname = $tblprefix.'my_db_table';
$result = mysql_query("SELECT dropdowndata FROM ".$tblname."");
echo '<select>';
while ($ary = mysql_fetch_array($result)){
echo "<option>" . $ary['dropdowndata '] . "</option>";
}
echo "</select>";
mysql_close($link);
}
But I think the code above is not the Magento way. Do you agree?
Now, I want to populate the data with this code in IndexController.php. This is the second code.
public function dropdownAction() {
$options= Mage::getModel('my/model')->getCollection();
foreach($options as $option){
$optionData = $option->getDropdowndata ();
echo "<select>";
echo "<option>" .$optionData."</option>";
echo "</select>";
}
}
Using the code above, the data was populated but one data with one drop down option. So there are so many drop down options appear on the browser, each drop down option will contain only one data.
I think I am missing the while ($ary = mysql_fetch_array($result)). But I confuse how to include that code?
So, my question is how to do mysql_fetch_array in Magento? Or can somebody please explain how to make the second code above work like the first code.
getData() function returns an array of the whole data, and of course need move 'select' nodes out of the foreach
echo "<select>";
foreach($options as $option){
$optionData = $option->getData();
echo "<option>" .$optionData['somekey'] ."</option>";
}
echo "</select>";
But I think would be better use the magento magic functions, for example if you have 'entity_id' column in DB you can get value using $option->getEntityId(), etc...
And why do you have select inside of foreach? I think something like this will solve your problem:
public function dropdownAction() {
$options= Mage::getModel('my/model')->getCollection();
echo "<select>";
foreach($options as $option){
$optionData = $option->getDropdowndata ();
echo "<option>" .$optionData."</option>";
}
echo "</select>";
}

Help creating selective IF statement

I have this code that sends a text message to your mobile phone...
$text = fopen("../data/textmembers/registry.txt","r") or die("couldent open file");
while (!feof($text)) {
$name = fgets($text);
$number = fgets($text);
$carrier = fgets($text);
$date = fgets($text);
$line = fgets($text);
$content = $_POST['message'];
$message .= $content;
$message .= "\n";
$number = trim($number);
mail($number . "#vtext.com", "SGA Event Alert", $message, "SGA");
Header("Location: mailconf.php");
everything works fine.. Here is my question, if you look at where I have "#vtext.com"
as you may or may not know, each carrier has its own extension, verizon is #vtext.com, at&t is #txt.att.net. I need to take the feed from "$carrier" decide what carrier it is, and then assign the extension to it...
I thought an ifelse would work, but I am not good with if statements...
the user's choices are
Verizon = 1234567890#vtext.com
AT&T = 1234567890#txt.att.net
T-mobile = #tmomail.net
Nextel = #messaging.nextel.com
thanks guys!!
$carriers = array(
"verizon" => "vtext.com",
"at&t" => "txt.att.net",
"t-mobile" => "tmomail.net",
"nextel" => "messaging.nextel.com"
);
Then, you get that value by looking up the key:
print $carriers[strtolower($carrier)];
If $carrier is "Nextel," "messaging.nextel.com" will be returned.
Probably better than using an if statement would be using a switch statement.
Have a look at the section of the PHP manual that deals with the switch statement.