I get the error "Conversion failed when converting the nvarchar value '23,24,3,45,91,' to data type int." The error seems to be occuring on the ON clause. E.ID is an integer field while F.LegalIssue is a varchar field of integers separated by commas. Below is the code with that error.
SELECT F.[FDTitle], E.PrimaryOpID as [FD Primary OP ID], F.County as [FD County], F.Status as [FD Status], F.IssueDate as [FD Date]
FROM [dbo].[tbl_FinalDetMain] F
LEFT OUTER JOIN [dbo].[tbl_lk_Exemptions_FD] E ON E.ID = F.LegalIssue
WHERE F.[FDNbr] = '2013-0041'
I have tried the code below for the on clause, but it only returns one integer value, instead of the entire string of integers.
E.ID = cast(LEFT(F.LegalIssue,PATINDEX('%[^0-9]%',F.LegalIssue)-1) as int)
The result should include five integers delimited by commas.
If LegalIssue contains a string of comma-delimited numbers, then you really want an association table. Lacking that, here is a convenient (but not efficient) way to do the join:
SELECT F.[FDTitle], E.PrimaryOpID as [FD Primary OP ID], F.County as [FD County],
F.Status as [FD Status], F.IssueDate as [FD Date]
FROM [dbo].[tbl_FinalDetMain] F LEFT OUTER JOIN
[dbo].[tbl_lk_Exemptions_FD] E
ON ','+F.LegalIssue+',' like '%,'cast(E.ID as varchar(255))+',%'
WHERE F.[FDNbr] = '2013-0041';
This prepends and postpends the list with commas to avoid conflicts, such as finding "10" in "1,100,1000".
Using xml datatype, you can explode your string to integers like this. Good candidate for a user defined function I would say :-)
declare #test varchar(max)
set #test = '1,2,3,4,5'
select
T2.item.value('(./text())[1]','int')
from
(select convert(xml,'<items><t>'+replace(#test,',','</t><t>')+'</t></items>') as xmldoc)
as xmltable
CROSS APPLY xmltable.xmldoc.nodes('/items/t') as T2(item)
You will either have to normalize the F.LegalIssue into many rows or you would have to use a LIKE
Something like
CAST(E.ID A VARCHAR(50)) = F.LegalIssue
OR F.LegalIssue LIKE CAST(E.ID A VARCHAR(50)) + ',%'
OR '%,' + F.LegalIssue LIKE CAST(E.ID A VARCHAR(50)) + ',%'
OR '%,' + F.LegalIssue LIKE CAST(E.ID A VARCHAR(50))
As you can see, the actual design of the table is the issue. You should rather avoid the design you have currently, and opt for a 1 to many or many to many design.
Here is a DEMO of how to flatten the values using a recursive CTE
SQL Fiddle DEMO
Creating test table and data
CREATE TABLE Tada(
ID INT,
SomeCommaString VARCHAR(50)
)
INSERT INTO Tada Values (1, '10'),(2,'5,6,12,16')
Flattening the table
;WITH Vals AS (
SELECT
ID,
CASE
WHEN CHARINDEX(',',SomeCommaString) = 0
THEN SomeCommaString
WHEN CHARINDEX(',',SomeCommaString) > 0
THEN LEFT(SomeCommaString,CHARINDEX(',',SomeCommaString) - 1)
END Val,
CASE
WHEN CHARINDEX(',',SomeCommaString) > 0
THEN RIGHT(SomeCommaString,LEN(SomeCommaString) - CHARINDEX(',',SomeCommaString))
ELSE NULL
END Remainder
FROM Tada
UNION ALL
SELECT
ID,
CASE
WHEN CHARINDEX(',',Remainder) = 0
THEN Remainder
WHEN CHARINDEX(',',Remainder) > 0
THEN LEFT(Remainder,CHARINDEX(',',Remainder) - 1)
END Val,
CASE
WHEN CHARINDEX(',',Remainder) > 0
THEN RIGHT(Remainder,LEN(Remainder) - CHARINDEX(',',Remainder))
ELSE NULL
END Remainder
FROM Vals
WHERE Remainder IS NOT NULL
)
SELECT ID, Val
FROM Vals
Related
I have a column in a table that looks like this
Name
WALKER^JAMES^K^^
ANDERSON^MICHAEL^R^^
HUFF^CHRIS^^^
WALKER^JAMES^K^^
SWEARINGEN^TOMMY^L^^
SMITH^JOHN^JACCOB^^
I need to write a query that looks like this
Name
FirstName
LastName
MiddleName
WALKER^JAMES^K^^
JAMES
WALKER
K
ANDERSON^MICHAEL^R^^
MICHAEL
ANDERSON
R
HUFF^CHRIS^^^
CHRIS
HUFF
BUTLER^STEWART^M^^
STEWART
BUTLER
M
SWEARINGEN^TOMMY^L^^
TOMMY
SWEARINGEN
L
SMITH^JOHN^JACCOB^^
JOHN
SMITH
JACCOB
I need help generating the LastName column.
This is what I've tried so far
SUBSTRING
(
--SEARCH THE NAME COLUMN
Name,
--Starting after the first '^'
CHARINDEX('^', Name) + 1 ),
--Index of second ^ minus the index of the first ^
(CHARINDEX('^', PatientName, CHARINDEX('^', PatientName) +1)) - (CHARINDEX('^', PatientName))
)
This produces:
Invalid length parameter passed to the LEFT or SUBSTRING function.
I know this can work because if I change the minus sign to a plus sign it performs as expected.
It produces the right integer.
Where am I going wrong? Is there a better way to do this?
If you are using the latest SQL Server versions 2016 13.x or higher, you can maximize the use of string_split function with ordinal (position).
declare #strTable table(sqlstring varchar(max))
insert into #strTable (sqlstring) values ('WALKER^JAMES^K^^')
insert into #strTable (sqlstring) values ('ANDERSON^MICHAEL^R^^')
insert into #strTable (sqlstring) values ('HUFF^CHRIS^^^')
insert into #strTable (sqlstring) values ('SWEARINGEN^TOMMY^L^^');
with tmp as
(select value s, Row_Number() over (order by (select 0)) n from #strTable
cross apply String_Split(sqlstring, '^', 1))
select t2.s as FirstName, t1.s as LastName, t3.s as MiddleInitial from tmp t1
left join tmp t2 on t2.n-t1.n = 1
left join tmp t3 on t3.n-t1.n = 2
where t1.n = 1 or t1.n % 5 = 1
I recommend SUBSTRING() as it will perform the best. The challenge with SUBSTRING is it's hard to account to keep track of the nested CHARDINDEX() calls so it's better to break the calculation into pieces. I use CROSS APPLY to alias each "^" found and start from there to search for the next. Also allows to do NULLIF() = 0, so if it can't find the "^", it just returns a NULL instead of erroring out
Parse Delimited String using SUBSTRING() and CROSS APPLY
DROP TABLE IF EXISTS #Name
CREATE TABLE #Name (ID INT IDENTITY(1,1) PRIMARY KEY,[Name] varchar(255))
INSERT INTO #Name
VALUES ('WALKER^JAMES^K^^')
,('ANDERSON^MICHAEL^R^^')
,('HUFF^CHRIS^^^')
,('SWEARINGEN^TOMMY^L^^');
SELECT ID
,A.[Name]
,LastName = NULLIF(SUBSTRING(A.[Name],0,idx1),'')
,FirstName = NULLIF(SUBSTRING(A.[Name],idx1+1,idx2-idx1-1),'')
,MiddleInitial = NULLIF(SUBSTRING(A.[Name],idx2+1,idx3-idx2-1),'')
FROM #Name AS A
CROSS APPLY (SELECT idx1 = NULLIF(CHARINDEX('^',[Name]),0)) AS B
CROSS APPLY (SELECT idx2 = NULLIF(CHARINDEX('^',[Name],idx1+1),0)) AS C
CROSS APPLY (SELECT idx3 = NULLIF(CHARINDEX('^',[Name],idx2+1),0)) AS D
I have a list of drug names that are stored in various upper and lower case combinations. I need to capitalize the first letter of each word in a string, excluding certain words. The string is separated by spaces, but can also be separated by a forward slash.
The following code works:
create table #exclusionlist (word varchar(25))
create table #drugnames (drugname varchar(50))
insert into #exclusionlist values ('ER')
insert into #exclusionlist values ('HCL')
insert into #drugnames values ('DRUGNAME ER')
insert into #drugnames values ('drugname hcl')
insert into #drugnames values ('ONEDRUG/OTHERDRUG')
select 'Product Name' = drugname
, 'Product Name 2' = STUFF((SELECT ' ' +
case when value in (select word from #exclusionlist) then upper(value)
else upper(left(value, 1)) + lower(substring(value, 2, len(value))) end
from STRING_SPLIT(drugname, ' ')
FOR XML PATH('')) ,1,1,'')
from #drugnames
The output looks like this:
Drugname ER
Drugname HCL
Onedrug/otherdrug
How can I get that last one to look like this:
Onedrug/Otherdrug
I did try STRING_SPLIT(replace(drugname, '/', ' '), ' ') but obviously replaces the slash with a space. And if the slash is at the end of the string like ONEDRUG/OTHERDRUG/ then the result looks like Onedrug Otherdrug
It's possible that the string may end in a forward slash due to the field only holding N number of characters. When data gets inserted into the table, only the first N characters of the drug name are inserted. If that Nth character is a slash, the string will end in a slash.
You can use a CASE expression for the separator parameter to the STRING_SPLIT function.
In the code below, a common table expression (CTE) uses STRING_SPLIT to split out all the drugname words and capitalize the first letter of each word as appropriate.
The CTE results are unioned together using STRING_AGG to join the drugnames back together. Note that separator parameter for STRING_AGG cannot be an expression. Using a CASE expression results in this error:
Msg 8733, Level 16, State 1, Line 14 Separator parameter for
STRING_AGG must be a string literal or variable.
For SQL Server, you would need to be on SQL 2017 or greater for the STRING_AGG function. (I added an id/identity column to the #drugnames temp table to assist with grouping.)
DROP TABLE IF EXISTS #exclusionlist;
DROP TABLE IF EXISTS #drugnames;
CREATE TABLE #exclusionlist (word VARCHAR(25))
CREATE TABLE #drugnames (id INT IDENTITY, drugname VARCHAR(50))
INSERT INTO #exclusionlist VALUES ('ER')
INSERT INTO #exclusionlist VALUES ('HCL')
INSERT INTO #drugnames VALUES ('DRUGNAME ER')
INSERT INTO #drugnames VALUES ('drugname hcl')
INSERT INTO #drugnames VALUES ('ONEDRUG/OTHERDRUG')
;WITH SomeStuff AS
(
select d.id, d.drugname,
sp.value AS SplitValue, el.word AS ExclusionListSpaceWord,
COALESCE(el.word,
UPPER(LEFT(sp.value, 1)) + LOWER(RIGHT(sp.value, LEN(sp.value) - 1))
) AS CapitalizedWord
from #drugnames d
CROSS APPLY STRING_SPLIT(d.drugname, CASE WHEN d.drugname LIKE '%/%' THEN '/' ELSE ' ' END ) sp
LEFT JOIN #exclusionlist el
ON el.word = sp.value
)
SELECT ss.id, STRING_AGG(ss.CapitalizedWord, '/') AS ReconstructedDrugname
FROM SomeStuff ss
WHERE ss.drugname LIKE '%/%'
GROUP BY ss.id
UNION
SELECT ss.id, STRING_AGG(ss.CapitalizedWord, ' ') AS ReconstructedDrugname
FROM SomeStuff ss
WHERE ss.drugname LIKE '% %'
GROUP BY ss.id
Output:
id ReconstructedDrugname
----------- ----------------------
1 Drugname ER
2 Drugname HCL
3 Onedrug/Otherdrug
If (hopefully) using SQL 2017+ you can somewhat compact the logic. first a single string split by using translate to create a common separator. THen apply the exclude word criteria forllowed by the upper-case criteria, then re-aggregate, noting which separator to use.
select *
from #drugnames
outer apply (
select case
when max(sep)=' ' then String_Agg(word,' ')
else String_Agg(word,'/') end NewName
from (
select
case
when exists (select * from #exclusionlist x where x.word = value)
then Upper(value)
else Stuff(Lower(value),1,1,Upper(Left(value,1)))
end word, Iif(drugname like '%/%','/',' ') sep
from String_Split(Translate(drugname,' /','**'),'*')
)w
)new;
Example DB<>Fiddle
Output:
Note - using string_split does not, according to the documentation, guarantee the ordering of the values. In practice, I've never seen this be the case and since you're already using the function I'm using here also. There's plenty of ways to split the string while retaining an ordering (using json for example) should it ever prove necessary.
If you are still on 2016 then the string_agg can just be replaced with the for xml implementation you're already using.
If the "/" is replaced to a " /", then the split can still happen on the space.
And the extra space can be removed afterwards.
SELECT
[Product Name] = d.drugname
, [Product Name 2] = ca.drugname2
FROM #drugnames d
CROSS APPLY (
SELECT
REPLACE(LTRIM(x.value('(./text())[1]','VARCHAR(MAX)')),' /','/') AS drugname2
FROM
(
SELECT ' '+
CASE
WHEN e.word IS NOT NULL THEN e.word
WHEN s.value LIKE '/%'
THEN STUFF(LOWER(s.value),1,2,UPPER(LEFT(s.value,2)))
ELSE STUFF(LOWER(s.value),1,1,UPPER(LEFT(s.value,1)))
END
FROM STRING_SPLIT(REPLACE(d.drugname,'/',' /'),' ') s
LEFT JOIN #exclusionlist e
ON e.word = s.value
FOR XML PATH(''), TYPE
) q(x)
) ca;
Product Name
Product Name 2
DRUGNAME ER
Drugname ER
drugname hcl
Drugname HCL
ONEDRUG/OTHERDRUG
Onedrug/Otherdrug
Test on db<>fiddle here
I’m fairly used to using MySQL, but not particularly familiar with SQL Server. Tough luck, the database I’m dealing with here is on SQL Server 2014.
I have a table with a column whose values are all integers with leading, separating, and trailing semicolons, like these three fictitious rows:
;905;1493;384;13387;29;933;467;28732;
;905;138;3084;1387;290;9353;4767;2732;
;9085;14493;3864;130387;289;933;4767;28732;
What I am trying to do now is to select all rows where more than one number taken from a list of numbers appears in this column. So for example, given the three rows above, if I have the group 905,467,4767, the statement I’m trying to figure out how to construct should return the first two rows: the first row contains 905 and 467; the second row contains 905 and 4767. The third row contains only 4767, so that row should not be returned.
As far as I can tell, SQL Server does not actually support regex directly (and I don’t even know what managed code is), which doesn’t help. Even with regex, I wouldn’t know where to begin. Oracle seems to have a function that would be very useful, but that’s Oracle.
Most similar questions on here deal with finding multiple instances of the same character (usually singular) and solve the problem by replacing the string to match with nothing and counting the difference in length. I suppose that would technically work here, too, but given a ‘filter’ group of 15 numbers, the SELECT statement would become ridiculously long and convoluted and utterly unreadable. Additionally, I only want to match entire numbers (so if one of the numbers to match is 29, the value 29 would match in the first row, but the value 290 in the second row should not match), which means I’d have to include the semicolons in the REPLACE clause and then discount them when calculating the length. A complete mess.
What I would ideally like to do is something like this:
SELECT * FROM table WHERE REGEXP_COUNT(column, ';(905|467|4767);') > 1
– but that will obviously not work, for all kinds of reasons (the most obvious one being the nonexistence of REGEXP_COUNT outside Oracle).
Is there some sane, manageable way of doing this?
You can do
SELECT *
FROM Mess
CROSS APPLY (SELECT COUNT(*)
FROM (VALUES (905),
(467),
(4767)) V(Num)
WHERE Col LIKE CONCAT('%;', Num, ';%')) ca(count)
WHERE count > 1
SQL Fiddle
Or alternatively
WITH Nums
AS (SELECT Num
FROM (VALUES (905),
(467),
(4767)) V(Num))
SELECT Mess.*
FROM Mess
CROSS APPLY (VALUES(CAST(CONCAT('<x>', REPLACE(Col, ';', '</x><x>'), '</x>') AS XML))) x(x)
CROSS APPLY (SELECT COUNT(*)
FROM (SELECT n.value('.', 'int')
FROM x.x.nodes('/x') n(n)
WHERE n.value('.', 'varchar') <> ''
INTERSECT
SELECT Num
FROM Nums) T(count)
HAVING COUNT(*) > 1) ca2(count)
Could you put your arguments into a table (perhaps using a table-valued function accepting a string (of comma-separated integers) as a parameter) and use something like this?
DECLARE #T table (String varchar(255))
INSERT INTO #T
VALUES
(';905;1493;384;13387;29;933;467;28732;')
, (';905;138;3084;1387;290;9353;4767;2732;')
, (';9085;14493;3864;130387;289;933;4767;28732;')
DECLARE #Arguments table (Arg int)
INSERT INTO #Arguments
VALUES
(905)
, (467)
, (4767)
SELECT String
FROM
#T
CROSS JOIN #Arguments
GROUP BY String
HAVING SUM(CASE WHEN PATINDEX('%;' + CAST(Arg AS varchar) + ';%', String) > 0 THEN 1 ELSE 0 END) > 1
And example of using this with a function to generate the arguments:
CREATE FUNCTION GenerateArguments (#Integers varchar(255))
RETURNS #Arguments table (Arg int)
AS
BEGIN
WITH cte
AS
(
SELECT
PATINDEX('%,%', #Integers) p
, LEFT(#Integers, PATINDEX('%,%', #Integers) - 1) n
UNION ALL
SELECT
CASE WHEN PATINDEX('%,%', SUBSTRING(#Integers, p + 1, LEN(#Integers))) + p = p THEN 0 ELSE PATINDEX('%,%', SUBSTRING(#Integers, p + 1, LEN(#Integers))) + p END
, CASE WHEN PATINDEX('%,%', SUBSTRING(#Integers, p + 1, LEN(#Integers))) = 0 THEN RIGHT(#Integers, PATINDEX('%,%', REVERSE(#Integers)) - 1) ELSE LEFT(SUBSTRING(#Integers, p + 1, LEN(#Integers)), PATINDEX('%,%', SUBSTRING(#Integers, p + 1, LEN(#Integers))) - 1) END
FROM cte
WHERE p <> 0
)
INSERT INTO #Arguments (Arg)
SELECT n
FROM cte
RETURN
END
GO
DECLARE #T table (String varchar(255))
INSERT INTO #T
VALUES
(';905;1493;384;13387;29;933;467;28732;')
, (';905;138;3084;1387;290;9353;4767;2732;')
, (';9085;14493;3864;130387;289;933;4767;28732;')
;
SELECT String
FROM
#T
CROSS JOIN GenerateArguments('905,467,4767')
GROUP BY String
HAVING SUM(CASE WHEN PATINDEX('%;' + CAST(Arg AS varchar) + ';%', String) > 0 THEN 1 ELSE 0 END) > 1
You can achieve this using the like function for the regex and row_number to determine the number of matches.
Here we declare the column values for testing:
DECLARE #tbl TABLE (
string NVARCHAR(MAX)
)
INSERT #tbl VALUES
(';905;1493;384;13387;29;933;467;28732;'),
(';905;138;3084;1387;290;9353;4767;2732;'),
(';9085;14493;3864;130387;289;933;4767;28732;')
Then we pass your search parameters into a table variable to be joined on:
DECLARE #search_tbl TABLE (
search_value INT
)
INSERT #search_tbl VALUES
(905),
(467),
(4767)
Finally we join the table with the column to search for onto the search table. We apply the row_number function to determine the number of times it matches. We select from this subquery where the row_number = 2 meaning that it joined at least twice.
SELECT
string
FROM (
SELECT
tbl.string,
ROW_NUMBER() OVER (PARTITION BY tbl.string ORDER BY tbl.string) AS rn
FROM #tbl tbl
JOIN #search_tbl search_tbl ON
tbl.string LIKE '%;' + CAST(search_tbl.search_value AS NVARCHAR(MAX)) + ';%'
) tbl
WHERE rn = 2
You could build a where clause like this :
WHERE
case when column like '%;905;%' then 1 else 0 end +
case when column like '%;467;%' then 1 else 0 end +
case when column like '%;4767;%' then 1 else 0 end >= 2
The advantage is that you do not need a helper table. I don't know how you build the query, but the following also works, and is useful if the numbers are in a tsql variable.
case when column like ('%;' + #n + ';%') then 1 else 0 end
So I am trying to write a query which, among other things, brings back the first character in a Varchar field, then returns the first character which appears after each / character throughout the rest of the field.
The field I am refrering too will contain a group of last names, separated by a '/'. For example: Fischer-Costello/Korbell/Morrison/Pearson
For the above example, I would want my select statement to return: FKMP.
So far, I have only been able to get my code to return the first character + the first character after the FIRST (and only the first) '/' character.
So for the above example input, my select statement would return: FK
Here is the code that I have written so far:
select rp.CONTACT_ID, ra.TRADE_REP, c.FIRST_NAME, c.LAST_NAME,
UPPER(LEFT(FIRST_NAME, 1)) + SUBSTRING(c.first_name,CHARINDEX('/',c.first_name)+1,1) as al_1,
UPPER(LEFT(LAST_NAME, 1)) + SUBSTRING(c.LAST_name,CHARINDEX('/',c.LAST_name)+1,1) as al_2
from dbo.REP_ALIAS ra
inner join dbo.REP_PROFILE rp on rp.CONTACT_ID = ra.CONTACT_ID
inner join dbo.CONTACT c on rp.CONTACT_ID = c.CONTACT_ID
where
rp.CRD_NUMBER is null and
ra.TRADE_REP like '%DNK%' and
(c.LAST_NAME like '%/%' or c.FIRST_NAME like '%/%') and
ra.TRADE_FIRM in
(
'xxxxxxx',
'xxxxxxx'
)
If you read the code, it's obvious that I am attempting to perform the same concatenation on the first_name column as well. However, I realize that a solution which will work for the Last_name column (used in my example), will also work for the first_name column.
Thank you.
Some default values
DECLARE #List VARCHAR(50) = 'Fischer-Costello/Korbell/Morrison/Pearson'
DECLARE #SplitOn CHAR(1) = '/'
This area just splits the string into a list
DECLARE #RtnValue table
(
Id int identity(1,1),
Value nvarchar(4000)
)
While (Charindex(#SplitOn, #List)>0)
Begin
Insert Into #RtnValue (value)
Select
Value = ltrim(rtrim(Substring(#List,1,Charindex(#SplitOn,#List)-1)))
Set #List = Substring(#List,Charindex(#SplitOn,#List)+len(#SplitOn+',')-1,len(#List))
End
Insert Into #RtnValue (Value)
Select Value = ltrim(rtrim(#List))
Now lets grab the first character of each name and stuff it back into a single variable
SELECT STUFF((SELECT SUBSTRING(VALUE,1,1) FROM #RtnValue FOR XML PATH('')),1,0,'') AS Value
Outputs:
Value
FKMP
Here is another way to do this would be a lot faster than looping. What you need is a set based splitter. Jeff Moden at sql server central has one that is awesome. Here is a link to the article. http://www.sqlservercentral.com/articles/Tally+Table/72993/
Now I know you have to signup for an account to view this but it is free and the logic in that article will change the way you look at data. You might also be able to find his code posted if you search for DelimitedSplit8K.
At any rate, here is how you could implement this type of splitter.
declare #Table table(ID int identity, SomeValue varchar(50))
insert #Table
select 'Fischer-Costello/Korbell/Morrison/Pearson'
select ID, STUFF((select '' + left(x.Item, 1)
from #Table t2
cross apply dbo.DelimitedSplit8K(SomeValue, '/') x
where t2.ID = t1.ID
for xml path('')), 1, 0 , '') as MyResult
from #Table t1
group by t1.ID
I have a column in a table that can have a string CSV, I want to run a query against all those values with a LIKE that is apart of a ON clause to a outer join.
DECLARE #to VARCHAR(max) = (SELECT value FROM dbo.table WHERE id = 'key');
DECLARE #t table ( value varchar(max) )
INSERT INTO #t SELECT item FROM fn_csv_splitstring ( #to , ',' )
After I have gotten all the CSV values, I now want to have each value in my temp table used as an expression on the LIKE keyword similar to the below select
SELECT * FROM
dbo.table e
where e.value LIKE '%' + (SELECT value FROM [#t]) + '%'
The exact statement is used on a left outer join statement, the ON clause links two table row IDs
e.id = t.id and then there is an additional AND expression AND e.value LIKE 'col%' At this point I need to be able to have all rows in my temp table as a bunch of OR LIKE '%' or something that acts as LIKE '%' + (SELECT value FROM [#t]) + '%'
I have tried the IN keyword, but IN seems to only work with exact matches and not the wild card.
Thanks in advance.
Use EXISTS to check whether e.value is like ANY t.value (wildcarded)
SELECT *
FROM dbo.table e
WHERE EXISTS (
SELECT *
FROM #t t
WHERE e.value LIKE '%' + t.value + '%')