I'm having some trouble trying to pass multiple dataProviders to a ClistView in Yii. What is the correct way of doing it?
I've tried:
$this->widget('zii.widgets.CListView', array(
'dataProvider'=>array($dataProvider, $dataProvider2),
I've also had a look at this What is the best method to merge two PHP objects?. Not sure if the best approach would be to try and do it with pure PHP or if the Framework has options for this and i've just missed them.
Appreciate any help.
thanks
Jonny
The easiest thing is if you have a relation between the two models.
Then you can just output it as is in your itemView:
echo $data->relationItem;
// Or if it is a HAS_MANY relation
foreach ($data->relationItems as $i)
echo $i->something;
Not what you were after?
Another solution could be to iterate through your models, cherry-pick the things you want into a new array and then feed it using a CArrayDataProvider to your ClistView.
In situation like this, I develop my own CListView:
class MyClistView extends CListView{
}
the dataProvider is required for CListView so pass ArrayDataProvider that contains your dataproviders and Iterate them and dont forget to implement your logic for rendering.
PS: Dont forget to take a look to CBaseListView
Related
I want to check if the current address is admin area IN MODEL to change conditions:
public function beforeFind(Event $event, Query $query, ArrayObject $options, $primary) {
debug($this->request['prefix']);
}
It's not working. I need only to access to request vars IN MODEL.
Thanks.
I resolve it by using $_SERVER variable. It's works good
$_SERVER['REQUEST_URI']
but I still need to add beforefind for each Model... while I need only general conditions for all queries... I really feel bad about the accessibility of cakephp
Brother you can use the class in model
use Cake\Network\Request;
and Get path if you want
I have a model which contains emails with some other fields.
I want a custom filter in Yii CGridView's advance search which when applied, lists only Invalid Email IDs (using regular expression '^[A-Z0-9._%-]+#[A-Z0-9.-]+\.[A-Z]{2,4}$')
Note: I dont want to add any column in CGridView
I hope to help you out,
you will need several things
the line for filtering in the column of your choice...(i recommend you create a new attribute for this, ask me in comments if you want to know more why.) this goes in the cgridview of course:
'filter'=>CHtml::activeCheckBox($model, $attributeEmail)
the condition in your search of function that brings up the model.
Supposing you have a criteria inside your search in your model wich help you with your filtering what you need is ...
if($this->EMAIL == TRUE)
{
$criteria->addCondition("\"t\".\"EMAIL\" email NOT LIKE '%_#__%.__%'");
}
Why not to use regex and make a KISS approach ? better read this first...
Sql script to find invalid email addresses
I'd be glad to hear your comments it is interesting question for yii dev's btw
I'm writing my first app in ZF2, and I want to create pagination system.
Currently, I have something like this in my controllers:
$pagLimit = $this->params()->fromQuery('limit', 1000);
$pagPage = $this->params()->fromQuery('page', 1);
$orderDir = $this->params()->fromQuery('dir', 'ASC');
$orderBy = $this->params()->fromQuery('column', 'id');
$result = $this->getMapper()->getList($orderDir, $orderBy);
$paginator = new Paginator(new ArrayAdapter($result));
$paginator->setItemCountPerPage($pagLimit);
$paginator->setCurrentPageNumber($pagPage);
I think that my solution is not quite good..
If I want to change e.g. default limit of items per page, I have to modify all my controllers. Also, I have to remember to send two arguments for all mapper methods which are getting lists of data.
My first thought was to use inheritance ("MyController" with methods like: setPaginationParams(), and setPaginator($data)).
Then I would have to remember to invoke "my controller" methods in every controller.
But maybe there is a better way to implement the same paginator for every controller in my module? MVC event? Create custom class and use DI?
What is the best way to implement this functionality?
Could you just give me some hints?
I'm new to ZF2 and OOP concepts. :(
You could always extend the paginator with your own, and have default values set.
You could even just pass in the request object or params object and then let the Paginator internally handle some things for you to save setting up default values etc.
I am attempting to assign a unique id to each table row in Yii's CGridView.
Preferably something like $data->id from the database table.
I have been unsuccessful at adding an id attribute to each rendered <tr>.
Any suggestions would be most appreciated.
CGridView have an option called 'rowHtmlOptionsExpression' , you can declare like the followings to assign row an id
'rowHtmlOptionsExpression' => 'array("id"=>$data->id)',
It's better than hacking into 'rowCssClassExpression'
Good luck !
Modern solution (since Yii 1.1.13)
This is now possible to do using the rowHtmlOptionsExpression attribute, which allows assigning arbitrary HTML attributes to each rendered table row. For example:
'rowHtmlOptionsExpression' => '["id" => $data->id]'
Original answer (earlier versions)
Not directly possible because CGridView does not support it, but there are a couple of straightforward solutions that you can try.
Subclass CGridView (good)
Simply create your own class MyGridView extends CGridView and override the renderTableRow method to spit out ids on every row. Have a look at the stock implementation, which does for the class attribute exactly what you 'd like to do for the id attribute.
Use a CSS class instead (not so good)
Speaking of class attributes, the rowCssClassExpression property can be used to dynamically generate classes out of the box. IMHO this is a bad workaround, but it's there.
You could extend CGridView to add that functionality.
or be a bit hacky with rowCssClassExpression.
'rowCssClassExpression' => '\'" data-id="\' . $data->rowID'
Try the information I posted here:
How to set key value in CGrideView when grid is populated from table-view
In essence, as long as your dataprovider to the CGridview provides the data->id in a form that it understands, it will auto handle the $data->id stuff for you automatically so that it's easily available to javascript.
CGridView.rowHtmlOptionsExpression is undefined
I don't think that we can use rowHtmlOptionsExpression
Basically, I want to render a view and layout from a model. Don't ask me why.
First of all, the views work as intended and I'm loading them into a variable for my perverse use later on. I am also fully aware that I could always do partial scripts. It seems to be a valid fallback, but it just doesn't cut it.
What I want to do is to get the layout to work automatically just like in the case with controllers and views.
Right now I employ something like this:
// Class blablabla
$layout = new Zend_Layout();
$layout->enableLayout();
$layout->setView($view);
// Ugly url, I know, I'm experimenting and they work
$body = $layout->render('mailer/layout/mail');
$body .= $view->render('mailer/templates/' . $type . '.phtml');
The problem is that $body contains the layout and only then the actual view. Any advice? What am I doing wrong?
Assuming that your layout contains the default $this->layout()->content somewhere, you'd want this:
$layout->content = $view->render('...');
$body = $layout->render('...');
Source: http://www.wowww.ch/2009/03/16/zend-mail-avec-template-standardise-avec-zend-layout-et-zend-view/
I think my first note would have to be that you're trying to use a hammer as a screwdriver. As I'm sure you know, in the MVC model the view is the rendering, and is logically distinct (separate) from the model. I'm not sure you're going to find a happy solution to this, since you're crossing the streams.