Does anyone know how can I calculate the number of weekdays between two date fields? I'm using oracle sql developer. I need to find the average of weekdays between multiple start and end dates. So I need to get the count of days for each record so I can average them out. Is this something that can be done as one line in the SELECT part of my query?
This answer is similar to Nicholas's, which isn't a surprise because you need a subquery with a CONNECT BY to spin out a list of dates. The dates can then be counted while checking for the day of the week. The difference here is that it shows how to get the weekday count value on each line of the results:
SELECT
FromDate,
ThruDate,
(SELECT COUNT(*)
FROM DUAL
WHERE TO_CHAR(FromDate + LEVEL - 1, 'DY') NOT IN ('SAT', 'SUN')
CONNECT BY LEVEL <= ThruDate - FromDate + 1
) AS Weekday_Count
FROM myTable
The count is inclusive, meaning it includes FromDate and ThruDate. This query assumes that your dates don't have a time component; if they do you'll need to TRUNC the date columns in the subquery.
You could do it the following way :
Lets say we want to know how many weekdays between start_date='01.08.2013' and end_date='04.08.2013' In this example start_date and end_date are string literals. If your start_date and end_date are of date datatype, the TO_DATE() function won't be needed:
select count(*) as num_of_weekdays
from ( select level as dnum
from dual
connect by (to_date(end_date, 'dd.mm.yyyy') -
to_date(start_date, 'dd.mm.yyyy') + 1) - level >= 0) s
where to_char(sysdate + dnum, 'DY',
'NLS_DATE_LANGUAGE=AMERICAN') not in ('SUN', 'SAT')
Result:
num_of_weekdays
--------------
2
Checkout my complete working function code and explanation at
https://sqljana.wordpress.com/2017/03/16/oracle-calculating-business-days-between-two-dates-in-oracle/
Once you have created the function just use the function as part of the SELECT statement and pass in the two date columns for Start and End dates like this:
SELECT Begin_Date, End_Date, fn_GetBusinessDaysInterval(Begin_Date, End_Date) AS BusinessDays FROM YOURTABLE;
Related
I want to get all dates of a month based on day name like if I want to get all FRIDAY dates from current date to a specific end date. I got a solution in SQL but can't find any solution in ORACLE.
You can use hierarchy query with next_day function as follows:
-- input variable
with dataa (start_date, end_date) as
(select date '2020-11-01', date '2020-12-15' from dual)
-- your query starts from here
select next_day((level-1)*7 + (start_date - 1), 'FRIDAY')
FROM DATAA
connect by
next_day((level-1)*7 + (start_date - 1),'FRIDAY') <= end_date
Db<>fiddle here
You can use hierarchical query as
WITH t AS
(
SELECT TRUNC(sysdate,'MM')+level-1 AS Fridays
FROM dual
WHERE TO_CHAR(TRUNC(sysdate,'MM')+level-1,'Dy','NLS_DATE_LANGUAGE=American')='Fri'
CONNECT BY level <= LAST_DAY(TRUNC(sysdate)) - TRUNC(sysdate,'MM') + 1
)
SELECT *
FROM t
WHERE Fridays BETWEEN :data1 AND :date2
Demo
Using connect by then filtering by Friday is a simple solution. In the example below I am using July 1st as the start date and December 1st as the end date.
SELECT DATE '2020-7-1' + LEVEL AS friday_dates
FROM DUAL
WHERE TO_CHAR (DATE '2020-7-1' + LEVEL, 'DY') = 'FRI'
CONNECT BY LEVEL <= DATE '2020-12-1' - DATE '2020-7-1';
I want No. of days between these 2 dates using Oracle SQL
Dates:
BETWEEN "1/1/2018" AND "6/11/2018"
How to write SQL Query?
between date '2018-01-01' and date '2018-11-06'
where DATE literal looks exactly like that: DATE 'YYYY-MM-DD'
In your example:
double quote's can't be used
even if you used single quotes, that would be a string, not DATE so you'd depend on whether Oracle is capable of converting it (implicitly) to date or not
therefore, always use dates, not strings
[EDIT]
This is how you select the whole calendar between those two dates:
select date '2018-01-01' + level - 1
from dual
connect by level <= date '2018-11-06' - date '2018-01-01' + 1;
As other answers have pointed out you can simply divide two dates, but there is also no need for any additional arithmetic.
The code:
select to_date('6/11/2018', 'DD/MM/YYYY') - to_date('1/1/2018', 'DD/MM/YYYY')
from dual;
The result: 309
you can simple do:
select date1-date2 form dual;
or
select (sysdate-to_date('01-jan-2018'))-(sysdate-to_date('10-jan-2018'))from dual;
Just use
select date'2018-11-06' - date'2018-01-01' + 1 as days_difference
from dual;
DAYS_DIFFERENCE
---------------
310
or
with t( myDate ) as
(
select date'2018-11-06' from dual union all
select date'2018-01-01' from dual
)
select max(myDate) - min(myDate) + 1 as days_difference
from t;
DAYS_DIFFERENCE
---------------
310
Oracle table in my application has a column with name "transaction_date" of type string. It stores date in the format MMDD, where MM = month and DD = day.
Please help me to write a SQL statement which will compare the transaction_date column with the current system date, if transaction_date is less than or equal to 120 days, then fetch the records from the table.
The problem I am facing is, transaction_date in db does not have year just month and day as a string value, so how to check if that value is not more than 120 days, that check should work if value in column is of previous year. For example, SQL should work for the scenario where current system date is lets say 01 feb 2018, and the transaction_date column in table has value "1225" (25th dec of previous year).
As a general disclaimer, your current table design is sub optimal, because a) you are storing dates as text, and b) you are not even storing the year for each date. From what you wrote, it looks like you want to consider all data as having occurred within the last year, from the current date.
One trick we can try here is to compare the MMDD text for each record in your table against TO_CHAR(SYSDATE, 'MMDD'), using the following logic:
If the MMDD is less than or equal to today, then it gets assigned to current year (2018 as of the time of writing this answer)
If the MMDD is greater than today, then it gets assigned to previous year (2017).
Then, we may build dates for each record using the appropriate year and check if it is within 120 days of SYSDATE.
WITH yourTable AS (
SELECT '0101' AS date_col FROM dual UNION ALL
SELECT '1001' FROM dual UNION ALL
SELECT '1027' FROM dual UNION ALL
SELECT '1215' FROM dual
)
SELECT
date_col
FROM yourTable
WHERE
(date_col <= TO_CHAR(SYSDATE, 'MMDD') AND
TO_DATE(date_col || TO_CHAR(SYSDATE, 'YYYY'), 'MMDDYYYY') >= SYSDATE - 120) OR
(date_col > TO_CHAR(SYSDATE, 'MMDD') AND
TO_DATE(date_col ||
TO_CHAR(TRUNC(ADD_MONTHS(SYSDATE, -12), 'YEAR'), 'YYYY'), 'MMDDYYYY') >=
SYSDATE - 120);
Demo
I have dates stored like String in database.
The format is 'yyyy-ww' (example: '2015-43').
I need to get the first day of the week.
I tried to convert this string into date but there is no 'ww' option for the function "to_date".
Do you have an idea to perform this convertion?
EDIT
Test results based on the answers -
Thanks for your anwsers, but I have many problems to apply your solutions to my context:
select
TRUNC ( 2015 + ((43 - 1) * 7), 'IW' )
from dual
==> Error : ORA-01722: invalid number
select
TRUNC(to_date('2015','YYYY')+ to_number('01') *7, 'IW')
from dual
==> 2015-02-02 00:00:00
I waited for a date in january
select
trunc(to_date(regexp_substr('2015-01', '\d+',1,2), 'YYYY') + regexp_substr('2015-01', '\d+') * 7, 'IW') dt2
from dual
==> 0039-09-14 00:00:00
select
regexp_substr('2015-01', '\d+',1,2) as res1,
regexp_substr('2015-01', '\d+') * 7 as res2
from dual
==> res1 = 01
==> res2 = 14105
try to use by truncate
with t as (
select '16-2010' dt from dual
)
--
--
select dt,
trunc(to_date(regexp_substr(dt, '\d+',1,2), 'YYYY') + regexp_substr(dt, '\d+') * 7, 'IW') dt2
from t
I have dates stored like String in database.
You should never do that. It is a bad design. you should store date as DATE and not as a string. For all kinds of requirements for date manipulations Oracle provides the required DATE functions and format models. As and when needed, you could extract/display the way you want.
I need to get the first day of the week.
TRUNC (dt, 'IW') returns the Monday on or before the given date.
Anyway, in your case, you have the literal as YYYY-WW format. You could first extract the year and week number and combine them together to get the date using TRUNC.
TRUNC ( year + ((week_number - 1) * 7)
, 'IW
)
So, the above should give you the Monday of the week number passed for that year.
SQL> WITH DATA AS
2 ( SELECT '2015-43' str FROM dual
3 )
4 SELECT TRUNC(to_date(SUBSTR(str, 1, 4),'YYYY')+ to_number(SUBSTR(str, instr(str, '-',1)+1))*7, 'IW')
5 FROM DATA
6 /
TRUNC(TO_
---------
23-NOV-15
SQL>
Similar to Lalit's, however, I think I've corrected the math (his seemed to be off a bit when I tested .. )
with w_data as (
select sysdate + level +200 d from dual connect by level <= 10
),
w_weeks as (
select d, to_char(d,'yyyy-iw') c
from w_data
)
SELECT d, c, trunc(d,'iw'),
TRUNC(
to_date(SUBSTR(c, 1, 4)||'0101','yyyymmdd')-8+to_char(to_date(SUBSTR(c, 1, 4)||'0101','yyyymmdd'),'d')
+to_number(SUBSTR(c, instr(c, '-',1)+1)-1)*7 ,'IW')
FROM w_weeks;
The extra columns help show the dates before, and after.
I would do the following:
WITH d1 AS (
SELECT '2015-43' AS mydate FROM dual
)
SELECT TRUNC(TRUNC(TO_DATE(REGEXP_SUBSTR(mydate, '^\d{4}'), 'YYYY'), 'YEAR') + (COALESCE(TO_NUMBER(REGEXP_SUBSTR(mydate, '\d+$')), 0)-1) * 7, 'IW')
FROM d1
The first thing the above query does is get the first four digits of the string 2015-43 and truncates that to the closest year (if you convert convert 2015 using TO_DATE() it returns a date within the current month; that is SELECT TO_DATE('2015', 'YYYY') FROM dual returns 01-FEB-2015; we need to truncate this value to the YEAR in order to get 01-JAN-2015). I then add the number of weeks minus one times seven and truncate the whole thing by IW. This returns a date of 01-OCT-2015 (see SQL Fiddle here).
According ISO the 4th of January is always in week 1, so your query should look like
Select
TRUNC(TO_DATE(REGEXP_SUBSTR(your_column, '^\d{4}')||'-01-04', 'YYYY-MM-DD')
+ 7*(REGEXP_SUBSTR(your_column, '\d$')-1), 'IW')
from your_table;
However, there is a problem. ISO year used for Week number can be different than actual year. For example, 1st Jan 2008 was in ISO week number 53 of 2007.
I think a proper working solution you get only when you generate ISO weeks from date value.
WITH w AS
(SELECT TO_CHAR(DATE '2010-01-04' + LEVEL * INTERVAL '7' DAY, 'IYYY-IW') AS week_number,
TRUNC(DATE '2010-01-04' + LEVEL * INTERVAL '7' DAY, 'IW') AS first_day
FROM dual
CONNECT BY DATE '2010-01-04' + LEVEL * INTERVAL '7' DAY < SYSDATE)
SELECT your_Column, first_day
FROM w your_table
JOIN w ON week_number = your_Column;
Your date range must bigger than 2010-01-04 and not bigger than current day.
This is what I used:
select
to_date(substr('2017/01',1,4)||'/'||to_char(to_number(substr('2017/01',6,2)*7)-5),'yyyy/ddd') from dual;
SELECT ORDER_NUM, CUSTOMER_NUM, CUSTOMER_NAME, ADD_DAYS (ORDER_DATE, 20)
FROM CUSTOMER, ORDERS;
Oracle Express says ADD_DAYS invalid? Any ideas what Am I doing wrong?
If you want to add N days to your days. You can use the plus operator as follows -
SELECT ( SYSDATE + N ) FROM DUAL;
You can use the plus operator to add days to a date.
order_date + 20
In a more general way you can use "INTERVAL". Here some examples:
1) add a day
select sysdate + INTERVAL '1' DAY from dual;
2) add 20 days
select sysdate + INTERVAL '20' DAY from dual;
2) add some minutes
select sysdate + INTERVAL '15' MINUTE from dual;
Some disadvantage of "INTERVAL '1' DAY" is that bind variables cannot be used for the number of days added. Instead, numtodsinterval can be used, like in this small example:
select trunc(sysdate) + numtodsinterval(:x, 'day') tag
from dual
See also: NUMTODSINTERVAL in Oracle Database Online Documentation
It's Simple.You can use
select (sysdate+2) as new_date from dual;
This will add two days from current date.
One thing about
select (sysdate+3) from dual
is that the sysdate is interpreted as date.
But if you want to use a custom date, not local, you need to make sure it is interpreted as date, not string. Like so (adding 3 days):
select (to_date('01/01/2020')+3) from dual