I am trying to write a query to Identify my subscribers who have abandoned a shopping cart in the last day but also I need a calculated field that represents weather or not they have received and incentive in the last 7 days.
I have the following tables
AbandonCart_Subscribers
Sendlog
The first part of the query is easy, get abandoners in the last day
select a.* from AbandonCart_Subscribers
where DATEDIFF(day,a.DateAbandoned,GETDATE()) <= 1
Here is my attempt to calculate the incentive but I am fairly certain it is not correct as IncentiveRecieved is always 0 even when I know it should not be...
select a.*,
CASE
WHEN DATEDIFF(D,s.SENDDATE,GETDATE()) >= 7
THEN 1
ELSE 0
END As IncentiveRecieved
from AbandonCart_Subscribers a
left join SendLog s on a.EmailAddress = s.EmailAddress and s.CampaignID IS NULL
where
DATEDIFF(day,a.DateAbandoned,GETDATE()) <= 1
Here is a SQL fiddle with the objects and some data. I would really appreciate some help.
Thanks
http://sqlfiddle.com/#!3/f481f/1
Kishore is right in saying the main problem is that it should be <=7, not >=7. However, there is another problem.
As it stands, you could get multiple results. You don't want to do a left join on SendLog in case the same email address is in there more than once. Instead you should be getting a unique result from that table. There's a couple of ways of doing that; here is one such way which uses a derived table. The table I have called s will give you a unique list of emails that have been sent an incentive in the last week.
select a.*,
CASE
WHEN s.EmailAddress is not null
THEN 1
ELSE 0
END As IncentiveRecieved
from AbandonCart_Subscribers a
left join (select distinct EmailAddress
from SendLog s
where s.CampaignID IS NULL
and DATEDIFF(D,s.SENDDATE,GETDATE()) <= 7
) s on a.EmailAddress = s.EmailAddress
where DATEDIFF(day,a.DateAbandoned,GETDATE()) <= 1
You can set a variable using a condition:
select a.*,(DATEDIFF(D,s.SENDDATE,GETDATE()) >= 7) as `IncentiveRecieved `
from AbandonCart_Subscribers a
left join SendLog s on a.EmailAddress = s.EmailAddress and s.CampaignID IS NULL
where
DATEDIFF(day,a.DateAbandoned,GETDATE()) <= 1
Is this what you're looking for?
should it not be less than 7 instead of greater than 7?
select a.*,
CASE
WHEN DATEDIFF(D,s.SENDDATE,GETDATE()) <= 7 AND CampaignID is not null
THEN 1
ELSE 0
END As IncentiveRecieved
from AbandonCart_Subscribers a
left join SendLog s on a.EmailAddress = s.EmailAddress --and s.CampaignID IS NULL
where
DATEDIFF(day,a.DateAbandoned,GETDATE()) <= 1
Hope this satisfies your need.
Related
I have two tables where I would like to compare information (In order to get from the initial table to the other I need to go through a reference table).
I am getting the results I am looking for except when a match is found an extra row of data is added (screen shot below). There should be only 4 rows, I don't understand why the value in column 1 row 5 wasn't just added to column 1 row 4.
Any help would be much appreciated.
Code
Select DISTINCT
CASE
WHEN LIC.ORDER_NUM = LN_STLIC.ORDER_NUMBER THEN LIC.ORDER_NUM
ELSE ''
END 'ORDER Number 1',
LN_STLIC.ORDER_NUMBER 'ORDER Number 2'
from LN_TABLE1 LN_STLIC
LEFT OUTER JOIN LN_REF LN_PDE_RTN on LN_STLIC.LNPID = LN_PDE_RTN.LNPID
LEFT OUTER JOIN LN_TABLE2 LIC on LN_PDE_RTN.ID = LIC.ID
where LIC.ID = '123456'
Example Table Data
LN_TABLE1
LN_REF
LN_TABLE2
Results
You've defined Order Number 1 as
CASE
WHEN LIC.ORDER_NUM = LN_STLIC.ORDER_NUMBER THEN LIC.ORDER_NUM
ELSE ''
END
So, you can reasonably infer that when Order Number 1 is blank, it's because LIC.ORDER_NUM doesn't match LN_STLIC.ORDER_NUMBER.
You asked for a DISTINCT on the combination of Order Number 1 and Order Number 2. So every combination of the two of them that appears in the data, will appear just once.
Because LN_TABLE1 has four different order numbers for the same value of LNPID, you're going to generate 3 records with a blank Order Number 1 and Order Number 2 set to 210414. But the distinct will take it down to just one, plus the one where they match (records 4 and 5 in your example).
You'd probably have to join on LIC.ORDER_NUM = LN_STLIC.ORDER_NUMBER in order to match the order numbers to each other, and get only 1 record for order number 210414.
I could give you a better query if I knew a bit more about what you were trying to achieve.
Your question is confusing:
We can do a simple LEFT JOIN with LN_STLIC and LIC :
Select CASE WHEN LN_STLIC.order_number = LIC.order_num THEN LIC.ORDER_NUM END ORD
Number1, LN_STLIC.order_number ORD Number2
from LN_TABLE1 LN_STLIC
LEFT OUTER JOIN LN_TABLE2 LIC ON LN_STLIC.order_number = LIC.order_num;
Also doing the below also gets you the same things in case you want to use LIC.ID = '1234' and there is no need to use DISTINCT.
Select
CASE WHEN LIC.ORDER_NUM = LN_STLIC.ORDER_NUMBER THEN LIC.ORDER_NUM
ELSE ''
END ORD_NBR_1,
LN_STLIC.ORDER_NUMBER ORD_NBR_2
from #LN_TABLE1 LN_STLIC
LEFT OUTER JOIN #LN_REF LN_PDE_RTN on LN_STLIC.LNPID = LN_PDE_RTN.LNPID
LEFT OUTER JOIN #LN_TABLE2 LIC on LN_PDE_RTN.ID = LIC.ID AND
LN_STLIC.ORDER_NUMBER =LIC.ORDER_NUM
;
I have these three tables:
table_things: [id]
table_location: [id]
[location]
[quantity]
table_reservation: [id]
[quantity]
[location]
[list_id]
Example data:
table_things:
id
1
2
3
table_location
id location quantity
1 100 10
1 101 4
2 100 1
table_reservation
id quantity location list_id
1 2 100 500
1 1 100 0
2 1 100 0
They are connected by [id] being the same in all three tables and [location] being the same in table_loation and table_reservation.
[quantity] in table_location shows how many ([quantity]) things ([id]) are in a certain place ([location]).
[quantity] in table_reservation shows how many ([quantity]) things ([id]) are reserved in a certain place ([location]).
There can be 0 or many rows in table_reservation that correspond to table_location.id = table_reservation_id, so I probably need to use an outer join for that.
I want to create a query that answers the question: How many things ([id]) are in this specific place (WHERE table_location=123), how many of of those things are reserved (table_reservation.[quantity]) and how many of those that are reserved are on a table_reservation.list_id where table_reservation.list_id > 0.
I can't get the aggregate functions right to where the answer contains only the number of lines that are in table_location with the given WHERE clause and at the same time I get the correct number of table_reservation.quantity.
If I do this I get the correct number of lines in the answer:
SELECT table_things.[id],
table_location.[quantity],
SUM(table_reservation.[quantity]
FROM table_location
INNER JOIN table_things ON table_location.[id] = table_things.[id]
RIGHT OUTER JOIN table_reservation ON table_things.location = table_reservation.location
WHERE table_location.location = 100
GROUP BY table_things.[id], table_location[quantity]
But the problem with that query is that I (of course) get an incorrect value for SUM(table_reservation.[quantity]) since it sums up all the corresponding rows in table_reservation and posts the same value on each of the rows in the result.
The second part is trying to get the correct value for the number of table_reservation.[quantity] whose list_id > 0. I tried something like this for that, in the SELECT list:
(SELECT SUM(CASE WHEN table_reservation.list_id > 0 THEN table_reservation.[quantity] ELSE 0 END)) AS test
But that doesn't even parse... I'm just showing it to show my thinking.
Probably an easy SQL problem, but it's been too long since I was doing these kinds of complicated queries.
For your first two questions:
How many things ([id]) are in this specific place (WHERE table_location=123), how many of of those things are reserved (table_reservation.[quantity])
I think you simply need a LEFT OUTER JOIN instead of RIGHT, and an additional join predicate for table_reservation
SELECT l.id,
l.quantity,
Reserved = SUM(ISNULL(r.quantity, 0))
FROM table_location AS l
INNER JOIN table_things AS t
ON t.id = l.ID
LEFT JOIN table_reservation r
ON r.id = t.id
AND r.location = l.location
WHERE l.location = 100
GROUP BY l.id, l.quantity;
N.B I have added ISNULL so that when nothing is reserved you get a result of 0 rather than NULL. You also don't actually need to reference table_things at all, but I am guessing this is a simplified example and you may need other fields from there so have left it in. I have also used aliases to make the query (in my opinion) easier to read.
For your 3rd question:
and how many of those that are reserved are on a table_reservation.list_id where table_reservation.list_id > 0.
Then you can use a conditional aggregate (CASE expression inside your SUM):
SELECT l.id,
l.quantity,
Reserved = SUM(r.quantity),
ReservedWithListOver0 = SUM(CASE WHEN r.list_id > 0 THEN r.[quantity] ELSE 0 END)
FROM table_location AS l
INNER JOIN table_things AS t
ON t.id = l.ID
LEFT JOIN table_reservation r
ON r.id = t.id
AND r.location = l.location
WHERE l.location = 100
GROUP BY l.id, l.quantity;
As a couple of side notes, unless you are doing it for the right reasons (so that different tables are queried depending on who is executing the query), then it is a good idea to always use the schema prefix, i.e. dbo.table_reservation rather than just table_reservation. It is also quite antiquated to prefix your object names with the object type (i.e. dbo.table_things rather than just dbo.things). It is somewhat subject, but this page gives a good example of why it might not be the best idea.
You can use a query like the following:
SELECT tt.[id],
tl.[quantity],
tr.[total_quantity],
tr.[partial_quantity]
FROM table_location AS tl
INNER JOIN table_things AS tt ON tl.[id] = tt.[id]
LEFT JOIN (
SELECT id, location,
SUM(quantity) AS total_quantity,
SUM(CASE WHEN list_id > 0 THEN quantity ELSE 0 END) AS partial_quantity
FROM table_reservation
GROUP BY id, location
) AS tr ON tl.id = tr.id AND tl.location = tr.location
WHERE tl.location = 100
The trick here is to do a LEFT JOIN to an already aggregated version of table table_reservation, so that you get one row per id, location. The derived table uses conditional aggregation to calculate field partial_quantity that contains the quantity where list_id > 0.
Output:
id quantity total_quantity partial_quantity
-----------------------------------------------
1 10 3 2
2 1 1 0
This was a classic case of sitting with a problem for a few hours and getting nowhere and then when you post to stackoverflow, you suddenly come up with the answer. Here's the query that gets me what I want:
SELECT table_things.[id],
table_location.[quantity],
SUM(table_reservation.[quantity],
(SELECT SUM(CASE WHEN table_reservation.list_id > 0 THEN ISNULL(table_reservation.[quantity], 0) ELSE 0 END)) AS test
FROM table_location
INNER JOIN table_things ON table_location.[id] = table_things.[id]
RIGHT OUTER JOIN table_reservation ON table_things.location = table_reservation.location AND table_things.[id] = table_reservation.[id]
WHERE table_location.location = 100
GROUP BY table_things.[id], table_location[quantity]
Edit: After having read GarethD's reply below, I did the changes he suggested (to my real code, not to the query above) which makes the (real) query correct.
I'm trying to create a query so that I can have a column show Y/N if a particular item was ordered for a group of orders. The item I'm looking for would be OLI.id = '538'.
So my results would be:
Order#, Customer#, FreightPaid
12345, 00112233, Y
12346, 00112233, N
I cannot figure out if I need to use a subquery or the where exists function ?
Here's my current query:
SELECT distinct
OrderID,
Accountuid as Customerno
FROM [SMILEWEB_live].[dbo].[OrderLog] OL
inner join Orderlog_item OLI on OLI.orderlogkey = OL.[key]
inner join Account A on A.uid = OL.Accountuid
where A.GroupId = 'X9955'
and OL.CreateDate >= GETDATE() - 60
I would suggest an exists clause instead of a join:
select ol.OrderID, ol.Accountuid as Customerno,
(case when exists (select 1
from Orderlog_item OLI join
Account A
on A.uid = OL.Accountuid
where OLI.orderlogkey = OL.[key] and A.GroupId = 'X9955'
)
then 1 else 0
end) as flag
from [SMILEWEB_live].[dbo].[OrderLog] OL
where OL.CreateDate >= GETDATE() - 60;
This prevents a couple of problems. First, duplicate rows which are caused when there are multiple matching rows (and select distinct add unnecessary overhead). Second, missing rows, which happen when you use inner join instead of an outer join.
I have the following table (person_program):
program_id person_id start_date end_date
1 15588499 01-01-2014 02-16-2014
2 15588499 02-17-2014 03-01-2014
3 15588499 02-15-2014 02-21-2014
I need to get the program_id that are contained by another time period in the same table (in this case, program_id = 3).
Any idea to solve this?
Thanks!!
Yes, you can reference the same table and get overlapping periods:
select t1.program_id ThisOne, t2.program_id OverlapsWith
from person_program t1
inner join person_program t2
on t1.program_id < t2.program_id
and t1.person_id = t2.person_id
and t2.start_date > t1.end_date
SQL Fiddle demo
Try:
select *
from person_program x
where exists (select 1 from person_program y where y.start_date <= x.start_date and y.person_id = x.person_id and y.program_id <> x.program_id)
or exists (select 1 from person_program y where y.end_date >= x.end_date and y.person_id = x.person_id and y.program_id <> x.program_id)
Note: This finds situations where, for the same person_id, there is another record on the table, with a different program_id, having a start and end date FULLY contained within the range of another.
EDIT: I just change the AND to OR, as it looks like, from your post, you are looking for partial, not necessarily full, overlaps. This should do that.
Assuming you are passing in the program_id you want to find overlaps for, and partial overlaps are OK:
DECLARE #program_id int = 3
SELECT PP.program_id,
PP.person_id
FROM person_program PP
INNER JOIN person_program Source
ON PP.start_date <= Source.end_date
AND PP.end_date >= Source.start_date
AND Source.program_id = #program_id
I have following sql query and my left join is not giving me distinct result please help me to trace out.
SELECT DISTINCT
Position.Date,
Position.SecurityId,
Position.PurchaseLotId,
Position.InPosition,
ISNULL(ClosingPrice.Bid, Position.Mark) AS Mark
FROM
Fireball_Reporting.dbo.Reporting_DailyNAV_Pricing POSITION WITH (NOLOCK, READUNCOMMITTED)
LEFT JOIN Fireball.dbo.AdditionalSecurityPrice ClosingPrice WITH (NOLOCK, READUNCOMMITTED) ON
ClosingPrice.SecurityID = Position.PricingSecurityID AND
ClosingPrice.Date = Position.Date AND
ClosingPrice.SecurityPriceSourceID = #SourceID AND
ClosingPrice.PortfolioID IN (5,6)
WHERE
DatePurchased > #NewPositionDate AND
Position.Date = #CurrentPositionDate AND
InPosition = 1 AND
Position.PortfolioId IN (
SELECT
PARAM
FROM
Fireball_Reporting.dbo.ParseMultiValuedParameter(#PortfolioId, ',')
) AND
(
Position > 1 OR
Position < - 1
)
Now here in above my when I use LEFT JOIN ISNULL(ClosingPrice.Bid, Position.Mark) AS Mark and LEFT JOIN it is giving me more no of records with mutiple portfolio ids
for e.g . (5,6)
If i put portfolioID =5 giving result as 120 records
If i put portfolioID =6 giving result as 20 records
When I put portfolioID = (5,6) it should give me 140 records
but it is giving result as 350 records which is wrong . :(
It is happening because when I use LEFT JOIN there is no condition of PurchaseLotID in that as table Fireball.dbo.AdditionalSecurityPrice ClosingPrice not having column PurchaseLotID so it is giving me other records also whoes having same purchaseLotID's with diferent prices .
But I dont want that records
How can I eliminate those records ?
You get one Entry per DailyLoanAndCashPosition.PurchaseLotId = NAVImpact.PurchaseLotId
which would mean you must have more entrys in with the same PurchaseLotId
The most likely cause is that the left join produces duplicated PurchaseLotIds. The best way to know if if you perform a select distinct(PurchaseLotId) on your left side of the inner join.