Is it possible to nest variables within variables in SASS? - variables

I have a mixin that accepts an argument that I want to pass into a variable.
#mixin my_mixin($arg) {
background-color: $state-#{$arg}-text;
}

Interpolation of variable names is currently not possible in SASS. Here is the issue that discusses.
However, you may use interpolation of placeholders:
%my-dark-styles {
background-color: #000;
}
%my-white-styles {
background-color: #FFF;
}
#mixin my_mixin($arg) {
#extend %my-#{$arg}-styles;
}
.header {
#include my_mixin("dark");
}
.footer {
#include my_mixin("white");
}
This compiles to:
.header {
background-color: #000;
}
.footer {
background-color: #FFF;
}

Since Sass 3.3 you can use maps also https://sass-lang.com/blog/sass-33-is-released
Here is an example:
$state-light-text : #FFFFFF;
$state-dark-text : #000000;
$color-map: ( //create a array to support the two colors light and dark
light: $state-light-text,
dark: $state-dark-text
);
#each $color-key, $color-var in $color-map {
.myclass--#{$color-key} { //will generate .myclass--light .myclass--dark
background-color: $color-var; // equal $state-light-text or $state-dark-text
}
}
It will compile into:
.myclass--light {
background-color: #FFFFFF;
}
.myclass--dark {
background-color: #000000;
}

Related

Generate rules via LESS plugin

I'd like to write a plugin that can generate a LESS function named alt that can do the following transformation:
.button {
background-color: alt(red, blue);
color: alt(black, white);
}
And output the following:
.button {
background-color: red;
color: black;
body.alt & {
background-color: blue;
color: white;
}
}
There doesn't seem to be much documentation about writing LESS plugins on the site, so hoping someone can provide an example of how this might be written :) Thanks!
I think a mixin would be best for this. Something like the following LESS:
.alt(#property, #primary-color, #alternate-color) {
#{property}: #primary-color;
body.alt & {
#{property}: #alternate-color;
}
}
.button {
.alt(background-color, red, blue);
.alt(color, black, white);
}
Which will compile to the following CSS:
.button {
background-color: red;
color: black;
}
body.alt .button {
background-color: blue;
}
body.alt .button {
color: white;
}

Extend in Less like it Sass can

I like to use :extend() in Less like I can do it in Sass.
Example in SCSS: http://codepen.io/Grawl/pen/qEeQPG
Example in Less: http://codepen.io/Grawl/pen/qEeQpz (not worked)
Expected output:
.datalist-item {
display: block;
}
.datalist-item-term {
font-weight: normal;
}
.datalist-item-description {
font-weight: bold;
}
.datalist-float .datalist-item {
display: inline-block;
}
.datalist-float .datalist-item:not(:last-of-type) {
margin-right: 1em;
padding-right: 1em;
border-right: 1px solid;
}
The purpose is to not self-repeat, so if I rename one class in Sass I have not to rename others.
I know I can put root class in a variable and use it twice with it http://codepen.io/Grawl/pen/qEeQpz but it looks ugly :(
Your Sass (SCSS) example uses #extend-Only Selectors which is some special form of extending which does not exists in Less.
Firstly a "normal" extend:
SCSS:
.class {
p: 1;
}
.class2 {
#extend .class;
}
and Less:
.class {
p: 1;
}
.class2 {
&:extend(.class);
}
both compile into:
.class,
.class2 {
p: 1;
}
In Less .class2 { &:extend(.class); } can also be written as .class2:extend(.class1){}
Now consider the following SCSS code which uses #extend-Only Selectors:
%class {
p: 1;
}
.class2 {
#extend %class;
}
The preceding code compile into CSS code as follows:
.class2 {
p: 1; }
Sass documentation tells you:
#extend-Only Selectors
Sometimes you’ll write styles for a class that you only ever want to
#extend, and never want to use directly in your HTML. This is
especially true when writing a Sass library, where you may provide
styles for users to #extend if they need and ignore if they don’t.
If you use normal classes for this, you end up creating a lot of extra
CSS when the stylesheets are generated, and run the risk of colliding
with other classes that are being used in the HTML. That’s why Sass
supports “placeholder selectors” (for example, %foo).
Placeholder selectors look like class and id selectors, except the #
or . is replaced by %. They can be used anywhere a class or id could,
and on their own they prevent rulesets from being rendered to CSS.
In Less you will have two options to have code that does not generate output:
1) use a mixin, mixins do not generate output:
.class() {
p: 1;
}
.class2 {
.class();
}
outputs:
.class2 {
p: 1;
}
2) put your classes which should not output in a different file and import this file with the reference kewyword:
file1.less:
.class {
p: 1;
}
file2.less:
#import (reference) "file1";
.class2 {
&:extend(.class);
}
lessc file2.less will output now:
.class2 {
p: 1;
}
But i agree with #seven-phases-max in the comments in the first place. In your example there is no need to use extend. #seven-phases-max shows you some examples to solve this use case. Alternatively you can consider; changing selector order with parent reference, which should work in both Less and SASS:
.datalist-item {
display: block;
&-term {
font-weight: normal;
}
&-description {
font-weight: bold;
}
.datalist-float & {
display: inline-block;
&:not(:last-of-type) {
margin-right: 1em;
padding-right: 1em;
border-right: 1px solid;
}
}
}
Compile into:
.datalist-item {
display: block;
}
.datalist-item-term {
font-weight: normal;
}
.datalist-item-description {
font-weight: bold;
}
.datalist-float .datalist-item {
display: inline-block;
}
.datalist-float .datalist-item:not(:last-of-type) {
margin-right: 1em;
padding-right: 1em;
border-right: 1px solid;
}
Finally notice that you are using nesting of properties such as:
border: {
right: 1px solid;
};
which should compile into:
border-right {
1px solid;
}
Less does NOT support nesting of properties.

Alter CSS applied by LESS Mixin when body class is present?

I have a LESS mixin. When I apply this to an element I want it be styled slightly differently if a body class is present.
This:
.mixin() {
font-weight: bold;
color: red;
}
.element {
.mixin()
}
Outputs to this:
.element {
font-weight: bold;
color: red;
}
But I also want this to be outputted:
.body-class .element {
color: blue;
}
You can define your mixin this way:
.mixin() {
font-weight: bold;
color: red;
.body-class & {
color: blue;
}
}

Inherit from a Class Which Name Is Composed Using the `&` character in Less

How can I inherit from a class which name is composed using the & character (e.g. &-rule), please?
Desired Output
.prefix-rule-extended,
.prefix-rule {
color: white;
}
.prefix-rule-extended {
background-color: black;
}
or
.prefix-rule {
color: white;
}
.prefix-rule-extended {
color: white;
background-color: black;
}
Non-working Approaches
.prefix {
&-rule {
color: white;
}
}
plus
.prefix-rule-extended:extend(.prefix-rule) {
background-color: black;
}
or
.prefix-rule-extended {
.prefix-rule();
background-color: black;
}
Ideal Approach
.prefix {
&-rule {
color: white;
}
&-rule-extended:extend(&-rule) {
background-color: black;
}
}
Note 1: I know :extend(&-rule) is currently not supported.
Note 2: .prefix-rule is not so simple, i.a. there are nested rules inside so the following will not work:
.prefix {
&-rule {
color: white;
&-extended {
background-color: black;
}
}
}
Thank you.
(Ok, so as always to not leave this one w/o an answer - a summary of comments above):
Currently it's impossible to extend that kind of things. For the moment extend can't match selector identifiers generated via "concatenation" so .prefix {&.rule { ... would be a valid extend target (as it's "two elements" -> "two identifiers") but .prefix {&-rule { ... won't (since it's "two elements" -> "one identifier").
So if you plan to use extend don't be keen on such kind of nesting, keep it more simple.
Here are three valid Less snippets (each having its pros and cons) to get the desired CSS output.
1:
.prefix-rule {
color: white;
&-extended:extend(.prefix-rule) {
background-color: black;
}
}
2:
.prefix-rule {
&, &-extended {
color: white;
}
&-extended {
background-color: black;
}
}
3:
.rule-base {
color: white;
}
.prefix-rule {
&:extend(.rule-base);
&-extended:extend(.rule-base) {
background-color: black;
}
}

Lighten color from parent in Less

I am starting out with Less and one of the reasons I wanted to is because of the ligthen() function. So my first attempt was to do something with that.
This is my HTML
<div class="box blue">
<div class="boxbar">Foo</div>
blue
</div>
I finally got it working, but I doubt it's supposed be like this:
#blue: #468ACE;
#green: #41A53D;
#red: #9C2525;
#purple: #8938BF;
div
{
padding: 10px;
}
.blue {
background-color: #blue;
.boxbar { background-color: lighten(#blue, 10%); }
}
.green {
background-color: #green;
.boxbar { background-color: lighten(#green, 10%); }
}
.red {
background-color: #red;
.boxbar { background-color: lighten(#red, 10%); }
}
.purple {
background-color: #purple;
.boxbar { background-color: lighten(#purple, 10%); }
}
.boxbar
{
height: 10px;
}
How can I refactor this? Surely it must be easier to say "get your parent color, and lighten it a bit". I tried a couple of things: inherit (was worth a shot!), have the lightened versions inside .boxcar. But this obviously compiled to .boxcar .blue.. which is not what I want and I ended with what you can see here.. it works.. but it doesn't feel right. Then I would need to write code for every new color I introduce..
I am not completely sure what your desired solution would be ... but maybe something like making a mixin would help you from having to write so much stuff out.
LESS:
.bgmixin(#color) {
(~".#{color}") {
background-color: ##color;
.boxbar {
background-color: lighten(##color, 10%);
}
}
}
#blue: #468ACE;
#green: #41A53D;
#red: #9C2525;
.bgmixin("blue");
.bgmixin("green");
.bgmixin("red");
CSS:
.blue{
background-color: #468ace;
}
.blue .boxbar {
background-color: #6ea3d9;
}
.green{
background-color: #41a53d;
}
.green .boxbar {
background-color: #59c055;
}
.red{
background-color: #9c2525;
}
.red .boxbar{
background-color: #c52f2f;
}
Update:
In LESS>=1.4 you would want to use something like this to interpolate the class name from the color name:
.bgmixin(#color) {
#classname: ~"#{color}";
.#{classname} {
background-color: ##color;
.boxbar {
background-color: lighten(##color, 10%);
}
}
}