I have a table with a column named Skills which contains comma separated values for different employees like
EmpID Skills
1 C,C++,Oracle
2 Java,JavaScript,PHP
3 C,C++,Oracle
4 JavaScript,C++,ASP
5 C,C++,JavaScript
So I want to write a query which will order all the employees first who knows JavaScript, how can I get this result?
You should not use one attribute to store multiple values. That goes against relation DB principles.
Instead of that you should create additional table to store skills and refer to employee in it. Then, your query will looks like:
SELECT
*
FROM
employees
LEFT JOIN employees_skills
ON employee.id=employees_skills.employee_id
WHERE
employees_skills='JavaScript'
Try this
SELECT *
FROM
(
SELECT *
,CASE WHEN Skills LIKE '%JavaScript%' THEN 0 ELSE 1 END AS Rnk
FROM MyTable
) T
ORDER BY rnk,EmpID
DEMO
OR
SELECT * FROM #MyTable
ORDER BY CASE WHEN Skills LIKE '%JavaScript%' THEN 0 ELSE 1 END,EmpID
select EmpID, Skills
from Table1
order by case when Skills like '%JavaScript%' then 0 else 1 end
Try this:
SELECT *
FROM YourTable
ORDER BY PATINDEX('%JavaScript%', Skills) DESC
But this is a bad way. You should really normalize your table.
For MySQL
select Skills from myTable
order by case Skills
when "Javascript" then 0
when "Java" then 1 when "C++" then 2
end
and so on
For SQL Server
select Skills from myTable
order by case
when Skills="Javascript" then 1
when Skill="Java" then 2
else 3
end
Make sure to start SQL server from 1 (That I'm not sure).
Include an else before end that will show all remaining results.
For more details about SQL Server see this or see this
This works for DB2/400:
with s (id, skill, rest) as
(select id, '', sk from skills
union all
select id, substr(rest, 1, locate(',',rest)-1),
substr(rest,locate(',',rest)+1)
from s
where locate(',',rest) > 0)
select id, skill from s
where skill = 'JavaScript'
order by id
Related
Plain and simple: Is it possible to create a dynamic ordering by system, depending on the value inside the column, the query will query.
The query goes something like this:
SELECT id, name, sortbycolumn FROM table
WHERE id = :in_id
UNION
SELECT id, name, null sortbycolumn FROM table
WHERE id = :in_id
ORDER BY -- This part I simply don't know how to write. I have tried case and decode...
To answer. I did finally find the solution. It was quite simple and whilst I read through other answers, I was confused as to why it did not work for me. Apparently the index of a column will not work when using case when.
In the end, I put up the whole query with unions into a subquery with the solution being:
SELECT * FROM(
SELECT id, name, sortbycolumn FROM table
WHERE id = :in_id
UNION
SELECT id, name, null sortbycolumn FROM table
WHERE id = :in_id
)
ORDER BY
case when sortbycolumn = 1 THEN id,
case when sortbycolumn = 2 then name
else id end
I have the bellow oracle query:
SELECT
table_to_check.managed_system_serial,
CASE
WHEN infraprod.aix_servers.managed_system_serial IS NULL THEN
'NO'
ELSE
'YES'
END serial_exists,
name
FROM
(
SELECT
column_value managed_system_serial
FROM
TABLE ( sys.odcivarchar2list('BW020', 'D761P', '22DFW', 'BW020') )
) table_to_check
LEFT JOIN infraprod.aix_servers ON table_to_check.managed_system_serial = infraprod.aix_servers.managed_system_serial
The result from running the above is:
I am trying to make the MANAGED_SYSTEM_SERIAL column appear in sequence as the serials are already in the list. What I want to achieve is this:
MANAGED_SYSTEM_SERIAL NAME SERIAL_EXISTS
BW020 NO
D761P gmp3dr YES
22DFW PROM1VIOS2 YES
22DFW PROM1VIOS1 YES
22DFW promdb1 YES
BW020 NO
*The serials above are just a sample. The real number is around 1000 in total.
**There might be multiple entries per serial but this is not a problem, I just need to get them to appear in the results ordered as they are here in this list:
(
'BW020',
'D761P',
'22DFW',
'BW020'
)
As my knowledge in SQL is almost zero this has troubled me for a week and I can't find a solution that fits.
Any help is greatly appreciated.
Include rownum in inner query and use it to sort output:
select t.managed_system_serial, name,
case when a.managed_system_serial is null then 'NO' else 'YES' end SERIAL_EXISTS
from (
select rownum rn, column_value managed_system_serial
from table(sys.odcivarchar2list('BW020', 'D761P', '22DFW', 'BW020'))) t
left join aix_servers a on a.managed_system_serial = t.managed_system_serial
order by t.rn
dbfiddle demo
Are you just looking for order by?
order by MANAGED_SYSTEM_SERIAL
Hello Stack Overflow Community.
I am retrieving data with SQL from PATSTAT (patent data base from the European Patent Office). I have two issues (see below). For your info the PATSAT sql commands are quite limited.
I. Charindex with multiple values
I am looking for specific two specific patent groups ["Y02E" and "Y02C"] and want to retrieve data on these. I have found that using the charindex function works if I insert one group;
and charindex ('Y02E', cpc_class_symbol) > 0
But if I want to use another charindex function the query just times out;
and charindex ('Y02E', cpc_class_symbol) > 0 or charindex ('Y02C', cpc_class_symbol) >0
I am an absolute SQL rookie but would really appreciate your help!
II. List values from column in one cell with comma separation
Essentially I want to apply what I found as the "string_agg"-command, however, it does not work for this database. I have entries with a unique ID, which have multiple patent categories. For example:
appln_nr_epodoc | cpc_class_symbol
EP20110185794 | Y02E 10/125
EP20110185794 | Y02E 10/127
I would like to have it like this, however:
appln_nr_epodoc | cpc_class_symbol
EP20110185794 | Y02E 10/125, Y02E 10/127
Again, I am very new to sql, so any help is appreciated! Thank you!
I will also attach the full code here for transparency
SELECT a.appln_nr_epodoc, a.appln_nr_original, psn_name, person_ctry_code, person_name, person_address, appln_auth+appln_nr,
appln_filing_date, cpc_class_symbol
FROM
tls201_appln a
join tls207_pers_appln b on a.appln_id = b.appln_id
join tls206_person c on b.person_id = c.person_id
join tls801_country on c.person_ctry_code= tls801_country.ctry_code
join tls224_appln_cpc on a.appln_id = tls224_appln_cpc.appln_id
WHERE appln_auth = 'EP'
and appln_filing_year between 2005 and 2012
and eu_member = 'Y'
and granted = 'Y'
and psn_sector = 'company'
and charindex ('Y02E', cpc_class_symbol) > 0
For your part 2 here is a sample data i created
And here is the code. It gives me YOUR requested output.
create table #test_1 (
appln_nr_epodoc varchar(20) null
,cpc_class_symbol varchar(20) null
)
insert into #test_1 values
('EP20110185794','Y02E 10/125')
,('EP20110185794','Y02E 10/127')
,('EP20110185795','Y02E 10/130')
,('EP20110185796','Y02E 20/140')
,('EP20110185796','Y02E 21/142')
with CTE_1 as (select *
from (
select *
,R1_1 = Rank() over(partition by appln_nr_epodoc order by cpc_class_symbol )
from #test_1
) as a
where R1_1 = 1
)
,CTE_2 as (select *
from (
select *
,R1_1 = Rank() over(partition by appln_nr_epodoc order by cpc_class_symbol )
from #test_1
) as a
where R1_1 = 2 )
select a.appln_nr_epodoc
,a.cpc_class_symbol+','+c.cpc_class_symbol
from CTE_1 a
join CTE_2 c on c.appln_nr_epodoc = a.appln_nr_epodoc
Out put
I have searched a lot, but most of solutions are for concatenation option and not what I really want.
I have a table called X (in a Postgres database):
anm_id anm_category anm_sales
1 a_dog 100
2 b_dog 50
3 c_dog 60
4 a_cat 70
5 b_cat 80
6 c_cat 40
I want to get total sales by grouping 'a_dog', 'b_dog', 'c_dog' as dogs and 'a_cat', 'b_cat', 'c_cat' as cats.
I cannot change the data in the table as it is an external data base from which I am supposed to get information only.
How to do this using an SQL query? It does not need to be specific to Postgres.
Use case statement to group the animals of same categories together
SELECT CASE
WHEN anm_category LIKE '%dog' THEN 'Dogs'
WHEN anm_category LIKE '%cat' THEN 'cats'
ELSE 'Others'
END AS Animals_category,
Sum(anm_sales) AS total_sales
FROM yourtables
GROUP BY CASE
WHEN anm_category LIKE '%dog' THEN 'Dogs'
WHEN anm_category LIKE '%cat' THEN 'cats'
ELSE 'Others'
END
Also this query should work with most of the databases.
By using PostgreSQL's split_part()
select animal||'s' animal_cat,count(*) total_sales,sum(anm_sales) sales_sum from(
select split_part(anm_cat,'_',2) animal,anm_sales from x
)t
group by animal
sqlfiddle
By creating split_str() in MySQL
select animal||'s' animal_cat,count(*) total_sales,sum(anm_sales) sales_sum from(
select split_str(anm_cat,'_',2) animal,anm_sales from x
)t
group by animal
sqlfiddle
You could group by a substr of anm_catogery:
SELECT SUBSTR(anm_catogery, 3) || 's', COUNT(*)
FROM x
GROUP BY anm_catogery
If you have a constant length of the appendix like in the example:
SELECT CASE right(anm_category, 3) AS animal_type -- 3 last char
, sum(anm_sales) AS total_sales
FROM x
GROUP BY 1;
You don't need a CASE statement at all, but if you use one, make it a "simple" CASE:
Simplify nested case when statement
Use a positional reference instead of repeating a possibly lengthy expression.
If the length varies, but there is always a single underscore like in the example:
SELECT split_part(anm_category, '_', 2) AS animal_type -- word after "_"
, sum(anm_sales) AS total_sales
FROM x
GROUP BY 1;
I would like to retrieve all rows matching a set of conditions on the same column. But I would like the rows only if ALL the conditions are good, and no row if only one condition fails.
For example, taking this table:
|id|name|
---------
|1 |toto|
|2 |tata|
I would like to be able to request if "tata" && "toto" are in this table. But when asking if "tata" and "tuto" are in, I would like an empty response if one of argument is in not in the table, for example asking if "toto" && "tutu" are included in the table.
How can I do that ?
Currently, I'am doing one query per argument, which is not very efficient. I tried several solutions including a subselect or a group+having, but no one is working like I want.
thanks for your support !
cheers
This isn't the most efficient way, but this query would work.
SELECT * FROM table_name
WHERE (name = 'toto' OR name = 'tata')
AND ( SELECT COUNT(*) FROM table_name WHERE name = 'toto') > 0
AND ( SELECT COUNT(*) FROM table_name WHERE name = 'tata') > 0
This is a little vague. If the names are unique, you could count the matching rows that match a where clause:
where name='toto' or name='tata'
If the count is 2, then you know both matched. If name is not unique you could potentially select the first ID (select top 1 id ...) that matches each in a union and count those with an outer select.
Even if you had an arbitrary number of names to match, you could create a stored procedure or code in whatever top-level language you are using to build the select statement.
SELECT 1 AS found FROM hehe
WHERE 1 IN (SELECT 1 FROM hehe WHERE name='tata')
AND 1 IN (SELECT 1 FROM hehe WHERE name='toto')
If name is unique you can simplify to:
SELECT *
FROM tbl
WHERE name IN ('toto', 'tata')
AND (SELECT count(*) FROM tbl WHERE name IN ('toto', 'tata')) > 1;
If it isn't:
SELECT *
FROM tbl
WHERE name IN ('toto', 'tata')
AND EXISTS (SELECT * FROM tbl WHERE name = 'toto')
AND EXISTS (SELECT * FROM tbl WHERE name = 'tata');
Or, in PostgreSQL, MySQL and possibly others:
SELECT *
FROM tbl
WHERE name IN ('toto', 'tata')
AND (SELECT count(DISTINCT name) FROM tbl WHERE name IN ('toto', 'tata')) > 1;