i'm currently developing a news-site.
So here is the problem. I want to select the 2nd and 3rd row in a TOP 3.
SELECT TOP 3 * FROM News ORDER BY Date DESC;
I want to remove the 1st row and only return the 2nd and 3rd row.
Can anyone help?
Try this:
SELECT TOP 2 FROM
( SELECT TOP 3 * FROM News ORDER BY Date DESC ) xx
ORDER BY Date
SQLFiddle: http://www.sqlfiddle.com/#!3/dbb7e/5
You can also do this generically using window functions:
select n.*
from (SELECT n.*, row_number() over (order by date desc) as seqnum
FROM News n
) n
where n.seqnum >= 2 and n.seqnum <= 3;
I just offer this as a general solution. You can also ensure that you get everything from the second date (in case there are more than two items on that date) by using dense_rank() rather than row_number().
If you know that no two dates will be the same, you could add
where date not in (select max(date) from News)
Or you could look at rowid if you know that the first item will have rowid=0, for example if you created a temp table with the results of your initial query.
I assume, you somehow know what you Top 3 news are by ordering by date descending.
Therfore you should use the LIMIT clause with an OFFSET [For sqlite]
SELECT * FROM News ORDER BY Date DESC LIMIT 2 OFFSET 1;
Select top 2 * from News cross apply (select top 3 from news order by date desc)x
Related
I have One table with StatusID in StatusHistory Table. One customer could be multiple statusID. I need to find just previous statusID that mean the second Status ID which just befor he was hold.
I am getting current one this bellow way:
SELECT top 1 StatusIDHeld
FROM dbo.UserStatusHistory
WHERE userid=2154
ORDER BY tatusChangedOn DESC
Question:
I need 2nd statusID means just previous statusID
How to find the Second value(StatusID) from a table.?
select StatusIDHeld
from
(select
StatusIDHeld,
ROW_NUMBER () over (order by tatusChangedOn DESC) as num
from dbo.UserStatusHistory
where userid=2154
) T
where T.num = 2
There's nothing like second value of table. It depends on many factors, like indexes, etc.
To be able to get 1., 2. or n-th record depending on sort order, use ROW_NUMBER() function.
SELECT StatusIDHeld
FROM
(
SELECT StatusIDHeld, ROW_NUMBER () OVER(ORDER by StatusIDHeld) as RowNo
FROM UserStatusHistory
) AS t
where t.RowNo = 2
Another way is to use TOP instruction twice:
SELECT TOP(1) StatusIDHeld
FROM (
SELECT TOP(2) StatusIDHeld
FROM UserStatusHistory
WHERE userid=2154
ORDER BY tatusChangedOn ASC
) AS t
ORDER BY StatusIDHeld DESC
One way to do this is to fetch the first 2, and then take the second one of them:
select top 1 StatusIDHeld from (
select top 2 StatusIDHeld, StatusChangedOn
from dbo.UserStatusHistory
order by StatusChangedOn DESC
) TMP order by StatusChangedOn ASC
You need to offset your query reset by 1.
Please try this:
select StatusIDHeld from dbo.UserStatusHistory order by tatusChangedOn DESC Limit 1 OFFSET 1;
Currently i am trying to output the top row for 2 condition. One is max and one is min.
Current code
Select *
from (MY SELECT STATEMENT order by A desc)
where ROWNUM <= 1
UPDATE
I am now able to do for both condition. But i need the A to be the highest, if same then check for the B lowest.
E.g Lets say there is 2 rows, Both A is 100 and B is 50 for one and 60 for other.
In this case the 100:50 shld be choose because A is same then B is lowest.
E.g
Lets say there is 2 rows, A is 100 for one and 90 for other, since one is higher no need to check for B.
I tried using max and min but this method seems to work better, any suggestions
Well, after your clarification, you are looking for one record. With Max A. And the smallest B, in case there is more than one record with MAX A. This is simply:
Select *
from (MY SELECT STATEMENT order by A desc, B)
where ROWNUM = 1;
This sorts by A descending first, so you get all maximal A records first. Then it sorts by B, so inside each A group you get the least B first. This gives you the desired A record first, no matter if the found A is unique or not.
or avoid the vagaries of rownun and go for row_number() instead:
SELECT
*
FROM (
SELECT
*
, ROW_NUMBER (ORDER BY A DESC) adesc
, ROW_NUMBER (ORDER BY B ASC) basc
FROM SomeQuery
)
WHERE adesc = 1
OR basc = 1
footnote: select * is a convenience only, please replace with the actual columns required along with table names etc.
Try this if that works
Select *
from (MY SELECT STATEMENT order by A desc)
where ROWNUM <= 1
union
Select *
from (MY SELECT STATEMENT order by A asc)
where ROWNUM <= 1
SELECT * FROM
(Select foo.*, 0 as union_order
from (MY SELECT STATEMENT order by A desc) foo
where ROWNUM <= 1
UNION
Select foo.*, 1
from (MY SELECT STATEMENT order by B asc) foo
where ROWNUM <= 1)
ORDER BY
union_order
You have three fields ID, Date and Total. Your table contains multiple rows for the same day which is valid data however for reporting purpose you need to show only one row per day. The row with the highest ID per day should be returned the rest should be hidden from users (not returned).
To better picture the question below is sample data and sample output:
ID, Date, Total
1, 2011-12-22, 50
2, 2011-12-22, 150
The correct result is:
2, 2012-12-22, 150
The correct output is single row for 2011-12-22 date and this row was chosen because it has the highest ID (2>1)
Assuming that you have a database that supports window functions, and that the date column is indeed just date (and not datetime), then something like:
SELECT
* --TODO - Pick columns
FROM
(
SELECT ID,[Date],Total,ROW_NUMBER() OVER (PARTITION BY [Date] ORDER BY ID desc) rn
FROM [Table]
) t
WHERE
rn = 1
Should produce one row per day - and the selected row for any given day is that with the highest ID value.
SELECT *
FROM table
WHERE ID IN ( SELECT MAX(ID)
FROM table
GROUP BY Date )
This will work.
SELECT *
FROM tableName a
INNER JOIN
(
SELECT `DATE`, MAX(ID) maxID
FROM tableName
GROUP BY `DATE`
) b ON a.id = b.MaxID AND
a.`date` = b.`date`
SQLFiddle Demo
Probably
SELECT * FROM your_table ORDER BY ID DESC LIMIT 1
Select MAX(ID),Data,Total from foo
for MySQL
Another simple way is
SELECT TOP 1 * FROM YourTable ORDER BY ID DESC
And, I think this is the most simple way!
SELECT * FROM TABLE_SUM S WHERE S.ID =
(
SELECT MAX(ID) FROM TABLE_SUM
WHERE CDATE = GG.CDATE
GROUP BY CDATE
)
How can i find the fifth record in a table using sql query?
If you are feeling argumentative, consider using "SELECT * FROM table LIMIT 1" and arguing that since SQL does not promise to return results in any particular order, the row returned is spiritually equivalent to the fifth, then show your tattoo: "The nth element of an unordered set is meaningless!"
SELECT TOP 1 * FROM (SELECT TOP 5 * FROM Table T ORDER BY Column ASC) ORDER BY Column Desc
If you are using SqlServer you could use the TOP keyword to achieve this.
select top 1 * from(
select top 5 * from myTable order by orderingColumn) as A
order by orderingColumn desc
If you are using Oracle this should work (however i am not able to test this now)
select *
from (
select *, row_number() over (order by orderingColumn) r
from items
)
where r = 5;
SELECT * FROM table LIMIT 1 OFFSET 4;
Fifth record only in MySQL
SELECT * FROM anytable LIMIT ORDER BY id LIMIT 4,1
For SQL Server (recent-ish incarnations, anyway) something like this should work:
SELECT
*
FROM
(
SELECT
*,
ROW_NUMBER() OVER (ORDER BY the_table.the_column) 'row_num'
FROM
the_table
) numbered_rows
WHERE
row_num = 5
However, I'd actually put my vote with Thomas L Holaday's answer :)
I have an SQL Query that i'm running but I only want to select a specific row. For example lets say my query was:
Select * from Comments
Lets say this returns 10 rows, I only want to select the 8th record returned by this query. I know I can do:
Select Top 5 * from Comments
To get the top 5 records of that query but I only want to select a certain record, is there anything I can put into this query to do that (similar to top).
Thanks
jack
This is a classic interview question.
In Ms SQL 2005+ you can use the ROW_NUMBER() keyword and have the Predicate ROW_NUMBER = n
USE AdventureWorks;
GO
WITH OrderedOrders AS
(
SELECT SalesOrderID, OrderDate,
ROW_NUMBER() OVER (ORDER BY OrderDate) AS 'RowNumber'
FROM Sales.SalesOrderHeader
)
SELECT *
FROM OrderedOrders
WHERE RowNumber = 5;
In SQL2000 you could do something like
SELECT Top 1 *FROM
[tblApplications]
where [ApplicationID] In
(
SELECT TOP 5 [ApplicationID]
FROM [dbo].[tblApplications]
order by applicationId Desc
)
How about
SELECT TOP 1 * FROM
(SELECT TOP 8 * FROM Comments ORDER BY foo ASC)
ORDER BY foo DESC
First, you should say which RDBMS you're using.
Second, you should give careful thought to what it is you're trying to accomplish. Relational Databases are set-based. In general, the order of elements in a set does not matter. You'll want to ask why it matters in this case, then see if there's a better way to embed the concept of order into the query itself.
For instance, in SQL Server 2005 (and other RDBMS), you can use the ROW_NUMBER function to assign a sequential number to each row returned, based on the criteria you specify. You could then select rows based on the row number. Example from Books Online:
USE AdventureWorks;
GO
WITH OrderedOrders AS
(
SELECT SalesOrderID, OrderDate,
ROW_NUMBER() OVER (ORDER BY OrderDate) AS 'RowNumber'
FROM Sales.SalesOrderHeader
)
SELECT *
FROM OrderedOrders
WHERE RowNumber BETWEEN 50 AND 60;
SELECT * FROM comments WHERE ...conditions... LIMIT 1 OFFSET 8
OFFSET is a good thing for MySQL
For SQL Server 2005:
select rank() OVER (ORDER BY c.subject, c.date) as rank, c.subject, c.date
from comments c
where rank = 8
Well, in T-SQL (the dialect for SQL Server) you can do the following:
SELECT TOP 1 *
FROM (SELECT TOP 8 *
FROM Table
ORDER
BY SortField)
ORDER
BY SortField DESC
This way you get the 8th record.
I have read the question & your comments on you would want next 3 blog comments etc.
How is your tables structured?
Assume that you have blog post Id & comment Id is generated in ascending order for each blog post, you could do a SELECT based on the current Id.
e.g. if the blogpostId = 101, you get the top 3 comments order by posted Id. Now lets say, you want to get the next 3 comments - you could do a SELECT WHERE commentId between the last comment id shown TO the comment id - 3
But all that depends on how your tables are defined.
In SQL 2000 where you do not have ROW_NUMBER() function you could use a work-around like this:
SELECT CommentsTableFieldList, IDENTITY(INT, 1,1) as seqNo
INTO #SeqComments
FROM Comments
SELECT * FROM #SeqComments
WHERE seqNo = 8
select top 1 *
from TableName
where ColumnName1 in
(
select top nth ColumnName1
from TableName
order by ColumnName1 desc
)
order by ColumnName1 desc
From the SELECT reference, use the LIMIT keyword:
SELECT * FROM tbl LIMIT 5,10; # Retrieve rows 6-15
SELECT * FROM tbl LIMIT 5; # Retrieve first 5 rows
Note: this is for MySQL, other SQL engines may have a different keyword.
Select from tablename limit nthrow,1;
try This
Let us assume , We want select 5th row of WC_Video Table
And
Select * from (Select Row_Number() over (Order by Uploadedon) as 'rownumber',* from Wc_Video )as Temp where rownumber=5