I have one column capturedatetime(Char(30)):
2006-04-25T15:50:59.997000 PM
And I want to convert it and load it at other table column which have is in DateTime. either by T-sql or SSIS which ever way.
I have tried with:
select CONVERT(datetime, '2006-04-25T15:50:59.997000 PM', 126)
But it creates an error:
Conversion failed when converting date and/or time from character string
Late update:
In this column I also have other data that is in a completely different format:
29-JAN-10 08.57.41.000000 PM
(1) STOP storing datetime data in string columns! This is nothing, nothing, nothing but trouble.
(2) Why on earth does your column get data in two different string formats that aren't even valid? Why does the string use 24 hour time and have AM/PM suffix? Why use a regional string format and Y2K disaster like 29-JAN-10?
Here is one way, but it's awfully ugly. I highly recommend you fix the SSIS process to give you valid datetime values in the first place, if not as datetimes, at least as valid ISO strings (yyyy-mm-ddThh:mm:ss.nnn):
DECLARE #x TABLE (d CHAR(30));
INSERT #x SELECT '2006-04-25T15:50:59.997000 PM'
UNION ALL SELECT '29-JAN-10 08.57.41.000000 PM';
SET LANGUAGE ENGLISH; -- this is important, else style 6 may not work
SELECT
CASE WHEN d LIKE '__[0-9]%' THEN
CONVERT(DATETIME, LEFT(d, 23))
WHEN d LIKE '[0-9][0-9]-%' THEN
CONVERT(DATETIME, CONVERT(CHAR(8),
CONVERT(DATETIME,REPLACE(LEFT(d,9),' ','-'),6),112)
+ ' ' + REPLACE(SUBSTRING(d,11,8),'.',':')
+ ' ' + RIGHT(RTRIM(d),2))
END
FROM #x;
The conversion for 126 requires no spaces ... I've got it to work like this:
declare #T varchar(50)
declare #dt datetime
set #T = '2006-04-25T15:50:59.997'
set #dt = convert(datetime,#t,126)
select #T, #dt
select convert(datetime,left('2006-04-25T15:50:59.997000 PM',23))
or
select convert(datetime,left(capturedatetime,23))
If you use cast, you do not even need to supply a format. Code snippet below tested on SQL 2012 Developer version.
declare #var_string varchar(50) = '2006-04-25T15:50:59.997';
declare #var_datetime datetime = cast(#var_string as datetime);
select #var_string as my_string, #var_datetime as my_variable;
Related
I have a table in my database that has has both the original user input date string, then tries to get the datetime from that by using CONVERT
CREATE TABLE #UserInput
(
actualDate DATETIME NULL,
dateString VARCHAR(50) NULL
)
The statement
SELECT CONVERT(DATETIME, dateString)
FROM #UserInput
works fine, and correctly converts the strings to datetime.
However, when I try to set the actualDate column, using the statement
UPDATE X
SET X.actualDate = CONVERT(DATETIME, X.dateString)
FROM #UserInput X
I get the error:
Conversion failed when converting date and/or time from character string.
Since I can run the select, I know all the dateStrings are formatted correctly and can be converted. So then why am I unable to do so with the update?
The specific format I've been testing with is mm/dd/yyyy hh:mm, but the solution would need to handle other formats as well.
I appreciate any help on this, thanks.
CREATE TABLE #UserInput (
actualDate datetime NULL,
dateString varchar(50) NULL)
insert #UserInput(dateString) values('20181231 12:15')
SELECT CONVERT(datetime, dateString)
FROM #UserInput
UPDATE X
SET X.actualDate = CONVERT(datetime, X.dateString)
FROM #UserInput X
select * from #UserInput
I tested it for two format yyyymmdd hh:mm and mm/dd/yyyy hh:mm this code working correctly. I didn't get any error for update or select run.
The simply solution is try_convert():
UPDATE X
SET X.actualDate = TRY_CONVERT(DATETIME, X.dateString)
FROM #UserInput X ;
I suspect the problem is that you are not seeing all the rows in X -- just a few that match. To test this, run:
select X.*
from #userinput X
where try_convert(datetime, x.dateString) is null;
In my table I have myDate column of type nvarchar(50).
The result I need is to select this date/time: 07/11/2013 11:22:07
And I need to get 07/11/2013 11:22:07 am from it (add am/pm to the original date&time).
I tried everything but get only the original data without am/pm.
This is an example from my query :
select convert(dateTime,myDate,100) as Date from Info
or
select convert(dateTime,myDate,0) as Date from Info
What am I missing ?
try this !!
declare #date datetime
set #date='07/11/2013 11:22:07'
SELECT cast(convert(varchar(20),substring(convert(nvarchar(20),#date, 9), 0, 21)
+ ' ' + substring(convert(nvarchar(30), #date, 9), 25, 2),105) as datetime)
Your field is a NVARCHAR field so just return it without any conversion. In your query you convert string representation into the DATETIME type and returns it. Your browser software which shows query results convert DateTime value into string representation to show it to you and conversion format depends on this software usually you can change it changing Windows Regional Settings.
You can get AM/PM data using following query
declare #date datetime
select #date= CAST('07/11/2013 11:22:07' AS datetime)
select RIGHT ( CONVERT(VARCHAR,#date,9),2)
I have two columns in my table, one to capture time and one to capture date. Unfortunately, both are varchar(). I need to take the two fields, concatenate them together, and then convert them to datetime.
I am trying to accomplish that with this:
select CONVERT(datetime,(select txt_returned_date+' '+CONVERT(varchar(20),CONVERT(TIME,txt_time_returned))),126)
from table_name
I am getting this error message:
Conversion failed when converting date and/or time from character string.
The date is being captured as "20130308" as a string. Time is being captures as "4:27 PM" as a string
What I am doing here is converting the string of the time to TIME, then back to varchar. Then I am concatenating them together. This works by itself, but once I introduce the CONVERT(datetime) to the whole query, it is giving me the error.
Any help to try to accomplish this is helpful. Thanks!
You can concatenate the DATE and TIME values together once they have been converted to a DATETIME. Here's a sample to play with that shows concatenating a DATE column and a TIME column that have been stored as VARCHAR:
-- Set up some variables to test with
DECLARE #myTime TIME = GETDATE()
, #myDate DATE = GETDATE()
, #myTimeTxt VARCHAR(16)
, #myDateTxt VARCHAR(10);
-- Initialize your variables
SELECT #myTimeTxt = #myTime
, #myDateTxt = #myDate;
-- Display your separated values
SELECT #myDateTxt, #myTimeTxt;
-- Display your concatenated value
SELECT CAST(#myDateTxt AS DATETIME) + CAST(CAST(#myTimeTxt AS TIME) AS DATETIME);
You can use this option
DECLARE #date date = '20010101',
#time time = '01:01:01'
SELECT CAST(#date AS datetime) + #time
Result:2001-01-01 01:01:01.000
Demo on SQLFiddle
Are you using SQL 2012? If so you may be able to use the datetimedromparts function to achieve this. If not for this specific example, it's always good to know for the future :)
http://technet.microsoft.com/en-gb/library/hh213233.aspx
This is in MS SQL Server.
I have a varchar in the format yyyy-MM-dd-hh.mm.ss.nnnnnn
For example: 2010-09-17-20.52.31.870000
I want to convert this into a datetime... but ISDATE function in MSSQL says that is not a valid date and CONVERT won't work. Is there a way to use the convert function so that I can tell it what format the date is in?
I also want to check first that it is a valid date since the varchar input may contain nothing or it may contain an invalid date.
For example, invalid data of 2010-xx-r7-99.53esdfd.31.870000... I would skip that data and not even try to convert.
As far as I'm aware, SQL Server 2005 only supports milliseconds up to 3 digits, so you could replace the periods with colons, and grab the left and right portions (ignoring the hyphen between the day and hours) and come up with something like this:
DECLARE #myDate varchar(50)
SET #myDate = '2010-09-17-20.52.31.870000'
PRINT isdate(left(#myDate, 10) + ' ' +
replace(substring(#myDate, 12, 12), '.', ':')) -- Should print '1'
PRINT cast(left(#myDate, 10) + ' ' +
replace(substring(#myDate, 12, 12), '.', ':') as datetime)
... which will effectively give you 870 milliseconds
The ISO 8601 standard separates the date and time with the letter T. Maybe that's all it needs to convert successfully? Some conversion implementations accept a space there too. I've never seen a hyphen there.
You would have to change the punctuation a bit to make it work, and reduce the precision from microseconds to millisecond. This works:
convert(datetime, '2010-09-17 20:52:31.870', 121)
What you are getting in is a bit wonky, but this works (tested):
DECLARE #temp as varchar(50)
SET #temp = '2010-09-17-20.52.31.870'
SET #temp = replace(#temp,'.',':')
set #temp = stuff(#temp,11,1,'T')
set #temp = stuff(#temp,20,1,'.')
select #temp
select cast(#temp as datetime)
NB I cut off the extra 0s, you could do this with substring if there really are those extra ones.
How do I convert a string of format mmddyyyy into datetime in SQL Server 2008?
My target column is in DateTime
I have tried with Convert and most of the Date style values however I get an error message:
'The conversion of a varchar data type to a datetime data type resulted in an out-of-range value.'
OP wants mmddyy and a plain convert will not work for that:
select convert(datetime,'12312009')
Msg 242, Level 16, State 3, Line 1
The conversion of a char data type to a datetime data type resulted in
an out-of-range datetime value
so try this:
DECLARE #Date char(8)
set #Date='12312009'
SELECT CONVERT(datetime,RIGHT(#Date,4)+LEFT(#Date,2)+SUBSTRING(#Date,3,2))
OUTPUT:
-----------------------
2009-12-31 00:00:00.000
(1 row(s) affected)
SQL Server can implicitly cast strings in the form of 'YYYYMMDD' to a datetime - all other strings must be explicitly cast. here are two quick code blocks which will do the conversion from the form you are talking about:
version 1 uses unit variables:
BEGIN
DECLARE #input VARCHAR(8), #mon CHAR(2),
#day char(2), #year char(4), #output DATETIME
SET #input = '10022009' --today's date
SELECT #mon = LEFT(#input, 2), #day = SUBSTRING(#input, 3,2), #year = RIGHT(#input,4)
SELECT #output = #year+#mon+#day
SELECT #output
END
version 2 does not use unit variables:
BEGIN
DECLARE #input CHAR(8), #output DATETIME
SET #input = '10022009' --today's date
SELECT #output = RIGHT(#input,4) + SUBSTRING(#input, 3,2) + LEFT(#input, 2)
SELECT #output
END
Both cases rely on sql server's ability to do that implicit conversion.
Likely you have bad data that cannot convert. Dates should never be stored in varchar becasue it will allow dates such as ASAP or 02/30/2009. Use the isdate() function on your data to find the records which can't convert.
OK I tested with known good data and still got the message. You need to convert to a different format becasue it does not know if 12302009 is mmddyyyy or ddmmyyyy. The format of yyyymmdd is not ambiguous and SQL Server will convert it correctly
I got this to work:
cast( right(#date,4) + left(#date,4) as datetime)
You will still get an error message though if you have any that are in a non-standard format like '112009' or some text value or a true out of range date.
I found this helpful for my conversion, without string manipulation. https://learn.microsoft.com/en-us/sql/t-sql/functions/cast-and-convert-transact-sql
CONVERT(VARCHAR(23), #lastUploadEndDate, 121)
yyyy-mm-dd hh:mi:ss.mmm(24h) was the format I needed.
Convert would be the normal answer, but the format is not a recognised format for the converter, mm/dd/yyyy could be converted using convert(datetime,yourdatestring,101) but you do not have that format so it fails.
The problem is the format being non-standard, you will have to manipulate it to a standard the convert can understand from those available.
Hacked together, if you can guarentee the format
declare #date char(8)
set #date = '12312009'
select convert(datetime, substring(#date,5,4) + substring(#date,1,2) + substring(#date,3,2),112)
Look at CAST / CONVERT in BOL that should be a start.
If your target column is datetime you don't need to convert it, SQL will do it for you.
Otherwise
CONVERT(datetime, '20090101')
Should do it.
This is a link that should help as well:
I'd use STUFF to insert dividing chars and then use CONVERT with the appropriate style. Something like this:
DECLARE #dt VARCHAR(100)='111290';
SELECT CONVERT(DATETIME,STUFF(STUFF(#dt,3,0,'/'),6,0,'/'),3)
First you use two times STUFF to get 11/12/90 instead of 111290, than you use the 3 to convert this to datetime (or any other fitting format: use . for german, - for british...) More details on CAST and CONVERT
Best was, to store date and time values properly.
This should be either "universal unseparated format" yyyyMMdd
or (especially within XML) it should be ISO8601: yyyy-MM-dd or yyyy-MM-ddThh:mm:ss More details on ISO8601
Any culture specific format will lead into troubles sooner or later...
use Try_Convert:Returns a value cast to the specified data type if the cast succeeds; otherwise, returns null.
DECLARE #DateString VARCHAR(10) ='20160805'
SELECT TRY_CONVERT(DATETIME,#DateString)
SET #DateString ='Invalid Date'
SELECT TRY_CONVERT(DATETIME,#DateString)
Link:MSDN TRY_CONVERT (Transact-SQL)
I had luck with something similar:
Convert(DATETIME, CONVERT(VARCHAR(2), #Month) + '/' + CONVERT(VARCHAR(2), #Day)
+ '/' + CONVERT(VARCHAR(4), #Year))
The root cause of this issue can be in the regional settings - DB waiting for YYYY-MM-DD while an app sents, for example, DD-MM-YYYY (Russian locale format) as it was in my case. All I did - change locale format from Russian to English (United States) and voilà.
This seems the easiest way..
SELECT REPLACE(CONVERT(CHAR(10), GETDATE(), 110),'-','')
SQL standard dates while inserting or updating Must be between 1/1/1753 12:00:00 AM and 12/31/9999 11:59:59 PM.
So if you are inserting/Updating below 1/1/1753 you will get this error.
DECLARE #d char(8)
SET #d = '06082020' /* MMDDYYYY means June 8. 2020 */
SELECT CAST(FORMAT (CAST (#d AS INT), '##/##/####') as DATETIME)
Result returned is the original date string in #d as a DateTime.