Hi everyone I am having three tables.
Customer(list of customers)
Payments(list of customer payment)
Orders(list of customer orders)
customer can have more than one payment and order that is one to many relation.
I tried following query but it is not showing proper result.
select a.name, b.job_date as JobDate, c.order_date as OrderDate from Customers a
inner join Jobs b on a.id = b.customer_id
inner join Orders c on a.id = c.customer_id
where a.id = 1;
What i need is to show a customer's orders and jobs.
Try left join instead of inner join. child tables might not have records assosiated with Customers.id =1.
select a.name, b.job_date as JobDate, c.order_date as OrderDate from Customers a
left join Jobs b on a.id = b.customer_id
left join Orders c on a.id = c.customer_id
where a.id = 1;
If you want to get all the orders you can use the following :
select a.name, c.order_date as OrderDate from Orders c
inner join Customers a on a.id = c.customer_id
where a.id = 1;
You get build a similar query to get all the employee's jobs:
select a.name, b.job_date as JobDate from Jobs b
inner join Customers a on a.id = b.customer_id
where a.id = 1;
Related
I am working with 3 tables sales, customer & product where I want to get all columns from the sales table and customer_name, customer age from customer table and product_name, category from the product table in the same result set. There's a condition that I have to use 2 join operations where one join will be inside subquery and the other outside subquery.
Here's my query that's not working:
SELECT a.*,
b.customer_name,
b.age,
b.customer_id
FROM sales AS a
LEFT JOIN customer AS b on a.customer_id = b.customer_id
LEFT JOIN (SELECT product_id, product_name, category from product) as c
ON a.product_id = c.product_id
ORDER BY a.customer_id, b.customer_id;
Only the first join is working in this query.
select
a.*,
b.customer_name,
b.age,
b.customer_id ,
c.*
from sales as a
left join customer as b
on a.customer_id = b.customer_id
LEFT JOIN (SELECT product_id, product_name, category from product) as c
ON a.product_id = c.product_id
order by a.customer_id;
https://www.db-fiddle.com/f/wKbMaD6UF1v3a4KCXE7248/0
I am trying to find sum of some columns using SQL like this:
select distinct c.customer,
c.customer_id,
sum(d.delay) as delay,
sum(d.delayed_amount) as delay_amt,
pd.product
from product pd
inner join mfg_company mfg on pd.product_id=mfg.product_id
inner join store s on mfg.store_id = s.store_id
inner join customer c on s.customer = c.customer_id
join delay_detail d on pd.product_id = d.material
where d.product_mfg_id = 466
group by c.customer,customer_id
order by c.customer,c.customer_id
The problem is mfg_company has duplicate product_id's(multiple mappings) ,So when I am trying to find the sum it's including those duplicates too.
Using product_id in group by clause doesn't help the result I want to see.So how to join only on distinct product_id's?
You can try below query if this helps -
select distinct c.customer
,c.customer_id
,sum(d.delay) as delay
,sum(d.delayed_amount) as delay_amt
,pd.product
from product pd
inner join (select distinct product_id
,store_id
from mfg_company) mfg on pd.product_id=mfg.product_id
inner join store s on mfg.store_id = s.store_id
inner join customer c on s.customer = c.customer_id
join delay_detail d on pd.product_id = d.material
where d.product_mfg_id = 466
group by c.customer,customer_id
order by c.customer,c.customer_id
I think the solution to your problem is to pre-aggregate the delays. It is entirely unclear if you want the product in the result set. Assuming you do not:
select c.customer, c.customer_id,
sum(d.delay) as delay, sum(d.delay_amt) as delay_amt
from product pd join
mfg_company mfg
on pd.product_id = mfg.product_id join
store s
on mfg.store_id = s.store_id
customer c
on s.customer = c.customer_id join
(select d.material, sum(d.delay) as delay, sum(d.delayed_amount) as delay_amt
from delay_detail d
group by d.material
) d
on pd.product_id = d.material
where d.product_mfg_id = 466
group by c.customer, customer_id
order by c.customer, c.customer_id;
Note that using select distinct with group by is almost never needed.
I have 4 tables:
sales
products
vender_info
venders
Question is: display list of product_id whose vender and customer is different.
Please solve this question.
tables
Not sure what would you do with this data, but this is the query:
SELECT vp.PRODUCT_ID, vv.VENDERS, vs.CUSTOMERNAME
FROM vna_sales vs
JOIN vna_products vp ON vs.ORDERID = vp.ORDERID
JOIN vna_venders vv ON vp.VENDER_ID = vv.VENDER_ID
WHERE vv.VENDERS <> vs.CUSTOMERNAME
Please try this
SELECT *
FROM vna_shipments a
inner join vna_parts b on a.id = b.id //some joing factor
inner vna_suppliers c on a.id = c.id //some joing factor
inner vna_projects d on a.id = d.id //some joing factor
group by vendor_id, customer_id
order by vendor_id desc
So Im trying to find the total amount spent on Cuts and Products by each Customer
I don't know if my Query is Wrong or my entire Database Schema any ideas?
My Query
`Select First_Name, SUM(B.Cost), SUM(C.Cost)
FROM bookings A, cuts B, products C, customers D
Where A.Customer_ID= D.Customer_ID
AND A.Cut_ID = B.Cut_ID
AND A.Product_ID= C.Product_ID;`
My Database
`Table: bookings
Booking_N0, Customer_ID, Cut_ID, Product_ID, TimeTaken`
`Table: customers
Customre_ID, First_Name, Sex`
`Table: products
Product_ID, Products, Cost`
`Table: cuts
Cut_ID, Cut, Cost`
You should GROUP BY to SUM by each customer :
Select D.First_Name
, SUM(B.Cost)
, SUM(C.Cost)
FROM bookings A LEFT JOIN cuts B ON A.Cut_ID = B.Cut_ID
JOIN products C ON A.Product_ID = C.Product_ID
JOIN customers D ON A.Customer_ID = D.Customer_ID
GROUP BY D.First_Name;
Also, look forward using explicit join notation (FROM table1 t1 JOIN table2 t2 ON t1.field1 = t2.field2) instead of implicit join notation (FROM table1 t1, table2 t2 WHERE t1.field1 = t2.field2), because it is has more intuitive view (tables are listed near conditions on which they are joined).
Start using recommended JOIN / ON syntax for joining instead of using WHERE clause . You also need a GROUP BY clause
Select First_Name, SUM(B.Cost), SUM(C.Cost)
FROM bookings A
INNER JOIN cuts B
ON A.Cut_ID = B.Cut_ID
INNER JOIN products C
ON A.Product_ID= C.Product_ID
INNER JOIN customers D
ON A.Customer_ID= D.Customer_ID
GROUP BY First_Name
If you use aggregate function like SUM you have to add a group by clause
in your case:
...
AND A.Product_ID= C.Product_ID
GROUP BY First_Name
I was tasked to create a new report on a legacy program. I needed to LEFT JOIN a table but I am getting Syntax error on JOIN Operation.
My SQL query as follows:
SELECT
SUM(b.qty) as qty,
b.price,
c.item_desc,
a.cust_name,
e.curr_symbol
FROM (
tran_hdr a,
tran_dtl b,
items c ,
tailoring e
(
LEFT JOIN
customers d
ON a.cust_name = d.name
)
)
WHERE a.tran_id = b.tran_id
AND b.item_no = c.item_no
GROUP BY b.price,
c.item_desc,
a.cust_name,
e.curr_symbol
I am joining the tran_hdr to customers. Because not all customers in Tran Header is maintained in customer table, but report requirest to show all Data in Transaction table.
You're messing up your JOINs.
And your Tailoring table has no relation whatsoever to other table.
So, just try this one out:
SELECT
b.price,
c.item_desc,
a.cust_name,
e.curr_symbol,
SUM(b.qty) as qty
FROM
tran_hdr a
INNER JOIN tran_dtl b
ON a.tran_id = b.tran_id
INNER JOIN items c
ON b.item_no = c.item_no
LEFT JOIN
customers d
ON a.cust_name = d.name
,tailoring e
GROUP BY b.price,
c.item_desc,
a.cust_name,
e.curr_symbol