I have a column of count and want to divide the column by max of this column to get the rate.
I tried
select t.count/max(t.count)
from table t
group by t.count
but failed.
I also tried the one without GROUP BY, still failed.
Order the count desc and pick the first one as dividend didn't work in my case. Consider I have different counts for product subcategory. For each product category, I want to divide the count of subcategory by the max of count in that category. I can't think of a way avoiding aggregate func.
If you want the MAX() per category you need a correlated subquery:
select t.count*1.0/(SELECT max(t.count)
FROM table a
WHERE t.category = a.category)
from table t
Or you need to PARTITION BY your MAX()
select t.count/(max(t.count) over (PARTITION BY category))
from table t
group by t.count
The following works in all dialects of SQL:
select t.count/(select max(t.count) from t)
from table t
group by t.count;
Note that some versions of SQL do integer division, so the result will be either 0 or 1. You can fix this by multiplying by 1.0 or casting to a float.
Most versions of SQL also support:
select t.count/(max(t.count) over ())
from table t
group by t.count;
The same caveat applies about integer division.
You might want to try using a subquery to derive the max value (including both in the same query might not work the way that you are expecting, since you are grouping on the same column that you are aggregating)
Select t.count / (select max(sub.count) from table sub)
from table t
group by t.count
Related
Can you filter a SQL table based on an aggregated value, but still show column values that weren't in the aggregate statement?
My table has only 3 columns: "Composer_Tune", "_Year", and "_Rank".
I want to use SQL to find which "Composer_Tune" values are repeated in each annual list, as well as which ranks the duplicated items had.
Since I am grouping by "Composer_Tune" & "Year", I can't list "_Rank" with my current code.
The image shows the results of my original "find the duplicates" query vs what I want:
Current vs Desired Results
I tried applying the concepts in this Aggregate Subquery StackOverflow post but am still getting "_Rank is invalid in the select list because it is not contained in either an aggregate function or the GROUP BY clause" from this code:
WITH DUPE_DB AS (SELECT * FROM DB.dbo.[NAME] GROUP BY Composer_Tune, _Year HAVING COUNT(*)>1)
SELECT Composer_Tune, _Year, _Rank
FROM DUPE_DB
You need to explicitly declare the columns used in the Group By expression in the select columns.
You can use the following documentation if you are using transact sql for the proper use of Group By.
Simply join the aggregated resultset to original unit level table:
WITH DUPE_DB AS (
SELECT Composer_Tune, _Year
FROM DB.dbo.[NAME]
GROUP BY Composer_Tune, _Year
HAVING COUNT(*) > 1
)
SELECT n.Composer_Tune, n._Year, n._Rank
FROM DB.dbo.[NAME] n
INNER JOIN DUPE_DB
ON n.Compuser_Tune = DUPE_DB.Composer_Tune
AND n._Year = DUPE_DB._Year
ORDER n.Composer_Tune, n._Year
I want to list out the product which has highest sales amount on date wise.
note: highest sales amount in the sense max(sum(sales_amnt)...
by using if or case In the procedure in sap hana SQL....
I did this by using with the clause :
/--------------------------CORRECT ONE ----------------------------------------------/
WITH ranked AS
(
SELECT Dense_RAnk() OVER (ORDER BY SUM("SALES_AMNT"), "SALES_DATE", "PROD_NAME") as rank,
SUM("SALES_AMNT") AS Amount, "PROD_NAME",count(*), "SALES_DATE" FROM "KABIL"."DATE"
GROUP BY "SALES_DATE", "PROD_NAME"
)
SELECT "SALES_DATE", "PROD_NAME",Amount
FROM ranked
WHERE rank IN ( select MAX(rank) from ranked group by "SALES_DATE")
ORDER BY "SALES_DATE" DESC;
this is my table
You can not use IF along with SELECT statement. Note that, you can achieve most of boolean logics with CASE statement syntax
In select, you are applying it over a column and your logic will be executed as many as times the count of result set rows. Hence , righting an imperative logic is not well appreciated. Still, if you want to do the same, create a calculation view and use intermediate calculated columns to achieve what you are expecting .
try this... i got an answer ...
select "SALES_DATE","PROD_NAME",sum("SALES_AMNT")
from "KABIL"."DATE"
group by "SALES_DATE","PROD_NAME"
having (SUM("SALES_AMNT"),"SALES_DATE") IN (select
MAX(SUM_SALES),"SALES_DATE"
from (select SUM("SALES_AMNT")
as
SUM_SALES,"SALES_DATE","PROD_NAME"
from "KABIL"."DATE"
group by "SALES_DATE","PROD_NAME"
)
group by "SALES_DATE");
How can I use a Distinct or Group by statement on 1 field with a SELECT of All or at least several ones?
Example: Using SQL SERVER!
SELECT id_product,
description_fr,
DiffMAtrice,
id_mark,
id_type,
NbDiffMatrice,
nom_fr,
nouveaute
From C_Product_Tempo
And I want Distinct or Group By nom_fr
JUST GOT THE ANSWER:
select id_product, description_fr, DiffMAtrice, id_mark, id_type, NbDiffMatrice, nom_fr, nouveaute
from (
SELECT rn = row_number() over (partition by [nom_fr] order by id_mark)
, id_product, description_fr, DiffMAtrice, id_mark, id_type, NbDiffMatrice, nom_fr, nouveaute
From C_Product_Tempo
) d
where rn = 1
And this works prfectly!
If I'm understanding you correctly, you just want the first row per nom_fr. If so, you can simply use a subquery to get the lowest id_product per nom_fr, and just get the corresponding rows;
SELECT * FROM C_Product_Tempo WHERE id_product IN (
SELECT MIN(id_product) FROM C_Product_Tempo GROUP BY nom_fr
);
An SQLfiddle to test with.
You need to decide what to do with the other fields. For example, for numeric fields, do you want a sum? Average? Max? Min? For non-numeric fields to you want the values from a particular record if there are more than one with the same nom_fr?
Some SQL Systems allow you to get a "random" record when you do a GROUP BY, but SQL Server will not - you must define the proper aggregation for columns that are not in the GROUP BY.
GROUP BY is used to group in conjunction with an aggregate function (see http://www.w3schools.com/sql/sql_groupby.asp), so it's no use grouping without counting, summing up etc. DISTINCT eleminates duplicates but how that matches with the other columns you want to extract, I can't imagine, because some rows will be removed from the result.
I want to find the average amount of a field where it meets a criterion. It is embedded in a big table but I would like this average field in there instead of doing it in a separate table.
This is what I have so far:
Select....
Avg( (currbal) where (select * from table
where ament2 in ('r1','r2'))
From table
If you want to AVG only a subset of a query use case when ... then to replace value in non-matching rows with null as nulls are ignored by avg().
Select id,
sum(something) SomethingSummed,
avg(case when ament2 in ('r1','r2') then currbal end) CurrbalAveragedForR1R2
From [table]
group by id
You can put all the other sums which you want to be embedded into the AVG statement, inside the table reference inside the FROM clause. Something like:
SELECT AVG(currbal)
FROM
(
SELECT * -- other sums
FROM table
WHERE ament2 IN ('r1','r2')
) t
You can write a full sub-select into the select list:
SELECT ...,
(SELECT AVG(Currbal) FROM Table WHERE ament2 IN ('r1', 'r2')) AS avg_currbal,
...
FROM ...
Whether that will do exactly what you want depends on a number of things. You might need to make that into a correlated subquery; assuming 'ament2' is in Table, it is not a correlated sub-query at the moment.
I need to get the ID based from what ever the max amount is. Below is giving me an error
select ID from Prog
where Amount = MAX(Amount)
An aggregate may not appear in the WHERE clause unless it is in a subquery contained in a HAVING clause or a select list, and the column being aggregated is an outer reference.
The end result is that I need to get the just the ID as I need to pass it something else that is expecting it.
You need to order by Amount and select 1 record instead...
SELECT ID
FROM Prog
ORDER BY Amount DESC
LIMIT 1;
This takes all the rows in Prog, orders them in descending order by Amount (in other words, the first sorted row has the highest Amount), then limits the query to select only one row (the one with the highest Amount).
Also, subqueries are bad for performance. This code runs on a table with 200k records in half the time as the subquery versions.
Just pass a subquery with the max value to the where clause :
select ID from Prog
where Amount = (SELECT MAX(Amount) from Prog)
If you're using SQL Server that should do it :
SELECT TOP 1 ID
FROM Prog
ORDER BY Amount DESC
This should be something like:
select P.ID from Prog P
where P.Amount = (select max(Amount) from Prog)
EDIT:
If you really want only 1 row, you should do:
select max(P.ID) from Prog P
where P.Amount = (select max(Amount) from Prog);
However, if you have multiple rows that would match amount and you only want 1 row, you should have some kind of logic behind how you pick your one row. Not just relying on this max trick, or limit 1 type logic.
Also, I don't write limit 1, because this is not ANSI sql -- it works in mysql but OP doesn't say what he wants. Every db is different -- see here: Is there an ANSI SQL alternative to the MYSQL LIMIT keyword? Don't get used to one db's extensions unless you only want to work in 1 db for the rest of your life.
select min(ID) from Prog
where Amount in
(
select max(amount)
from prog
)
The min statement ensures that you get only one result.