Two domain name join to one web site .
Eg , Domain A and B link with Web site C.
At contact.php page ,
When user view with domain A,
I want to hide some content in contact.html.
Eg, images, word etc...
But with Domain B , he can see all the contact.php page .
Working Demo
this demo will log current domain name of site in console
var current_domain = document.location.hostname;
console.log(current_domain);
if (current_domain == "example.com") {
//code for hiding stuff goes here
} else if (current_domain == "example21.com") {
//code for that page here
}
Related
I'm new on prestashop, I have a separated php page in the same host of the prestashop installation, how can I access the logged prestashop user from this page?
thanks!
As N.Wouda told you, you have to use the context, by exemple to get the email of current user logged :
<?php
include(dirname(__FILE__) . '/config/config.inc.php');
$c = Context::getContext();
$emailOfLoggedUser = $c->customer->email;
echo $emailOfLoggedUser;
?>
As pointed out by Melvita, you first need to include config.inc.php and use the Context object
What is stored by the Context?
These objects are always accessible through the context:
Language. Set with the customer or employee language.
Country. Default country.
Currency. Set with the customer currency or the shop's default currency.
Shop. Current shop.
Cookie. Cookie instance.
Link. Link instance.
Smarty. Smarty instance.
These objects are only accessible for the customer Context:
Customer. Existing customer retrieved from the cookie or default customer.
Cart. Current cart.
Controller. Current controller instance.
These objects are only accessible for the administrator Context: Employee. Current employee.
<?php
include(dirname(__FILE__) . '/config/config.inc.php');
$context = Context::GetContext(); //call getContext() from context class
$customer = $context->customer; //get logged customer info
$customerName = $customer->firstname; //get user first name
$customerLastName = $customer->lastname; //get user last name
//to see all information that the context object can give you on your customer, just so a var_dump on $customer
?>
Source : http://doc.prestashop.com/display/PS16/Using+the+Context+Object#UsingtheContextObject-WhatisstoredbytheContext?
I am using quick order (opc) mode in my shop. The problem is that there are visible delivery options before customer create account or save address. I would like to hide this section, as it is done with payment.
Customers see low shipping rates and finish an order , then prices change and are angry. I would like show delivery options after cutromer register acc or save delivery address.
You can add this script inside $(document).ready(function(){ in file /themes/[your_theme]/js/order-opc.js:
$(document).ready(function() {
if($('.address_address1').length == 0) {
$('#opc_delivery_methods').hide();
}
else {
$('#opc_delivery_methods').show();
}
[...]
I am trying to generate routes from one template "tuning.blade.php"
I have a DB with 250 rows I would like to dynamically create 250 routes with one route or one controller.
I want to be able to use these URLs
laravel.dev/tuning/(field from DB row 1)
laravel.dev/tuning/(field from DB row 2 and so on)
I want to put the DB requests in tuning.blade.php so that this template can display all 250 rows using 250 different URLS
I have tried to use the first example from Laravel Docs
class UserController extends BaseController {
/**
* Show the profile for the given user.
*/
public function showProfile($id)
{
$user = User::find($id);
return View::make('user.profile', array('user' => $user));
}
}
Route::get('user/{id}', 'UserController#showProfile');
I also got some interesting search results from http://forumsarchive.laravel.io/viewtopic.php?id=9010
But alsas I always end up with a notfound exception
But I am unsure what to put in my tuning template to display anything at all. my Tuning template reside in app/views/home/tuning.blade.php
Currently I have got the error "Symfony \ Component \ HttpKernel \ Exception \ NotFoundHttpException"
Can anyone put me in the right direction of where I can find a resource to help me understand?
You said you want to be able to use these URLs:
laravel.dev/tuning/(field from DB row 1)
laravel.dev/tuning/(field from DB row 2 and so on)
You can do this by declaring a route like this:
Route::any('/tuning/{field}', 'TuningController#someMethod'); you may get/post
You shouldn't run sql queries from your view and if you want to really declare some dynamic routes for each fields from your database then you may do id right from your routes.php file, for example, assume that you have a table named tunings and that table contains some fields including id, name and some others. Now, to declare routes individually for each routes dynamically using the tuning field of table tunings you may create a method in your TuningController, something like this:
class TuningController extends baseController {
// other methods...
public function registerTuningRoutes()
{
$tunings = Tuning::all(); // Assume that you have a model Tuning
// Or you may use this instead
$tunings = DB::table('tuning')->get();
// Now loop all tunings and declare routes
foreach($tunings as $tuning) {
$url = '/tuning/' . $tuning->name;
$route_name = 'tuning.' . $tuning->name;
Route::any($url, $route_name); // You may use get/post
}
}
public function TuningMethod($tuning = null)
{
// $tuning will contain the current tuning name, check
dd($tuning);
}
}
Now in your routes.php file use something like this:
Registers route for each tuning name in database
App::make('TuningController')->registerTuningRoutes();
From your terminal/command prompt check the routes by running following command:
php artisan routes
But, I think, you don't need to do this, only one route is enough as I mentioned earlier in my answer.
I have written one extension for making service order.
The issue I am facing here is,
There are FE users belong to three FE user groups namely "client", "Admin" and "Employee".
Here the client can make order and he should be able to see only his orders.
And the admin can see all orders done by different clients.
And the employee should be able to see only some clients orders.
Currently I made a order table with N:1 relation with FE user table. So every order should relate with any one client.
So in controller, I am checking the login user and using custom query in repository, I am accessing order related to loggedin client (FE user)
In file OrdersController.php
public function listAction() {
$orders = $this->ordersRepository->orderForLoginUsr();
$this->view->assign('orders', $orders);
}
In file OrdersRepository.php
public function orderForLoginUsr(){
$loggedInUserId = $GLOBALS ['TSFE']->fe_user->user['uid'];
$query = $this->createQuery();
$query->matching(
$query->equals('user', $loggedInUserId)
);
$query->setOrderings(array('crdate' => \TYPO3\CMS\Extbase\Persistence\QueryInterface::ORDER_DESCENDING));
return $query->execute();
}
But here my question is how to make admin user able to see all the orders done by all clients?
I have to write different template and action that calling function findAll() ?
$orders = $this->ordersRepository->findAll();
And how to set for usergroup Employee ?
Thanks in Advance
I think that the easiest way is to actually implement 3 actions with 3 different plugins, something like: listClientAction, listAdminAction and listEmployeeAction
In each of those action, you implement a method in your repository that fetch the right list of order with the good ordering:
orderForLoginClient(), orderForLoginEmployee(), orderForLoginAdmin()
What does the trick actually is that there will be 3 plugins on your page, one for each action. In each instance of your plugin, you set the access for the right be_group.
Don't forget to add the actions and plugin in the localconf and ext_table files.
I hope it will help!
Olivier
If your view is almost the same for client, admin, employee you should simply add a method like getOrderWithPermissionsForUser($currentUser);
In the method itself you should check for the usergroup and call different queries on your Repo.
If your view is different from usergroup to usergroup, you should use different templates with partials for the same parts.
If the data of the views is the same, just change the template for each usergroup in the action. If not use different actions.
Here is a helper method for easily changing your templatefile.
/**
* This method can change the used template file in an action method.
*
* #param string $templateName Something like "List" or "Foldername/Actionname".
* #param string $templateExtension Default is "html", but for other output types this may be changed as well.
* #param string $controllerName Optionally uses another subfolder of the Templates/ directory
* By default, the current controller name is used. Example value: "JobOffer"
* #param \TYPO3\CMS\Fluid\View\AbstractTemplateView $viewObject The view to set this template to. Default is $this->view
*/
protected function changeTemplateFile($templateName, $templateExtension = 'html', $controllerName = null, AbstractTemplateView $viewObject = null)
{
if (is_null($viewObject)) {
$viewObject = $this->view;
}
if (is_null($controllerName)) {
$controllerName = $this->getControllerContext()->getRequest()->getControllerName();
}
$templatePathAndFilename = $this->getTemplateRootpathForView($controllerName . '/' . $templateName . '.' . $templateExtension);
$viewObject->setTemplatePathAndFilename($templatePathAndFilename);
}
I'm using the following code to get the members of a group on my domain:
Dim de As New DirectoryEntry("LDAP://" & GroupDN)
For Each user As String In CType(de.Properties("member"), IEnumerable)
GroupCollection.Add(Username, Username)
Next
My problem is that when GroupDN (the distinguishedname of the group) is "CN=Domain Users,CN=Users,DC=Mydomain,DC=local", the For...Each loop doesn't execute, and when I check the Properties statement manually, it's got a count of zero. This seems to work for every other group in my domain, but the "Domain Users" group should contain everybody, and it appears to contain nobody.
I've checked, and the group lists everybody correctly in my Windows AD tools. Is there something obvious that I'm missing here? On a side note, is there a better way to get all the members of a group?
Unless you change the primary group id of a user, the user is not stored in the member attribute of the Domain Users group, rather it uses the fact that the primary group id is set to the Domain Users RID to determine membership in Domain Users. The normal case is that the Domain Users member attribute is empty; it would require that you make some changes to the default Active Directory implementation for this to not be the case.
The Domain Users group uses a
"computed" mechanism based on the
"primary group ID" of the user to
determine membership and does not
typically store members as
multi-valued linked attributes. If the
primary group of the user is changed,
their membership in the Domain Users
group is written to the linked
attribute for the group and is no
longer calculated. This was true for
Windows 2000 and has not changed for
Windows Server 2003.
Reference
The accepted answer is absolutely correct. By default every (user) object has 513 set in the property primarygroupid, which is the fixed "tail" of the Domain Users sid. But: this can be changed and every other group can be configured there, so we can't rely on that.
Here is an example method how to get the group members anyway (regardless if the default is kept or changed). I call a method like this after any query for members of active directory groups. In this example I get an array of distinguished names as result. But all other properties are possible, just add them to dSearcher.PropertiesToLoad.Add(...) and modify the result.
I know, this is a question about VB, I hope its easy to port it.
using System.DirectoryServices;
using System.Security.Principal;
public static string[] GetMembersDnByPrimaryGroupId(string domainName, SecurityIdentifier sidOfGroupToGetMembersByPrimaryGroupId)
{
// In a single domain environement the domain name is probably not needed, but
// we expect a multy domain environement
if (string.IsNullOrWhiteSpace(domainName) || sidOfGroupToGetMembersByPrimaryGroupId == null)
{
throw new ArgumentNullException($"Neither domainName nor sid may be null / blank: DomainName: { domainName }; sid: { sidOfGroupToGetMembersByPrimaryGroupId }");
//<----------
}
List<string> membersDnResult = new List<string>();
// Get the last segment of the group sid, this is what is stored in the "primaryGroupId"
string groupSidTail = sidOfGroupToGetMembersByPrimaryGroupId.Value.Split('-').Last();
string path = $"LDAP://{ domainName }";
DirectoryEntry dEntry = new DirectoryEntry(path);
SearchResultCollection adSearchResult = null;
DirectorySearcher dSearcher = new DirectorySearcher(dEntry);
// For this example we need just the distinguished name but you can add
// here the property / properties you want
dSearcher.PropertiesToLoad.Add("distinguishedName");
// set the filter to primarygroupid
dSearcher.Filter = $"(&(primarygroupid={ groupSidTail }))";
// May die thousand deaths, therefore exception handling is needed.
// My exception handling is outside of this method, you may want
// to add it here
adSearchResult = dSearcher.FindAll();
// Get the domains sid and check if the domain part of the wanted sid
// fits the domain sid (necesarry in multy domain environments)
byte[] domainSidBytes = (byte[])dEntry.Properties["objectSid"].Value;
SecurityIdentifier domainSid = new SecurityIdentifier(domainSidBytes, 0);
if (sidOfGroupToGetMembersByPrimaryGroupId.AccountDomainSid != domainSid)
{
throw new ArgumentException($"Domain sid of the wanted group { sidOfGroupToGetMembersByPrimaryGroupId.AccountDomainSid } does not fit the sid { domainSid } of the searched through domain \"{ domainName }\"");
//<----------
}
// We found entries by the primarygroupid
if (adSearchResult.Count > 0)
{
foreach (SearchResult forMemberByPrimaryGroupId in adSearchResult)
{
// Every AD object has a distinguishedName, therefore we acess "[0]"
// wihtout any further checking
string dn = forMemberByPrimaryGroupId.Properties["distinguishedName"][0].ToString();
membersDnResult.Add(dn);
}
}
return membersDnResult.ToArray();
}