background reverses border-radius - background

Question

Why reverses a background property of a lower element the border-radius set on a higher element?
I have this HTML code:
<div class="wrapper">
<div class="content">
<div class="header">Title</div>
<div class="form"></div>
</div>
</div>
And this CSS code:
.wrapper {
background: none repeat scroll 0 0 #F8F8F8;
border-radius: 5px 5px 5px 5px;
height: 250px;
left: 100px;
overflow: visible;
position: absolute;
top: 10%;
width: 400px;
z-index: 10000
.header {
background: none repeat scroll 0 0 #222222;
border-top-left-radius: 5px;
box-shadow: 0 0 5px #444444;
position: relative;
z-index: 1;
}
}
The result is that there is no border-radius at the top, just at the bottom. If I remove the background property of the .headerclass the border-radius works on all four sides. What is the problem here?

Answer 1

You are nesting a selector inside other, which is wrong.
Try this.
.wrapper {
background: none repeat scroll 0 0 #F8F8F8;
border-radius: 5px 5px 5px 5px;
height: 250px;
left: 100px;
overflow: visible;
position: absolute;
top: 10%;
width: 400px;
z-index: 10000
}
.header {
background: none repeat scroll 0 0 #222222;
border-top-left-radius: 5px;
box-shadow: 0 0 5px #444444;
position: relative;
z-index: 1;
}
this must work,
and if you apply any background color on any of the child div then you have to explicitly set its corner radius..

Answer 2

Check this
http://jsfiddle.net/arunberti/LtRUu/
.wrapper {
background: none repeat scroll 0 0 red;
border-radius: 5px 5px 5px 5px;
height: 250px;
left: 100px;
overflow: visible;
position: absolute;
top: 10%;
width: 400px;
z-index: 10000;
color:red;
}
.header {
background: none repeat scroll 0 0 #222222;
border-top-left-radius: 5px;
box-shadow: 0 0 5px #444444;
position: relative;
z-index: 1;
}