I am using SQL Server 2008 Management Studio. I have a datetime column in my table.
When I select all contents of the table, the date column has data like 10/10/2013 12:00:00 AM.
I need a query to display all contents from the table with date column data as 10/10/2013.
SELECT CONVERT(VARCHAR(10), column, 101) -- u.s standard format mm/dd/yyyy
SELECT CONVERT(VARCHAR(10), column, 103) -- British/French standard format dd/mm/yyyy
Try this one (2008 and higher) -
SELECT CAST('10/10/2013 12:00:00 AM' AS DATE)
For 2005 -
SELECT CAST('10/10/2013 12:00:00 AM' AS VARCHAR(10))
Output -
10/10/2013
This will help you
cast(floor(cast(#dateVariable as float)) as datetime)
Using CONVERT function along with styles for DATETIME you can choose the way dates are displayed. 101 would give you mm/dd/yyyy, 103 = dd/mm/yyyy
SELECT CONVERT(NVARCHAR(20),your_datetime_col, 103) FROM your_table
SQLFiddle DEMO
You can use FORMAT() function:
SELECT FORMAT(<your_column>, 'MM/dd/YYYY') FROM <your_table>;
For your question i was created one table as
create table dateverify(date_v varchar(20));
Inserted single column value
declare #a varchar(20);
set #a='10/10/2013';
begin
insert into dateverify(date_v) values(#a);
end;
using below query,
SELECT CONVERT(VARCHAR(20), date_v , 103) AS [DD/MM/YYYY] from dateverify;
got an answer like you are asked..10/10/2013
Related
I am trying to convert/select the nvarchar datatype to date format (YYYY-MM-DD).
The table contains the date in DD/MM/YYYY format & also the null values.
Below SQL query is working fine but it has timestamp in the output
select Date4 = Convert(datetime, Last_Paid_Date, 103) FROM table
2021-01-30 00:00:00.000
My requirement is to have only the date in (YYYY-MM-DD) format
normally this should work
select Convert(date, Last_Paid_Date, 103) from tablename
But if you get conversion errors you can try this
SELECT convert(date, convert(datetime, Last_Paid_Date, 103)) FROM TableName
if Date cannot be used to convert from your format, the trick is to convert to a datetime first, and then convert that into a date.
Much much better would be to store the data in a column with type Date instead of varchar off course
I find this also some good reading
EDIT
if you keep getting conversion errors, then probably there are invalid dates in your varchar column. That is why you should never never never store dates/time in a varchar column.
To fix this, you could use this
SELECT try_Convert(date, Last_Paid_Date, 103) from tablename
this will put NULL in all columns that have an invalid date/time.
Drawback is that from all the rows that will have a value NULL, you cannot know if the original value was also NULL or an invalid date/time value.
Please try the below.
SELECT Date4 = CONVERT(DATE, Last_Paid_Date, 103) FROM TableName
OR
SELECT Date4 = CAST(GETDATE() AS DATE) FROM TableName
This will remove the Timestamp and give you only the Date values in the (YYYY-MM-DD) format.
You can go for simple conversion.
SELECT Convert(date, '20/01/2020', 103)
2020-01-20
You can go for conversion for the table as given below:
SELECT Convert(date, val, 103) as dateval FROM
(
values
('20/01/2020'),(null)
) as t(val)
dateval
2020-01-20
NULL
The issue with your query is that the column: "Last_Paid_Date" contains NULL String, which needs the conversion as they are characters.
You can try the below query:
SELECT convert(date, REPLACE(Last_Paid_Date,'NULL','01/01/2001'), 103)
, convert(datetime, REPLACE(Last_Paid_Date,'NULL','01/01/2001'), 103)
FROM table
The query will replace the NULL strings with a default value if any and then do the date/datetime conversions accordingly
You can chain two conversions : the first one converts the original dd/mm/yyyy (103) to a datetime value, and the second conversion turns that datetime into a yyyy-mm-dd (120) string.
select Date4 = convert(varchar(10), convert(date, Last_Paid_Date, 103), 120)
from table
I've got a string here which needs to be converted into date but the problem is that it could either be in 'DD/MM/YYYY' or 'YYYY-MM-DD' format.
I've already tried convert which only works for one of the two formats but not both:
declare #string nvarchar(255) = '2019-05-21'
declare #table table (date date)
insert into #table
select convert(date, #string, 111) as date
select * from #table
declare #string nvarchar(255) = '21/05/2019'
declare #table table (date date)
insert into #table
select convert(date, #string, 103) as date
select * from #table
Both of the above solutions result in an error is I use the other format.
Is there a way to get a string converted to date regardless of what format it is in?
Use try_convert():
insert into #table
select coalesce(try_convert(date, #string, 111),
try_convert(date, #string, 103)
) as date
try_convert() returns NULL if the conversion fails. In that case, the conversion will move on to the next pattern. With coalesce(), you can have as many different formats as you like.
You can use TRY_PARSE or PARSE to parse the date literal using a specific culture.
The second format YYYY-MM-DD is an unambiguous date format for the "new" date types like date and datetime2. It's not affected by the DATEFORMAT setting like datetime.
This means you only need to find one culture that can handle the first format. All of the following queries will return the same value :
select parse('21/05/2019' as date using 'en-GB')
-----
2019-05-21
select parse('2019-05-21' as date using 'en-GB')
-----
2019-05-21
select try_parse('21/05/2019' as date using 'en-GB')
-----
2019-05-21
select try_parse('2019-05-21' as date using 'en-GB')
-----
2019-05-21
If you are on SQL 2012 and above, you can use the FORMAT function.
The signature of this function is - FORMAT (value,format[,culture])
Example: SELECT FORMAT (getdate(), 'dd-MM-yyyy') as date and in your case SELECT FORMAT(CAST(<str_value> as DATE), 'yyyy-mm-dd')
I want to convert this time_stamp column (nvarchar50) into datetime column in SQL server. the value of time_stamp is "2018-02-16 13:30:27+09:00".
I don't know which datetime code should I use to convert it. Can you help?
This is what I tried:
select convert(datetime,time_stamp, 110) from table;
select convert(datetime,time_stamp, 120) from table;
It is failing because of the timezone embedded in the string. However, it will work if you remove the timezone using string function such as LEFT.
SELECT CONVERT(DATETIME, LEFT(time_stamp, 19), 110)
FROM tableName
Here's a Demo.
There is timezone offset in your sample date. If we want to ignore timezone offset then we can use below code -
declare #x nvarchar(50) = '2018-02-16 13:30:27+09:00'
select convert(datetime,convert(datetimeoffset, #x))
Declare #dt NVARCHAR(100) = '2018-02-16 13:30:27+09:00'
select CAST(SWITCHOFFSET(TODATETIMEOFFSET( LEFT(#dt , 19) ,RIGHT(#dt, 6)),0) AS DATETIME)
Returns:
2018-02-16 04:30:27.000
I am using the below SQL Query to get the data from a table for the last 7 days.
SELECT *
FROM emp
WHERE date >= (SELECT CONVERT (VARCHAR(10), Getdate() - 6, 101))
AND date <= (SELECT CONVERT (VARCHAR(10), Getdate(), 101))
ORDER BY date
The data in the table is also holding the last year data.
Problem is I am getting the output with Date column as
10/11/2013
10/12/2012
10/12/2013
10/13/2012
10/13/2013
10/14/2012
10/14/2013
10/15/2012
10/15/2013
10/16/2012
10/16/2013
10/17/2012
10/17/2013
I don't want the output of 2012 year. Please suggest on how to change the query to get the data for the last 7 days of this year.
Instead of converting a date to a varchar and comparing a varchar against a varchar. Convert the varchar to a datetime and then compare that way.
SELECT
*
FROM
emp
WHERE
convert(datetime, date, 101) BETWEEN (Getdate() - 6) AND Getdate()
ORDER BY
date
Why convert to varchar when processing dates? Try this instead:
DECLARE #Now DATETIME = GETDATE();
DECLARE #7DaysAgo DATETIME = DATEADD(day,-7,#Now);
SELECT *
FROM emp
WHERE date BETWEEN #7DaysAgo AND #Now
ORDER BY date
Use this, simply.
Select columnname
from tablename
WHERE datecolumn> dateadd(day,-7,GETDATE())
How to get time part from SQL Server 2005 datetime in HH:mm tt format
E.g.
11:25 AM
14:36 PM
One way is:
SELECT LTRIM(RIGHT(CONVERT(VARCHAR(20), GETDATE(), 100), 7))
If you have a look at Books Online here, format 100 is the one that has the time element in the format you want it in, it's just a case of stripping off the date from the front.
You'll need two converts, one to get the HH:mm time, and one to get AM/PM. For example:
declare #date datetime
set #date = '20:01'
SELECT CONVERT(VARCHAR(5), #date, 108) + ' ' +
SUBSTRING(CONVERT(VARCHAR(19), #date, 100),18,2)
This prints:
20:01 PM
In a select query, replace #date with your column's name.
SQL Server 2008
SELECT
CONVERT(TIME,GETDATE()) AS HourMinuteSecond,
CONVERT(DATE,GETDATE(),101) AS DateOnly
GO
Result
HourMinuteSecond: 13:06:56.5770000
DateOnly: 2012-07-26
SQL Server 2000/2005
SELECT
CONVERT(VARCHAR(8),GETDATE(),108) AS HourMinuteSecond,
CONVERT(VARCHAR(8),GETDATE(),101) AS DateOnly
GO
http://blog.sqlauthority.com/2009/08/06/sql-server-get-time-in-hourminute-format-from-a-datetime-get-date-part-only-from-datetime/
SQL Server 2008
SELECT
CONVERT(TIME,GETDATE()) AS HourMinuteSecond,
CONVERT(DATE,GETDATE(),101) AS DateOnly
GO
Result:
HourMinuteSecond: 13:06:56.5770000
DateOnly: 2012-07-26
SQL Server 2000/2005
SELECT
CONVERT(VARCHAR(8),GETDATE(),108) AS HourMinuteSecond,
CONVERT(VARCHAR(8),GETDATE(),101) AS DateOnly
GO
select substring(CONVERT(VARCHAR, getdate(), 114),1,5)
resault : 22:05
You need to use CONVERT function:
CONVERT(VARCHAR, yourdatetimefiled, 114) AS [HH:MI(12H)]
select cast(getdate() as time)) [time],
This gives you an actual datetime and not varchar
CAST(LEFT(YOURDATETIME,12) AS SMALLDATETIME) AS YOURNEWDATE
select right(convert(char(20),getdate(),0),7)
No check though
For SQL Server 2012 and above use this:
SELECT Format(GetDate(), 'hh:mm tt')