I have a table
ID NAME
--------
1 AAA
2 BBB
2 AAA
2 CCC
1 DDD
2 DDD
I have to display records which are linked with both ID 1 and 2
NAME
----
AAA
DDD
I am using below query -
Select Name from table1 where ID IN (1,2);
But it is displaying me -
NAME
-----
AAA
BBB
CCC
DDD
How do I change my query to solve this problem?
SELECT DISTINCT NAME
FROM tabel1 t1
join table1 t2
on t1.id = 1 and t2.id = 2 and t1.name = t2.name
or if there can be many matches
SELECT DISTINCT NAME
FROM tabel1 t1
WHERE EXISTS (SELECT 1 FROM table1 t2 WHERE t1.name = t2.name and t2.id = 2)
and t1.id = 1
or
SELECT NAME FROM tabel1 WHERE id = 1
INTERSECT
SELECT NAME FROM tabel1 WHERE id = 2
You need to group by the name, then count the distinct IDs that you wish to filter by.
select name
from table
where id in (1,2)
group by name
having count (distinct ID) = 2
Select Name
from table1
where ID IN (1,2)
and Name in ( select Name
from table1
where ID IN (1,2)
group by Name
having count(id) =2
) ;
Select Name from TableName
where id in (1,2)
group by Name having Count(Distinct Id)>1
select name
from table t
where id = 1 and exists
(select 1 from table where name = t.name and id = 2)
Related
I have two tables that look like the following:
Table 1 (IDs):
ID
1
2
3
4
5
Table 2 (Categories):
ID CAT
1 A
1 B
2 A
3 A
4 B
5 A
5 B
5 C
What I would like to do is join table 2 to table 1 and only keep instances where there is 1) Only one match 2) That match is CAT = A
So my final table would look like:
ID CAT
2 A
3 A
One method is aggregation and having:
select id, max(cat)
from t
group by id
having count(*) = 1 and
max(cat) = 'A';
You can use a subquery with not exists:
select t1.id, t2.cat
from table1 t1
join table2 t2 on t1.id = t2.id
where t2.cat = 'A' and not exists (select 1 from table2 t3 where t3.id = t1.id and t3.cat != 'A');
Output:
id
cat
2
A
3
A
How can I delete rows based on just two column conditions.
Example
Table 1
id name phone
1 aa 123
1 aa 345
1 bb 123
2 aa 456
1 NULL 123
1 123
My Expected output
id name phone
1 bb 123
2 aa 456
My condition to delete: if id and name is same, delete the rows
If one of the value in a condition is null or blank it should also delete the row as given in the input.
Delete from table1 t where exists (
Select * from
(Select id, name from table1 group by id, name having count(*) > 1) t2 where t.id = t2.id and t.name = t2.name)
This should do what you want. You can do the select first for testing purposes, then remove the Select and uncomment out the delete.
-- This joins on the table the set of data that has more then 1 row with duplicate IDs, and names. Then you can delete from here.
--DELETE t1
SELECT *
FROM Table1 T1
INNER JOIN (
-- this gets all the records that have more then 1 ID and Name that are the same.
SELECT ID, name
FROM Table1
GROUP BY ID, name
HAVING COUNT(*) > 1
) ToDelete ON T1.ID = ToDelete.ID
AND T1.name = ToDelete.name
create table #tablea (
id int,
name varchar(3),
phone int
)
insert into #tablea (id, name, phone)
values
(1,'aa','123'),
(1,'aa','345'),
(1,'bb','123'),
(2,'aa','456')
select * from #tablea
delete a
from #tablea a
inner join (
select id, name
from #tablea
group by id, name
having COUNT(*) > 1
) b on a.id = b.id and a.name = b.name
select * from #tablea
drop table #tablea
Table1
ID SystemID Description
---------------------------
1 25 Test1
1 25 Test2
2 40 Test1
2 40 Test3
3 26 Test9
3 36 Test5
4 70 Test2
4 70 Test9
Table2
ID Department
------------------
1 Sales
2 Marketing
3 Accounting
4 Purchasing
I have these 2 tables, Table1 and Table2.
I need to select all the distinct ids from Table1 that have the same description as ID = 1 and SystemID = 25, and then select all the rows from Table2 from the query result.
Is there a better way to query for this, without using nested subqueries?
select *
from Table2
where ID in (select distinct(ID)
from Table1
where SystemID = 25
and Description in (select Description
from Table1
where ID = 1 and SystemID = 25))
Final output is
1 Sales
2 Marketing
4 Purchasing
Any help is appreciated. Thank you.
I think you want:
select t1.id, t2.department
from table1 t1 join
table2 t2
on t1.id = t2.id
where t1.description in (select tt1.description from table1 tt1 where tt1.id = 1 and tt1.systemid = 25);
This is standard SQL and should work in both SQL Server and Oracle.
You can also use a modification of an outer join to detect presence of a value.
SELECT DISTINCT t2.ID, t2.DEPARTMENT
FROM
table2 AS t2
INNER JOIN table1 AS t1a ON table2.ID = table1.ID
LEFT OUTER JOIN table1 AS t1b ON t1b.id = 1 AND t1b.systemID = 25 AND t1b.description = t1a.description
WHERE t1b.ID IS NOT NULL
AND t1a.systemID = 25
This will filter out all entries who don't have a description matching an entry with id 1 and systemID 25
I believe this should give you the same result. Instead of using an IN I used an EXISTS and then instead of a futher subquery you can then use a JOIN:
SELECT *
FROM Table2 T2
WHERE EXISTS (SELECT 1
FROM Table1 T1
JOIN Table1 T1t ON T1.[Description] = T1t.[Description]
WHERE T1.ID = T2.ID
AND T1t.ID = 1 AND T1t.SystemID = 25);
SELECT DISTINCT T2.* --Use a distinct for simplicity but a group by is better
FROM Table2 AS T2
INNER JOIN Table1 AS T1_Source ON T1_Source.SystemID = 25 AND T1_Source.ID = 1
/*^ Find table1 with System and ID
Expected Result
ID SystemID Description
1 25 Test1
1 25 Test2
Note Rows are duplicated use distinct or group by
*/
INNER JOIN Table1 AS T1_Target ON T1_Target.Description = T1_Source.Description
/*^ Find table1 with all the Description matching the result we found
Expected Result
ID SystemID Description
1 25 Test1
1 25 Test2
2 40 Test1
4 70 Test2
Note Rows are duplicated use distinct or group by
*/
I want to search between 2 tables but that field i want to search is foreign key in other table
my tables are like this:
table 1
ID TitleSR
1 888
2 999
table 2
ID TitleSR
1 11
2 22
3 33
4 44
table contain value
ID value
11 italy
22 swiss
888 lilium
999 mount
33 england
I think I understand you. Try this one:
Select *
From table3 as VCT Inner Join
(Select * From table1
Union
Select * From table2) as FGT
On VCT.ID = FGT.TitleSR
Where value = 'italy';
You can use either of these methods:
Returns only t1 fields
SELECT * FROM Table1 t1
WHERE t1.ID in (SELECT ID FROM Table2);
Returns ALL fields
SELECT * FROM Table1 t1
JOIN Table2 t2 on t1.ID = t2.ID;
If your 'values' exist in a separate table (tblValues), you can use any of these:
Returns tblValues fields
SELECT * FROM tblValues tval
WHERE tval.ID in (SELECT TitleSR FROM Table1);
returns ALL fields
SELECT *
FROM (tblValues tval
JOIN Table1 t1 on tval.ID = t1.TitleSR)
JOIN Table2 on tval.ID = Table2.TitleSR;
I have a query that groups easily. I need to get the groups that have exactly the same records to another table (relationship).
I'm using ANSI-SQL under SQL Server, but I accept an answer of any implementation.
For example:
Table1:
Id | Value
---+------
1 | 1
1 | 2
1 | 3
2 | 4
3 | 2
4 | 3
Table2:
Value | ...
------+------
1 | ...
2 | ...
3 | ...
In my example, the result is:
Id |
---+
1 |
How imagined that it could be the code:
SELECT Table1.Id
FROM Table1
GROUP BY Table1.Id
HAVING ...? -- The group that has exactly the same elements of Table2
Thanks in advance!
You can try the following:
select t1.Id
from Table2 t2
join Table1 t1 on t1.value = t2.value
group by t1.Id
having count(distinct t1.value) = (select count(*) from Table2)
SQLFiddle
To get the same sets use an inner join:
SELECT Table1.Id
FROM Table1
INNER JOIN table2 ON table1.id=table2.id
GROUP BY Table1.Id
HAVING ...? --
CREATE TABLE #T1 (ID INT , [Values] INT) INSERT INTO #T1 VALUES (1,1),(1,2),(1,3),(2,4),(2,5),(3,6)
CREATE TABLE #T2 ([Values] INT) INSERT INTO #T2 VALUES (1),(2),(3),(4)
SELECT * FROM #T1
SELECT * FROM #T2
SELECT A.ID
FROM
( SELECT ID , COUNT(DISTINCT [Values]) AS Count FROM #T1
GROUP BY ID
) A
JOIN
(
SELECT T1.ID, COUNT(DISTINCT T2.[Values]) Count
FROM #T1 T1
JOIN #t2 T2
ON T1.[Values] = T2.[Values]
GROUP BY T1.ID
) B
ON A.ID = B.ID AND A.Count = B.Count