I get the error message when I run the following query in MSSQL Server 2005.
Error Message is Incorrect syntax near ','. I think query is ok. But I don't know why I get error.
INSERT INTO PERSON (ID, EMP_NAME) VALUES ('E001', 'AAA'), ('E002', 'BBB');
SQL Server does not support?
If your DB is lower than SQL Server 2008
INSERT INTO PERSON (ID, EMP_NAME) VALUES ('E001', 'AAA');
INSERT INTO PERSON (ID, EMP_NAME) VALUES ('E002', 'BBB');
Try to use UNION ALL -
INSERT INTO Person (id, EMP_NAME)
SELECT id = 'E001', EMP_NAME = 'AAA'
UNION ALL
SELECT 'E002', 'BBB'
Try this:
INSERT INTO Person (id, EMP_NAME)
SELECT 'E001', 'AAA'
UNION ALL
SELECT 'E002', 'BBB'
Related
I've read here that the syntax looks like this:
INSERT
WHEN ([Condition]) THEN
INTO [TableName] ([ColumnName])
VALUES ([VALUES])
ELSE
INTO [TableName] ([ColumnName])
VALUES ([VALUES])
SELECT [ColumnName] FROM [TableName];
But I don't want to provide values from another table. I just want to type them, so I've got:
INSERT
WHEN EXISTS (SELECT 1 FROM FOO WHERE NAME = 'JOE')
THEN
INTO BAR (NAME, AGE)
VALUES ('JOE', 50)
and this produces exception: ORA-00928: missing SELECT keyword.
I want to perform an insert if given value is found in another table.
Using with select works. Your query wasn't working because there is a problem with values keyword when inserting conditionally.
INSERT
WHEN EXISTS (SELECT 1 FROM FOO WHERE NAME = 'JOE')
THEN
INTO BAR (NAME, AGE)
SELECT 'JOE', 50 FROM DUAL
So, I've found an indirect way here and solution for my question would be:
INSERT INTO BAR (NAME, AGE)
SELECT 'JOE', 50
FROM DUAL
WHERE EXISTS (SELECT 1 FROM FOO WHERE NAME = 'JOE')
but it doesn't explain why I have to use SELECT statement in INSERT WHEN
I already have a table built in oracle.
Im trying to insert some data like this:
INSERT INTO movies_actor('name','id')
VALUES ('Nuno','2'), ('Pedro','3'), ('Jose','1');
select * from movies_actor;
I always get this error
ORA-00928: missing SELECT keyword
What am I doing wrong?
I don't think you need the single quote around your field names.
You need to do:
INSERT INTO TableName(Column1, Column2)
VALUES('Nuno', '2');
In your example, it would be:
INSERT INTO movies_actor(name, id)
VALUES ('Nuno','2');
INSERT INTO movies_actor(name, id)
VALUES ('Pedro','3');
INSERT INTO movies_actor(name, id)
VALUES ('Jose','1');
select * from movies_actor;
Another way.
insert into table
(field1, field2)
select value1, value2
from dual
union
select value3, value4
from dual
etc
You cannot insert multiple records in one statement using VALUES. You can either use Tenzin's solution or use INSERT ALL :
INSERT ALL
INTO movies_actor(name, id) VALUES ('Nuno', '2')
INTO movies_actor(name, id) VALUES ('Pedro', '3')
INTO movies_actor(name, id) VALUES ('Jose', '1')
SELECT * FROM dual;
I know in sql server to
Insert into table ( id, name) values ('1', 'John'), ('2','Peter');
but in firebid 1.5 i don't know how to insert the values.
I tried with
Insert into table ( id, name)
select '1', 'John' from rdb$database
union all select '2', 'Peter' from rdb$database;
but does it not work
The documentation says:
UNION allowed in feeding SELECT
Changed in: 2.0
Description: A SELECT query used in an INSERT statement may now be a
UNION.
Since you're using version 1.5, it looks like you'll have to use multiple insert statements.
I have two database tables with some demo data like shown below
Create table demo(uuid int, addressname varchar(50));
insert into demo values(1, 'intersportprofi');
insert into demo values(2, 'intersportprofi');
insert into demo values(3, 'intersportprofi');
insert into demo values(4, 'intersportmarket');
insert into demo values(5, 'intersportmarket');
insert into demo values(6, 'intersportmarket');
create table demo_av(uuid int, testid int, name varchar(50), value varchar(50));
insert into demo_av values(1, 1, 'sport','football basketball cricket');
insert into demo_av values(2, 1, 'brand','reebok addidas nike');
insert into demo_av values(3, 2, 'sport','football basketball ');
insert into demo_av values(4, 2, 'brand','reebok addidas ');
I wrote the following query to get the results from those tables, but oracle returning empty result set.
SELECT d.addressname FROM demo d, demo_av dv
WHERE d.uuid = dv.testid AND d.addressname='intersportprofi'
AND REGEXP_LIKE( dv.value, 'reebok') AND REGEXP_LIKE( dv.value, 'cricket')
Why? where i am doing wrong ? Any help will be greatly appriciated
Change this:
AND REGEXP_LIKE( dv.value, 'reebok') AND REGEXP_LIKE( dv.value, 'cricket')
To this:
AND (REGEXP_LIKE( dv.value, 'reebok') OR REGEXP_LIKE( dv.value, 'cricket'))
Because:
You have no record in the "demo_av" table that matches with "reebok" AND "cricket". The operator you need is "OR" and the parantheses are necessary because of existing of the first condition.
UPDATE
Here is the capture screen of the results:
Cheers
Based on your comments, I think you want a query that will search over multiple rows with same testid. This can be done with joins or like this:
SELECT DISTINCT d.addressname
FROM demo AS d
WHERE d.addressname = 'intersportprofi'
AND EXISTS
( SELECT *
FROM demo_av AS dv
WHERE d.uuid = dv.testid
AND dv.value LIKE '%reebok%'
)
AND EXISTS
( SELECT *
FROM demo_av AS dv
WHERE d.uuid = dv.testid
AND dv.value LIKE '%cricket%'
) ;
In SQL Server 2005, I'm trying to figure out why I'm not able to insert multiple fields into a table. The following query, which inserts one record, works fine:
INSERT INTO [MyDB].[dbo].[MyTable]
([FieldID]
,[Description])
VALUES
(1000,N'test')
However, the following query, which specifies more than one value, fails:
INSERT INTO [MyDB].[dbo].[MyTable]
([FieldID]
,[Description])
VALUES
(1000,N'test'),(1001,N'test2')
I get this message:
Msg 102, Level 15, State 1, Line 5
Incorrect syntax near ','.
When I looked up the help for INSERT in SQL Sever Management Studio, one of their examples showed using the "Values" syntax that I used (with groups of values in parentheses and separated by commas). The help documentation I found in SQL Server Management Studio looks like it's for SQL Server 2008, so perhaps that's the reason that the insert doesn't work. Either way, I can't figure out why it won't work.
The syntax you are using is new to SQL Server 2008:
INSERT INTO [MyDB].[dbo].[MyTable]
([FieldID]
,[Description])
VALUES
(1000,N'test'),(1001,N'test2')
For SQL Server 2005, you will have to use multiple INSERT statements:
INSERT INTO [MyDB].[dbo].[MyTable]
([FieldID]
,[Description])
VALUES
(1000,N'test')
INSERT INTO [MyDB].[dbo].[MyTable]
([FieldID]
,[Description])
VALUES
(1001,N'test2')
One other option is to use UNION ALL:
INSERT INTO [MyDB].[dbo].[MyTable]
([FieldID]
,[Description])
SELECT 1000, N'test' UNION ALL
SELECT 1001, N'test2'
You can also use the following syntax:-
INSERT INTO MyTable (FirstCol, SecondCol)
SELECT 'First' ,1
UNION ALL
SELECT 'Second' ,2
UNION ALL
SELECT 'Third' ,3
UNION ALL
SELECT 'Fourth' ,4
UNION ALL
SELECT 'Fifth' ,5
GO
From here
In SQL Server 2008,2012,2014 you can insert multiple rows using a single SQL INSERT statement.
INSERT INTO TableName ( Column1, Column2 ) VALUES
( Value1, Value2 ), ( Value1, Value2 )
Another way
INSERT INTO TableName (Column1, Column2 )
SELECT Value1 ,Value2
UNION ALL
SELECT Value1 ,Value2
UNION ALL
SELECT Value1 ,Value2
UNION ALL
SELECT Value1 ,Value2
UNION ALL
SELECT Value1 ,Value2