I am looking for the access query to replace first occurrence of "." in a string.
Example:
A.xcvb.NS
.sdfg.FX
O/P:
A-xcvb.NS
-sdfg.FX
Let me know if this is possible in access query.
In Microsoft Access, the Replace function replaces a sequence of characters in a string with another set of characters (a number of times).
Syntax
The syntax for the Replace function is:
Replace ( string1, find, replacement, [start, [count, [compare]]] )
string1 is the string to replace a sequence of characters with another set of characters.
find is the string that will be searched for in string1.
replacement will replace find in string1.
start is optional. This is the position in string1 to begin the search. If this parameter is omitted, the Replace function will begin the search at position 1.
count is optional. This is the number of occurrences to replace. If this parameter is omitted, the Replace function will replace all occurrences of find with replacement.
Replace function
Use the built in VBA Replace function to replace all instances
UPDATE tbl
SET fld = Replace(fld,'.','')
To replace only the first instance you will need a custom function instead of the above Replace function
Public Function ReplaceFirstInstance(str As String, strFind As String, strReplace As String) As String
Dim pos As Long
pos = InStr(str, strFind)
If pos > 0 Then
Mid(str, pos, 1) = strReplace
End If
ReplaceFirstInstance = str
End Function
E Mett's solution didn't work for me...
Public Function ReplaceFirstInstance(str As String, strFind As String, strReplace As String) As String
Dim pos As Long
pos = InStr(str, strFind)
If pos > 0 Then
ReplaceFirstInstance = Left(str, pos - 1) & strReplace & Mid(str, pos + Len(strFind))
'Mid(str, pos, 1) = strReplace
Else
ReplaceFirstInstance = str
End If
End Function
Related
I have a string ABC(N9KGRTLMN9(0J)M3.
I want to return the character after GRTLM which is N. Thanks.
Look at the System.Text.RegularExpressions namespace, and create a RegEx object with this expression:
GRTLM(.)
Then you will be able to check the Matches for the expression to find your character. Depending on what you know about that string, you may be able to narrow things even further. For example:
GRTLM([A-Za-z])
or
GRTLM([A-Z])
If you don't want to use regular expressions (for any reason), here's an alternative:
Private Function ReturnCharAfter(Source As String, after As String) As Char
Dim i As Integer = Source.IndexOf(after)
If i < 0 Then Return Nothing
Return Source(i + after.Length)
End Function
usage:
Dim N As Char = ReturnCharAfter("ABC(N9KGRTLMN9(0J)M3.", "GRTLM")
You could use String.Split() to get the N
Dim input = "ABC(N9KGRTLMN9(0J)M3"
Dim s = "GRTLM"
Dim n = input.Split({s}, StringSplitOptions.RemoveEmptyEntries)(1)(0)
It splits the string into substrings using GRTLM as a delimiter, then returns the first character of the second array item.
Or to get the index of N
Dim i = input.Split({s}, StringSplitOptions.RemoveEmptyEntries)(0).Length + s.Length
It splits the string and returns the length of the first array item plus the length of the delimiter string.
But perhaps the simplest way to do it is using String.IndexOf()
Dim n = input(input.IndexOf(s) + s.Length)
Dim i = input.IndexOf(s) + s.Length
I created a simple function designed to remove a string of characters from another string and replace it with what ever string the user wants (or no string as a default)
Private Function RemoveString(scontainer As String, Optional rcontainer As String = "", Optional rstring As String = "") As String
Dim container As String = scontainer
Dim tcontainer As String
If InStr(container, rcontainer) <> 0 Then
Do While (InStr(container, rcontainer) <> 0)
tcontainer = Microsoft.VisualBasic.Left(container, InStr(container, rcontainer) - 1)
tcontainer = tcontainer & rstring & Microsoft.VisualBasic.Right(container, (Len(container) - (InStr(container, rcontainer) + 2)))
container = tcontainer
Loop
RemoveString = container 'return modded string
Else
RemoveString = scontainer 'return string as is
End If
End Function
The problem is:
While this is suppose to be a general use function, I really need it to be concerned with 2 different strings
%20
amp;
the function works perfectly for the %20 situation but it leaves the semi-colon behind for the amp; string. Any ideas why this might be?
Do I get you right ?
You want to replace a certain char sequence in your string with another char sequence or just delete it.
If thats the case you could use String.Replace(oldValue As String, newValue As String) As String
Dim startString as String = "%20 amp;"
Dim resultString as String = startString.Replace("%20 ",String.Empty)
resultString = resultString.Replace(";",String.Empty)
After these lines resultString would be "amp"
I'm simply wondering what symbol/character I can use to define any character in a string...
Basically I have a number of records with RR 2, RR#2, RR1, RR 1, etc. and I want to use a symbol that will define anything after the RR and replace it with nothing "". I know in SQL it's the "%" symbol, but not sure in VBA.
I am using the Replace function in ArcGIS field calculator.
I tried searching but cannot come up with the right question to find the answer I'm looking for.
Any ideas?
Since it's unclear if you want VBA or VB.Net,
Here's a VBA answer just use the ChopString function using the format shown in the Test sub:
Function ChopString(str As String, after As String, Optional caseInsensitive As Boolean = True) As String
Dim x As Long
If caseInsensitive Then
x = InStr(1, str, after, vbTextCompare)
Else
x = InStr(1, str, after, vbBinaryCompare)
End If
If x Then
str = Left(str, x + Len(after) - 1)
End If
ChopString = str
End Function
Sub Test()
Dim OriginalString As String
Dim choppedString As String
OriginalString = "1234RR this will be chopped"
choppedString = ChopString(OriginalString, "RR")
MsgBox choppedString
End Sub
Sadly the .net REPLACE() function doesn't support wildcard characters, you can use a function as described here but it's a bit long winded.
In an MS Access 2007 project report, I have the following (redacted) query:
SELECT SomeCol FROM SomeTable
The problem is, that SomeCol apparently contains some invisible characters. For example, I see one result returned as 123456 but SELECT LEN(SomeCol) returns 7. When I copy the result to Notepad++, it shows as ?123456.
The column is set to TEXT. I have no control over this data type, so I can't change it.
How can I modify my SELECT query to strip out anything non-numeric. I suspect RegEx is the way to go... alternatively, is there a CAST or CONVERT function?
You mentioned using a regular expression for this. It is true that Access' db engine doesn't support regular expressions directly. However, it seems you are willing to use a VBA user-defined function in your query ... and a UDF can use a regular expression approach. That approach should be simple, easy, and faster performing than iterating through each character of the input string and storing only those characters you want to keep in a new output string.
Public Function OnlyDigits(ByVal pInput As String) As String
Static objRegExp As Object
If objRegExp Is Nothing Then
Set objRegExp = CreateObject("VBScript.RegExp")
With objRegExp
.Global = True
.Pattern = "[^\d]"
End With
End If
OnlyDigits = objRegExp.Replace(pInput, vbNullString)
End Function
Here is an example of that function in the Immediate window with "x" characters as proxies for your invisible characters. (Any characters not included in the "digits" character class will be discarded.)
? OnlyDigits("x1x23x")
123
If that is the output you want, just use the function in your query.
SELECT OnlyDigits(SomeCol) FROM SomeTable;
There is no RegEx in Access, at least not in SQL. If you venture to VBA, you might as well use a custom StripNonNumeric VBA function in the SQL statement.
e.g. SELECT StripNonNumeric(SomeCol) as SomeCol from SomeTable
Function StripNonNumeric(str)
keep = "0123456789"
outstr = ""
For i = 1 to len(str)
strChar = mid(str,i,1)
If instr(keep,strChar) Then
outstr = outstr & strChar
End If
Next
StripNonNumeric = outstr
End Function
You can do it all in a query, combining this question with your previous question, you get:
SELECT IIf(IsNumeric([atext]),
IIf(Len([atext])<4,Format([atext],"000"),
Replace(Format(Val([atext]),"#,###"),",",".")),
IIf(Len(Mid([atext],2))<4,Format(Mid([atext],2),"000"),
Replace(Format(Val(Mid([atext],2)),"#,###"),",","."))) AS FmtNumber
FROM Table AS t;
Public Function fExtractNumeric(strInput) As String
' Returns the numeric characters within a string in
' sequence in which they are found within the string
Dim strResult As String, strCh As String
Dim intI As Integer
If Not IsNull(strInput) Then
For intI = 1 To Len(strInput)
strCh = Mid(strInput, intI, 1)
Select Case strCh
Case "0" To "9"
strResult = strResult & strCh
Case Else
End Select
Next intI
End If
fExtractNumeric = strResult
End Function
How do I find last but one character in a vbstring
for e.g. In the string V1245-12V0 I want to return V
Don't use substring to get just one character
Dim MyString As String = "V1245-12V0"
Dim MyChar As Char = MyString(MyString.Length - 2)
Sorry it's been a while since I did VB so this may not be perfect (and is probably a mixture of C# and VB) but you get the idea:
Dim s = "V1245-12V0"
Dim lastButOneLetter = String.Empty
If s.Length > 1 Then
'Can only get the last-but-one letter from a string that is minimum 2 characters
lastButOneLetter = s.Substring(s.Length - 2, 1)
Else
'do something if string is less than 2 characters
End If
EDIT: fixed to be compilable VB.NET code.
Dim secondToLastChar As Char
secondToLastChar = Microsoft.VisualBasic.Strings.GetChar(mystring, mystring.Length - 2)
http://msdn.microsoft.com/en-us/library/4dhfexk4(VS.80).aspx
Or just remember that any string is an array of chars;
secondToLastChar = mystring(mystring.Length - 2)
If you want to get the last alpha-character in a string you could use a LINQ query such as (C#):
var d = from c in myString.ToCharArray().Reverse()
where Char.IsLetter(c)
select c;
return d.First();
string.Substring(string.Length - 2, 1);
Was it difficult?
dim mychar as string
dim yourstring as string
yourstring="V1245-12V0"
mychar=yourstring.Substring(yourstring.Length - 2, 1)
Use the Substring on the string s which contains 'V1245-12V0'
s.Substring(s.Length - 2, 1);
Here's a VB solution:
Dim text = "V1245-12V0"
Dim v = Left(Right(text, 2), 1)
You do not need to check the length of text, except for your semantics as to what you want to happen for empty (and Nothing) and single character strings.
You can have your own functions like
Function Left(ByVal str as string, byval index as integer) As String
Left=str.Substring(0,index);
End Function
Function Right(ByVal str as string, byval index as integer) As String
Right=str.Substring(str.Length-index)
End Function
And use them to get what you need.