Access to NSUInteger property - objective-c

Question

I've some problem with accessing NSUInteger property in my code, which look like that:
MyController.h
#interface MyController : UIViewController
#property (retain, nonatomic) NSArray *updatesArray;
#property (nonatomic) NSUInteger madeUpdatesCounter;
#property (nonatomic) NSUInteger allUpdatesCounter;
#end
MyController.m
#implementation MyController
#synthesize updatesArray;
#synthesize madeUpdatesCounter;
#synthesize allUpdatesCounter;
- (void)viewDidLoad
{
....
madeUpdatesCounter = 0;
allUpdatesCounter = [updatesArray count];
....
// Register for progress notifications
[[NSNotificationCenter defaultCenter] addObserver:self
selector:#selector(makeProgressChange)
name:#"MadeOneUpdateNotification"
object:nil];
}
- (void)makeProgressChange
{
madeUpdatesCounter++;
NSLog(#"Update progress: %d/%d", madeUpdatesCounter, allUpdatesCounter);
}
#end
I'm prosessing my updates as NSInvocationOperation by adding to NSOperationQueue. In the end of the one update action I'm sending notification:
[[NSNotificationCenter defaultCenter] postNotificationName:#"MadeOneUpdateNotification" object:nil];
After executing above code, receiving notifocation is execute only once and in logs I see someting like this:
Update progress: 1/3
When I change line:
allUpdatesCounter = [updatesArray count];
to
allUpdatesCounter = 3;
then everything works ok, and I see in logs:
Update progress: 1/3
Update progress: 2/3
Update progress: 3/3
Variable updatedArray is initialized before view is loaded. Is done in this way:
MyController *doUpdatesVC = [self.storyboard instantiateViewControllerWithIdentifier:#"MyController"];
doUpdatesVC.updatesArray = updatesArray;
[self presentViewController:doUpdatesVC animated:YES completion:nil];
Do you have any advices or hints what I'm doing wrong in my code?

Answer 1

OK, I've found reason of my problems. The applications locked by accessing to the same variable by operations launched from queue. When I changed logic of my code, then everything start working correctly.