I'm using sql server 2008. How to query out a data which is the date is today and 7 days before today ?
Try this way:
select * from tab
where DateCol between DateAdd(DD,-7,GETDATE() ) and GETDATE()
Query in Parado's answer is correct, if you want to use MySql too instead GETDATE() you must use (because you've tagged this question with Sql server and Mysql):
select * from tab
where DateCol between adddate(now(),-7) and now()
Related
This question already has answers here:
how to get current datetime in SQL?
(9 answers)
Closed 7 years ago.
I want to find few data from SQL Server that only query by current date. The purpose is to view today transaction only
Here is my code
SELECT * FROM dbo.Student.studentProfile
WHERE TransactionDate = curdate()
RESULT
Curdate is not a recongined built-in function name
If you are looking for the current date:
WHERE TransactionDate = cast(getdate() as date)
Or if you prefer ANSI standards:
WHERE TransactionDate = cast(CURRENT_TIMESTAMP as date)
Different sql implementations (ie SQL Server, Mysql, postgresql etc) can have different methods supported. For SQL Server the method you want to use is GETDATE() instead of CURDATE()
The documentation for this method is here: https://msdn.microsoft.com/en-us/library/ms188383.aspx
Try this.
select * from dbo.Student.studentProfile
WHERE TransactionDate >= dateadd(day,datediff(day,1,GETDATE()),0)
AND TransactionDate < dateadd(day,datediff(day,0,GETDATE()),0)
What am trying to do is, I have table with Date field. Date field has entry in datetime format. Using that i have to display todays records after 5PM. Can anyone help me on this to get this query.
Thanks
After 5 Pm ?
Try this:
select *From Table where DATEPART(hh,yourdatefield)>=17 and and convert(date,yourdatefield,103)='2014-04-03'
this will the the records after 5pm .
Try this.
Select *
FROM tablename
WHERE datefield < '1/1/2014 17:00:00.000'
select * from table1
where
CONVERT(date,Datefield) = CONVERT(date,GETDATE()) and
CONVERT(time,Datefield) > convert(time,'17:00')
I'm writing a SQL query on a timesheet report. I need the report to return only the details for the week of the selected date.
E.g., if I pick 02/01/2012 (dd/MM/yyyy), then it should only return results between 02/01/2012 and 08/01/2012.
Thanks
SELECT
*
FROM
yourTable
WHERE
dateField >= #yourDate
AND dateField < #yourDate + 7
Some variations of SQL may have specific ways of adding 7 days to a datevalue. Such as...
- DateAdd(Day, 7, #date)
- DATE_ADD(#date, INTERVAL 7 DAYS)
- etc, etc
This option is both index friendly, and is resilient to database fields that have time parts as well as date parts.
You easiest is the equivalent of WEEK_OF_YEAR function in your SQL engine
But you can also use DATE_ADD
WHERE table.date BETWEEN target_date AND DATE_ADD(target_date,INTERVAL 7 DAY)
That depends on the database system you're using. MySQL has a function calles WEEK(), SQL Server can do something like this with the DATEPART() function:
MySQL:
SELECT
*
FROM table
WHERE WEEK(date_col) = WEEK('02/01/2012');
SQL SERVER:
SELECT
*
FROM table
WHERE DATEPART(WEEK, datecol) = DATEPART(WEEK,'02/01/2012');
SELECT * FROM table_name
WHERE date BETWEEN '1/02/2012' AND '1/08/2012';
you can replace the example date with your date and yourdate + 6.
Look here for example: http://www.roseindia.net/sql/sql-between-datetime.shtml
Suppose I have a date 2010-07-29. Now I would like to check the result of one day ahead. how to do that
For example,
SELECT *
from table
where date = date("2010-07-29")
How to do one day before without changing the string "2010-07-29"?
I searched and get some suggestion from web and I tried
SELECT *
from table
where date = (date("2010-07-29") - 1 Day)
but failed.
MySQL
SELECT *
FROM TABLE t
WHERE t.date BETWEEN DATE_SUB('2010-07-29', INTERVAL 1 DAY)
AND '2010-07-29'
Change DATE_SUB to DATE_ADD if you want to add a day (and reverse the BETWEEN parameters).
SQL Server
SELECT *
FROM TABLE t
WHERE t.date BETWEEN DATEADD(dd, -1, '2010-07-29')
AND '2010-07-29'
Oracle
SELECT *
FROM TABLE t
WHERE t.date BETWEEN TO_DATE('2010-07-29', 'YYYY-MM-DD') - 1
AND TO_DATE('2010-07-29', 'YYYY-MM-DD')
I used BETWEEN because the date column is likely DATETIME (on MySQL & SQL Server, vs DATE on Oracle), which includes the time portion so equals means the value has to equal exactly. These queries give you the span of a day.
If you're using Oracle, you can use the + and - operators to add a number of days to a date.
http://psoug.org/reference/date_func.html
Example:
SELECT SYSDATE + 1 FROM dual;
Will yield tomorrow's date.
If you're not using Oracle, please tell use what you ARE using so we can give better answers. This sort of thing depends on the database you are using. It will NOT be the same across different databases.
Depends of the DateTime Functions available on the RDBMS
For Mysql you can try:
mysql> SELECT DATE_ADD('1997-12-31',
-> INTERVAL 1 DAY);
mysql> SELECT DATE_SUB('1998-01-02', INTERVAL 31 DAY);
-> '1997-12-02'
If youre using MSSQL, you're looking for DateAdd() I'm a little fuzzy on the syntax, but its something like:
Select * //not really, call out your columns
From [table]
Where date = DateAdd(dd, -1, "2010-07-29",)
Edit: This syntax should be correct: it has been updated in response to a comment.
I may have the specific parameters in the wrong order, but that should get you there.
In PL SQL : select sysdate+1 from dual;
I need some help figuring out and SQL Statement.
I know what I want I just cant express it.
Im using php, so it doesnt need to be exclusivly SQL, its to act as a filter.
Pseudo code
$query="SELECT * FROM MyTable WHERE 'TIS' is not older than 2 days or empty = ''$ORDER"; }
TIS in the name of the column in my table were I store dates in this format 03-12-09 (d,m,y).
The $ORDER is for ordering the values based on values from other fields not dates.
Im looking at
SELECT *
FROM orders
WHERE day_of_order >
(SELECT DATEADD(day,-30, (SELECT MAX(day_of_order) FROM orders)) AS "-30 Days");
But i dont quite think im on the rigth track with this.
Thanks
Try the following:
SELECT *
FROM MyTable
WHERE COALESCE(TIS, SYSDATE) > SYSDATE - INTERVAL '2' DAY
$ORDER
I don't know what database you're using - the above uses Oracle's method of dealing with time intervals. If you're using SQL Server the following should be close:
SELECT *
FROM MyTable
WHERE COALESCE(TIS, GETDATE()) > DATEADD(Day, -2, GETDATE())
$ORDER
In MySQL try this:
SELECT *
FROM MyTable
WHERE COALESCE(TIS, NOW()) > DATE_SUB(NOW(), INTERVAL 2 DAYS)
$ORDER
I hope this helps.
So, I was pretty lost in all this.
How did it got solved:
First I understood that the Statement I was using was not supported by MySql thanks to eligthment from Bob Jarvis.
_ Second In a comment by vincebowdren wich "strongly" adviced me to change the data type on that field to Date wich indeed I had not, it was a string.
It was pretty Dumb for me to try using SQL operations for Dates on a field that had String values.
So I just RTFM: http://dev.mysql.com/doc/refman/5.1/en/date-and-time-functions.html
and:
mysql> SELECT something FROM tbl_name
-> WHERE DATE_SUB(CURDATE(),INTERVAL 30 DAY) <= date_col;
Then proceeded to change the field value to date.
and this is my perfectly working query:
$query="SELECT * FROM MyTable WHERE DATE_SUB(CURDATE(),INTERVAL 2 DAY) <= TIS OR TIS = 0000-00-00 $ORDER "; }
I would like to thank the posters for their aid.