SQL query resultset, I need SUM(quantity) COLUMN grouped by DAY - sql

Question

This is the Query I am using on the product table LEFT JOIN on the page table ON the productid column in page being the id in product.. pretty straightforward.
SELECT
COUNT(DISTINCT `p`.`id`) as `quantity`,
DATE_FORMAT(`p`.`created_time`,'%Y-%m-%d') AS `day`
FROM
`product` AS `p`
LEFT JOIN
`page` AS `pg` ON `p`.`id` = `pg`.`productid`
WHERE
`p`.`created_time` BETWEEN '2013-07-03 00:00:00' AND '2013-07-10 23:59:59'
AND
`p`.`group` = '101'
GROUP BY `day`, `p`.`id` HAVING COUNT(`pg`.`productid`)>=10
ORDER BY `p`.`created_time`
The two example tables concerned:
**product**
id created_time
32 2013-07-09
33 2013-07-09
**page**
id productid
1 33
2 33
.. ..
20 33
21 32
22 32
.. ..
54 32
Now my resultset looks like this:
quantity day
1 2013-07-09
1 2013-07-09
1 2013-07-10
But I would like the following output without UNION and without using temp tables:
quantity day
2 2013-07-09
1 2013-07-10
Two tables are now added to my code example on top. I need the number of product with ten or more page grouped by day

Answer 1

I think that is because you are leaving p.id in the group by clause. Try this:
SELECT COUNT(DISTINCT `p`.`id`) as `quantity`,
DATE_FORMAT(`p`.`created_time`,'%Y-%m-%d') AS `day`
FROM `product` AS `p` LEFT JOIN
`page` AS `pg`
ON `p`.`id` = `pg`.`productid`
WHERE `p`.`created_time` BETWEEN '2013-07-03 00:00:00' AND '2013-07-10 23:59:59'
AND `p`.`group` = '101'
GROUP BY `day`
HAVING COUNT(`pg`.`productid`)>=10
ORDER BY `p`.`created_time`

Answer 2

Don't GROUP BY the id value and also the ORDER BY can be on day too
Note that day is not available in the GROUP BY in standard SQL or when sql_mode is using "only_full_group_by". MySQL allows it as an extension but it is misleading
SELECT
COUNT(*) as `quantity`,
DATE_FORMAT(`p`.`created_time`,'%Y-%m-%d') AS `day`
FROM
`product` AS `p`
JOIN
`page` AS `pg` ON `p`.`id` = `pg`.`productid`
WHERE
`p`.`created_time` BETWEEN '2013-07-03 00:00:00' AND '2013-07-10 23:59:59'
AND
`p`.`group` = '101'
GROUP BY
`pg`.`productid`, DATE_FORMAT(`p`.`created_time`,'%Y-%m-%d') AS `day`
HAVING
COUNT(*) >= 10
ORDER BY
`day`;

Answer 3

I found the solution to my query:
SELECT
COUNT(`p`.`id`) as `quantity`,
DATE_FORMAT(`p`.`created_time`,'%Y-%m-%d') AS `day`
FROM
`product` AS `p`
INNER JOIN
(
SELECT
`productid` AS `id`,
count(id) AS pagesNR
FROM
`page`
GROUP BY
`productid` HAVING COUNT(`id`) >= 10
)
AS
`pg` USING (`id`)
WHERE
`p`.`created_time` BETWEEN '2013-07-03 00:00:00' AND '2013-07-10 23:59:59'
AND
`p`.`group` = '101'
GROUP BY
`day`
ORDER BY
`created_time`
Thanks to a friend of my co-worker Daniël Versteeg