UPDATE and REPLACE part of a string - sql

Question

I've got a table with two columns, ID and Value. I want to change a part of some strings in the second column.
Example of Table:
ID Value
---------------------------------
1 c:\temp\123\abc\111
2 c:\temp\123\abc\222
3 c:\temp\123\abc\333
4 c:\temp\123\abc\444
Now the 123\ in the Value string is not needed. I tried UPDATE and REPLACE:
UPDATE dbo.xxx
SET Value = REPLACE(Value, '%123%', '')
WHERE ID <= 4
When I execute the script SQL Server does not report an error, but it does not update anything either. Why is that?

Answer 1

You don't need wildcards in the REPLACE - it just finds the string you enter for the second argument, so the following should work:
UPDATE dbo.xxx
SET Value = REPLACE(Value, '123', '')
WHERE ID <=4
If the column to replace is type text or ntext you need to cast it to nvarchar
UPDATE dbo.xxx
SET Value = REPLACE(CAST(Value as nVarchar(4000)), '123', '')
WHERE ID <=4

Answer 2

Try to remove % chars as below
UPDATE dbo.xxx
SET Value = REPLACE(Value, '123', '')
WHERE ID <=4

Answer 3

To make the query run faster in big tables where not every line needs to be updated, you can also choose to only update rows that will be modified:
UPDATE dbo.xxx
SET Value = REPLACE(Value, '123', '')
WHERE ID <= 4
AND Value LIKE '%123%'

Answer 4

query:
UPDATE tablename
SET field_name = REPLACE(field_name , 'oldstring', 'newstring')
WHERE field_name LIKE ('oldstring%');

Answer 5

You have one table where you have date Code which is seven character something like
"32-1000"
Now you want to replace all
"32-"
With
"14-"
The SQL query you have to run is
Update Products Set Code = replace(Code, '32-', '14-') Where ...(Put your where statement in here)

Answer 6

For anyone want to replace your script.
update dbo.[TABLE_NAME] set COLUMN_NAME= replace(COLUMN_NAME, 'old_value', 'new_value') where COLUMN_NAME like %CONDITION%

Answer 7

CREATE TABLE tbl_PersonalDetail
(ID INT IDENTITY ,[Date] nvarchar(20), Name nvarchar(20), GenderID int);
INSERT INTO Tbl_PersonalDetail VALUES(N'18-4-2015', N'Monay', 2),
(N'31-3-2015', N'Monay', 2),
(N'28-12-2015', N'Monay', 2),
(N'19-4-2015', N'Monay', 2)
DECLARE #Date Nvarchar(200)
SET #Date = (SELECT [Date] FROM Tbl_PersonalDetail WHERE ID = 2)
Update Tbl_PersonalDetail SET [Date] = (REPLACE(#Date , '-','/')) WHERE ID = 2

Answer 8

you should use the below update query
UPDATE dbo.xxx SET Value=REPLACE(Value,'123\','') WHERE Id IN(1, 2, 3, 4)
UPDATE dbo.xxx SET Value=REPLACE(Value,'123\','') WHERE Id <= 4
Either of the above queries should work.

Answer 9

replace for persian word
UPDATE dbo.TblNews
SET keyWords = REPLACE(keyWords, '-', N'،')
help:
dbo.TblNews -- table name
keyWords -- fild name