good day everyone . I've been searching for a long time for the activity that our professor wants us to do .
for example my column name is tax, tax has these values:
TAX
-----
3681
4292
4895
1894
1127
the program should show numbers 3681 and 1127 . any response is much appreciated . btw our school is using MS SQL Server 2000 .
From my understanding of your question, you are looking for the rows with the lowest or highest odd number as the last character? If so, then this should work:
select t.tax
from yourtable t
join (
select min(right(tax,1)) minoddchar, max(right(tax,1)) maxoddchar
from yourtable
where tax % 2 = 1 --ensure odd result
) t2 on right(t.tax,1) in (t2.minoddchar, t2.maxoddchar)
SQL Fiddle Demo
SELECT MIN(tax), Max(tax)
FROM Table
WHERE tax %2 <> 0
Demo: SQL Fiddle
If you actually want first and last from your unordered list, it's a trickier proposition and results could be inconsistent, since without a value to ORDER BY you can't guarantee order. Would usually use ROW_NUMBER(), but not available in 2000, if that's what you're after there are options, the easiest would be to do:
SELECT Tax, IDENTITY(1,1) as TaxID
INTO Table2
FROM Table1
SELECT (SELECT TOP 1 Tax FROM Table2 WHERE Tax %2 <> 0 ORDER BY TaxID)
,(SELECT TOP 1 Tax FROM Table2 WHERE Tax %2 <> 0 ORDER BY TaxID DESC)
You can use this:
SELECT tax FROM Table ORDER BY tax.id ASC LIMIT 1
UNION
SELECT tax FROM Table ORDER BY tax.id DESC LIMIT 1
or this:
SELECT MIN(tax.id), tax FROM Table
UNION
SELECT MAX(tax.id), tax FROM Table
select tax from Table fetch first 1 row only;
select tax from table fetch last 1 row only;
Related
One table is a sample of users and their purchases.
Structure:
Email | NAME | TRAN_DATETIME (Varchar)
So we have customer email + FirstName&LastName + Date of transaction
and the second table that comes from second system contains all users, they sensitive data and when they got registered in our system.
Simplified Structure:
Email | InstertDate (varchar)
My task is to count minutes difference between the rows insterted from sale(first table)and the rows with users and their sensitive data.
The issue is that second table contain many rows and I want to find the nearest in time row that was inserted in 2nd table, because sometimes it may be a few minutes difeerence(delay or opposite of delay)and sometimes it can be a few days.
So for x email I have row in 1st table:
E_MAIL NAME TRAN_DATETIME
p****#****.eu xxx xxx 2021-10-04 00:03:09.0000000
But then I have 3 rows and the lastest is the one I want to count difference
Email InstertDate
p****#****.eu 2021-05-20 19:12:07
p****#****.eu 2021-05-20 19:18:48
p****#****.eu 2021-10-03 18:32:30 <--
I wrote that some query, but I have no idea how to match nearest row in the 2nd table
SELECT DISTINCT TOP (100)
,a.[E_MAIL]
,a.[NAME]
,a.[TRAN_DATETIME]
,CASE WHEN b.EMAIL IS NOT NULL THEN 'YES' ELSE 'NO' END AS 'EXISTS'
,(ABS(CONVERT(INT, CONVERT(Datetime,LEFT(a.[TRAN_DATETIME],10),120))) - CONVERT(INT, CONVERT(Datetime,LEFT(b.[INSERTDATE],10),120))) as 'DateAccuracy'
FROM [crm].[SalesSampleTable] a
left join [crm].[SensitiveTable] b on a.[E_MAIL]) = b.[EMAIL]
Totally untested: I'd need sample data and database the area of suspect is the casting of dates and the datemath.... since I dont' know what RDBMS and version this is.. consider the following "pseudo code".
We assign a row number to the absolute difference in seconds between the dates those with rowID of 1 win.
WTIH CTE AS (
SELECT A.*, B.* row_number() over (PARTITION BY A.e_mail
ORDER BY abs(datediff(second, cast(Tran_dateTime as Datetime), cast(InsterDate as DateTime)) desc) RN
FROM [crm].[SalesSampleTable] a
LEFT JOIN [crm].[SensitiveTable] b
on a.[E_MAIL] = b.[EMAIL])
SELECT * FROM CTE WHERE RN = 1
I'm looking to filter out rows in the database (PostgreSQL) if one of the values in the status column occurs. The idea is to sum the amount column if the unique reference only has a status equals to 1. The query should not SELECT the reference at all if it has also a status of 2 or any other status for that matter. status refers to the state of the transaction.
Current data table:
reference | amount | status
1 100 1
2 120 1
2 -120 2
3 200 1
3 -200 2
4 450 1
Result:
amount | status
550 1
I've simplified the data example but I think it gives a good idea of what I'm looking for.
I'm unsuccessful in selecting only references that only have status 1.
I've tried sub-queries, using the HAVING clause and other methods without success.
Thanks
Here's a way using not exists to sum all rows where the status is 1 and other rows with the same reference and a non 1 status do not exist.
select sum(amount) from mytable t1
where status = 1
and not exists (
select 1 from mytable t2
where t2.reference = t1.reference
and t2.status <> 1
)
SELECT SUM(amount)
FROM table
WHERE reference NOT IN (
SELECT reference
FROM table
WHERE status<>1
)
The subquery SELECTs all references that must be excluded, then the main query sums everything except them
select sum (amount) as amount
from (
select sum(amount) as amount
from t
group by reference
having not bool_or(status <> 1)
) s;
amount
--------
550
You could use windowed functions to count occurences of status different than 1 per each group:
SELECT SUM(amount) AS amount
FROM (SELECT *,COUNT(*) FILTER(WHERE status<>1) OVER(PARTITION BY reference) cnt
FROM tc) AS sub
WHERE cnt = 0;
Rextester Demo
I have three columns, all consisting of 1's and 0's. For each of these columns, how can I calculate the percentage of people (one person is one row/ id) who have a 1 in the first column and a 1 in the second or third column in oracle SQL?
For instance:
id marketing_campaign personal_campaign sales
1 1 0 0
2 1 1 0
1 0 1 1
4 0 0 1
So in this case, of all the people who were subjected to a marketing_campaign, 50 percent were subjected to a personal campaign as well, but zero percent is present in sales (no one bought anything).
Ultimately, I want to find out the order in which people get to the sales moment. Do they first go from marketing campaign to a personal campaign and then to sales, or do they buy anyway regardless of these channels.
This is a fictional example, so I realize that in this example there are many other ways to do this, but I hope anyone can help!
The outcome that I'm looking for is something like this:
percentage marketing_campaign/ personal campaign = 50 %
percentage marketing_campaign/sales = 0%
etc (for all the three column combinations)
Use count, sum and case expressions, together with basic arithmetic operators +,/,*
COUNT(*) gives a total count of people in the table
SUM(column) gives a sum of 1 in given column
case expressions make possible to implement more complex conditions
The common pattern is X / COUNT(*) * 100 which is used to calculate a percent of given value ( val / total * 100% )
An example:
SELECT
-- percentage of people that have 1 in marketing_campaign column
SUM( marketing_campaign ) / COUNT(*) * 100 As marketing_campaign_percent,
-- percentage of people that have 1 in sales column
SUM( sales ) / COUNT(*) * 100 As sales_percent,
-- complex condition:
-- percentage of people (one person is one row/ id) who have a 1
-- in the first column and a 1 in the second or third column
COUNT(
CASE WHEN marketing_campaign = 1
AND ( personal_campaign = 1 OR sales = 1 )
THEN 1 END
) / COUNT(*) * 100 As complex_condition_percent
FROM table;
You can get your percentages like this :
SELECT COUNT(*),
ROUND(100*(SUM(personal_campaign) / sum(count(*)) over ()),2) perc_personal_campaign,
ROUND(100*(SUM(sales) / sum(count(*)) over ()),2) perc_sales
FROM (
SELECT ID,
CASE
WHEN SUM(personal_campaign) > 0 THEN 1
ELSE 0
end AS personal_campaign,
CASE
WHEN SUM(sales) > 0 THEN 1
ELSE 0
end AS sales
FROM the_table
WHERE ID IN
(SELECT ID FROM the_table WHERE marketing_campaign = 1)
GROUP BY ID
)
I have a bit overcomplicated things because your data is still unclear to me. The subquery ensures that all duplicates are cleaned up and that you only have for each person a 1 or 0 in marketing_campaign and sales
About your second question :
Ultimately, I want to find out the order in which people get to the
sales moment. Do they first go from marketing campaign to a personal
campaign and then to sales, or do they buy anyway regardless of these
channels.
This is impossible to do in this state because you don't have in your table, either :
a unique row identifier that would keep the order in which the rows were inserted
a timestamp column that would tell when the rows were inserted.
Without this, the order of rows returned from your table will be unpredictable, or if you prefer, pure random.
I have a little problem.
My table is:
Bill Product ID Units Sold
----|-----------|------------
1 | 10 | 25
1 | 20 | 30
2 | 30 | 11
3 | 40 | 40
3 | 20 | 20
I want to SELECT the product which has sold the most units; in this sample case, it should be the product with ID 20, showing 50 units.
I have tried this:
SELECT
SUM(pv."Units sold")
FROM
"Products" pv
GROUP BY
pv.Product ID;
But this shows all the products, how can I select only the product with the most units sold?
Leaving aside for the moment the possibility of having multiple products with the same number of units sold, you can always sort your results by the sum, highest first, and take the first row:
SELECT pv."Product ID", SUM(pv."Units sold")
FROM "Products" pv
GROUP BY pv."Product ID"
ORDER BY SUM(pv."Units sold") DESC
LIMIT 1
I'm not quite sure whether the double-quote syntax for column and table names will work - exact syntax will depend on your specific RDBMS.
Now, if you do want to get multiple rows when more than one product has the same sum, then the SQL will become a bit more complicated:
SELECT pv.`Product ID`, SUM(pv.`Units sold`)
FROM `Products` pv
GROUP BY pv.`Product ID`
HAVING SUM(pv.`Units sold`) = (
select max(sums)
from (
SELECT SUM(pv2.`Units sold`) as "sums"
FROM `Products` pv2
GROUP BY pv2.`Product ID`
) as subq
)
Here's the sqlfiddle
SELECT SUM(pv."Units sold") as `sum`
FROM "Products" pv
group by pv.Product ID
ORDER BY sum DESC
LIMIT 1
limit 1 + order by
The Best and effective way to this is Max function
Here's The General Syntax of Max function
SELECT MAX(ID) AS id
FROM Products;
and in your Case
SELECT MAX(Units Sold) from products
Here is the Complete Reference to MIN and MAX functions in Query
Click Here
I need to join two tables with the same number of rows. Each table has 1 column. There is NO CONNECTING COLUMN to reference for a join. I need to join them side by side because each table was sorted separately so that numeric values are at the top in descinding order.
The Table Earners has income values from say 200K down to 0. I cannot just select using 2 cases, because then I will have my first row with Incomes above 100K, but the first 20 or so entries in the second row are NULL. I want the second row to also be sorted descending.
I looked up using ORDER BY within CASE but there is no such thing. I have tried to read about row_number() but none of the examples seem to match or make sense.
drop table #20plus
select
case
when Income >= 20000 AND Income < 100000
then Income end as 'mula'
into #20plus
from Earners
order by mula desc
drop table #100plus
select
case
when Income >= 100000
then Income end as 'dinero'
into #100plus
from Earners
order by dinero desc
Select A.dinero, B.mula
FROM #100plus as A JOIN #20plus as B
ON A.????? = B.?????
Since both A and B are sorted descending, moving all NULL to the bottom, what can I reference to join the two tables?
Previous output using one SELECT statement with 2 CASE statements
dinero mula
2.12688e+007 NULL
1.80031e+007 NULL
1.92415e+006 NULL
… …
NULL 93530.7
NULL 91000
NULL 84500
Desired output using one SELECT statement after creating two temp TABLES
dinero mula
2.12688e+007 93530.7
1.80031e+007 91000
1.92415e+006 84500
… 82500
NULL 82000
NULL …
NULL NULL
This is Microsoft SQL Server 2008. I'm super new to this, so please give an answer as clear and simplified as possible. Thank you.
Select A.dinero, B.mula
FROM #100plus as A FULL OUTER JOIN #20plus as B
ON A.dinero = B.mula
ORDER BY A.dinero,B.mula;
If you divide your table into two and use row_number() to generate numbers by descending order, you can connect them by row_number. Note how numbers are produced - row_number is given order by.
; WITH _20plus AS (
SELECT CASE WHEN income >= 20000 AND income < 100000
THEN income
END AS Mula,
Row_number() OVER (ORDER BY CASE WHEN income >= 20000 AND income
< 100000 THEN income END DESC) rn
FROM earners
),
_100plus AS (
SELECT CASE WHEN income >= 100000 THEN income
END AS Dinero,
Row_number() OVER (ORDER BY CASE WHEN income >= 100000
THEN income END DESC) rn
FROM earners
)
SELECT a.dinero,
b.mula
FROM _100plus AS a
INNER JOIN _20plus AS b
ON a.rn = b.rn