Group query results by month and year in postgresql - sql

Question

I have the following database table on a Postgres server:
id date Product Sales
1245 01/04/2013 Toys 1000
1245 01/04/2013 Toys 2000
1231 01/02/2013 Bicycle 50000
456461 01/01/2014 Bananas 4546
I would like to create a query that gives the SUM of the Sales column and groups the results by month and year as follows:
Apr 2013 3000 Toys
Feb 2013 50000 Bicycle
Jan 2014 4546 Bananas
Is there a simple way to do that?

Answer 1

I can't believe the accepted answer has so many upvotes -- it's a horrible method.
Here's the correct way to do it, with date_trunc:
SELECT date_trunc('month', txn_date) AS txn_month, sum(amount) as monthly_sum
FROM yourtable
GROUP BY txn_month
It's bad practice but you might be forgiven if you use
GROUP BY 1
in a very simple query.
You can also use
GROUP BY date_trunc('month', txn_date)
if you don't want to select the date.

Answer 2

select to_char(date,'Mon') as mon,
extract(year from date) as yyyy,
sum("Sales") as "Sales"
from yourtable
group by 1,2
At the request of Radu, I will explain that query:
to_char(date,'Mon') as mon, : converts the "date" attribute into the defined format of the short form of month.
extract(year from date) as yyyy : Postgresql's "extract" function is used to extract the YYYY year from the "date" attribute.
sum("Sales") as "Sales" : The SUM() function adds up all the "Sales" values, and supplies a case-sensitive alias, with the case sensitivity maintained by using double-quotes.
group by 1,2 : The GROUP BY function must contain all columns from the SELECT list that are not part of the aggregate (aka, all columns not inside SUM/AVG/MIN/MAX etc functions). This tells the query that the SUM() should be applied for each unique combination of columns, which in this case are the month and year columns. The "1,2" part is a shorthand instead of using the column aliases, though it is probably best to use the full "to_char(...)" and "extract(...)" expressions for readability.

Answer 3

to_char actually lets you pull out the Year and month in one fell swoop!
select to_char(date('2014-05-10'),'Mon-YY') as year_month; --'May-14'
select to_char(date('2014-05-10'),'YYYY-MM') as year_month; --'2014-05'
or in the case of the user's example above:
select to_char(date,'YY-Mon') as year_month
sum("Sales") as "Sales"
from some_table
group by 1;

Answer 4

There is another way to achieve the result using the date_part() function in postgres.
SELECT date_part('month', txn_date) AS txn_month, date_part('year', txn_date) AS txn_year, sum(amount) as monthly_sum
FROM yourtable
GROUP BY date_part('month', txn_date)
Thanks

Answer 5

Why not just use date_part function. https://www.postgresql.org/docs/8.0/functions-datetime.html
SELECT date_part('year', txn_date) AS txn_year,
date_part('month', txn_date) AS txn_month,
sum(amount) as monthly_sum
FROM payment
GROUP BY txn_year, txn_month
order by txn_year;

Answer 6

Take a look at example 6) of this tutorial -> https://www.postgresqltutorial.com/postgresql-group-by/
You need to call the function on your GROUP BY instead of calling the name of the virtual attribute you created on select.
I was doing what all the answers above recommended and I was getting a column 'year_month' does not exist error.
What worked for me was:
SELECT
date_trunc('month', created_at), 'MM/YYYY' AS month
FROM
"orders"
GROUP BY
date_trunc('month', created_at)

Answer 7

Postgres has few types of timestamps:
timestamp without timezone - (Preferable to store UTC timestamps) You find it in multinational database storage. The client in this case will take care of the timezone offset for each country.
timestamp with timezone - The timezone offset is already included in the timestamp.
In some cases, your database does not use the timezone but you still need to group records in respect with local timezone and Daylight Saving Time (e.g. https://www.timeanddate.com/time/zone/romania/bucharest)
To add timezone you can use this example and replace the timezone offset with yours.
"your_date_column" at time zone '+03'
To add the +1 Summer Time offset specific to DST you need to check if your timestamp falls into a Summer DST. As those intervals varies with 1 or 2 days, I will use an aproximation that does not affect the end of month records, so in this case i can ignore each year exact interval.
If more precise query has to be build, then you have to add conditions to create more cases. But roughly, this will work fine in splitting data per month in respect with timezone and SummerTime when you find timestamp without timezone in your database:
SELECT
"id", "Product", "Sale",
date_trunc('month',
CASE WHEN
Extract(month from t."date") > 03 AND
Extract(day from t."date") > 26 AND
Extract(hour from t."date") > 3 AND
Extract(month from t."date") < 10 AND
Extract(day from t."date") < 29 AND
Extract(hour from t."date") < 4
THEN
t."date" at time zone '+03' -- Romania TimeZone offset + DST
ELSE
t."date" at time zone '+02' -- Romania TimeZone offset
END) as "date"
FROM
public."Table" AS t
WHERE 1=1
AND t."date" >= '01/07/2015 00:00:00'::TIMESTAMP WITHOUT TIME ZONE
AND t."date" < '01/07/2017 00:00:00'::TIMESTAMP WITHOUT TIME ZONE
GROUP BY date_trunc('month',
CASE WHEN
Extract(month from t."date") > 03 AND
Extract(day from t."date") > 26 AND
Extract(hour from t."date") > 3 AND
Extract(month from t."date") < 10 AND
Extract(day from t."date") < 29 AND
Extract(hour from t."date") < 4
THEN
t."date" at time zone '+03' -- Romania TimeZone offset + DST
ELSE
t."date" at time zone '+02' -- Romania TimeZone offset
END)

Answer 8

I also need to find results grouped by YEAR and MONTH.
When I grouped them by TIMESTAMP, sum function grouped them with dates and minutes, but that wasn't what I wanted.
Using this query may be helpful for you.
select sum(sum),
concat(year, '-', month, '-', '01')::timestamp
from (select sum(t.final_price) as sum,
extract(year from t.created_at) as year,
extract(month from t.created_at) as month
from transactions t
where status = 'SUCCESS'
group by t.created_at) t
group by year, month;
transactions table
query result
As you can see in the picture, in '2022-07-01' I have two columns in table, and in query result they are grouped together.