I have a mesh model in a .ply file, I have converted it to an obj and obj.mtl (material) file using an online converter (http://www.greentoken.de/onlineconv/). When I load the obj file into maya I see none of the texture being rendered. I've done some googling and this seems like a common problem, but am yet to find a solution.
Any help is appreciated.
Thanks
Check the texture file paths in your mtl file path. If they have path separators, make sure they are forward slashes not back slashes. For some reason if they are back slashes, the parent directory name will be inserted over the filename and a space when Maya parses them into the File node 'Image Name' field.
e.g. This filepath in the mtl:
map_Ka textures\vase_round.tga
will become this in the Maya File node:
textures nd.tga
Related
I have a txt file which contains numbers. I want to draw a histogram according to this file in root. But I can't do this.
{
TFile *f = new TFile("myfile.root");
f.ls();
TH1F * h1 = (TH1F*)f.Get("h1");
h1->Draw();
}
Have a look at this tutorial from the ROOT website. As far as I know ROOT can't open a plain text file directly. The TFile("myfile.root") call can be used to open a ROOT file (i.e. a binary file created by ROOT containing persistified ROOT objects such as histograms), which as you point out causes errors if you try to open a plain text file using it. The approach shown in the tutorial page is to create a TH1, then use standard C++ I/O streams to read from your text fiule and fill the histogram in the normal way.
I have a csv file that is tared and zipped. So I have test.tar.gz.
I would like, through text file input, read csv file.
I try this tar:gz:file://C:/test/test.tar.gz!/test.tar! use wildcard like ".*\.csv".
But it sometime can't read success.
It throws Exception
org.apache.commons.vfs.FileNotFolderException:
Could not list the contents of
"tar:gz:file:///C:/test/test.tar.gz!/test.tar!/"
because it is not a folder.
I use windows8.1, pdi 5.2
Where it might be wrong?
For a compressed file csv reading, "Text File Input" step in Pentaho Kettle only supports the first files inside the compressed folder(either in Zip/GZip file). Check the Pentaho Wiki in the compression section.
Now for your issue, try removing the wildcard entry since only the first file inside the zip/gzip file will be read. (as explained above)
I have placed a sample code containing both reading zip and gzip files. Check it here.
Hope it helps :)
Intellij taking file path incorrectly: D:\jetty-distribution-9.2.1.v20140609\?D:\images\a.txt
When I give files like
File file = new File("D:\images\1.txt");
System.out.println(file.getAbsolutePath());
The output is
D:\jetty-distribution-9.2.1.v20140609\?D:\images\1.txt
It is considering the file path along with server bin
Where do i need to change the setting to detect the absolute path in intelij.
Please help me.
Use double backslashes \\ to escape the \, then it will work.
File file = new File("D:\\images\\1.txt"); System.out.println(file.getAbsolutePath());
I just downloaded psychopy this morning and have spent the day trying to figure out how to work with builder view. I watched the youtube video "Build your first PsychoPy experiment (Stroop task)" by Jon Pierce. In his video he was explaining how to make a conditions file with excel that would be used in his experiment. I wanted to make a very similar test where images would appear and subjects would be required to give a yes or no answer to them (the correct answer is already predefined). In his conditions file he had the columns 'word' 'colour' and 'corrANS'. I was wondering if instead of a 'word' column, I can have an 'image' column. In this column I would like to upload all my images to them in the same way I would words, and have them correlated to a correct answer of either 'yes' or 'no'. We tried doing this and uploaded images to the conditions file, but we haven't had any success in running the test successfully and were hoping somebody could help us.
Thank you in advance.
P.S. we are not familiar with python, or code in general, so we were hoping to get this running using the builder view.
EDIT: Here is the error message we are receiving when running the program
#### Running: C:\Users\mr00004\Desktop\New folder\1_lastrun.py
4.8397 ERROR Couldn't find image file 'C:/Users/mr00004/Desktop/New folder/PPT Retention 1/ Slide102.JPG'; check path?
Traceback (most recent call last):
File "C:\Users\mr00004\Desktop\New folder\1_lastrun.py", line 174, in
image.setImage(images)
File "C:\Program Files (x86)\PsychoPy2\lib\site-packages\psychopy-1.80.03-py2.7.egg\psychopy\visual\image.py", line 271, in setImage
maskParams=self.maskParams, forcePOW2=False)
File "C:\Program Files (x86)\PsychoPy2\lib\site-packages\psychopy-1.80.03-py2.7.egg\psychopy\visual\basevisual.py", line 652, in createTexture
% (tex, os.path.abspath(tex))#ensure we quit
OSError: Couldn't find image file 'C:/Users/mr00004/Desktop/New folder/PPT Retention 1/ Slide102.JPG'; check path? (tried: C:\Users\mr00004\Desktop\New folder\PPT Retention 1\ Slide102.JPG)
Yes, certainly, that is exactly how PsychoPy is designed to work. Simply place the image names in a column in your conditions file. You can then use the name of that column in the Builder Image component's "Image" field. The appropriate image file for a given trial will be selected.
It is difficult to help you further, though, as you haven't specified what went wrong. "we haven't had any success" doesn't give us much to go on.
Common problems:
(1) Make sure you use full filenames, including extensions (.jpg, .png, etc). These aren't always visible in Windows at least I think, but they are needed by Python.
(2) Have the images in the right place. If you just use a bare filename (e.g. image01.jpg), then PsychoPy will expect that the file is in the same directory as your Builder .psyexp file. If you want to tidy the images away, you could put them in a subfolder. If so, you need to specify a relative path along with the filename (e.g. images/image01.jpg).
(3) Avoid full paths (starting at the root level of your disk): they are prone to errors, and stop the experiment being portable to different locations or computers.
(4) Regardless of platform, use forward slashes (/) not backslashes (\) in your paths.
make a new folder in H drive and fill in the column of image in psychopy as e.g. 'H:\psych\cat.jpg' it works for me
I would like to parse the file location information in an M3U playlist into fully qualified paths. The possible formats in M3U files seem to be:
c:\mydir\songs\tune.mp3
\songs\tune.mp3
..\songs\tune.mp3
For the first example, just leave it alone. For the second add the directory that the playlist resides in so it would become c:\playlists\songs\tune.mp3 and the same for the third case so it would also become: c:\playlists\songs\tune.mp3.
I'm using vb under VS2008 and I can't find a way to recognise each of the potential location formats in the M3U file. System.IO.Path offers no solution that I can find. I've searched extensively for terms like "convert relative path to absolute" but no luck.
Any advice appreciated.
Thanks.
Write a batch script that just reads the m3u file line by line, and then just parse each line looking for ":" , and for "..", and edit the string as needed. You can then just write the "converted" strings to another file...