Calculate Duration between two dates (Month and Year will be Considered) - sql

Question

I have two dates
06-Jan-2009 and 12-Dec-2010
I want to calculate the date difference between these two dates.. (basis on the month and year).
I want to get the answer 2 Year.
But if dates is 06-Jan-2009 And 12-Oct-2010
then I need 10 Months as output.

Answer 1

Try this one:
Declare #SDate DateTime ='06-Jan-2009'
Declare #EDate DateTime ='12-Oct-2009'
select case when DateDiff(M,#sDate,#EDate) <=12
then DateDiff(M,#sDate,#EDate)
else Round( ( Convert(Decimal(18,0)
,DateDiff(M,#sDate,#EDate)/12.0)),0) end

Answer 2

declare #Birthdate datetime
declare #AsOnDate datetime
declare #years int
declare #months int
declare #days int
declare #hours int
declare #minutes int
--NOTE: date of birth must be smaller than As on date,
--else it could produce wrong results
set #Birthdate = '1989-11-30 9:27 pm' --birthdate
set #AsOnDate = Getdate() --current datetime
--calculate years
select #years = datediff(year,#Birthdate,#AsOnDate)
--calculate months if it's value is negative then it
--indicates after __ months; __ years will be complete
--To resolve this, we have taken a flag #MonthOverflow...
declare #monthOverflow int
select #monthOverflow = case when datediff(month,#Birthdate,#AsOnDate) -
( datediff(year,#Birthdate,#AsOnDate) * 12) <0 then -1 else 1 end
--decrease year by 1 if months are Overflowed
select #Years = case when #monthOverflow < 0 then #years-1 else #years end
select #months = datediff(month,#Birthdate,#AsOnDate) - (#years * 12)
--as we do for month overflow criteria for days and hours
--& minutes logic will followed same way
declare #LastdayOfMonth int
select #LastdayOfMonth = datepart(d,DATEADD
(s,-1,DATEADD(mm, DATEDIFF(m,0,#AsOnDate)+1,0)))
select #days = case when #monthOverflow<0 and
DAY(#Birthdate)> DAY(#AsOnDate)
then #LastdayOfMonth +
(datepart(d,#AsOnDate) - datepart(d,#Birthdate) ) - 1
else datepart(d,#AsOnDate) - datepart(d,#Birthdate) end
declare #hoursOverflow int
select #hoursOverflow = case when datepart(hh,#AsOnDate) -
datepart(hh,#Birthdate) <0 then -1 else 1 end
select #hours = case when #hoursOverflow<0 then 24 +
datepart(hh,#AsOnDate) - datepart(hh,#Birthdate)
else datepart(hh,#AsOnDate) - datepart(hh,#Birthdate) end
declare #minutesOverflow int
select #minutesOverflow = case when datepart(mi,#AsOnDate) -
datepart(mi,#Birthdate) <0 then -1 else 1 end
select #minutes = case when #hoursOverflow<0
then 60 - (datepart(mi,#AsOnDate) -
datepart(mi,#Birthdate)) else abs(datepart
(mi,#AsOnDate) - datepart(mi,#Birthdate)) end
select
#Months=case when #days < 0 or DAY(#Birthdate)> DAY(#AsOnDate) then #Months-1 else #Months end
Declare #lastdayAsOnDate int;
set #lastdayAsOnDate = datepart(d,DATEADD(s,-1,DATEADD(mm, DATEDIFF(m,0,#AsOnDate),0)));
Declare #lastdayBirthdate int;
set #lastdayBirthdate = datepart(d,DATEADD(s,-1,DATEADD(mm, DATEDIFF(m,0,#Birthdate)+1,0)));
if (#Days < 0)
(
select #Days = case when( #lastdayBirthdate > #lastdayAsOnDate) then
#lastdayBirthdate + #Days
else
#lastdayAsOnDate + #Days
end
)
print convert(varchar,#years) + ' year(s), ' +
convert(varchar,#months) + ' month(s), ' +
convert(varchar,#days) + ' day(s), ' +
convert(varchar,#hours) + ':' +
convert(varchar,#minutes) + ' hour(s)'

Answer 3

Please tried with below query
Declare #SDate DateTime ='01-Jan-2009'
Declare #EDate DateTime ='12-Oct-2009'
SET #EDate = DATEADD(M, 1, #EDate)
select DateDiff(M,#sDate,#EDate)

Answer 4

select Round( (
Convert(Decimal(18,2),DateDiff(M,'06-Jan-2009','12-Dec-2010')/12.0)),0)
as Years

Answer 5

I think that would be work for me:
DECLARE #start DATETIME='01-Jan-2008'
DECLARE #end DATETIME='10-Nov-2011'
DECLARE #duration INT
--SELECT #start = '2011-10-10', #end = '2013-10-10'
--select DATEPART(dd,#start)
SET #Start = Dateadd(DAY, -( Datepart(DD, #Start) - 1 ), #Start)
SET #end = Dateadd(DAY, -( Datepart(day, #end) - 1 ), #end)
SET #end = Dateadd(day, Day(Dateadd(mm, Datediff(mm, -1, #end), -1)), #end)
SELECT #duration = Datediff(mm, #Start, #end)
SELECT CASE
WHEN #duration = 0 THEN NULL
WHEN #duration%12 = 0 THEN( CONVERT(NVARCHAR, #duration / 12) + ' Year ' )
WHEN #duration > 12 THEN( CONVERT(NVARCHAR, #duration / 12) + ' Year ' + CONVERT(NVARCHAR, #duration % 12) + ' Month ' )
ELSE (SELECT CONVERT(NVARCHAR, #duration % 12) + ' Month')
END

Answer 6

declare #Birthdate datetime
declare #AsOnDate datetime
declare #years varchar(4)
declare #months varchar(3)
declare #days varchar(3)
declare #hours varchar(3)
declare #minutes varchar(2)
set #Birthdate = '1989-11-30 9:27 AM' --birthdate
set #AsOnDate = getdate() --current datetime
select #years = datediff(year,#Birthdate,#AsOnDate)
select #months = datediff(month,#Birthdate,#AsOnDate) -
( datediff(year,#Birthdate,#AsOnDate) * 12)
select #days = datepart(d,#AsOnDate) - datepart(d,#Birthdate)
select #hours = datepart(hh,#AsOnDate) - datepart(hh,#Birthdate)
select #minutes = abs(datepart(mi,#AsOnDate) - datepart(mi,#Birthdate))
print #years + ' year(s), ' +
#months + ' month(s), ' +
#days + ' day(s), ' +
#hours + ':' + #minutes + ' hour(s)'
OUT PUT: