Return tomorrow's day name - objective-c

Question

I would like to return the weekday name of tomorrow (i.e. if today is Sunday, I want Monday). Here's my code that yields today's weekday name.
NSDateFormatter *formatter = [[NSDateFormatter alloc] init];
[formatter setDateFormat:#"EEEE"];
weekDay = [formatter stringFromDate:[NSDate date]];
Rather than messing with NSCalendar, what would be a concise way of doing this (following the code I have here)?
Thank you.

Answer 1

user's language aware:
NSDateFormatter * df = [[NSDateFormatter alloc] init];
NSArray *weekdays = [df weekdaySymbols];
NSDateComponents *c = [[NSDateComponents alloc] init];
c.day = 1;
NSDate *tomorrow = [[NSCalendar currentCalendar] dateByAddingComponents:c
toDate:[NSDate date]
options:0];
c = [[NSCalendar currentCalendar] components:NSWeekdayCalendarUnit
fromDate:tomorrow];
NSString *tomorrowname = weekdays[c.weekday-1];// the value of c.weekday may
// range from 1 (sunday) to 7 (saturday)
NSLog(#"%#", tomorrowname);
if you need to have the name in a certain language, add
[df setLocale:[[NSLocale alloc] initWithLocaleIdentifier:#"en_US_POSIX"]];
after the creation of the date formatter.

Answer 2

Why are you afraid of "messing" with NSCalendar? For using the NSDateComponents methods, you will actually have to make use of NSCalendar. This is my solution for your problem.
// Get the current weekday
NSCalendar *calendar = [[NSCalendar alloc] initWithCalendarIdentifier:NSGregorianCalendar];
NSDateComponents *weekdayComponents = [calendar components:NSWeekdayCalendarUnit fromDate:[NSDate date]];
// !! Sunday = 1
NSInteger weekday = [weekdayComponents weekday];
Now, you can use the NSDateFormatter method -(NSArray *)weekdaySymbols which contains weekdays starting with Sunday at index 0. As the integer returned by [weekdayComponents weekday] starts with 0 for Saturday, we do not have to increase the value stored in weekday:
NSDateFormatter *formatter = [[NSDateFormatter alloc] init];
// !! Sunday = 0
NSUInteger symbolIndex = (weekday < 7) ? weekday : 0;
NSString *weekdaySymbol = [[formatter weekdaySymbols] objectAtIndex:(NSUInteger)symbolIndex];
I hope this was helpful although using NSCalendar to some extent.
EDIT: glektrik's solution is pretty straight ahead. But mind the following statement in the NSDate class reference of - dateByAddingTimeInterval:.
Return Value:
A new NSDate object that is set to seconds seconds relative to the receiver. The date returned might have a representation different from the receiver’s.

Answer 3

Thank you for your comment, Abizern. Here's what I did:
NSDateFormatter *formatter = [[NSDateFormatter alloc] init];
[formatter setDateFormat:#"EEEE"];
weekDay = [formatter stringFromDate:[NSDate date]];
NSDateComponents *tomorrowComponents = [[NSCalendar currentCalendar] components:NSDayCalendarUnit | NSMonthCalendarUnit | NSYearCalendarUnit fromDate:[NSDate date]];
NSDate *compDate = [[NSCalendar currentCalendar] dateFromComponents:tomorrowComponents];
NSDateComponents *offsetComponents = [[NSDateComponents alloc] init];
offsetComponents.day = 1;
NSDate *tomorrow = [[NSCalendar currentCalendar] dateByAddingComponents:offsetComponents toDate:compDate options:0];
nextWeekDay = [formatter stringFromDate:tomorrow];
Two NSString objects (weekDay and nextWeekDay) now store the days of the week names for today and tomorrow (currently Sunday and Monday).
This works well, but I wonder if there's an easier way. Objective-C dates are quite cumbersome :(
Thanks again.