Should be a pretty simple one today. I have a column with a list of contracts:
As you see, some contracts have a "-...." at the end. I need to removed this and any character after this (see desired output). Unfortunately, it's not just 1 character (could be multiple/differenct #s). So I imagine it's going to be a right/len/search combo.
Thoughts?
If the contracts all have the same form, the following is almost standard SQL for doing what you want:
select (case when CTNumber like '%-%-%'
then left(CTNumber, 7)
else CTNumber
end) as DesiredOutput
from t
The like syntax is standard, the case is standard, and most databases have a left() function. This does assume that the form of the CTNumber is such that you always want the first seven characters.
You can use patindex to confirm the presence of two dashes. With a double charindex, you can then return the part of the string before the second dash:
select case
when patindex('%-%-%', col1) > 0 then
left(col1, charindex('-', col1, charindex('-', col1) + 1) - 1)
else col1
end as col1
from dbo.YourTable
Related
I have this query here.
WITH Cte_Reverse
AS (
SELECT CASE PATINDEX('%[^0-9.- ]%', REVERSE(EmailName))
WHEN 0
THEN REVERSE(EmailName)
ELSE left(REVERSE(EmailName), PATINDEX('%[^0-9.- ]%', REVERSE(EmailName)) - 1)
END AS Platform_Campaign_ID,
EmailName
FROM [Arrakis].[xtemp].[Stage_SendJobs_Marketing]
)
SELECT REVERSE(Platform_Campaign_ID) AS Platform_Campaign_ID, EmailName
FROM Cte_Reverse
WHERE REVERSE(Platform_Campaign_ID) <> '2020'
AND REVERSE(Platform_Campaign_ID) <> ''
AND LEN(REVERSE(Platform_Campaign_ID)) = 4;
It is working for the most part, below is a screenshot of the result set.
The query I posted above extracts the 4 numbers to the right out of the initial value that is set for the column I am extracting out of. But I am unable to figure out how I can also have the query ignore cases when the right most value is -v2, -v1, etc. essentially anything with -v and whatever number version it is.
If you want four digits, then one method is:
select substring(emailname, patindex('%[0-9][0-9][0-9][0-9]%', emailname), 4)
SQL Server 2012
I have 3 columns in my table that will be using a function. '[usr].[Udf_OverPunch]'. and substring.
Here is my code:
[usr].[Udf_OverPunch](SUBSTRING(col001, 184, 11)) as REPORTED_GAP_DISCOUNT_PREVIOUS_AMOUNT
This function works appropriately for what I need it to do. It is basically converting symbols or letters to a designated number based on a data dictionary.
The problem I am having is that there are leading zeros. I just asked a questions about leading zeroes but it won't allow me to do it with the function columns because of the symbols cannot be converted to int.
This is what I am using to get rid of leading zeros (but leave one zero) in my code for the other columns:
cast(cast(SUBSTRING(col001, 217, 6) as int) as varchar(25)) as PREVIOUS_REPORTING_PERIOD
This works well at turning a value of '000000' to just one '0' or a value of '000060' to '60' but will not work with the function because of the symbol or letter (when trying to convert to int).
As I mentioned, I have 3 columns which produce values that look something like this when the function is not being used:
'0000019753{'
'0000019748G'
'0000019763H'
My goal here is to use the function while also removing the leading zeros (unless they are all zeros then keep one zero).
This is what I attempted that isn't working because the value contains a character that isn't an integer:
[usr].[Udf_OverPunch]cast(cast(SUBSTRING(col001, 184, 6) as int) as varchar(25)) as REPORTED_GAP_DISCOUNT_PREVIOUS_AMOUNT,
Please let me know if you have any ideas or need more information. :)
select case when col like '%[^0]%' then substring(col,patindex('%[^0]%',col),len(col)) when col like '%0%' then '0' else col end
from tab
or
select case when col like '%[^0]%' then right(col,len(ltrim(replace(col,'0',' ')))) when col like '%0%' then '0' else col end
from tab
I am handling such replacement with T-SQL CLR function that allows replacement using regular expressions. So, the solution will be like this:
[dbo].[fn_Utils_RegexReplace] ([value], '^0{1,}(?=.)', '')
You need to create such function because there are no regular expression support in T-SQL (build-in).
How to create regex replace function in T-SQL?
For example:
try this,
declare #i varchar(50)='0000019753}'--'0000019753'
select case when ISNUMERIC(#i)=1 then
cast(cast(#i as bigint) as varchar(50)) else #i end
or
[usr].[Udf_OverPunch]( case when ISNUMERIC(col001)=1 then
cast(cast(col001 as bigint) as varchar(50)) else col001 end)
Have a ncarchar(MAX) field in SQL table. It has numbers such as 717.08064182582, 39.0676048113, etc. in which I need to only have 3 places after decimal. For instance 717.080, 39.067.
Without converting the field type, would like to get rid of those last n characters, however every row has different number of characters. I believe I could use ROUND (correct me if wrong), but would rather not.
Try this
SELECT CAST(ColumnName AS DECIMAL(18,3))
Without converting it data type As per #vkp Comment
SELECT SUBSTRING(ColumnName ,0,CHARINDEX('.', ColumnName )+4)
select CASE WHEN CHARINDEX('.', Your_column) > 0
THEN SUBSTRING(Your_column, 1, CHARINDEX('.', Your_column) + 3)
ELSE Your_column
END
this is similar as previous answers but more faster and safer
Try this:
SELECT SUBSTRING(Your_column, 1, PATINDEX('%.%', Your_column) + 3)
FROM Your_Table
I have a column string that may be one of the following.
10.0.2531.0
10.50.2500
10.0.2531.60
My requirement is, if there are 3 periods/decimal points, remove the last period/decimal and everything after that.
If I use the following, this will take care of the first row where there is only ".0", however, it does not work for the third row.
select
case
when right(column_1,2) = '.0' then left(column_1,len(column_1)-2)
else column_1 end,
FROM
table_1
I also tried the following but that didn't work.
select
case
when right(column_1,2) = '.' then left(column_1,len(column_1)-2)
when right(column_1,3) = '.' then left(column_1,len(column_1)-3)
else column_1 end,
FROM
table_1
The number after the third period/decimal may be a 0 or another number.
The following works, under the assumption that there are never five periods:
select (case when ip like '%.%.%.%'
then left(ip, len(ip) - charindex('.', reverse(ip))
else ip
end) as firstThree
Use a combination of charindex and substring.
SQL Fiddle
select reverse(substring(reverse(column_1), charindex('.',reverse(column_1))+1, len(column_1)))
from table_1
where len(column_1) - len(replace(column_1,'.','')) = 3
I am working with a database of products, trying to extract the product color from a combined ID/color code column where the color code is always the string following the last hyphen in the column. The issue is that the number of hyphens, product ID, and color code can all be different.
Here are four examples:
ABC123-001
BCD45678-0165
S-XYZ999-M2235
A-S-ABC123-001
The color codes in this case would be 001, 0165, M2235, and 001. What would be the best way to select these into their own column?
I think the following does what you want:
select right(col, charindex('-', reverse(col)) - 1)
In the event that you might have no hyphens in the value, then use a case:
select (case when col like '%-%'
then right(col, charindex('-', reverse(col)) - 1)
else col
end)
It is great to check whether the hyphen exists or not in the string, to avoid the following error:
Invalid length parameter passed to the right function.
SELECT CASE WHEN Col like '%\%' THEN RIGHT(Col,CHARINDEX('\',REVERSE(Col))-1) ELSE '' END AS ColName