How to group by week (7 days) in SQL Server - sql

Question

I would like to show the week column in 7 days increment. Below is my desired output example. Is there a way to write in SQL Server?
Week Football soccer baseball
10/01 - 10/07 1 2 3
10/08 - 10/14 4 5 6
10/15 - 10/21 5 8 0
Here is my attempted script:
CREATE TABLE #TEMP
(
DT CHAR(10),
TO_DT CHAR(10),
BALLs VARCHAR(100),
PRODUCT INT,
Week INT
)
DECLARE
#DT DATETIME,
#TO_DT DATETIME,
#i INT
BEGIN
SET #_DT = '10/01/2012'
SET #TO_DT = DATEADD(DAY,7,#_DT)
set #i=1
WHILE (#DT <= '12/31/2013')
BEGIN
INSERT INTO #TEMP (DT, TO_DT, BALLs, PRODUCT, week)
SELECT
CONVERT(CHAR(10),#DT,101) AS FROM_DT,
CONVERT(CHAR(10),DATEADD(DAY,-1,#TO_DT),101) AS TO_DT,
BALLS,
COUNT(PRODUCT) AS PRODUCT,
#I AS WEEK
FROM #TABLE
GROUP BY BALLS
SET #DT = DATEADD(DAY,7,#DT)
SET #TO_DT = DATEADD(DAY, 7,#TO_DT)
set #i = #i + 1
END
SELECT * FROM #TEMP
DROP TABLE #TEMP
END

Answer 1

DATEDIFF(WK, 0, ) should do the trick.
SELECT
DATEDIFF(WK, 0, MyDate)
, COUNT(*)
FROM (VALUES
('2013-01-01')
, ('2013-01-02')
, ('2013-01-03')
, ('2013-01-04')
, ('2013-01-05')
, ('2013-01-06')
, ('2013-01-07')
) AS X(MyDate)
GROUP BY DATEDIFF(WK, 0, MyDate)
EDIT:
With date formatting it goes like this:
SELECT
CONVERT(VARCHAR(5), DATEADD(WK, WK, 0), 103) + ' - ' + CONVERT(VARCHAR(5), DATEADD(DD, 6, DATEADD(WK, WK, 0)), 103)
, Cnt
FROM (
SELECT
DATEDIFF(WK, 0, MyDate) AS WK
, COUNT(*) AS Cnt
FROM (VALUES
('2013-01-01')
, ('2013-01-02')
, ('2013-01-03')
, ('2013-01-04')
, ('2013-01-05')
, ('2013-01-06')
, ('2013-01-07')
) AS X(MyDate)
GROUP BY DATEDIFF(WK, 0, MyDate)
) AS X