I have a Root controller and I want to authenticate the user, so I added the authentication codes in the layout for Root. I wanted to exclude the index and the login page from the layout, so I added:
layout 'roots', :except => ['index', 'login']
in my RootsController. However, when I open the index and login page, the layout still appears. I tried to use :only to include all the pages I wanted to include, but again, the layout was applied to all pages.
I am really confused. Thanks!
It should work. Have you tried passing layout option in format.html block?
For example:
format.html { :layout => 'roots' }
Related
I'm making an app in Ruby on Rails 3.1.3. I have different types of users (i.e. admin, operator, advertiser, etc...), and each has a different main (or home) page. I want to make a route helper that will give me the respective route for the home page of the current logged in user by using something like home_path. This is mainly for redirecting after certain actions (I want to redirect back to the respective home pages depending on the type of user).
I already have some methods available such as current_user (returns the current logged in user), current_user.admin? (returns true if the current logged in user is admin), current_user.operator?, etc.
Right now I'm using a helper method to do this, but it doesn't seem like a very Rails way to do it. The code follows anyway:
def home_path(params = {})
user = current_user
case user
when user.admin?
params = {:controller => 'administrators', :action => 'index'}.merge(params)
when user.advertiser?
params = {:controller => 'advertisers', :action => 'show', :id => user.advertiser_id}.merge(params)
when user.operator?
params = {:controller => 'callcenter', :action => 'index'}.merge(params)
else
params = {:controller => 'posts', :action => 'home'}.merge(params)
end
url_for(params)
end
I figure this should be done with constrained routes, but I still don't get how it could be done to depend on the .admin?, .operator?, etc. methods. Any help on this would be greatly appreciated.
Using a helper method is fine for this. It should probably end up in your controller, rather than a view helper, though, which gives it access to the current_user. With some cleanup, you can arrive at something that ain't half bad with the same idea you have now.
module DefaultHomeHelper
DEFAULT_PARAMS = { controller: :posts, action: :home }.freeze
ROLE_SPECIFIC_PARAMS = {
admin: { controller: :administrators, action: :index },
advertiser: { controller: :advertisers, action: :show },
operator: { controller: :callcenter, :action: :index }
}.freeze
def home_path(params = {})
url_for params.reverse_merge(ROLE_SPECIFIC_PARAMS[current_user.role] || DEFAULT_PARAMS)
end
end
I've made the assumption you can be more direct and ask your User object to just tell you its role instead of guessing one after the other. You will almost certainly need to tweak the code to accomodate whatever you're calling this on your user. I've also used the newer hash syntax, but if you're running or accommodating Ruby < 1.9 you will need to update. I've used symbols for the actions and controller names, too, because I like referring to objects and methods with symbols instead of strings (and controllers and actions are objects and methods).
You could do a simple include DefaultHomeHelper in your ApplicationController to use this. You can also make it available to your views with helper_method :home_path.
I'm attempting to use a sweeper to clear the home page index action when a new article is published.
The home page cache is working fine in development environment and expires after 1 minute. However when an article is saved, the sweeper action is not triggered.
class HomeController < ApplicationController
caches_action :index, :expires_in => 1.minute
cache_sweeper :article_sweeper
def index
#articles = Article.published.limit(5)
end
end
class ArticleSweeper < ActionController::Caching::Sweeper
observe Article
def after_update(article)
expire_action(:controller => 'home', :action => 'index')
end
end
Either I've gone wrong somewhere or a different approach is needed to expire the home page cache.
My app uses ActiveAdmin to update articles, and Dalli for Memcache (as I'll be using Heroku).
Two steps to the solution:
The controller performing the changes on the model needs to have the sweeper reference, not the destination controller as shown above. In this case it is active_admin, so I added this to my admin/articles.rb file (source) instead of the home controller.
controller do
cache_sweeper :article_sweeper
end
And the controller name needs a slash
expire_action(:controller => '/home', :action => 'index')
That's basically it. I want most of the views in my Ruby on Rails 3.1 app to be rendered without layout, as they will be assigned to divs by jQuery, but I don't want to go to every controller action and set render :layout => false in the respond_to block.
Is it possible to change the default rendering of views to :layout => false? How would I go about configuring that?
Thank you for your help
EDIT
I could also solve it with a way to have something along the lines of:
if request.xhr?
format.html { render :layout => false }
end
be executed on every respond_to block.
class UserController < ApplicationController
layout nil # this sets default layout for all actions in this controller
end
If you want some more advanced behavior (such as determine de layaout in execution time) you also can pass a block that returns nil or a valid layout name:
class UserController < ApplicationController
layout lambda{ ...your stuff... }
end
Here is my controller code:-
def image_test
respond_to do |format|
format.js {render :layout => false}
format.html {redirect_to image_test_path}
end
end
I have got a partial by the name of _image_test.html.erb and and a simple view image_test.html.erb
In my routes I have done this:-
match "/image_test", :to => "/index#image_test"
It works fine when the javascript is enabled in the borwser however when I disable the javascript I want it to redirect me to my image_test.html.erb file. Instead I get a no route match error.
Please help me with this.
Thanks,
I created a workaround for this solution which is giving the desired result of redirecting to another page if javascript is disabled in a browser but I do not know if this is the rails way.
I created empty action corresponding view for those actions and redirected to those views in case javascript is disabled.
Here is an example of what I did :-
def javascript_enabled_view
respond_to do |format|
format.js {render :layout => false}
format.html {redirect_to :action => "javscript_disabled_view"}
end
end
I have got a corresponding js.erb file and the partial for the above action which will work if javascript is enabled in the browser.
def javascript_disabled_view
end
I have got the corresponding html.erb file which will work in case javascript is disabled in the browser.
Thanks,
I have a column in a table called Complete that is a boolean.
How can I (using the Rails 3 / JQuery way) provide a link that will toggle that via AJAX?
Historically, I've simply created my own jquery file, grabbed the click event, and done it by hand. But it really seems like I'm missing something by not doing it the "rails" way. If that makes sense.
I guess I still don't understand how the responds_to JS works, JS with ERB, etc.
Is there a good, up-to-date tutorial on how to do this?
Thanks.
see this post,
Rails 3, Custom Actions, and HTML request methods
and use UJS on top of it.
so you have a fallback, if javascript is disabled
a possible method in the controller looks like that:
# GET /surveys/1/close
def close
#survey.close!
flash[:success] = "Survey successfully closed!"
respond_to do |format|
format.html { redirect_to(surveys_url) }
format.xml { head :ok }
format.js { render :partial => 'list_item', :locals => { :survey => #survey } }
end
end
you could also use a state machine to change the state of your object.